We have a tree with N vertices, whose i-th edge connects Vertex u_i and Vertex v_i. Vertex i has an integer a_i written on it. For every integer k from 1 through N, solve the following problem:

* We will make a sequence by lining up the integers written on the vertices along the shortest path from Vertex 1 to Vertex k, in the order they appear. Find the length of the longest increasing subsequence of this sequence.



Here, the longest increasing subsequence of a sequence A of length L is the subsequence A_{i_1} , A_{i_2} , ... , A_{i_M} with the greatest possible value of M such that 1 \leq i_1 < i_2 < ... < i_M \leq L and A_{i_1} < A_{i_2} < ... < A_{i_M}.

Constraints

* 2 \leq N \leq 2 \times 10^5
* 1 \leq a_i \leq 10^9
* 1 \leq u_i , v_i \leq N
* u_i \neq v_i
* The given graph is a tree.
* All values in input are integers.

Input

Input is given from Standard Input in the following format:


N
a_1 a_2 ... a_N
u_1 v_1
u_2 v_2
:
u_{N-1} v_{N-1}


Output

Print N lines. The k-th line, print the length of the longest increasing subsequence of the sequence obtained from the shortest path from Vertex 1 to Vertex k.

Example

Input

10
1 2 5 3 4 6 7 3 2 4
1 2
2 3
3 4
4 5
3 6
6 7
1 8
8 9
9 10


Output

1
2
3
3
4
4
5
2
2
3
# coding: utf-8
import sys
from bisect import bisect_left, bisect_right, insort
sys.setrecursionlimit(10 ** 7)

sr = lambda: sys.stdin.readline().rstrip()
ir = lambda: int(sr())
lr = lambda: list(map(int, sr().split()))

N = ir()
A = [0] + lr()  # 1-indexed
graph = [[] for _ in range(N+1)]  # 1-indexed
for _ in range(N-1):
    a, b = lr()
    graph[a].append(b)
    graph[b].append(a)

answer = [0] * (N+1)  # 1-indexed
INF = 10 ** 10
parent = [-1] * (N+1)

def dfs(n):
    """answerのリストを更新してからdfsして、oldで戻す"""
    i = bisect_left(dp, INF)
    answer[n] = i
    for c in graph[n]:
        if c == parent[n]:
            continue
        parent[c] = n
        i = bisect_left(dp, A[c])
        old = dp[i]
        dp[i] = A[c]
        dfs(c)
        dp[i] = old

dp = [INF] * (N+1)
dp[0] = A[1]
dfs(1)
for a in answer[1:]:
    print(a)
