Fox Ciel has some flowers: r red flowers, g green flowers and b blue flowers. She wants to use these flowers to make several bouquets. There are 4 types of bouquets:

  * To make a "red bouquet", it needs 3 red flowers. 
  * To make a "green bouquet", it needs 3 green flowers. 
  * To make a "blue bouquet", it needs 3 blue flowers. 
  * To make a "mixing bouquet", it needs 1 red, 1 green and 1 blue flower. 



Help Fox Ciel to find the maximal number of bouquets she can make.

Input

The first line contains three integers r, g and b (0 ≤ r, g, b ≤ 109) — the number of red, green and blue flowers.

Output

Print the maximal number of bouquets Fox Ciel can make.

Examples

Input

3 6 9


Output

6


Input

4 4 4


Output

4


Input

0 0 0


Output

0

Note

In test case 1, we can make 1 red bouquet, 2 green bouquets and 3 blue bouquets.

In test case 2, we can make 1 red, 1 green, 1 blue and 1 mixing bouquet.
import java.util.Scanner;

public class Tester {
	public static void main(String args[]){
		Scanner scan = new Scanner(System.in);
		int r = scan.nextInt();
		int g = scan.nextInt();
		int b = scan.nextInt();
		int r1 = r;
		int g1 = g;
		int b1=  b;
		int ans1 = 0;
        ans1 = (r/3) + (b/3) + (g/3);
        r=r%3;
        g=g%3;
        b=b%3;
        while(true){
        	if(r>0 && b>0 && g>0){
        		ans1++;
        		r--;
        		b--;
        		g--;
        	}
        	else
        		break;
        }
	    if(((r==2 && b==2 && g!=2) || (r!=2 && b==2 && g==2) || (r==2 && b!=2 && g==2)) && (((r1/3)>=1 && (g1/3)>=1 && (b1/3)>=1)))
	    	ans1++;
			System.out.println(ans1);
	}
}
