Fox Ciel has some flowers: r red flowers, g green flowers and b blue flowers. She wants to use these flowers to make several bouquets. There are 4 types of bouquets:

  * To make a "red bouquet", it needs 3 red flowers. 
  * To make a "green bouquet", it needs 3 green flowers. 
  * To make a "blue bouquet", it needs 3 blue flowers. 
  * To make a "mixing bouquet", it needs 1 red, 1 green and 1 blue flower. 



Help Fox Ciel to find the maximal number of bouquets she can make.

Input

The first line contains three integers r, g and b (0 ≤ r, g, b ≤ 109) — the number of red, green and blue flowers.

Output

Print the maximal number of bouquets Fox Ciel can make.

Examples

Input

3 6 9


Output

6


Input

4 4 4


Output

4


Input

0 0 0


Output

0

Note

In test case 1, we can make 1 red bouquet, 2 green bouquets and 3 blue bouquets.

In test case 2, we can make 1 red, 1 green, 1 blue and 1 mixing bouquet.
import java.util.*;

public class ProblemA {

	public static void main(String[] args) {
		Scanner sc = new Scanner(System.in);
		long g = sc.nextLong();
		long r = sc.nextLong();
		long b =  sc.nextLong();
		long count=0;
		ArrayList<Long> a = new ArrayList<Long>();
		while(!(b<=3 && g<=3 && r<=3))
		{
			if(b>=3)
			{
				count = count+b/3;
				b=b%3;
				if(b==0)
				{
					b=3;
					count--;
				}
			}
			if(r>=3)
			{
				count = count+r/3;
				r=r%3;
				if(r==0)
				{
					r=3;
					count--;
				}
			}
			if(g>=3)
			{
				count = count+g/3;
				g=g%3;
				if(g==0)
				{
					g=3;
					count--;
				}
			}
		}
		a.add(b);
		a.add(g);
		a.add(r);
		a.sort(null);
		if(a.get(0)==0)
		{
			if(a.get(1)==3)
				count++;
			
			if(a.get(2)==3)
				count++;
		}
		if(a.get(0)==1)
		{
			if(a.get(1)==3 && a.get(2)==3)
				count+=2;
			else
			count = count + a.get(0);
			
		}
		else
			count = count + a.get(0);
		System.out.println(count);
	}

}
