You are given two matrices A and B. Each matrix contains exactly n rows and m columns. Each element of A is either 0 or 1; each element of B is initially 0.

You may perform some operations with matrix B. During each operation, you choose any submatrix of B having size 2 × 2, and replace every element in the chosen submatrix with 1. In other words, you choose two integers x and y such that 1 ≤ x < n and 1 ≤ y < m, and then set B_{x, y}, B_{x, y + 1}, B_{x + 1, y} and B_{x + 1, y + 1} to 1.

Your goal is to make matrix B equal to matrix A. Two matrices A and B are equal if and only if every element of matrix A is equal to the corresponding element of matrix B.

Is it possible to make these matrices equal? If it is, you have to come up with a sequence of operations that makes B equal to A. Note that you don't have to minimize the number of operations.

Input

The first line contains two integers n and m (2 ≤ n, m ≤ 50).

Then n lines follow, each containing m integers. The j-th integer in the i-th line is A_{i, j}. Each integer is either 0 or 1.

Output

If it is impossible to make B equal to A, print one integer -1.

Otherwise, print any sequence of operations that transforms B into A in the following format: the first line should contain one integer k — the number of operations, and then k lines should follow, each line containing two integers x and y for the corresponding operation (set B_{x, y}, B_{x, y + 1}, B_{x + 1, y} and B_{x + 1, y + 1} to 1). The condition 0 ≤ k ≤ 2500 should hold.

Examples

Input


3 3
1 1 1
1 1 1
0 1 1


Output


3
1 1
1 2
2 2


Input


3 3
1 0 1
1 0 1
0 0 0


Output


-1


Input


3 2
0 0
0 0
0 0


Output


0

Note

The sequence of operations in the first example:

\begin{matrix} 0 & 0 & 0 & & 1 & 1 & 0 & & 1 & 1 & 1 & & 1 & 1 & 1 \\\ 0 & 0 & 0 & → & 1 & 1 & 0 & → & 1 & 1 & 1 & → & 1 & 1 & 1 \\\ 0 & 0 & 0 & & 0 & 0 & 0 & & 0 & 0 & 0 & & 0 & 1 & 1 \end{matrix} 

import java.io.*;
import java.util.*;
public class B1027 
{
    static int check(int arr[][],int i,int j)
    {
        if(arr[i][j]==1 && arr[i][j+1]==1 && arr[i+1][j]==1 && arr[i+1][j+1]==1)
            return 1;
        else
            return 0;
    }
    public static void main(String args[])throws IOException
        {
            Scanner sc=new Scanner(System.in);
            int n=sc.nextInt();
            int m=sc.nextInt();
            int arr[][]=new int[n][m];
            for(int i=0;i<n;i++)
            {
                for(int j=0;j<m;j++)
                {
                    arr[i][j]=sc.nextInt();
                }
            }
            int b[][]=new int[n][m];
            StringBuffer sb=new StringBuffer("");int c=0;
            for(int i=0;i<n-1;i++)
            {
                for(int j=0;j<m-1;j++)
                {
                    if(check(arr,i,j)==1)
                    {
                        b[i][j]=1;b[i+1][j]=1;b[i][j+1]=1;b[i+1][j+1]=1;
                        c++;
                        sb.append(Integer.toString(i+1)+" "+Integer.toString(j+1)+"\n");
                    }
                }
            }
            for(int i=0;i<n;i++)
            {
                for(int j=0;j<m;j++)
                {
                    if(b[i][j]!=arr[i][j])
                    {
                        System.out.println(-1);
                        System.exit(0);
                    }
                }
            }
            System.out.println(c);
            System.out.println(sb);
           
        }

}
