There are N points on the 2D plane, i-th of which is located on (x_i, y_i). There can be multiple points that share the same coordinate. What is the maximum possible Manhattan distance between two distinct points?

Here, the Manhattan distance between two points (x_i, y_i) and (x_j, y_j) is defined by |x_i-x_j| + |y_i-y_j|.

Constraints

* 2 \leq N \leq 2 \times 10^5
* 1 \leq x_i,y_i \leq 10^9
* All values in input are integers.

Input

Input is given from Standard Input in the following format:


N
x_1 y_1
x_2 y_2
:
x_N y_N


Output

Print the answer.

Examples

Input

3
1 1
2 4
3 2


Output

4


Input

2
1 1
1 1


Output

0
import java.io.IOException;
import java.io.InputStream;
import java.util.*;

public class Main {
	
	public Main() {
		FastScanner scanner = new FastScanner();
		int N = scanner.nextInt();
		
		long[][] IN = new long[N][2];
		TreeMap<Long, long[]> XPY = new TreeMap<>();
		TreeMap<Long, long[]> XMY = new TreeMap<>();
		for (int i = 0; i < N; i++) {
			long x = scanner.nextLong();
			long y = scanner.nextLong();
			
			IN[i][0] = x;
			IN[i][1] = y;
			
			long [] t = new long[]{x,y};
			XPY.put(x+y, t);
			XMY.put(x-y, t);
		}
		
		long[] A = XPY.firstEntry().getValue();
		long[] B = XPY.lastEntry().getValue();
		long[] C = XMY.firstEntry().getValue();
		long[] D = XMY.lastEntry().getValue();
		
		long Ans = Long.MIN_VALUE;
		for (int i = 0; i < N; i++) {
			Ans = Math.max(Ans, d(IN[i], A));
			Ans = Math.max(Ans, d(IN[i], B));
			Ans = Math.max(Ans, d(IN[i], C));
			Ans = Math.max(Ans, d(IN[i], D));
		}
		
		System.out.println(Ans);
	}
	
	long d(long[] a, long[] b) {
		return Math.abs(a[0] - b[0]) + Math.abs(a[1] - b[1]);
	}
	
	public static void main(String[] args) {
		new Main();
	}
}

class FastScanner {
	private final InputStream in = System.in;
	private final byte[] buffer = new byte[1024];
	private int ptr = 0;
	private int buflen = 0;
	
	private boolean hasNextByte() {
		if (ptr < buflen) {
			return true;
		} else {
			ptr = 0;
			try {
				buflen = in.read(buffer);
			} catch (IOException e) {
				e.printStackTrace();
			}
			if (buflen <= 0) {
				return false;
			}
		}
		return true;
	}
	
	private int readByte() {
		if (hasNextByte()) return buffer[ptr++];
		else return -1;
	}
	
	private static boolean isPrintableChar(int c) {
		return 33 <= c && c <= 126;
	}
	
	public boolean hasNext() {
		while (hasNextByte() && !isPrintableChar(buffer[ptr])) ptr++;
		return hasNextByte();
	}
	
	public String next() {
		if (!hasNext()) throw new NoSuchElementException();
		StringBuilder sb = new StringBuilder();
		int b = readByte();
		while (isPrintableChar(b)) {
			sb.appendCodePoint(b);
			b = readByte();
		}
		return sb.toString();
	}
	
	public long nextLong() {
		if (!hasNext()) throw new NoSuchElementException();
		long n = 0;
		boolean minus = false;
		int b = readByte();
		if (b == '-') {
			minus = true;
			b = readByte();
		}
		if (b < '0' || '9' < b) {
			throw new NumberFormatException();
		}
		while (true) {
			if ('0' <= b && b <= '9') {
				n *= 10;
				n += b - '0';
			} else if (b == -1 || !isPrintableChar(b)) {
				return minus ? -n : n;
			} else {
				throw new NumberFormatException();
			}
			b = readByte();
		}
	}
	
	public int nextInt() {
		long nl = nextLong();
		if (nl < Integer.MIN_VALUE || nl > Integer.MAX_VALUE) throw new NumberFormatException();
		return (int) nl;
	}
	
	public double nextDouble() {
		return Double.parseDouble(next());
	}
}
