You are planning to buy an apartment in a n-floor building. The floors are numbered from 1 to n from the bottom to the top. At first for each floor you want to know the minimum total time to reach it from the first (the bottom) floor.

Let:

  * a_i for all i from 1 to n-1 be the time required to go from the i-th floor to the (i+1)-th one (and from the (i+1)-th to the i-th as well) using the stairs; 
  * b_i for all i from 1 to n-1 be the time required to go from the i-th floor to the (i+1)-th one (and from the (i+1)-th to the i-th as well) using the elevator, also there is a value c — time overhead for elevator usage (you need to wait for it, the elevator doors are too slow!). 



In one move, you can go from the floor you are staying at x to any floor y (x ≠ y) in two different ways:

  * If you are using the stairs, just sum up the corresponding values of a_i. Formally, it will take ∑_{i=min(x, y)}^{max(x, y) - 1} a_i time units. 
  * If you are using the elevator, just sum up c and the corresponding values of b_i. Formally, it will take c + ∑_{i=min(x, y)}^{max(x, y) - 1} b_i time units. 



You can perform as many moves as you want (possibly zero).

So your task is for each i to determine the minimum total time it takes to reach the i-th floor from the 1-st (bottom) floor.

Input

The first line of the input contains two integers n and c (2 ≤ n ≤ 2 ⋅ 10^5, 1 ≤ c ≤ 1000) — the number of floors in the building and the time overhead for the elevator rides.

The second line of the input contains n - 1 integers a_1, a_2, ..., a_{n-1} (1 ≤ a_i ≤ 1000), where a_i is the time required to go from the i-th floor to the (i+1)-th one (and from the (i+1)-th to the i-th as well) using the stairs.

The third line of the input contains n - 1 integers b_1, b_2, ..., b_{n-1} (1 ≤ b_i ≤ 1000), where b_i is the time required to go from the i-th floor to the (i+1)-th one (and from the (i+1)-th to the i-th as well) using the elevator.

Output

Print n integers t_1, t_2, ..., t_n, where t_i is the minimum total time to reach the i-th floor from the first floor if you can perform as many moves as you want.

