You are given a string s of length n. Does a tree with n vertices that satisfies the following conditions exist?

* The vertices are numbered 1,2,..., n.
* The edges are numbered 1,2,..., n-1, and Edge i connects Vertex u_i and v_i.
* If the i-th character in s is `1`, we can have a connected component of size i by removing one edge from the tree.
* If the i-th character in s is `0`, we cannot have a connected component of size i by removing any one edge from the tree.



If such a tree exists, construct one such tree.

Constraints

* 2 \leq n \leq 10^5
* s is a string of length n consisting of `0` and `1`.

Input

Input is given from Standard Input in the following format:


s


Output

If a tree with n vertices that satisfies the conditions does not exist, print `-1`.

If a tree with n vertices that satisfies the conditions exist, print n-1 lines. The i-th line should contain u_i and v_i with a space in between. If there are multiple trees that satisfy the conditions, any such tree will be accepted.

Examples

Input

1111


Output

-1


Input

1110


Output

1 2
2 3
3 4


Input

1010


Output

1 2
1 3
1 4
#include<bits/stdc++.h>
using namespace std;
#define pii pair<int,int>

pii h[100010];

int n;
char s[100010];

int main()
{
	scanf("%s",s+1);
	n=strlen(s+1);
	if (s[n]=='1'||s[1]=='0'||s[n-1]=='0') { puts("-1");return 0; }
	for (int i=1;i<n;i++) if (s[i]!=s[n-i]) { puts("-1");return 0; }
	int tot=1,now=1,tt=0,sum=1;
	while (233)
	{
		int fa=++tot;sum++;
		h[++tt]=pii(fa,now);
		while (s[sum]=='0'&&sum<n) h[++tt]=pii(fa,++tot),sum++;
		now=fa;if (sum==n) break;
	}
	for (int i=1;i<n;i++) printf("%d %d\n",h[i].first,h[i].second);
	return 0;
}