While walking down the street Vanya saw a label "Hide&Seek". Because he is a programmer, he used & as a bitwise AND for these two words represented as a integers in base 64 and got new word. Now Vanya thinks of some string s and wants to know the number of pairs of words of length |s| (length of s), such that their bitwise AND is equal to s. As this number can be large, output it modulo 109 + 7.

To represent the string as a number in numeral system with base 64 Vanya uses the following rules:

  * digits from '0' to '9' correspond to integers from 0 to 9; 
  * letters from 'A' to 'Z' correspond to integers from 10 to 35; 
  * letters from 'a' to 'z' correspond to integers from 36 to 61; 
  * letter '-' correspond to integer 62; 
  * letter '_' correspond to integer 63. 

Input

The only line of the input contains a single word s (1 ≤ |s| ≤ 100 000), consisting of digits, lowercase and uppercase English letters, characters '-' and '_'.

Output

Print a single integer — the number of possible pairs of words, such that their bitwise AND is equal to string s modulo 109 + 7.

Examples

Input

z


Output

3


Input

V_V


Output

9


Input

Codeforces


Output

130653412

Note

For a detailed definition of bitwise AND we recommend to take a look in the corresponding article in Wikipedia.

In the first sample, there are 3 possible solutions: 

  1. z&_ = 61&63 = 61 = z
  2. _&z = 63&61 = 61 = z
  3. z&z = 61&61 = 61 = z

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;

public class ProblemC {
	
	public static int getInt (char A ) {
		if (Character.isDigit(A)) {
			return A - '0' ; 
		}
		if (A >= 'A' && A <= 'Z' ) {
			return A - 'A' +10 ; 
		}
		if(A>='a' && A <='z' ) {
			return A-'A' +4 ; 
		}
		if(A == '-') 
			return 62 ; 
		else return 63 ; 
					
	}
	
public static void main(String[] args) throws IOException {
BufferedReader bf = new BufferedReader(new InputStreamReader(System.in)) ; 
String s = bf.readLine() ; 
long result = 1 ; 
for (int i = 0; i < s.length(); i++) {
	

char c = s.charAt(i) ; 
int n = getInt(c) ; 

int nn = 6 ; 
while (nn-->0) {
	if((n&1) == 0 ) {
		result= (result*3 )  % 1000000007 ; 
	 
	}
	n = n>>1 ;
}
}
System.out.println(result);


}
}
