

Input

The first line of the input contains a single integer N (1 ≤ N ≤ 24). The next N lines contain 5 space-separated integers each. The first three integers will be between 0 and 2, inclusive. The last two integers will be between 0 and 3, inclusive. The sum of the first three integers will be equal to the sum of the last two integers.

Output

Output the result – a string of lowercase English letters.

Examples

Input


1
1 0 0 1 0


Output


a


Input


10
2 0 0 1 1
1 1 1 2 1
2 1 0 1 2
1 1 0 1 1
2 1 0 2 1
1 1 1 2 1
1 2 1 3 1
2 0 0 1 1
1 1 0 1 1
1 1 2 2 2


Output


codeforcez


d={
    "i":(1,1,0,1,1), #aie
    "a":(1,0,0,1,0),
    "b":(1,1,0,2,0),
    "c":(2,0,0,1,1),
    "d":(2,1,0,1,2),
    "e":(1,1,0,1,1),
    "f":(2,1,0,2,1),
    "g":(2,2,0,2,2),
    "h":(1,2,0,2,1),
    "j":(1,2,0,1,2),

    "s":(1,1,1,2,1),
    "k":(1,0,1,2,0),
    "l":(1,1,1,3,0),
    "m":(2,0,1,2,1),
    "n":(2,1,1,2,2),
    "o":(1,1,1,2,1),
    "p":(2,1,1,3,1),
    "q":(2,2,1,3,2),
    "r":(1,2,1,3,1),
    "t":(1,2,1,2,2),

    "u":(1,0,2,2,1),
    "v":(1,1,2,3,1),
    "x":(2,0,2,2,2),
    "y":(2,1,2,2,3),
    "z":(1,1,2,2,2),

    "w":(1,2,1,1,3),

}

ks=d.keys()
invdict= dict(zip([d[k] for k in ks],ks))

#print(d)
#print(invdict)

#print(len(d), len(invdict))

n=int(input())
res=""
for i in range(n):
   a=tuple([int(k) for k in input().split()])
   res+=invdict[a]
print(res)