Fox Ciel has some flowers: r red flowers, g green flowers and b blue flowers. She wants to use these flowers to make several bouquets. There are 4 types of bouquets:

  * To make a "red bouquet", it needs 3 red flowers. 
  * To make a "green bouquet", it needs 3 green flowers. 
  * To make a "blue bouquet", it needs 3 blue flowers. 
  * To make a "mixing bouquet", it needs 1 red, 1 green and 1 blue flower. 



Help Fox Ciel to find the maximal number of bouquets she can make.

Input

The first line contains three integers r, g and b (0 ≤ r, g, b ≤ 109) — the number of red, green and blue flowers.

Output

Print the maximal number of bouquets Fox Ciel can make.

Examples

Input

3 6 9


Output

6


Input

4 4 4


Output

4


Input

0 0 0


Output

0

Note

In test case 1, we can make 1 red bouquet, 2 green bouquets and 3 blue bouquets.

In test case 2, we can make 1 red, 1 green, 1 blue and 1 mixing bouquet.
import java.io.BufferedInputStream;
import java.util.Scanner;

/**
 * @author Evgeniy Kiselev
 *         Date: 28.06.13
 */
public class B {

    public static void main(String[] arg) {
        final Scanner scanner = new Scanner(new BufferedInputStream(System.in));
        final String[] input = scanner.nextLine().split(" ");
        final int r = Integer.parseInt(input[0]);
        final int g = Integer.parseInt(input[1]);
        final int b = Integer.parseInt(input[2]);

        int result = 0;

        if (r == 0 && g == 0 && b == 0) {
            System.out.println(0);
            return;
        }
        result = r /3 + g / 3 + b / 3;
        if (r % 3 == 0 && g % 3 == 0 && b % 3 == 0) {
            System.out.println(result);
            return;
        }
        int r1 = r % 3;
        int g1 = g % 3;
        int b1 = b % 3;

        int min = Math.min(r1, g1);
        min = Math.min(b1, min);

        if (min == 2 || min == 1) {
            result += min;
            System.out.println(result);
            return;
        }

        if (min == 0) {
            if (r1 == 2 && g1 == 2 && b > 2|| r1 == 2 && b1 == 2 && g > 2 || b1 == 2 && g1 == 2 && r > 2) {
                result++;
            }
            System.out.println(result);
            return;
        }
    }
}