Polycarp has created his own training plan to prepare for the programming contests. He will train for n days, all days are numbered from 1 to n, beginning from the first.

On the i-th day Polycarp will necessarily solve a_i problems. One evening Polycarp plans to celebrate the equator. He will celebrate it on the first evening of such a day that from the beginning of the training and to this day inclusive he will solve half or more of all the problems.

Determine the index of day when Polycarp will celebrate the equator.

Input

The first line contains a single integer n (1 ≤ n ≤ 200 000) — the number of days to prepare for the programming contests.

The second line contains a sequence a_1, a_2, ..., a_n (1 ≤ a_i ≤ 10 000), where a_i equals to the number of problems, which Polycarp will solve on the i-th day.

Output

Print the index of the day when Polycarp will celebrate the equator.

Examples

Input

4
1 3 2 1


Output

2


Input

6
2 2 2 2 2 2


Output

3

Note

In the first example Polycarp will celebrate the equator on the evening of the second day, because up to this day (inclusive) he will solve 4 out of 7 scheduled problems on four days of the training.

In the second example Polycarp will celebrate the equator on the evening of the third day, because up to this day (inclusive) he will solve 6 out of 12 scheduled problems on six days of the training.
/*
    Author: @__goku__
            ssrivastava990@gmail.com
 
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     | |    \         `\_/'                  //      \.     |
     | |     |                 _Seal_      /' |       |     |
 */

import java.io.*;
import java.util.*;

public class E42A
{
    static PrintWriter out = new PrintWriter((System.out));

    public static void main(String args[]) throws IOException
    {
        Kioken sc = new Kioken();
        int n=sc.nextInt();
        long ar[]=new long[n];
        ar[0]=sc.nextLong();
        for(int x=1;x<n;x++)
        {
            ar[x]=ar[x-1]+sc.nextLong();
        }
        for(int x=0;x<n;x++)
        {
            if(ar[x]>=ar[n-1]/2.0)
            {
                out.println(x+1);
                break;
            }
        }
        out.close();
    }

    public static void kamehameha()
    {
    }

    static class Kioken
    {
        BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
        StringTokenizer st = new StringTokenizer("");

        public String next()
        {
            while (!st.hasMoreTokens())
            {
                try
                {
                    st = new StringTokenizer(br.readLine());
                } catch (Exception e)
                {
                    e.printStackTrace();
                }
            }
            return st.nextToken();
        }

        public int nextInt()
        {
            return Integer.parseInt(next());
        }

        public long nextLong()
        {
            return Long.parseLong(next());
        }

        public double nextDouble()
        {
            return Double.parseDouble(next());
        }

        public String nextLine()
        {
            try
            {
                return br.readLine();
            } catch (Exception e)
            {
                e.printStackTrace();
            }
            return null;
        }

        public boolean hasNext()
        {
            String next = null;
            try
            {
                next = br.readLine();
            } catch (Exception e)
            {
            }
            if (next == null)
            {
                return false;
            }
            st = new StringTokenizer(next);
            return true;
        }
    }
}