One day Misha and Andrew were playing a very simple game. First, each player chooses an integer in the range from 1 to n. Let's assume that Misha chose number m, and Andrew chose number a.

Then, by using a random generator they choose a random integer c in the range between 1 and n (any integer from 1 to n is chosen with the same probability), after which the winner is the player, whose number was closer to c. The boys agreed that if m and a are located on the same distance from c, Misha wins.

Andrew wants to win very much, so he asks you to help him. You know the number selected by Misha, and number n. You need to determine which value of a Andrew must choose, so that the probability of his victory is the highest possible.

More formally, you need to find such integer a (1 ≤ a ≤ n), that the probability that <image> is maximal, where c is the equiprobably chosen integer from 1 to n (inclusive).

Input

The first line contains two integers n and m (1 ≤ m ≤ n ≤ 109) — the range of numbers in the game, and the number selected by Misha respectively.

Output

Print a single number — such value a, that probability that Andrew wins is the highest. If there are multiple such values, print the minimum of them.

Examples

Input

3 1


Output

2

Input

4 3


Output

2

Note

In the first sample test: Andrew wins if c is equal to 2 or 3. The probability that Andrew wins is 2 / 3. If Andrew chooses a = 3, the probability of winning will be 1 / 3. If a = 1, the probability of winning is 0.

In the second sample test: Andrew wins if c is equal to 1 and 2. The probability that Andrew wins is 1 / 2. For other choices of a the probability of winning is less.
//Author: Mo Abjal, MJP Rohilkhand University Bareilly, UP, India 2018.
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import java.util.*;
import java.io.*;
import java.text.*;
import java.math.*;
public class Main{
	public static StringTokenizer token = new StringTokenizer("");
	public static BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
	public static PrintWriter output = new PrintWriter(System.out);
	public static void main(String[] afzal) throws Exception {	
		int N = ni();
		int M = ni();
		if(N==1){
			output.println(1);
		}
		else if(N-M>=M-0){
			output.println(++M);
		}
		else if(N-M<M-0){
			output.println(--M);
		}
		output.close();
		/*int T = ni();
		for(int e=0;e<T;e++){
			long N = nl();  		long M = nl();
			int n = 100000;  
			
	        if((Math.pow(N,2) - Math.pow(M,2))<100005){
	        	int s = (int)(Math.pow(N,2) - Math.pow(M,2));
	        	if(prime[s]){
	        		output.println("YES");
	        	}
	        	else{
	        		output.println("NO");
	        	}
	        }
	        else
			output.println("NO");
		}
		output.close();*/
	}
	public String pc(char c){
		return Character.toString(c);
	} 
	public static Integer pi(String str){
		return Integer.parseInt(str);
	}
	public static Long pl(String str){
		return Long.parseLong(str);
	}
	public static String ps(Integer N){
		return Integer.toString(N);
	}
	public static char[] pcc(String str){
		return str.toCharArray();
	}
	public static Integer ni() throws IOException{
		if(!token.hasMoreElements()){
			token = new StringTokenizer(br.readLine());
		}
		return Integer.parseInt(token.nextToken());
	}
	public static Long nl() throws IOException{
		if(!token.hasMoreElements()){
			token = new StringTokenizer(br.readLine());
		}
		return Long.parseLong(token.nextToken());
	}
	public static String ns() throws IOException{
		return new StringTokenizer(br.readLine()).nextToken();
	}
	public static Integer[] ai(int N) throws IOException{
		Integer A[] = new Integer[N];
		token = new StringTokenizer(br.readLine());
		for(int i=0;i<A.length;i++){
			A[i] = pi(token.nextToken());
		}
		return A;
	}
	public static long[] al(int N) throws IOException{
		long A[] = new long[N];
		token = new StringTokenizer(br.readLine());
		for(int i=0;i<N;i++){
			A[i] = Long.parseLong(token.nextToken());
		}
		return A;
	}
	public static char[][] acc(int N,int M) throws IOException{
		char C[][] = new char[N][M];
		for(int i=0;i<N;i++){
			token = new StringTokenizer(br.readLine());
			String s = token.nextToken();
			for(int j=0;j<M;j++){
				C[i][j] = s.charAt(j);
			}
		}
		return C;
	}
	public static String[] as(int N) throws IOException{
		String S[] = new String[N];
		token = new StringTokenizer(br.readLine());
		for(int i=0;i<S.length;i++){
			S[i] = token.nextToken();
		}
		return S;
	}

	public static long fact(long N){
		long fact = 1;
		for(int i=1;i<=N;i++){
			fact = fact * i;
		}
		return fact;
	}
	public static BigInteger factB(int N){
		BigInteger b = new BigInteger("1");
		for(int i=1;i<=N;i++){
			b = b.multiply(BigInteger.valueOf(i));
		}
		return b;
	}
	public static long sod(long N){
		long sum = 0;
		while(N>0){
			long x = N%10;
			sum = sum + x;
			N = N/10;
		}
		return sum;
	}
	public static Integer cd(long N){
		int count=0;
		while(N>0){
			N = N/10; count++;
		}
		return count=0;
	}
}
class Pair implements Comparable{
	int a,b;
	public Pair(int a,int b){
		this.a = a;
		this.b = b;
	}
	public int compareTo(Object p){
		Pair pa = (Pair)p;
		if(this.a==pa.a) return this.b - pa.b;
		return this.a - pa.a;
	} 
}
//Copyright Reserved - Mo Abjal.