Fox Ciel has some flowers: r red flowers, g green flowers and b blue flowers. She wants to use these flowers to make several bouquets. There are 4 types of bouquets:

  * To make a "red bouquet", it needs 3 red flowers. 
  * To make a "green bouquet", it needs 3 green flowers. 
  * To make a "blue bouquet", it needs 3 blue flowers. 
  * To make a "mixing bouquet", it needs 1 red, 1 green and 1 blue flower. 



Help Fox Ciel to find the maximal number of bouquets she can make.

Input

The first line contains three integers r, g and b (0 ≤ r, g, b ≤ 109) — the number of red, green and blue flowers.

Output

Print the maximal number of bouquets Fox Ciel can make.

Examples

Input

3 6 9


Output

6


Input

4 4 4


Output

4


Input

0 0 0


Output

0

Note

In test case 1, we can make 1 red bouquet, 2 green bouquets and 3 blue bouquets.

In test case 2, we can make 1 red, 1 green, 1 blue and 1 mixing bouquet.
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;

public class B {

	public static void main(String[] args) throws IOException {
		StringBuilder buf = new StringBuilder();
		BufferedReader in = new BufferedReader(new InputStreamReader(System.in));

		String[] rgb = in.readLine().split(" ");
		int r = Integer.parseInt(rgb[0]);
		int g = Integer.parseInt(rgb[1]);
		int b = Integer.parseInt(rgb[2]);

		int f = 0;

		if (r * g * b == 0) {
			f += r / 3;
			f += g / 3;
			f += b / 3;
		} else {
			if (r > 3) {
				f += (r - 1) / 3;
			}
			if (g > 3) {
				f += (g - 1) / 3;
			}
			if (b > 3) {
				f += (b - 1) / 3;
			}

			int rr = r % 3;
			if (rr == 0) {
				rr += 3;
			}
			int gg = g % 3;
			if (gg == 0) {
				gg += 3;
			}
			int bb = b % 3;
			if (bb == 0) {
				bb += 3;
			}
			int c = rr + gg + bb;
			if (c == 9) {
				f += 3;
			} else if (c > 6) {
				f += 2;
			} else if (rr * bb * gg == 8) {
				f += 2;
			} else {
				f++;
			}
		}

		System.out.println(Integer.toString(f));
	}
}