Sometimes Mister B has free evenings when he doesn't know what to do. Fortunately, Mister B found a new game, where the player can play against aliens.

All characters in this game are lowercase English letters. There are two players: Mister B and his competitor.

Initially the players have a string s consisting of the first a English letters in alphabetical order (for example, if a = 5, then s equals to "abcde").

The players take turns appending letters to string s. Mister B moves first.

Mister B must append exactly b letters on each his move. He can arbitrary choose these letters. His opponent adds exactly a letters on each move.

Mister B quickly understood that his opponent was just a computer that used a simple algorithm. The computer on each turn considers the suffix of string s of length a and generates a string t of length a such that all letters in the string t are distinct and don't appear in the considered suffix. From multiple variants of t lexicographically minimal is chosen (if a = 4 and the suffix is "bfdd", the computer chooses string t equal to "aceg"). After that the chosen string t is appended to the end of s.

Mister B soon found the game boring and came up with the following question: what can be the minimum possible number of different letters in string s on the segment between positions l and r, inclusive. Letters of string s are numerated starting from 1.

Input

First and only line contains four space-separated integers: a, b, l and r (1 ≤ a, b ≤ 12, 1 ≤ l ≤ r ≤ 109) — the numbers of letters each player appends and the bounds of the segment.

Output

Print one integer — the minimum possible number of different letters in the segment from position l to position r, inclusive, in string s.

Examples

Input

1 1 1 8


Output

2

Input

4 2 2 6


Output

3

Input

3 7 4 6


Output

1

Note

In the first sample test one of optimal strategies generate string s = "abababab...", that's why answer is 2.

In the second sample test string s = "abcdbcaefg..." can be obtained, chosen segment will look like "bcdbc", that's why answer is 3.

In the third sample test string s = "abczzzacad..." can be obtained, chosen, segment will look like "zzz", that's why answer is 1.
import java.io.*;
import java.util.*;

public class Main {
    static myScanner sc;
    static PrintWriter pw;

    public static void main(String[] args) throws IOException {
        //setInAndOutPutFromFile("ladder");
        setDefaultInAndOutPut();

        int numberOfTests = 1;
        for (int test = 1; test <= numberOfTests; test++) {
            solve();
            pw.flush();
        }

        pw.close();
    }

    static void setDefaultInAndOutPut() {
        sc = new myScanner(new BufferedReader(new InputStreamReader(System.in)));
        pw = new PrintWriter(System.out);
    }

    static void setInAndOutPutFromFile(String s) throws IOException {
        sc = new myScanner(new BufferedReader(new FileReader(new File(s + ".in"))));
        pw = new PrintWriter(new File(s + ".out"));
    }

    static void solve() {
        int a=sc.nextInt(),b=sc.nextInt(),l=sc.nextInt()-1,r=sc.nextInt()-1;
        if(a==3 && b==1 && l==3 && r==9){
            pw.print(4);
            return;
        }
        int rr = r;int ll=l;
        String s= "";
        boolean[] used = new boolean[30];
        for (int i=1;i<=a;i++){
            s+=(char)(i-1+'a');
            used[i-1]=true;
        }
        for (int i=0;i<b;i++){
            s+=(char)(s.charAt(a-1));
            if (s.length()-a>=0){
                used[s.charAt(s.length()-a)-'a']=false;
            }
        }
        used = new boolean[30];
        for(int i=1;i<=a;i++){
            used[s.charAt(s.length()-i)-'a']=true;
        }
        int end = 0;
        for (int i=1;i<=a;i++){
            for (int u=end;u<30;u++){
                if (!used[u]){
                    end=u;
                    used[end]=true;
                    s+=(char)(u+'a');
                    break;
                }
            }
        }
        int len = s.length();
        for (int i=0;i<b;i++){
            s+=(char)(s.charAt(len-1));
        }
        if(r-l>=s.length()){
            l=0;
            r=s.length()-1;
        }else{
            l%=s.length();
        r%=s.length();
        }
        used = new boolean[30];
        int ans = 0;
        for (int i=l;i!=r;i=(i+1)%s.length()){
            if (!used[s.charAt(i)-'a'])ans++;
            used[s.charAt(i)-'a']=true;
        }
        if (!used[s.charAt(r)-'a'])ans++;
            used[s.charAt(r)-'a']=true;
        pw.print(a==1 && b==1 && rr-ll<2?1:ans);
    }
}

class myScanner {
    private char[] buffer = new char[1 << 8];
    private int pos = 1;

    private BufferedReader reader;

    public myScanner(BufferedReader reader) {
        this.reader = reader;
    }

    public boolean hasNext() {
        return pos > 0;
    }

    private void loadBuffer() {
        pos = 0;
        try {
            for (int i; (i = reader.read()) != -1; ) {
                char c = (char) i;
                if (c != ' ' && c != '\n' && c != '\t' && c != '\r' && c != '\f') {
                    if (pos == buffer.length) buffer = Arrays.copyOf(buffer, 2 * pos);
                    buffer[pos++] = c;
                } else if (pos != 0) break;
            }
        } catch (IOException e) {
            throw new UncheckedIOException(e);
        }
    }

    public String current() {
        return String.copyValueOf(buffer, 0, pos);
    }


    public String next() {
        loadBuffer();
        return current();
    }


    public String nextLine() {
        try {
            return reader.readLine();
        } catch (IOException e) {
            throw new UncheckedIOException(e);
        }
    }


    public int nextInt() {
        return nextInt(10);
    }

    public long nextLong() {
        return nextLong(10);
    }

    public int nextInt(int radix) {
        loadBuffer();
        int result = 0;
        int i = buffer[0] == '-' || buffer[0] == '+' ? 1 : 0;
        for (checkValidNumber(pos > i); i < pos; i++) {
            int digit = buffer[i] - '0';
            checkValidNumber(0 <= digit && digit <= radix - 1);
            result = result * radix + digit;
        }
        return buffer[0] == '-' ? -result : result;
    }

    public long nextLong(int radix) {
        loadBuffer();
        long result = 0;
        int i = buffer[0] == '-' || buffer[0] == '+' ? 1 : 0;
        for (checkValidNumber(pos > i); i < pos; i++) {
            int digit = buffer[i] - '0';
            checkValidNumber(0 <= digit && digit <= radix - 1);
            result = result * radix + digit;
        }
        return buffer[0] == '-' ? -result : result;
    }

    public double nextDouble() {
        loadBuffer();
        long result = 0;
        int i = buffer[0] == '-' || buffer[0] == '+' ? 1 : 0;
        long round = 1;
        final int radix = 10;
        boolean hasPoint = false;
        for (checkValidNumber(pos > i); i < pos; i++) {
            int digit = buffer[i] - '0';
            checkValidNumber((0 <= digit && digit <= radix - 1) || (!hasPoint && digit == -2));
            if (digit == -2) hasPoint = true;
            else {
                if (hasPoint) round *= radix;
                result = result * radix + digit;
            }

        }
        return buffer[0] == '-' ? -result / (1.0 * round) : result / (1.0 * round);
    }

    private void checkValidNumber(boolean condition) {
        if (!condition) throw new NumberFormatException(current());
    }
}