Fox Ciel has some flowers: r red flowers, g green flowers and b blue flowers. She wants to use these flowers to make several bouquets. There are 4 types of bouquets:

  * To make a "red bouquet", it needs 3 red flowers. 
  * To make a "green bouquet", it needs 3 green flowers. 
  * To make a "blue bouquet", it needs 3 blue flowers. 
  * To make a "mixing bouquet", it needs 1 red, 1 green and 1 blue flower. 



Help Fox Ciel to find the maximal number of bouquets she can make.

Input

The first line contains three integers r, g and b (0 ≤ r, g, b ≤ 109) — the number of red, green and blue flowers.

Output

Print the maximal number of bouquets Fox Ciel can make.

Examples

Input

3 6 9


Output

6


Input

4 4 4


Output

4


Input

0 0 0


Output

0

Note

In test case 1, we can make 1 red bouquet, 2 green bouquets and 3 blue bouquets.

In test case 2, we can make 1 red, 1 green, 1 blue and 1 mixing bouquet.
import java.util.Scanner;

public class CielAndFlowers {
    public static void main(String[] args) {
        Scanner s = new Scanner(System.in);
        int[] f = new int[3];
        for (int i = 0; i < 3; i++) {
            f[i] = s.nextInt();
        }
        solve(f);
    }

    public static void solve(int[] arr) {
        long sum = 0;
        long sum_1 = 0;
        long sum_2 = 0;

        boolean mix_1 = false;
        boolean mix_2 = false;

        for (int i = 0; i < arr.length; i++) {
            sum += arr[i] / 3;
            if (arr[i] <= 0) {
                mix_1 = true;
            }

            if (arr[i] <= 1) {
                mix_2 = true;
            }
        }

        if (!mix_1) {
            sum_1 = 1;
            for (int i = 0; i < arr.length; i++) {
                sum_1 += (arr[i] - 1) / 3;
            }
        } else {
            sum_1 = sum;
        }

        if (!mix_2) {
            sum_2 = 2;
            for (int i = 0; i < arr.length; i++) {
                sum_2 += (arr[i] - 2) / 3;
            }
        } else {
            sum_2 = sum;
        }
        System.out.println(Math.max(sum, Math.max(sum_1, sum_2)));
    }
}
