Dima and Anya love playing different games. Now Dima has imagined a new game that he wants to play with Anya.

Dima writes n pairs of integers on a piece of paper (li, ri) (1 ≤ li < ri ≤ p). Then players take turns. On his turn the player can do the following actions:

  1. choose the number of the pair i (1 ≤ i ≤ n), such that ri - li > 2; 
  2. replace pair number i by pair <image> or by pair <image>. Notation ⌊x⌋ means rounding down to the closest integer. 



The player who can't make a move loses.

Of course, Dima wants Anya, who will move first, to win. That's why Dima should write out such n pairs of integers (li, ri) (1 ≤ li < ri ≤ p), that if both players play optimally well, the first one wins. Count the number of ways in which Dima can do it. Print the remainder after dividing the answer by number 1000000007 (109 + 7).

Two ways are considered distinct, if the ordered sequences of the written pairs are distinct.

Input

The first line contains two integers n, p (1 ≤ n ≤ 1000, 1 ≤ p ≤ 109). The numbers are separated by a single space.

Output

In a single line print the remainder after dividing the answer to the problem by number 1000000007 (109 + 7).

Examples

Input

2 2


Output

0


Input

4 4


Output

520


Input

100 1000


Output

269568947
import java.util.Map;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.InputMismatchException;
import java.util.TreeMap;
import java.util.Set;
import java.io.BufferedReader;
import java.io.OutputStream;
import java.util.NavigableMap;
import java.io.PrintWriter;
import java.io.Reader;
import java.io.Writer;
import java.util.SortedMap;
import java.io.InputStream;

/**
 * Built using CHelper plug-in
 * Actual solution is at the top
 * @author Niyaz Nigmatullin
 */
public class Main {
	public static void main(String[] args) {
		InputStream inputStream = System.in;
		OutputStream outputStream = System.out;
		FastScanner in = new FastScanner(inputStream);
		FastPrinter out = new FastPrinter(outputStream);
		TaskE solver = new TaskE();
		solver.solve(1, in, out);
		out.close();
	}
}

class TaskE {

    static final int MOD = 1000000007;

    public void solve(int testNumber, FastScanner in, FastPrinter out) {
        int n = in.nextInt();
        int p = in.nextInt();
        NavigableMap<Integer, Integer> g = new TreeMap<Integer, Integer>();
        g.put(1, 0);
        g.put(3, 1);
        int lastG = 1;
        for (int d = 3; d < p - 1; ) {
            int a = d / 3;
            int b = d - d / 3;
            Integer na = g.higherKey(a);
            Integer nb = g.higherKey(b);
            long z1 = na * 3L;
            long z2 = 3L * nb / 2;
            while (z2 - z2 / 3 >= nb) {
                z2--;
            }
            while (z2 - z2 / 3 < nb) {
                ++z2;
            }
            long z = Math.min(z1, z2);
            if (z > p - 1) {
                break;
            }
            int zi = (int) z;
            int ga = g.get(g.floorKey(zi / 3));
            int gb = g.get(g.floorKey(zi - zi / 3));
            int ng = -1;
            for (int j = 0; j < 3; j++) {
                if (j == ga || j == gb) {
                    continue;
                }
                ng = j;
                break;
            }
            if (ng != lastG) {
                g.put(zi, ng);
            }
            lastG = ng;
            d = zi;
        }
        long[] count = new long[3];
        for (int i : g.keySet()) {
            Integer ni = g.higherKey(i);
            if (ni == null) {
                ni = p;
            }
            int first = p - i;
            int second = p - ni;
            count[g.get(i)] += s(second + 1, first + 1);
        }
        for (int i = 0; i < 3; i++) {
            count[i] %= MOD;
        }
        int[][] dp = new int[n + 1][4];
        dp[0][0] = 1;
        for (int i = 1; i <= n; i++) {
            for (int x = 0; x < 3; x++) {
                for (int y = 0; y < 4; y++) {
                    dp[i][x ^ y] = (int) ((dp[i][x ^ y] + (long) dp[i - 1][y] * count[x]) % MOD);
                }
            }
        }
        long ans = 0L + dp[n][1] + dp[n][2] + dp[n][3];
        out.println(ans % MOD);
    }

    static long s(int a, int b) {
        if (a >= b) {
            return 0;
        }
        --b;
        --a;
        long ret = ss(b) - ss(a);
        return ret;
    }

    static long ss(int n) {
        return (long) n * (n + 1) / 2;
    }
}

class FastScanner extends BufferedReader {

    boolean isEOF;

    public FastScanner(InputStream is) {
        super(new InputStreamReader(is));
    }

    public int read() {
        try {
            int ret = super.read();
            if (isEOF && ret < 0) {
                throw new InputMismatchException();
            }
            isEOF = ret == -1;
            return ret;
        } catch (IOException e) {
            throw new InputMismatchException();
        }
    }

    static boolean isWhiteSpace(int c) {
        return c >= -1 && c <= 32;
    }

    public int nextInt() {
        int c = read();
        while (isWhiteSpace(c)) {
            c = read();
        }
        int sgn = 1;
        if (c == '-') {
            sgn = -1;
            c = read();
        }
        int ret = 0;
        while (!isWhiteSpace(c)) {
            if (c < '0' || c > '9') {
                throw new NumberFormatException("digit expected " + (char) c
                        + " found");
            }
            ret = ret * 10 + c - '0';
            c = read();
        }
        return ret * sgn;
    }

    }

class FastPrinter extends PrintWriter {

    public FastPrinter(OutputStream out) {
        super(out);
    }

    public FastPrinter(Writer out) {
        super(out);
    }


}

