You are given a string s of length n. Does a tree with n vertices that satisfies the following conditions exist?

* The vertices are numbered 1,2,..., n.
* The edges are numbered 1,2,..., n-1, and Edge i connects Vertex u_i and v_i.
* If the i-th character in s is `1`, we can have a connected component of size i by removing one edge from the tree.
* If the i-th character in s is `0`, we cannot have a connected component of size i by removing any one edge from the tree.



If such a tree exists, construct one such tree.

Constraints

* 2 \leq n \leq 10^5
* s is a string of length n consisting of `0` and `1`.

Input

Input is given from Standard Input in the following format:


s


Output

If a tree with n vertices that satisfies the conditions does not exist, print `-1`.

If a tree with n vertices that satisfies the conditions exist, print n-1 lines. The i-th line should contain u_i and v_i with a space in between. If there are multiple trees that satisfy the conditions, any such tree will be accepted.

Examples

Input

1111


Output

-1


Input

1110


Output

1 2
2 3
3 4


Input

1010


Output

1 2
1 3
1 4
#include <bits/stdc++.h>

using namespace std;

int main() {
  ios::sync_with_stdio(0);
  cin.tie(0);

  int n;
  string s;

  cin >> s;

  n = (int)s.size();
  s = '0' + s;

  if (s[1] == '0') {
    cout << "-1\n";
    return 0;
  }

  if (s[n] == '1') {
    cout << "-1\n";
    return 0;
  }

  for (int i = 1; i < n; i++) {
    if (s[i] != s[n - i]) {
      cout << "-1\n";
      return 0;
    }
  }

  int rt = 1;
  for (int i = 1; i <= n - 1; i++) {
    cout << rt << ' ' << i + 1 << '\n';
    if (s[i] == '1') rt = i + 1;
  }

  return 0;
}
