Fox Ciel has some flowers: r red flowers, g green flowers and b blue flowers. She wants to use these flowers to make several bouquets. There are 4 types of bouquets:

  * To make a "red bouquet", it needs 3 red flowers. 
  * To make a "green bouquet", it needs 3 green flowers. 
  * To make a "blue bouquet", it needs 3 blue flowers. 
  * To make a "mixing bouquet", it needs 1 red, 1 green and 1 blue flower. 



Help Fox Ciel to find the maximal number of bouquets she can make.

Input

The first line contains three integers r, g and b (0 ≤ r, g, b ≤ 109) — the number of red, green and blue flowers.

Output

Print the maximal number of bouquets Fox Ciel can make.

Examples

Input

3 6 9


Output

6


Input

4 4 4


Output

4


Input

0 0 0


Output

0

Note

In test case 1, we can make 1 red bouquet, 2 green bouquets and 3 blue bouquets.

In test case 2, we can make 1 red, 1 green, 1 blue and 1 mixing bouquet.
import java.util.Scanner;


public class Flowers {
	public static void main(String[] args) {
		Scanner sc = new Scanner(System.in);
		
		int r = sc.nextInt();
		int g = sc.nextInt();
		int b = sc.nextInt();
		
		int min = 0;
		int rr = r % 3;
		int gr = g % 3;
		int br = b % 3;
		
		int count1 = 0;
		int count2 = 0;
		int count3 = 0;
		
		{
			count1 = r / 3 + b / 3 + g / 3;
		}
		
		if(r >= 1 && g >= 1 && b >= 1){
			int r1 = r - 1;
			int g1 = g - 1;
			int b1 = b - 1;
			
			count2 = r1 / 3 + b1 / 3 + g1 / 3 + 1;
		}
		
		if(r >= 2 && g >= 2 && b >= 2){
			int r1 = r - 2;
			int g1 = g - 2;
			int b1 = b - 2;
			
			count3 = r1 / 3 + b1 / 3 + g1 / 3 + 2;
		}
		
		System.out.println(Math.max(count1, Math.max(count2, count3)));
				
		sc.close();
	}

}

