A permutation of length n is an array p=[p_1,p_2,...,p_n], which contains every integer from 1 to n (inclusive) and, moreover, each number appears exactly once. For example, p=[3,1,4,2,5] is a permutation of length 5.

For a given number n (n ≥ 2), find a permutation p in which absolute difference (that is, the absolute value of difference) of any two neighboring (adjacent) elements is between 2 and 4, inclusive. Formally, find such permutation p that 2 ≤ |p_i - p_{i+1}| ≤ 4 for each i (1 ≤ i < n).

Print any such permutation for the given integer n or determine that it does not exist.

Input

The first line contains an integer t (1 ≤ t ≤ 100) — the number of test cases in the input. Then t test cases follow.

Each test case is described by a single line containing an integer n (2 ≤ n ≤ 1000).

Output

Print t lines. Print a permutation that meets the given requirements. If there are several such permutations, then print any of them. If no such permutation exists, print -1.

Example

Input


6
10
2
4
6
7
13


Output


9 6 10 8 4 7 3 1 5 2 
-1
3 1 4 2 
5 3 6 2 4 1 
5 1 3 6 2 4 7 
13 9 7 11 8 4 1 3 5 2 6 10 12 
import sys
ints = (int(x) for x in sys.stdin.read().split())
sys.setrecursionlimit(3000)

def main():
    ntc = next(ints)
    for tc in range(ntc):
        n = next(ints)
        if n==1: ans = [1]
        elif n<=3: ans = [-1]
        elif n<=4: ans = [2, 4, 1, 3]
        elif n<=5: ans = [1, 4, 2, 5, 3]
        else:
            ans = []
            x = 1+(n%2)
            while x < n-5:
                ans.append(x) ; x+=2
            ans.extend([n-5, n-2, n, n-3, n-1, n-4])
            x = n-6
            while x > 0:
                ans.append(x) ; x-=2
        print(' '.join(map(str,ans)))
    return

main()
