Fox Ciel has some flowers: r red flowers, g green flowers and b blue flowers. She wants to use these flowers to make several bouquets. There are 4 types of bouquets:

  * To make a "red bouquet", it needs 3 red flowers. 
  * To make a "green bouquet", it needs 3 green flowers. 
  * To make a "blue bouquet", it needs 3 blue flowers. 
  * To make a "mixing bouquet", it needs 1 red, 1 green and 1 blue flower. 



Help Fox Ciel to find the maximal number of bouquets she can make.

Input

The first line contains three integers r, g and b (0 ≤ r, g, b ≤ 109) — the number of red, green and blue flowers.

Output

Print the maximal number of bouquets Fox Ciel can make.

Examples

Input

3 6 9


Output

6


Input

4 4 4


Output

4


Input

0 0 0


Output

0

Note

In test case 1, we can make 1 red bouquet, 2 green bouquets and 3 blue bouquets.

In test case 2, we can make 1 red, 1 green, 1 blue and 1 mixing bouquet.
a,b,c=map(int,input().split())

x=a//3+b//3+c//3+min(a%3,b%3,c%3)
y=min(a,b,c)
if ((a-y+1)%3==0 and ((b-y+1)%3==0) and c!=0)or  ((a-y+1)%3==0 and (c-y+1)%3==0 and b!=0) or ((b-y+1)%3==0 and (c-y+1)%3==0 and a!=0):
    a-=(y-1)
    b-=(y-1)
    c-=(y-1)
    #print(a,b,c)
    y+=(-1+(a//3+b//3+c//3))
else:
    a-=y 
    b-=y
    c-=y
    y+=(a//3+b//3+c//3)
print(max(y,x))
#print(y)
