Snuke is introducing a robot arm with the following properties to his factory:

* The robot arm consists of m sections and m+1 joints. The sections are numbered 1, 2, ..., m, and the joints are numbered 0, 1, ..., m. Section i connects Joint i-1 and Joint i. The length of Section i is d_i.
* For each section, its mode can be specified individually. There are four modes: `L`, `R`, `D` and `U`. The mode of a section decides the direction of that section. If we consider the factory as a coordinate plane, the position of Joint i will be determined as follows (we denote its coordinates as (x_i, y_i)):
* (x_0, y_0) = (0, 0).
* If the mode of Section i is `L`, (x_{i}, y_{i}) = (x_{i-1} - d_{i}, y_{i-1}).
* If the mode of Section i is `R`, (x_{i}, y_{i}) = (x_{i-1} + d_{i}, y_{i-1}).
* If the mode of Section i is `D`, (x_{i}, y_{i}) = (x_{i-1}, y_{i-1} - d_{i}).
* If the mode of Section i is `U`, (x_{i}, y_{i}) = (x_{i-1}, y_{i-1} + d_{i}).



Snuke would like to introduce a robot arm so that the position of Joint m can be matched with all of the N points (X_1, Y_1), (X_2, Y_2), ..., (X_N, Y_N) by properly specifying the modes of the sections. Is this possible? If so, find such a robot arm and how to bring Joint m to each point (X_j, Y_j).

Constraints

* All values in input are integers.
* 1 \leq N \leq 1000
* -10^9 \leq X_i \leq 10^9
* -10^9 \leq Y_i \leq 10^9

Input

Input is given from Standard Input in the following format:


N
X_1 Y_1
X_2 Y_2
:
X_N Y_N


Output

If the condition can be satisfied, follow the following format. If the condition cannot be satisfied, print `-1`.


m
d_1 d_2 ... d_m
w_1
w_2
:
w_N


m and d_i are the configurations of the robot arm. Refer to the problem statement for what each of them means. Here, 1 \leq m \leq 40 and 1 \leq d_i \leq 10^{12} must hold. Also, m and d_i must all be integers.

w_j is a string of length m that represents the way to bring Joint m of the robot arm to point (X_j, Y_j). The i-th character of w_j should be one of the letters `L`, `R`, `D` and `U`, representing the mode of Section i.

Examples

Input

3
-1 0
0 3
2 -1


Output

2
1 2
RL
UU
DR


Input

5
0 0
1 0
2 0
3 0
4 0


Output

-1


Input

2
1 1
1 1


Output

2
1 1
RU
UR


Input

3
-7 -3
7 3
-3 -7


Output

5
3 1 4 1 5
LRDUL
RDULR
DULRD
#include <bits/stdc++.h>
using namespace std;

#define rep(i,n) for(int (i)=0;(i)<(n);(i)++)
#define reps(i,s,n) for(int (i)=(s);(i)<(n);(i)++)
#define repr(i,n) for(int (i)=(n)-1;(i)>=0;(i)--)
#define forin(i,array) for(auto& x:array)
#define all(v) (v).begin(),(v).end()
#define pb push_back
#define mod 1000000007
#define inf 10000000000000


typedef long long ll;
typedef vector<int> vint;
typedef vector<ll> vll;
typedef pair<int,int> pint;
typedef pair<ll,ll> pll;
typedef vector<pint> vpint;

vll x(1000),y(1000);
vll arm(40);

int main(){

    int n;

    cin>>n;

    rep(i,n){
        cin>>x[i]>>y[i];
        if(abs(x[i]+y[i])%2!=abs(x[0]+y[0])%2){
            cout<<-1<<endl;
            return 0;
        }
    }

    int m=39;
    rep(i,m)arm[i]=(ll)pow(2,m-i-1);
    if(abs(x[0]+y[0])%2==0){
        m++;
        arm[m-1]=1;
    }
    cout<<m<<endl;
    rep(i,m)cout<<arm[i]<<" ";
    cout<<endl;
    rep(i,n){
        string s="";
        rep(j,m){
            if(abs(x[i])>=abs(y[i])){
                if(x[i]>=0){
                    s+="R";
                    x[i]-=arm[j];
                }
                else{
                    s+="L";
                    x[i]+=arm[j];                  
                }
            }
            else{
                if(y[i]>=0){
                    s+="U";
                    y[i]-=arm[j];
                }
                else{
                    s+="D";
                    y[i]+=arm[j];                  
                }
            }
        }
        cout<<s<<endl;
    }
}