Fox Ciel has some flowers: r red flowers, g green flowers and b blue flowers. She wants to use these flowers to make several bouquets. There are 4 types of bouquets:

  * To make a "red bouquet", it needs 3 red flowers. 
  * To make a "green bouquet", it needs 3 green flowers. 
  * To make a "blue bouquet", it needs 3 blue flowers. 
  * To make a "mixing bouquet", it needs 1 red, 1 green and 1 blue flower. 



Help Fox Ciel to find the maximal number of bouquets she can make.

Input

The first line contains three integers r, g and b (0 ≤ r, g, b ≤ 109) — the number of red, green and blue flowers.

Output

Print the maximal number of bouquets Fox Ciel can make.

Examples

Input

3 6 9


Output

6


Input

4 4 4


Output

4


Input

0 0 0


Output

0

Note

In test case 1, we can make 1 red bouquet, 2 green bouquets and 3 blue bouquets.

In test case 2, we can make 1 red, 1 green, 1 blue and 1 mixing bouquet.
r,g,b=map(int,input().split())
k=min(r,g,b)
t1=(r//3)+(g//3)+(b//3)+min(r%3,g%3,b%3)
t2=(r//3)+(g//3)
p=min(r%3,g%3,b)
t2=t2+p+(b-p)//3
t3=(r//3)+(b//3)
p=min(r%3,b%3,g)
t3=t3+p+(g-p)//3
t4=(b//3)+(g//3)
p=min(b%3,g%3,r)
t4=t4+p+(r-p)//3
t5=(r//3)
p=min(r%3,g,b)
t5=t5+p+(g-p)//3+(b-p)//3
t6=(g//3)
p=min(g%3,r,b)
t6=t6+p+(r-p)//3+(b-p)//3
t7=(b//3)
p=min(b%3,r,g)
t7=t7+p+(g-p)//3+(r-p)//3
t8=min(r,g,b)+(r-k)//3+(b-k)//3+(g-k)//3
print(max(t1,t2,t3,t4,t5,t6,t7,t8))
    
