We have a sequence of N \times K integers: X=(X_0,X_1,\cdots,X_{N \times K-1}). Its elements are represented by another sequence of N integers: A=(A_0,A_1,\cdots,A_{N-1}). For each pair i, j (0 \leq i \leq K-1,\ 0 \leq j \leq N-1), X_{i \times N + j}=A_j holds.

Snuke has an integer sequence s, which is initially empty. For each i=0,1,2,\cdots,N \times K-1, in this order, he will perform the following operation:

* If s does not contain X_i: add X_i to the end of s.
* If s does contain X_i: repeatedly delete the element at the end of s until s no longer contains X_i. Note that, in this case, we do not add X_i to the end of s.



Find the elements of s after Snuke finished the operations.

Constraints

* 1 \leq N \leq 2 \times 10^5
* 1 \leq K \leq 10^{12}
* 1 \leq A_i \leq 2 \times 10^5
* All values in input are integers.

Input

Input is given from Standard Input in the following format:


N K
A_0 A_1 \cdots A_{N-1}


Output

Print the elements of s after Snuke finished the operations, in order from beginning to end, with spaces in between.

Examples

Input

3 2
1 2 3


Output

2 3


Input

5 10
1 2 3 2 3


Output

3


Input

6 1000000000000
1 1 2 2 3 3


Output




Input

11 97
3 1 4 1 5 9 2 6 5 3 5


Output

9 2 6
n, k = map(int, input().split())
arr = list(map(int, input().split()))

if n == 1:
    if k % 2:
        print(*arr)
    else:
        print(*[])
    exit()

table = {}
original_table = {}
move = {}

for i, a in enumerate(arr):
    if a not in table:
        table[a] = i
        original_table[a] = i
    else:
        move[table[a]], move[i] = i + 1, original_table[a] + 1
        table[a] = i

res = {}
idx = 0

for i in range(1, k + 1):
    while idx in move and move[idx] > idx:
        idx = move[idx]

    res[i] = idx
    if idx == len(arr):
        k %= len(res)
        if not k:
            k = len(res)
        break

    if idx in move:
        idx = move[idx]
    else:
        idx += 1

idx = res[k]
response = []

while idx < len(arr):
    while idx in move and move[idx] > idx:
        idx = move[idx]
    if idx < len(arr):
        response.append(arr[idx])
    idx += 1

print(*response)
