Fox Ciel has some flowers: r red flowers, g green flowers and b blue flowers. She wants to use these flowers to make several bouquets. There are 4 types of bouquets:

  * To make a "red bouquet", it needs 3 red flowers. 
  * To make a "green bouquet", it needs 3 green flowers. 
  * To make a "blue bouquet", it needs 3 blue flowers. 
  * To make a "mixing bouquet", it needs 1 red, 1 green and 1 blue flower. 



Help Fox Ciel to find the maximal number of bouquets she can make.

Input

The first line contains three integers r, g and b (0 ≤ r, g, b ≤ 109) — the number of red, green and blue flowers.

Output

Print the maximal number of bouquets Fox Ciel can make.

Examples

Input

3 6 9


Output

6


Input

4 4 4


Output

4


Input

0 0 0


Output

0

Note

In test case 1, we can make 1 red bouquet, 2 green bouquets and 3 blue bouquets.

In test case 2, we can make 1 red, 1 green, 1 blue and 1 mixing bouquet.

import java.util.Scanner;

public class Zad2 {

    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        int r = sc.nextInt();
        int g = sc.nextInt();
        int b = sc.nextInt();

        int min = Math.min(r, Math.min(g, b));
        int minr = 0;
        if (min>=3){
            min-=3;
            minr+=3;
        }  
        int output = (min / 3) * 3;
        minr += min % 3;


        r = r - output;
        g = g - output;
        b = b - output;

        int minRest = 0;
        for (int i=0;i<=minr;i++){
            int out = i;
            out += (r-i) / 3;
            out += (g-i) / 3;
            out += (b-i) / 3;
            minRest = (minRest>out)? minRest : out;
        }
 
        System.out.println(output+minRest);
    }
}