Bob is playing a game named "Walk on Matrix".

In this game, player is given an n × m matrix A=(a_{i,j}), i.e. the element in the i-th row in the j-th column is a_{i,j}. Initially, player is located at position (1,1) with score a_{1,1}. 

To reach the goal, position (n,m), player can move right or down, i.e. move from (x,y) to (x,y+1) or (x+1,y), as long as player is still on the matrix.

However, each move changes player's score to the [bitwise AND](https://en.wikipedia.org/wiki/Bitwise_operation#AND) of the current score and the value at the position he moves to.

Bob can't wait to find out the maximum score he can get using the tool he recently learnt — dynamic programming. Here is his algorithm for this problem. 

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However, he suddenly realize that the algorithm above fails to output the maximum score for some matrix A. Thus, for any given non-negative integer k, he wants to find out an n × m matrix A=(a_{i,j}) such that 

  * 1 ≤ n,m ≤ 500 (as Bob hates large matrix); 
  * 0 ≤ a_{i,j} ≤ 3 ⋅ 10^5 for all 1 ≤ i≤ n,1 ≤ j≤ m (as Bob hates large numbers); 
  * the difference between the maximum score he can get and the output of his algorithm is exactly k. 



It can be shown that for any given integer k such that 0 ≤ k ≤ 10^5, there exists a matrix satisfying the above constraints.

Please help him with it!

Input

The only line of the input contains one single integer k (0 ≤ k ≤ 10^5).

Output

Output two integers n, m (1 ≤ n,m ≤ 500) in the first line, representing the size of the matrix. 

Then output n lines with m integers in each line, a_{i,j} in the (i+1)-th row, j-th column.

Examples

Input


0


Output


1 1
300000

Input


1


Output


3 4
7 3 3 1
4 8 3 6
7 7 7 3

Note

In the first example, the maximum score Bob can achieve is 300000, while the output of his algorithm is 300000.

In the second example, the maximum score Bob can achieve is 7\&3\&3\&3\&7\&3=3, while the output of his algorithm is 2.

import java.io.*;
import java.util.*;
import static java.lang.Math.*;

public class d implements Runnable
{
    boolean multiple = false; // for multiple test cases
    long MOD = 998244353;

    @SuppressWarnings("Duplicates")
    void solve() throws Exception
    {


    	
    	
    	
    	int k = sc.nextInt();
    	if(k==0) {
    		System.out.println("1 1");
    		System.out.println("3");
    	}else {
    		int[][] arr = new int[3][3];
    		int put = (int)Math.pow(2, 18)-1;
    		arr[0][0] = put;
    		arr[0][1] = put;
    		arr[0][2] = put;
    		arr[1][0] = put;
    		arr[2][1] = put;
    		arr[1][2] = 0;
    		arr[2][2] = k;
    		arr[1][1] = k;
    		
    		arr[2][0] =put ^ k ;
    		System.out.println("3 3");
    		for(int i = 0 ; i < 3 ; i++) {
    			for(int  j= 0 ; j < 3 ; j++) {
    				System.out.print(arr[i][j]+" ");
    			}
    			System.out.println();
    		}
    		
    	}
    }

  
    class Node implements Comparable<Node>
    {
        int k, pos, idx;
        Node(int K, int P, int I)
        {
            k = K;
            pos = P;
            idx = I;
        }

        @Override
        public int compareTo(Node o)
        {
            return Integer.compare(k, o.k);
        }
    }


    long powmod(long x, long y){
        if(y==0) return 1L;
        long t=powmod(x,y/2);
        if (y%2==0) return (t*t)%MOD;
        return (((x*t)%MOD)*t)%MOD;
    }
    long inv(long a, long b){return 1<a ? b - inv(b%a,a)*b/a : 1;}
    TreeMap<Integer, TreeSet<Integer>> buildGraph(int n, int m) throws Exception{TreeMap<Integer, TreeSet<Integer>> graph = new TreeMap<>();for (int i = 1; i <= n; i++) graph.put(i, new TreeSet<>());for (int i = 0; i < m; i++) { int u = sc.nextInt();int v = sc.nextInt();graph.get(u).add(v);graph.get(v).add(u); }return graph; }
    TreeMap<Integer, TreeSet<Integer>> buildDirGraph(int n, int m) throws Exception { TreeMap<Integer, TreeSet<Integer>> graph = new TreeMap<>();for (int i = 1; i <= n; i++) graph.put(i, new TreeSet<>());for (int i = 0; i < m; i++) graph.get(sc.nextInt()).add(sc.nextInt());return graph; }
    TreeMap<Integer, TreeSet<Integer>> revGraph(TreeMap<Integer, TreeSet<Integer>> graph) { TreeMap<Integer, TreeSet<Integer>> rev = new TreeMap<>();for (Integer u : graph.keySet()) rev.put(u, new TreeSet<>());for (Integer u : graph.keySet()) for (Integer v : graph.get(u)) rev.get(v).add(u);return rev; }
    TreeMap<Long, Integer> counts(long[] arr) { TreeMap<Long, Integer> counts = new TreeMap<>(); for (long a : arr) { if (!counts.containsKey(a)) counts.put(a, 0); counts.put(a, counts.get(a) + 1);} return counts; }
    String reverse(String s, int i, int j) /*[i, j] closed*/ { return (i > j) ? reverse(s, j, i) : s.substring(0, i) + (new StringBuilder(s.substring(i, j + 1))).reverse() + ((j + 1 <= s.length() - 1) ? s.substring(j + 1) : "");}

    @Override public void run() { try { in = new BufferedReader(new InputStreamReader(System.in));out = new PrintWriter(System.out);sc = new FastScanner(in);if (multiple) { int q = sc.nextInt();for (int i = 0; i < q; i++) solve(); } else solve(); } catch (Throwable uncaught) { d.uncaught = uncaught; } finally { out.close(); }} public static void main(String[] args) throws Throwable{ Thread thread = new Thread(null, new d(), "", (1 << 26));thread.start();thread.join();if (d.uncaught != null) {throw d.uncaught;} } static Throwable uncaught; BufferedReader in; FastScanner sc; PrintWriter out; } class FastScanner { BufferedReader in; StringTokenizer st; public FastScanner(BufferedReader in) {this.in = in;}public String nextToken() throws Exception { while (st == null || !st.hasMoreTokens()) { st = new StringTokenizer(in.readLine()); }return st.nextToken(); }public int nextInt() throws Exception { return Integer.parseInt(nextToken()); }public long nextLong() throws Exception { return Long.parseLong(nextToken()); }public double nextDouble() throws Exception { return Double.parseDouble(nextToken()); }
}