Fox Ciel has some flowers: r red flowers, g green flowers and b blue flowers. She wants to use these flowers to make several bouquets. There are 4 types of bouquets:

  * To make a "red bouquet", it needs 3 red flowers. 
  * To make a "green bouquet", it needs 3 green flowers. 
  * To make a "blue bouquet", it needs 3 blue flowers. 
  * To make a "mixing bouquet", it needs 1 red, 1 green and 1 blue flower. 



Help Fox Ciel to find the maximal number of bouquets she can make.

Input

The first line contains three integers r, g and b (0 ≤ r, g, b ≤ 109) — the number of red, green and blue flowers.

Output

Print the maximal number of bouquets Fox Ciel can make.

Examples

Input

3 6 9


Output

6


Input

4 4 4


Output

4


Input

0 0 0


Output

0

Note

In test case 1, we can make 1 red bouquet, 2 green bouquets and 3 blue bouquets.

In test case 2, we can make 1 red, 1 green, 1 blue and 1 mixing bouquet.
import java.io.BufferedOutputStream;
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.OutputStream;

public class CielAndFlowers {

    public static void main(String[] args) throws IOException {
        BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
        OutputStream out = new BufferedOutputStream(System.out);
        String[] l = br.readLine().split("\\s+");
        int[] arr = { Integer.parseInt(l[0]), Integer.parseInt(l[1]),
                Integer.parseInt(l[2]) };
        int r = arr[0];
        int g = arr[1];
        int b = arr[2];
        int total = r / 3 + g / 3 + b / 3;

        for (int i = 0; i < 3; i++)
            if ((r - i) > 0 && (b - i) > 0 && (g - i) > 0)
                total = Math.max(total, i
                        + ((r - i) / 3 + (g - i) / 3 + (b - i) / 3));

        out.write((total + "").getBytes());
        out.flush();
        br.close();

    }
}