Vladik and Chloe decided to determine who of them is better at math. Vladik claimed that for any positive integer n he can represent fraction <image> as a sum of three distinct positive fractions in form <image>.

Help Vladik with that, i.e for a given n find three distinct positive integers x, y and z such that <image>. Because Chloe can't check Vladik's answer if the numbers are large, he asks you to print numbers not exceeding 109.

If there is no such answer, print -1.

Input

The single line contains single integer n (1 ≤ n ≤ 104).

Output

If the answer exists, print 3 distinct numbers x, y and z (1 ≤ x, y, z ≤ 109, x ≠ y, x ≠ z, y ≠ z). Otherwise print -1.

If there are multiple answers, print any of them.

Examples

Input

3


Output

2 7 42


Input

7


Output

7 8 56
import java.io.*;
import java.util.*;

public class Main {

    static FastReader in = new FastReader("in.txt");
    static PrintWriter out = new PrintWriter(System.out);

    public static void main(String[] args) throws IOException {
        int n = in.nextInt();

        if(n == 1)
            out.println(-1);
        else
            out.println(n + " " + (n+1) + " " + (n*n+n));

        out.flush();
    }

    static class FastReader {

        BufferedReader br;
        StringTokenizer st;

        public FastReader(String file) {
            try {
                br = new BufferedReader(new FileReader(file));
            } catch (FileNotFoundException e) {
                br = new BufferedReader(new InputStreamReader(System.in));
            }
        }

        String next() {

            while (st == null || !st.hasMoreElements()) {
                try {
                    st = new StringTokenizer(br.readLine());
                } catch (IOException e) { e.printStackTrace(); }
            }

            return st.nextToken();
        }

        int nextInt() { return Integer.parseInt(next()); }

        long nextLong() { return Long.parseLong(next()); }

        double nextDouble() { return Double.parseDouble(next()); }

        String nextLine() {

            String str = "";

            try {
                str = br.readLine();
            } catch (IOException e) { e.printStackTrace(); }

            return str;
        }
    }
}