Given is a sequence of N digits a_1a_2\ldots a_N, where each element is 1, 2, or 3. Let x_{i,j} defined as follows:

* x_{1,j} := a_j \quad (1 \leq j \leq N)
* x_{i,j} := | x_{i-1,j} - x_{i-1,j+1} | \quad (2 \leq i \leq N and 1 \leq j \leq N+1-i)



Find x_{N,1}.

Constraints

* 2 \leq N \leq 10^6
* a_i = 1,2,3 (1 \leq i \leq N)

Input

Input is given from Standard Input in the following format:


N
a_1a_2\ldotsa_N


Output

Print x_{N,1}.

Examples

Input

4
1231


Output

1


Input

10
2311312312


Output

0
#include <cstdio>
#include <iostream>
#include <algorithm>
#include <cstring>
#include <vector>
#include <map>
#include <queue>
using namespace std;
typedef long long LL;
const LL INF = 0x3f3f3f3f3f3f3f3f;

LL n,m,tmp = 2,ans = 0;
LL a[2000005];
char ch;
map <LL,LL> mp;

int main(){
	ios::sync_with_stdio(false);
	cin >> n;
	for(LL i = 1;i <= n;i ++){
		cin >> ch;
		a[i] = ch - '0' - 1;
		if(a[i] == 1) tmp = 1;
	}
	if(tmp == 2){
		for(LL i = 1;i <= n;i ++){
			if(a[i] == 2) a[i] = 1;
		}
	}
	else{
		for(LL i = 1;i <= n;i ++){
			if(a[i] == 2) a[i] = 0;
		}
	}
	for(LL i = 1;i <= n;i ++) if(((n - 1) & (i - 1)) == i - 1) ans ^= a[i]; 
	cout << (ans ? tmp : 0) << endl;
	return 0;
}