Examples

Input


10 2
7 6 18 6 16 18 1 17 17
6 9 3 10 9 1 10 1 5


Output


0 7 13 18 24 35 36 37 40 45 


Input


10 1
3 2 3 1 3 3 1 4 1
1 2 3 4 4 1 2 1 3


Output


0 2 4 7 8 11 13 14 16 17 
import java.util.*;
import java.lang.*;
import java.io.*;
public class Codechef
{       static PrintWriter out=new PrintWriter(System.out);static FastScanner in = new FastScanner(System.in);static class FastScanner {BufferedReader br;StringTokenizer stok;FastScanner(InputStream is) {br = new BufferedReader(new InputStreamReader(is));}
        String next() throws IOException {while (stok == null || !stok.hasMoreTokens()) {String s = br.readLine();if (s == null) {return null;}
                stok = new StringTokenizer(s);}return stok.nextToken();}
        int ni() throws IOException {return Integer.parseInt(next());}long nl() throws IOException {return Long.parseLong(next());}double nd() throws IOException {return Double.parseDouble(next());}char nc() throws IOException {return (char) (br.read());}String ns() throws IOException {return br.readLine();}
        int[] nia(int n) throws IOException{int a[] = new int[n];for (int i = 0; i < n; i++)a[i] = ni();return a;}long[] nla(int n) throws IOException {long a[] = new long[n];for (int i = 0; i < n; i++)a[i] = nl();return a;}
        double[] nda(int n)throws IOException {double a[] = new double[n];for (int i = 0; i < n; i++)a[i] = nd();return a;}int [][] imat(int n,int m) throws IOException{int mat[][]=new int[n][m];for(int i=0;i<n;i++){for(int j=0;j<m;j++)mat[i][j]=ni();}return mat;}
    }
	static long mod=Long.MAX_VALUE;
	static int temp=0;
	public static void main (String[] args) throws java.lang.Exception
	{   int i,j;
	    HashMap<Integer,Integer> hm=new HashMap<Integer,Integer>();
		/*  if(hm.containsKey(z))
		        hm.put(z,hm.get(z)+1);
		    else
		        hm.put(z,1);
		 */       
        ArrayList<Integer> arr=new ArrayList<Integer>();
        HashSet<Integer> set=new HashSet<Integer>();
        PriorityQueue<Integer> pq=new PriorityQueue<Integer>();
        int n=in.ni();
        long c=in.nl();
        long a[]=in.nla(n-1);
        long b[]=in.nla(n-1);
        long dp[][]=new long[2][n];
        dp[1][0]=c;
        for(i=1;i<n;i++)
        {   dp[0][i]=Math.min(dp[0][i-1]+a[i-1],dp[1][i-1]+a[i-1]);
            dp[1][i]=Math.min(dp[1][i-1]+b[i-1],dp[0][i-1]+c+b[i-1]);
        }
        for(i=0;i<n;i++)
            out.print(Math.min(dp[0][i],dp[1][i])+" ");
        out.close();
	}
	static void withcarry(String str1, String str2)  
    {  if (str1.length() > str2.length()){  
        String t = str1; 
        str1 = str2; 
        str2 = t; 
        } 
        String str = "";  
        int n1 = str1.length(), n2 = str2.length();  
        str1=new StringBuilder(str1).reverse().toString(); 
        str2=new StringBuilder(str2).reverse().toString(); 
        int carry = 0;  
        for (int i = 0; i < n1; i++)  
        {  int sum = ((int)(str1.charAt(i) - '0') +  
                    (int)(str2.charAt(i) - '0') + carry);  
            str += (char)(sum % 10 + '0');  
            carry = sum / 10;  
        }  
      for (int i = n1; i < n2; i++)  
        {   int sum = ((int)(str2.charAt(i) - '0') + carry);  
        str += (char)(sum % 10 + '0');  
        carry = sum / 10;  
        }  
    if (carry > 0)  
        str += (char)(carry + '0');  
    str = new StringBuilder(str).reverse().toString(); 
    System.out.print(str);  
    } 
	static String withoutcarry(String str1, String str2)  
    {  if (str1.length() > str2.length()){  
        String t = str1; 
        str1 = str2; 
        str2 = t; 
        } 
        String str = "";  
        int n1 = str1.length(), n2 = str2.length();  
        str1=new StringBuilder(str1).reverse().toString(); 
        str2=new StringBuilder(str2).reverse().toString(); 
        int carry = 0;  
        for (int i = 0; i < n1; i++)  
        {  int sum = ((int)(str1.charAt(i) - '0') +  
                    (int)(str2.charAt(i) - '0') + carry);  
            str += (char)(sum % 10 + '0');  
            carry = sum / 10;  
        }  
      for (int i = n1; i < n2; i++)  
        {   int sum = ((int)(str2.charAt(i) - '0') + carry);  
        str += (char)(sum % 10 + '0');  
        carry = sum / 10;  
        }  
        temp=carry;
        if (carry > 0)  
            str += (char)(carry + '0');  
        str = new StringBuilder(str).reverse().toString(); 
        return str;
} 
	
	
	static class pair implements Comparable<pair>{
		int x, y;
		public pair(int x, int y){this.x = x; this.y = y;}
		@Override
		public int compareTo(pair arg0) 
		{   if(x<arg0.x)    return -1;
		    else if(x==arg0.x)
		    {   if(y<arg0.y)    return -1;
		        else if(y>arg0.y)   return 1;
		        else    return 0;
		    }
		    else    return 1;
		}
	}
	static long gcd(long a,long b)
	{   if(b==0)
	        return a;
	    return gcd(b,a%b);    
	}
	static long exponent(long a,long n)
	{   long ans=1;
	    while(n!=0)
	    {   if(n%2==1)
	            ans=(ans*a)%mod;
	       a=(a*a)%mod;
	       n=n>>1;
	    }
	    return ans;
	}
	static int binarySearch(int a[], int item, int low, int high) 
    {   if (high <= low) 
            return (item > a[low])?  (low + 1): low; 
        int mid = (low + high)/2; 
        if(item == a[mid]) 
            return mid+1; 
        if(item > a[mid]) 
            return binarySearch(a, item, mid+1, high); 
        return binarySearch(a, item, low, mid-1); 
    } 
    static void merge(int arr[], int l, int m, int r) {   
        int n1 = m - l + 1; int n2 = r - m; int L[] = new int [n1]; int R[] = new int [n2]; 
        
        for (int i=0; i<n1; ++i) L[i] = arr[l + i]; for (int j=0; j<n2; ++j) R[j] = arr[m + 1+ j]; int i = 0, j = 0; int k = l; while (i < n1 && j < n2) {   if (L[i] <= R[j]) {   arr[k] = L[i]; i++; } else{   arr[k] = R[j]; j++; } k++; } while (i < n1){   arr[k] = L[i]; i++; k++; } while (j < n2) { arr[k] = R[j];   j++;     k++; } 
    } 
    static void Sort(int arr[], int l, int r) {if (l < r) {   int m = (l+r)/2; Sort(arr, l, m); Sort(arr , m+1, r); merge(arr, l, m, r); } } 
    
    static void sort(int a[])
    {Sort(a,0,a.length-1);}
}