Today Tavas got his test result as an integer score and he wants to share it with his girlfriend, Nafas.

His phone operating system is Tavdroid, and its keyboard doesn't have any digits! He wants to share his score with Nafas via text, so he has no choice but to send this number using words.

<image>

He ate coffee mix without water again, so right now he's really messed up and can't think.

Your task is to help him by telling him what to type.

Input

The first and only line of input contains an integer s (0 ≤ s ≤ 99), Tavas's score. 

Output

In the first and only line of output, print a single string consisting only from English lowercase letters and hyphens ('-'). Do not use spaces.

Examples

Input

6


Output

six


Input

99


Output

ninety-nine


Input

20


Output

twenty

Note

You can find all you need to know about English numerals in <http://en.wikipedia.org/wiki/English_numerals> .
#include <bits/stdc++.h>
unsigned long long mulmod(unsigned long long a, unsigned long long b,
                          unsigned long long c) {
  unsigned long long x = 0, y = a % c;
  while (b > 0) {
    if (b % 2 == 1) {
      x = (x + y) % c;
    }
    y = (y * 2) % c;
    b /= 2;
  }
  return x % c;
}
unsigned long long pow(unsigned long long a, unsigned long long b,
                       unsigned long long c) {
  unsigned long long x = 1, y = a;
  while (b > 0) {
    if (b & 1) x = mulmod(x, y, c);
    y = mulmod(y, y, c);
    b >>= 1;
  }
  return x;
}
bool Miller(unsigned long long p, int iteration) {
  if (p < 2) {
    return false;
  }
  if (p != 2 && p % 2 == 0) {
    return false;
  }
  unsigned long long second = p - 1;
  while (second % 2 == 0) {
    second /= 2;
  }
  for (int i = 0; i < iteration; i++) {
    unsigned long long a = rand() % (p - 1) + 1, temp = second;
    unsigned long long mod = pow(a, temp, p);
    while (temp != p - 1 && mod != 1 && mod != p - 1) {
      mod = mulmod(mod, mod, p);
      temp *= 2;
    }
    if (mod != p - 1 && temp % 2 == 0) {
      return false;
    }
  }
  return true;
}
using namespace std;
int main() {
  int n;
  scanf("%d", &n);
  int pos = 0;
  string ans = "";
  string text[2][10] = {{"zero", "one", "two", "three", "four", "five", "six",
                         "seven", "eight", "nine"},
                        {"", "ten-", "twenty-", "thirty-", "forty-", "fifty-",
                         "sixty-", "seventy-", "eighty-", "ninety-"}};
  string tens[9] = {"ten",   "twenty",  "thirty", "forty", "fifty",
                    "sixty", "seventy", "eighty", "ninety"};
  if (n % 10 == 0 && n != 0) {
    cout << tens[(n / 10) - 1] << "\n";
    return 0;
  } else if (n < 20) {
    if (n < 10) {
      cout << text[0][n] << "\n";
    } else {
      switch (n) {
        case 11:
          cout << "eleven\n";
          break;
        case 12:
          cout << "twelve\n";
          break;
        case 13:
          cout << "thirteen\n";
          break;
        case 14:
          cout << "fourteen\n";
          break;
        case 15:
          cout << "fifteen\n";
          break;
        case 16:
          cout << "sixteen\n";
          break;
        case 17:
          cout << "seventeen\n";
          break;
        case 18:
          cout << "eighteen\n";
          break;
        case 19:
          cout << "nineteen\n";
      }
    }
    return 0;
  }
  while (n) {
    int d = n % 10;
    ans.insert(0, text[pos][d]);
    pos++;
    n /= 10;
  }
  cout << ans << "\n";
  return 0;
}
