There is a new TV game on BerTV. In this game two players get a number A consisting of 2n digits. Before each turn players determine who will make the next move. Each player should make exactly n moves. On it's turn i-th player takes the leftmost digit of A and appends it to his or her number Si. After that this leftmost digit is erased from A. Initially the numbers of both players (S1 and S2) are «empty». Leading zeroes in numbers A, S1, S2 are allowed. In the end of the game the first player gets S1 dollars, and the second gets S2 dollars.

One day Homer and Marge came to play the game. They managed to know the number A beforehand. They want to find such sequence of their moves that both of them makes exactly n moves and which maximizes their total prize. Help them.

Input

The first line contains integer n (1 ≤ n ≤ 18). The second line contains integer A consisting of exactly 2n digits. This number can have leading zeroes.

Output

Output the line of 2n characters «H» and «M» — the sequence of moves of Homer and Marge, which gives them maximum possible total prize. Each player must make exactly n moves. If there are several solutions, output any of them.

Examples

Input

2
1234


Output

HHMM

Input

2
9911


Output

HMHM
import javax.annotation.processing.SupportedSourceVersion;
import java.io.*;
import java.util.*;
import java.util.regex.Matcher;

public class Main {

    public static void main(String[] args) throws IOException {
        InputStream inputStream = System.in;
        OutputStream outputStream = System.out;
        InputReader in = new InputReader(inputStream);
        PrintWriter out = new PrintWriter(outputStream);
        TaskB solver = new TaskB();
        solver.solve(in, out);
        out.close();
    }

    private static class TaskB {

        static final long max = 1000000000000000000L;
        static final double eps = 0.0000001;
        static final long mod = 1000000007;
        static int M, K;
        static long X, Y;

        void solve(InputReader in, PrintWriter out) throws IOException {

            int N = in.nextInt();
            String S = in.nextLine();
            int len = S.length();

            long[][] dp = new long[2 * N + 1][N + 1];
            boolean[][] state = new boolean[2 * N + 1][N + 1];

            for (int i = 1; i <= 2 * N; i++) {


                for (int j = 0; j <= i && j <= N; j++) {

                    if (i - j <= N) {

                        long res1, res2;
                        res1 = res2 = Long.MIN_VALUE;

                        if (j >= 1) {
                            res1 = (long) (S.charAt(len - i) - 48) * (long) Math.pow(10, j - 1) + dp[i - 1][j - 1];
                        }
                        if (i - j - 1 >= 0) {
                            res2 = (long) (S.charAt(len - i) - 48) * (long) Math.pow(10, i - j - 1) + dp[i - 1][j];
                        }

                        if (res1 > res2) state[i][j] = true;
                        dp[i][j] = Math.max(res1, res2);
                    }
                }
            }

            int j = N;
            for (int i = 2 * N; i >= 1; --i) {
                if (state[i][j]) {
                    out.print('M');
                    j--;
                } else {
                    out.print('H');
                }
            }
            out.println();

        }

        long gcd(long A, long B) {
            if (B == 0) return A;
            return gcd(B, A % B);
        }

        boolean isPrime(long n) {
            if (n <= 1 || n > 3 && (n % 2 == 0 || n % 3 == 0))
                return false;
            for (long i = 5, j = 2; i * i <= n; i += j, j = 6 - j)
                if (n % i == 0)
                    return false;
            return true;
        }

        boolean isEqual(double A, double B) {
            return Math.abs(A - B) < eps;
        }

        double dist(double X1, double Y1, double X2, double Y2) {
            return Math.sqrt((X1 - X2) * (X1 - X2) + (Y1 - Y2) * (Y1 - Y2));
        }

        boolean nextPer(int[] data) {
            int i = data.length - 1;
            while (i > 0 && data[i] < data[i - 1]) {
                i--;
            }
            if (i == 0) {
                return false;
            }
            int j = data.length - 1;
            while (data[j] < data[i - 1]) {
                j--;
            }
            int temp = data[i - 1];
            data[i - 1] = data[j];
            data[j] = temp;
            Arrays.sort(data, i, data.length);
            return true;
        }

        long pow(long A, long B, long MOD) {
            if (B == 0) {
                return 1;
            }
            if (B == 1) {
                return A;
            }
            long val = pow(A, B / 2, MOD);
            if (B % 2 == 0) {
                return val * val % MOD;
            } else {
                return val * (val * A % MOD) % MOD;
            }
        }
    }

    private static class InputReader {
        StringTokenizer st;
        BufferedReader br;

        public InputReader(InputStream s) {
            br = new BufferedReader(new InputStreamReader(s));
        }

        public InputReader(FileReader s) throws FileNotFoundException {
            br = new BufferedReader(s);
        }

        public String next() {
            while (st == null || !st.hasMoreTokens())
                try {
                    st = new StringTokenizer(br.readLine());
                } catch (IOException e) {
                    throw new RuntimeException(e);
                }
            return st.nextToken();
        }

        public int nextInt() {
            return Integer.parseInt(next());
        }

        public long nextLong() {
            return Long.parseLong(next());
        }

        public String nextLine() {
            try {
                return br.readLine();
            } catch (IOException e) {
                throw new RuntimeException(e);
            }
        }

        public double nextDouble() {
            return Double.parseDouble(next());
        }

        public boolean ready() {
            try {
                return br.ready();
            } catch (IOException e) {
                throw new RuntimeException(e);
            }
        }
    }
}