There are N points on the 2D plane, i-th of which is located on (x_i, y_i). There can be multiple points that share the same coordinate. What is the maximum possible Manhattan distance between two distinct points?

Here, the Manhattan distance between two points (x_i, y_i) and (x_j, y_j) is defined by |x_i-x_j| + |y_i-y_j|.

Constraints

* 2 \leq N \leq 2 \times 10^5
* 1 \leq x_i,y_i \leq 10^9
* All values in input are integers.

Input

Input is given from Standard Input in the following format:


N
x_1 y_1
x_2 y_2
:
x_N y_N


Output

Print the answer.

Examples

Input

3
1 1
2 4
3 2


Output

4


Input

2
1 1
1 1


Output

0

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.io.OutputStream;
import java.io.PrintWriter;
import java.math.BigDecimal;
import java.math.BigInteger;
import java.util.Arrays;
import java.util.Objects;

public class Main {
	
public static void main(String[] args) {
	InputStream inputStream = System.in;
	OutputStream outputStream = System.out;
	FastInput in = new FastInput(inputStream);
	PrintWriter out = new PrintWriter(outputStream);
	ABC178E solver = new ABC178E();
	solver.solve(1, in, out);
	out.close();
}

static class ABC178E {

	public void solve(int testNum, FastInput in, PrintWriter out) {
		
		int n = in.nextInt();
	
		int []x = new int [n];
		int []y = new int [n];
		
		for(int i = 0 ; i < n ;i++) {
			x[i] = in.nextInt();
			y[i] = in.nextInt();
		}
		
		int []x1 = new int [n];
		int []y1 = new int [n];
		
		
		for(int i = 0 ; i < n ; i++) {
			x1[i] = x[i] + y[i];
			y1[i] = x[i] - y[i];
		}
		
		Arrays.sort(x1);
		Arrays.sort(y1);
		
		
		int ans = Math.max(x1[n-1] - x1[0], y1[n-1] - y1[0]);
		out.println(ans);
		
			
		}
	}
static class FastInput{
	private final BufferedReader in;
	private String[] buff;
	private int index = 0;
	
	public FastInput(InputStream is) {
		in = new BufferedReader(new InputStreamReader(is));
	}
	String nextLine() {
		try {
			return in.readLine();
		} catch (IOException e) {
			e.printStackTrace();
		}
		return null;
	}
	String next() {
		while (buff == null || index >= buff.length) {
			buff = nextLine().split(" ");
			index = 0;
		}
		return buff[index++];
	}
	int nextInt() {
		return Integer.parseInt(next());
	}
	
	long nextLong() {
		return Long.parseLong(next());
	}
	
	Double nextDouble() {
		return Double.parseDouble(next());
	}
	
	BigInteger nextBigInteger() {
		return new BigInteger(next());
	}
	
	BigDecimal nextBigDecimal() {
		return new BigDecimal(next());
	}
	
	public int[] nextIntArray(final int n) {
		final int[] res = new int [n];
		
		for(int i = 0 ; i < n ;i++) {
			res[i] = nextInt();
		}
		return res;
	}
	
	public long[] nextLongArray(final int n) {
		final long[] res= new long [n];
		
		for(int i = 0 ; i < n ;i++) {
			res[i] = nextLong();
		}
		return res;
	}
	
	public double[] nextDoubleArray(final int n ) {
		final double[] res = new double [n];
		
		for(int i = 0 ; i < n ;i++) {
			res[i] = nextDouble();
		}
		return res;
	}
	
	
	public int[][] nextInt2DArray(final int n , final int m){
		int [][]res = new int [n][m];
		
		for(int i = 0 ; i < n ;i++) {
			for(int j = 0 ; j < m ;j++) {
				res[i][j] = nextInt();
			}
		}
		return res;
	}
	public long[][] nextLong2DArray(final int n , final int m){
		long [][]res = new long [n][m];
		
		for(int i = 0 ; i < n ;i++) {
			for(int j = 0 ; j < m ;j++) {
				res[i][j] = nextLong();
			}
		}
		return res;
	}
	
	public char[][] nextChar2DArray(final int n){
		char [][]res = new char [n][];
		
		for(int i = 0 ; i < n ;i++) {
			String s = next();
			res[i] = s.toCharArray();
		}
		
		return res;
	}
}

}
