There are n people participating in some contest, they start participating in x minutes intervals. That means the first participant starts at time 0, the second participant starts at time x, the third — at time 2 ⋅ x, and so on.

Duration of contest is t minutes for each participant, so the first participant finishes the contest at time t, the second — at time t + x, and so on. When a participant finishes the contest, their dissatisfaction equals to the number of participants that started the contest (or starting it now), but haven't yet finished it.

Determine the sum of dissatisfaction of all participants.

Input

The first line contains a single integer k (1 ≤ k ≤ 1000) — the number of test cases.

Each of the next k lines contains three integers n, x, t (1 ≤ n, x, t ≤ 2 ⋅ 10^9) — the number of participants, the start interval and the contest duration.

Output

Print k lines, in the i-th line print the total dissatisfaction of participants in the i-th test case.

Example

Input


4
4 2 5
3 1 2
3 3 10
2000000000 1 2000000000


Output


5
3
3
1999999999000000000

Note

In the first example the first participant starts at 0 and finishes at time 5. By that time the second and the third participants start, so the dissatisfaction of the first participant is 2. 

The second participant starts at time 2 and finishes at time 7. By that time the third the fourth participants start, so the dissatisfaction of the second participant is 2. 

The third participant starts at 4 and finishes at 9. By that time the fourth participant starts, so the dissatisfaction of the third participant is 1.

The fourth participant starts at 6 and finishes at 11. By time 11 everyone finishes the contest, so the dissatisfaction of the fourth participant is 0.

In the second example the first participant starts at 0 and finishes at time 2. By that time the second participants starts, and the third starts at exactly time 2. So the dissatisfaction of the first participant is 2. 

The second participant starts at time 1 and finishes at time 3. At that time the third participant is solving the contest.
import java.io.*;
import java.util.*;
import java.lang.Math;

public class Main{
	static BufferedReader reader;
	static StringTokenizer tokenizer;
	static PrintWriter writer;

	static int nextInt() throws IOException {
		return Integer.parseInt(nextToken());
	}

	static long nextLong() throws IOException {
		return Long.parseLong(nextToken());
	}

	static double nextDouble() throws IOException {
		return Double.parseDouble(nextToken());
	}

	static String nextToken() throws IOException {
		while (tokenizer == null || !tokenizer.hasMoreTokens()) {
			tokenizer = new StringTokenizer(reader.readLine());
		}
		return tokenizer.nextToken();
	}
	static String nexts() throws IOException {
	  	  tokenizer = new StringTokenizer(reader.readLine());
	   	 String s="";
	   	 while (tokenizer.hasMoreTokens()) {
			s+=tokenizer.nextElement()+" ";
		}
		return s;
	}
	public static int gcd(int x, int y){
		if (y == 0) return x; else return gcd(y, x % y);
	}
	public static long gcd(long x, long y){
		if (y == 0) return x; else return gcd(y, x % y);
	}
    static long digitSum(String x) {
		long a = 0;
		for (int i = 0; i < x.length(); i++) {
			a += x.charAt(i) - '0';
		}
		return a;
	}

