Snuke is introducing a robot arm with the following properties to his factory:

* The robot arm consists of m sections and m+1 joints. The sections are numbered 1, 2, ..., m, and the joints are numbered 0, 1, ..., m. Section i connects Joint i-1 and Joint i. The length of Section i is d_i.
* For each section, its mode can be specified individually. There are four modes: `L`, `R`, `D` and `U`. The mode of a section decides the direction of that section. If we consider the factory as a coordinate plane, the position of Joint i will be determined as follows (we denote its coordinates as (x_i, y_i)):
* (x_0, y_0) = (0, 0).
* If the mode of Section i is `L`, (x_{i}, y_{i}) = (x_{i-1} - d_{i}, y_{i-1}).
* If the mode of Section i is `R`, (x_{i}, y_{i}) = (x_{i-1} + d_{i}, y_{i-1}).
* If the mode of Section i is `D`, (x_{i}, y_{i}) = (x_{i-1}, y_{i-1} - d_{i}).
* If the mode of Section i is `U`, (x_{i}, y_{i}) = (x_{i-1}, y_{i-1} + d_{i}).



Snuke would like to introduce a robot arm so that the position of Joint m can be matched with all of the N points (X_1, Y_1), (X_2, Y_2), ..., (X_N, Y_N) by properly specifying the modes of the sections. Is this possible? If so, find such a robot arm and how to bring Joint m to each point (X_j, Y_j).

Constraints

* All values in input are integers.
* 1 \leq N \leq 1000
* -10^9 \leq X_i \leq 10^9
* -10^9 \leq Y_i \leq 10^9

Input

Input is given from Standard Input in the following format:


N
X_1 Y_1
X_2 Y_2
:
X_N Y_N


Output

If the condition can be satisfied, follow the following format. If the condition cannot be satisfied, print `-1`.


m
d_1 d_2 ... d_m
w_1
w_2
:
w_N


m and d_i are the configurations of the robot arm. Refer to the problem statement for what each of them means. Here, 1 \leq m \leq 40 and 1 \leq d_i \leq 10^{12} must hold. Also, m and d_i must all be integers.

w_j is a string of length m that represents the way to bring Joint m of the robot arm to point (X_j, Y_j). The i-th character of w_j should be one of the letters `L`, `R`, `D` and `U`, representing the mode of Section i.

Examples

Input

3
-1 0
0 3
2 -1


Output

2
1 2
RL
UU
DR


Input

5
0 0
1 0
2 0
3 0
4 0


Output

-1


Input

2
1 1
1 1


Output

2
1 1
RU
UR


Input

3
-7 -3
7 3
-3 -7


Output

5
3 1 4 1 5
LRDUL
RDULR
DULRD
#include <bits/stdc++.h>
using namespace std;
#define int long long
#define FOR(i,n) for(int (i)=0;(i)<(n);(i)++)
#define rep(i,n) for(int (i)=0;(i)<(n);(i)++)
#define rrep(i,n) for(int (i)=((n)-1);(i)>=0;(i)--)
#define itn int
#define all(x) (x).begin(),(x).end()
const long long INF = 1LL << 60;
const int MOD = 1000000007;
signed main(void){
    int n; cin>>n;
    int X[n],Y[n];
    rep(i,n) cin>>X[i]>>Y[i];
    int t = (abs(X[0]) + abs(Y[0]) )%2;
    rep(i,n) if((abs(X[i]) + abs(Y[i]))%2 != t ) {cout<<-1<<endl; return 0;}
    int m = 32;
    vector <int> d(m); 
    rep(i,m) d[i] = 1LL<<(31-i);
    if(t == 0) {d.push_back(1); m++;}
    sort(d.begin(),d.end(), greater <int>());
    cout<<m<<endl;
    rep(i, m) cout<<d[i]<<' ';
    cout<<endl;
    FOR(i,n) {
		string S;
		FOR(j,m) {
			if(abs(X[i])>=abs(Y[i])) {
				if(X[i]>=0) {
					S+='R';
					X[i]-=d[j];
				}
				else {
					S+='L';
					X[i]+=d[j];
				}
			}
			else {
				if(Y[i]>=0) {
					S+='U';
					Y[i]-=d[j];
				}
				else {
					S+='D';
					Y[i]+=d[j];
				}
			}
		}
		cout<<S<<endl;
	}
}
