One day Jeff got hold of an integer sequence a1, a2, ..., an of length n. The boy immediately decided to analyze the sequence. For that, he needs to find all values of x, for which these conditions hold:

  * x occurs in sequence a. 
  * Consider all positions of numbers x in the sequence a (such i, that ai = x). These numbers, sorted in the increasing order, must form an arithmetic progression. 



Help Jeff, find all x that meet the problem conditions.

Input

The first line contains integer n (1 ≤ n ≤ 105). The next line contains integers a1, a2, ..., an (1 ≤ ai ≤ 105). The numbers are separated by spaces.

Output

In the first line print integer t — the number of valid x. On each of the next t lines print two integers x and px, where x is current suitable value, px is the common difference between numbers in the progression (if x occurs exactly once in the sequence, px must equal 0). Print the pairs in the order of increasing x.

Examples

Input

1
2


Output

1
2 0


Input

8
1 2 1 3 1 2 1 5


Output

4
1 2
2 4
3 0
5 0

Note

In the first test 2 occurs exactly once in the sequence, ergo p2 = 0.
#include <bits/stdc++.h>
using namespace std;
bool sortBySec(const pair<long long, long long> &a,
               const pair<long long, long long> &b) {
  return (a.second < b.second);
}
bool sortbysecdesc(const pair<long long, long long> &a,
                   const pair<long long, long long> &b) {
  return a.second > b.second;
}
bool prime(long long n) {
  if (n < 2) return false;
  for (long long x = 2; x * x <= n; x++) {
    if (n % x == 0) return false;
  }
  return true;
}
bool isPerfectSquare(long double x) {
  if (x >= 0) {
    long long sr = sqrt(x);
    return (sr * sr == x);
  }
  return false;
}
vector<long long> sieve(long long n) {
  long long *arr = new long long[n + 1]();
  vector<long long> vect;
  for (long long i = 2; i <= n; i++)
    if (arr[i] == 0) {
      vect.push_back(i);
      for (long long j = 2 * i; j <= n; j += i) arr[j] = 1;
    }
  return vect;
}
string decimalToBinary(long long n) {
  string s = bitset<64>(n).to_string();
  const auto loc1 = s.find('1');
  if (loc1 != string::npos) return s.substr(loc1);
  return "0";
}
void extendgcd(long long a, long long b, long long *v) {
  if (b == 0) {
    v[0] = 1;
    v[1] = 0;
    v[2] = a;
    return;
  }
  extendgcd(b, a % b, v);
  long long x = v[1];
  v[1] = v[0] - v[1] * (a / b);
  v[0] = x;
  return;
}
long long __gcd(long long a, long long b) {
  if (b > a) {
    return __gcd(b, a);
  }
  if (b == 0) {
    return a;
  }
  return __gcd(b, a % b);
}
long long expo(long long a, long long b, long long mod) {
  long long res = 1;
  while (b > 0) {
    if (b & 1) res = (res * a) % mod;
    a = (a * a) % mod;
    b = b >> 1;
  }
  return res;
}
long long mod_add(long long a, long long b, long long m) {
  a = a % m;
  b = b % m;
  return (((a + b) % m) + m) % m;
}
long long mod_mul(long long a, long long b, long long m) {
  a = a % m;
  b = b % m;
  return (((a * b) % m) + m) % m;
}
long long mod_sub(long long a, long long b, long long m) {
  a = a % m;
  b = b % m;
  return (((a - b) % m) + m) % m;
}
const long long INF = 1e18;
const int32_t M = 1e9 + 7;
const int32_t MM = 998244353;
void solve() {
  long long n;
  cin >> n;
  map<long long, vector<long long>> ma;
  vector<pair<long long, long long>> v;
  long long a;
  for (long long i = 0; i < (n); ++i) {
    cin >> a;
    ma[a].push_back(i + 1);
  }
  for (auto x : ma) {
    long long f = 0;
    long long sam = x.second[0] - x.second[1];
    if ((long long)(x.second).size() == 1) {
      v.push_back({x.first, 0});
    } else {
      for (long long i = 1; i < ((long long)(x.second).size()); ++i) {
        if (sam != x.second[i - 1] - x.second[i]) {
          f = 1;
          break;
        }
      }
      if (f == 0) {
        v.push_back({x.first, abs(sam)});
      }
    }
  }
  cout << (long long)(v).size() << "\n";
  for (auto x : v) {
    cout << x.first << " " << x.second << "\n";
  }
}
signed main() {
  ios_base::sync_with_stdio(false);
  cin.tie(0);
  cout.tie(0);
  long long t = 1;
  while (t--) {
    solve();
  }
  return 0;
}