	static long digitSum(long x) {
		long a = 0;
		while (x > 0) {
			a += x % 10;
			x /= 10;
		}
		return a;
	}
static int max(int x, int y) {
		return Math.max(x, y);
	}
	static int min(int x, int y) {
		return Math.min(x, y);
	}
	static int max(int x, int y, int z) {
		x = Math.max(x, y);
		x = Math.max(x, z);
		return x;
	}
	static int min(int x, int y, int z) {
		x = Math.min(x, y);
		x = Math.min(x, z);
		return x;
	}
	static long max(long x, long y) {
		return Math.max(x, y);
	}
	static long min(long x, long y) {
		return Math.min(x, y);
	}
	static long max(long x, long y, long z) {
		x = Math.max(x, y);
		x = Math.max(x, z);
		return x;
	}
	static long min(long x, long y, long z) {
		x = Math.min(x, y);
		x = Math.min(x, z);
		return x;
	}
	static double max(double x, double y) {
		return Math.max(x, y);
	}
	static double min(double x, double y) {
		return Math.min(x, y);
	}
	static double max(double x, double y, double z) {
		x = Math.max(x, y);
		x = Math.max(x, z);
		return x;
	}
	static double min(double x, double y, double z) {
		x = Math.min(x, y);
		x = Math.min(x, z);
		return x;
	}
    static void rsort(int[] ar) {
		Arrays.sort(ar);
		int len = ar.length;
		for (int i = 0; i < len / 2; i++) {
			int tmp = ar[i];
			ar[i] = ar[len - 1 - i];
			ar[len - 1 - i] = tmp;
		}
	}
	static void rsort(long[] ar) {
		Arrays.sort(ar);
		int len = ar.length;
		for (int i = 0; i < len / 2; i++) {
			long tmp = ar[i];
			ar[i] = ar[len - 1 - i];
			ar[len - 1 - i] = tmp;
		}
	}
	static void rsort(double[] ar) {
		Arrays.sort(ar);
		int len = ar.length;
		for (int i = 0; i < len / 2; i++) {
			double tmp = ar[i];
			ar[i] = ar[len - 1 - i];
			ar[len - 1 - i] = tmp;
		}
	}
	static void rsort(char[] ar) {
		Arrays.sort(ar);
		int len = ar.length;
		for (int i = 0; i < len / 2; i++) {
			char tmp = ar[i];
			ar[i] = ar[len - 1 - i];
			ar[len - 1 - i] = tmp;
		}
	}
    static long lcm(long a, long b) throws IOException {
		return a * b / gcd(a, b);
	}
    static int lcm(int a, int b) throws IOException {
		return a * b / gcd(a, b);
	}
    static int rev(int x) {
		int a = 0;
		while (x > 0) {
			a = a * 10 + x % 10;
			x /= 10;
		}
		return a;
	}
	public static boolean isPrime(int nn) 
	    { 
	         if(nn<=1)return false;
		  if(nn<=3){return true; }
		 if (nn%2==0||nn%3==0){return false; }
		 for (int i=5;i*i<=nn;i=i+6){ 
	            if(nn%i==0||nn%(i+2)==0){return false;  }}
	         return true; 
	    } 
public static void shuffle(int[] A) {
		for (int i = 0; i < A.length; i++) {
			int j = (int)(i * Math.random());
			int tmp = A[i];A[i] = A[j];A[j] = tmp;
		}
	}
	public static void shufflel(Long[] A) {
		for (int i = 0; i < A.length; i++) {
			int j = (int)(i * Math.random());
			long tmp = A[i];A[i] = A[j];A[j] = tmp;
		}
	}

	public static String reverse(String input)
 	   {
	        StringBuilder input2=new StringBuilder();
	        input2.append(input);
	        input2 = input2.reverse();
	        return input2.toString();
	    }
    public static long power(int x, long n)
	{
	//    long mod = 1000000007;
		if (n == 0) {
			return 1;
		}
        long pow = power(x, n / 2);

		if ((n & 1) == 1) {
			return (x * pow * pow);
		}
		return (pow * pow);
	}
	public static long power(long x, long y, long p)     //x^y%p
	    { 
  	       long res = 1; 
	       x = x % p; 
  	       while (y > 0) { 
 	 	 if (y % 2 == 1) {
      	        	        res = (res * x) % p; 
		 }
  		 y = y >> 1; // y = y/2 
     	     	 x = (x * x) % p; 
     	         } 
  	         return res; 
    	} 

	 static long ncr(int n, int k)  
   	 { 
           		 long res = 1; 
  		   // Since C(n, k) = C(n, n-k)  
 		       if (k > n - k) { 
     		       k = n - k; 
      		  } 
  		  // Calculate value of [n*(n-1)*---*(n-k+1)] / [k*(k-1)*---*1]  
     		   for (int i = 0; i < k; ++i) { 
        		    res *= (n - i); 
         		   res /= (i + 1); 
     		   } 
  		  return res; 
 	   }
	public static int inv(int a, int m)     //Returns modulo inverse of a with respect to m using extended euclid algorithm
	    { 
	        int m0=m,t,q; 
	        int x0=0,x1=1; 
      	        if(m==1){
	                return 0; }
                 	         while(a>1) 
     	        {  
   	                q=a/m; 
    	                t=m; 
                                 m=a%m;a=t; 
    	                t=x0; 
     	                x0=x1-q*x0; 
      	                x1=t; } 
    	          if(x1<0){
 	   	 x1+=m0; }
   	           return x1; 
	    } 

