You are given a forest with N vertices and M edges. The vertices are numbered 0 through N-1. The edges are given in the format (x_i,y_i), which means that Vertex x_i and y_i are connected by an edge.

Each vertex i has a value a_i. You want to add edges in the given forest so that the forest becomes connected. To add an edge, you choose two different vertices i and j, then span an edge between i and j. This operation costs a_i + a_j dollars, and afterward neither Vertex i nor j can be selected again.

Find the minimum total cost required to make the forest connected, or print `Impossible` if it is impossible.

Constraints

* 1 ≤ N ≤ 100,000
* 0 ≤ M ≤ N-1
* 1 ≤ a_i ≤ 10^9
* 0 ≤ x_i,y_i ≤ N-1
* The given graph is a forest.
* All input values are integers.

Input

Input is given from Standard Input in the following format:


N M
a_0 a_1 .. a_{N-1}
x_1 y_1
x_2 y_2
:
x_M y_M


Output

Print the minimum total cost required to make the forest connected, or print `Impossible` if it is impossible.

Examples

Input

7 5
1 2 3 4 5 6 7
3 0
4 0
1 2
1 3
5 6


Output

7


Input

5 0
3 1 4 1 5


Output

Impossible


Input

1 0
5


Output

0
n,m=map(int,input().split())
a=list(map(int,input().split()))
f=[[] for _ in range(n)]
for _ in range(m):
  x,y=map(int,input().split())
  f[x].append(y)
  f[y].append(x)
if m==n-1:
  print(0)
  exit()
if (n-m-1)*2>n:
  print('Impossible')
  exit()
from heapq import heappop,heappush,heapify
mi=set(list(range(n)))
dg={}
dg1c=[]
while mi:
  gk=mi.pop()
  #if len(f[gk])==0:
  #  dg1c.append(a[gk])
  #  continue
  todo=[gk]
  dg[gk]=[]
  while todo:
    v=todo.pop()
    dg[gk].append(a[v])
    for nv in f[v]:
      if nv in mi:
        todo.append(nv)
        mi.discard(nv)
# 頂点が2以上ある連結成分の個数
ren=n-m-len(dg1c)
topheap=[]
ans=0
ary=[]
cnt=0
#print(dg)
#print(f)
#print(dg1c)

for k in dg.keys():
  t=min(dg[k])
  ans+=t
  cnt+=1
  dg[k].remove(t)
  ary+=dg[k]
ary.sort()
ans+=sum(ary[:(n-m-1)*2-cnt])
print(ans)
