Fox Ciel has some flowers: r red flowers, g green flowers and b blue flowers. She wants to use these flowers to make several bouquets. There are 4 types of bouquets:

  * To make a "red bouquet", it needs 3 red flowers. 
  * To make a "green bouquet", it needs 3 green flowers. 
  * To make a "blue bouquet", it needs 3 blue flowers. 
  * To make a "mixing bouquet", it needs 1 red, 1 green and 1 blue flower. 



Help Fox Ciel to find the maximal number of bouquets she can make.

Input

The first line contains three integers r, g and b (0 ≤ r, g, b ≤ 109) — the number of red, green and blue flowers.

Output

Print the maximal number of bouquets Fox Ciel can make.

Examples

Input

3 6 9


Output

6


Input

4 4 4


Output

4


Input

0 0 0


Output

0

Note

In test case 1, we can make 1 red bouquet, 2 green bouquets and 3 blue bouquets.

In test case 2, we can make 1 red, 1 green, 1 blue and 1 mixing bouquet.
import java.util.Scanner;

public class Main {
	public static void main(String[] args) {
		Scanner sc = new Scanner(System.in);

		int r = sc.nextInt();
		int g = sc.nextInt();
		int b = sc.nextInt();
		System.out.println(solve(r, g, b));

		sc.close();
	}

	static int solve(int r, int g, int b) {
		int result = computeIndependentNum(r, g, b);
		if (r >= 1 && g >= 1 && b >= 1) {
			result = Math.max(result, 1 + computeIndependentNum(r - 1, g - 1, b - 1));
		}
		if (r >= 2 && g >= 2 && b >= 2) {
			result = Math.max(result, 2 + computeIndependentNum(r - 2, g - 2, b - 2));
		}

		return result;
	}

	static int computeIndependentNum(int r, int g, int b) {
		return r / 3 + g / 3 + b / 3;
	}
}