	static int modInverse(int n, int p) 
  	{ 
    	          return (int)power((long)n, (long)(p - 2),(long)p); 
	 } 
	static int ncrmod(int n, int r, int p) 
   	 { 
	        if (r == 0)        // Base case 
	            return 1; 
  	        int[] fac = new int[n + 1];         // Fill factorial array so that we can find all factorial of r, n and n-r 
	        fac[0] = 1; 
	        for (int i = 1; i <= n; i++) 
                                     fac[i] = fac[i - 1] * i % p; 
   	         return (fac[n] * modInverse(fac[r], p) % p * modInverse(fac[n - r], p) % p) % p;     //IMPORTANT
    	}	 

	static int upper(int a[], int x)   //Returns rightest index of x in sorted arr else -1
  	  {                                                //If not present returns index of just smaller element
  	            int n=a.length;
    	        int l=0;
                int r=n-1;
                int ans=-1;
                while(l<=r){
                    int m=(r-l)/2+l;
                    if(a[m]<=x){
                        ans=m;
                        l=m+1;
                    }
                    else{
                        r=m-1;
                    }
                }
                 return ans;  
                } 
	static int lower(int a[], int x)     //Returns leftest index of x in sorted arr else n
 	   {                                                  //If not present returns index of just greater element
 	            int n=a.length;
   	            int l=0;
                int r=n-1;
                int ans=n;
                while(l<=r){
                    int m=(r-l)/2+l;
                    if(a[m]>=x){
                        ans=m;
                        r=m-1;
                    }
                    else{
                         l=m+1;
                    }
                }
                 return ans; 
                 } 

	public static long stringtoint(String s){ // Convert bit string to number
		long a = 1;
		long ans = 0;
		StringBuilder sb = new StringBuilder();
		sb.append(s);  
		sb.reverse();
		s=sb.toString();
		for(int i=0;i<s.length();i++){
			ans = ans + a*(s.charAt(i)-'0');
			a = a*2;
		}
		return ans;
	}
 
	String inttostring(long a,long m){        // a is number and m is length of string required
		String res = "";                     // Convert a number in bit string representation
		for(int i=0;i<(int)m;i++){
			if((a&(1<<i))==1){
				res+='1';
			}else
				res+='0';
		}
		StringBuilder sb = new StringBuilder();
		sb.append(res);  
		sb.reverse();
		res=sb.toString();
		return res;
    }
    static final int inf = Integer.MAX_VALUE / 2;
	static final long linf = Long.MAX_VALUE / 3;
	static final long mod = (long) 1e9 + 7;
    
	
	 static class R implements Comparable<R>{
	        int x, y;
	        public  R(int x, int y) {           //a[i]=new R(x,y);
	            this.x = x;
	            this.y = y;
	        }
	        public int compareTo(R o) {
            		return x-o.x;     //Increasing order(Which is usually required)
        		}
	    }   

//Check if palindrome string - System.out.print(A.equals(new StringBuilder(A).reverse().toString())?"Yes":"No");
	public static void main(String[] args) throws IOException {
		reader = new BufferedReader(new InputStreamReader(System.in));
		tokenizer = null;
		writer = new PrintWriter(System.out);
		solve();
		reader.close();
		writer.close();
	}
	//public static boolean check() {
//
//	}
	private static void solve() throws IOException {
		int tt = nextInt();
		while(tt-->0){
			//String s= nextToken();
			//String[] s = str.split("\\s+");
			//ArrayList<Integer> ar=new ArrayList<Integer>();
			//HashSet<Integer> set=new HashSet<Integer>();
			//HashMap<Integer,String> h=new HashMap<Integer,String>();
			//R[] a1=new R[n];
			//char[] c=nextToken().toCharArray();
			//PriorityQueue<Integer> pq=new PriorityQueue<Integer>(Collections.reverseOrder());
			//NavigableSet<Integer> pq=new TreeSet<>();
			long n = nextLong();
			long x = nextLong();
			long t = nextLong();
			if(n==1){
			    writer.println(0);
			    continue;
			}
			if(t<x){
			    writer.println(0);
			    continue;
			}
			if(t==x){
			    writer.println(n-1);
			    continue;
			}
			long o=t/x;
			if(n<o){
			    writer.println((n-1)*n/2);
			    continue;
			}
			long a=(n-o)*o;
			a+=((o-1)*o)/2;
		//	for(int i=0;i<)
			//shuffle(a);
			//shufflel(a);rsort();
			//Arrays.sort(a);
			//StringBuilder ans=new StringBuilder();
			
            writer.println(a);
            
			
		 }
	}
}