Tashizan Hikizan (Calculation Training)

square1001 You gave E869120 two numbers, $ A $ and $ B $, as birthday presents.

E869120 You decided to use these two numbers for calculation training.

Specifically, E869120 does the following for these numbers exactly $ N $ times:

* Replace $ A $ with $ A-B $ on odd-numbered operations
* Replace $ B $ with $ A + B $ on even-numbered operations




E869120 Find out what the values ​​of $ A $ and $ B $ are after you have operated $ N $ times.

input

Input is given from standard input in the following format.


$ N $
$ A $ $ B $


output

E869120 Please output the values ​​of $ A $ and $ B $ after you have operated $ N $ times in this order, separated by blanks.

However, insert a line break at the end.

Constraint

* $ 1 \ leq N \ leq 1000000000000000000 \ (= 10 ^ {18}) $
* $ 1 \ leq A \ leq 1000000000 \ (= 10 ^ 9) $
* $ 1 \ leq B \ leq 1000000000 \ (= 10 ^ 9) $
* All inputs are integers.



Input example 1


3
3 4


Output example 1


-4 3


The value of $ (A, B) $ changes as $ (3,4) → (-1,4) → (-1,3) → (-4,3) $.

Input example 2


8
6 9


Output example 2


3 -6






Example

Input

3
3 4


Output

-4 3
#define _USE_MATH_DEFINES
#include<iostream>
#include<string>
#include<queue>
#include<cmath>
#include<map>
#include<set>
#include<list>
#include<iomanip>
#include<vector>
#include<random>
#include<functional>
#include<algorithm>
#include<stack>
#include<cstdio>
#include<cstring>
#include<bitset>
#include<unordered_map>
#include<climits>
#include<fstream>
#include<time.h>
#include<cassert>

using namespace std;
#define ll long long
#define ld long double
#define int long long
#define all(a) (a).begin(),(a).end()
#define EPS (1e-13)
#define fs first
#define sc second
#define xx first
#define yy second.first
#define zz second.second
#define H pair<int, int>
#define P pair<int, pair<int, int>>
#define Q(i,j,k) mkp(i,mkp(j,k))
#define rep(i,n) for(int (i) = 0 ; (i) < (n) ; (i)++)
#define mkp make_pair
#define pb push_back
#define lb lower_bound
#define ub upper_bound
#define crdcomp(b) sort(all((b)));(b).erase(unique(all((b))),(b).end())
#define ssp(i,n) (i==n-1?"\n":" ")
const int mod = 1e9 + 7;
const int Mod = 998244353;
const ll Inf = 3 * 1e18;
const int inf = 15 * 1e8;
ll read() {
	ll u, k = scanf("%lld", &u);
	return u;
}
ll gcd(ll i, ll j) {
	if (i > j) swap(i, j);
	if (i == 0) return j;
	return gcd(j % i, i);
}
ll mod_pow(ll x, ll n, ll p) {
	ll res = 1;
	while (n > 0) {
		if (n & 1) res = res * x % p;
		x = x * x % p;
		n >>= 1;
	}
	return res;
}
ll bcount(ll x) {
	int sum = 0;
	for (int i = 0; i < 20; i++)
		if ((1ll << i) & x) sum++;
	return sum;
}
const int fn_ = 2000000;
ll fact_[fn_], comp_[fn_];
ll comb(ll x, ll y, ll Mod = mod) {
	if (!fact_[0]) {
		fact_[0] = 1; comp_[0] = 1;
		for (int i = 1; i < fn_; i++) {
			fact_[i] = fact_[i - 1] * i % Mod;
			comp_[i] = mod_pow(fact_[i], Mod - 2, Mod);
		}
	}
	if (x < y) return 0;
	return fact_[x] * comp_[x - y] % Mod * comp_[y] % Mod;
}
//---------------------------------------------------
signed main() {
	int a, b;
	int n;
	cin >> n >> a >> b;
	n %= 12;
	for (int i = 0; i < n; i++) {
		if (i % 2 == 0) a = a - b;
		else b = a + b;
	}
	cout << a << " " << b << endl;
}
