Unlucky year in Berland is such a year that its number n can be represented as n = xa + yb, where a and b are non-negative integer numbers. 

For example, if x = 2 and y = 3 then the years 4 and 17 are unlucky (4 = 20 + 31, 17 = 23 + 32 = 24 + 30) and year 18 isn't unlucky as there is no such representation for it.

Such interval of years that there are no unlucky years in it is called The Golden Age.

You should write a program which will find maximum length of The Golden Age which starts no earlier than the year l and ends no later than the year r. If all years in the interval [l, r] are unlucky then the answer is 0.

Input

The first line contains four integer numbers x, y, l and r (2 ≤ x, y ≤ 1018, 1 ≤ l ≤ r ≤ 1018).

Output

Print the maximum length of The Golden Age within the interval [l, r].

If all years in the interval [l, r] are unlucky then print 0.

Examples

Input

2 3 1 10


Output

1


Input

3 5 10 22


Output

8


Input

2 3 3 5


Output

0

Note

In the first example the unlucky years are 2, 3, 4, 5, 7, 9 and 10. So maximum length of The Golden Age is achived in the intervals [1, 1], [6, 6] and [8, 8].

In the second example the longest Golden Age is the interval [15, 22].
import java.io.*;
import java.util.*;

public class ProblemB {

    public static void main(String[] args) throws IOException {
        init();
        new ProblemB().run();
        out.flush();
        out.close();
    }

    static void init() throws IOException {
        in = new StreamTokenizer(new BufferedReader(new InputStreamReader(System.in)));
        out = new PrintWriter(new OutputStreamWriter(System.out));
        in.ordinaryChars(0, 65535);
        in.wordChars(0, 65535);
        in.whitespaceChars(' ', ' ');
        in.whitespaceChars('\n', '\n');
        in.whitespaceChars('\r', '\r');
    }

    // класс для пар
    class Pair<L, R> {
        private final L X;
        private final R Y;

        public Pair(L X, R Y) {
            this.X = X;
            this.Y = Y;
        }

        public L getX() {
            return X;
        }

        public R getY() {
            return Y;
        }

        @Override
        public int hashCode() {
            return X.hashCode() ^ Y.hashCode();
        }

        @Override
        public boolean equals(Object o) {
            if (!(o instanceof Pair)) return false;
            Pair pairo = (Pair) o;
            return X.equals(pairo.getX()) && Y.equals(pairo.getY());
        }
    }

    static final long INFL = 200000000000000000L;
    static final int INF = 2000000000;
    static final boolean DEBUG = true;

    static StreamTokenizer in;
    static PrintWriter out;

    static void print(String s) {
        print(s, 0);
    }

    static void print(String s, int debug) {
        if (debug == 0 || DEBUG) {
            out.print(s);
        }
    }

    static void println(String s) {
        println(s, 0);
    }

    static void println(String s, int debug) {
        if (debug == 0 || DEBUG) {
            out.println(s);
        }
    }

    static void printArray(int[] arr) {
        println(Arrays.toString(arr));
    }

    static void printArray(char[] arr) {
        println(Arrays.toString(arr));
    }

    static void printArray(String[] arr) {
        println(Arrays.toString(arr));
    }

    static void sort(int[] a) {
        Random rnd = new Random();
        for (int i = a.length - 1; i > 0; i--) {
            int index = rnd.nextInt(i);
            a[i] ^= a[index];
            a[index] ^= a[i];
            a[i] ^= a[index];
        }
        Arrays.sort(a);
    }

    static char[] inChars;
    static int inCharsInd;

    static String next() throws IOException {
        in.nextToken();
        return in.sval;
    }

    static char nextChar() throws IOException {
        while (inChars == null || inCharsInd >= inChars.length) {
            inChars = next().toCharArray();
            inCharsInd = 0;
        }
        return inChars[inCharsInd++];
    }

    static int nextInt() throws IOException {
        return Integer.valueOf(next());
    }

    static double nextDouble() throws IOException {
        return Double.valueOf(next());
    }

    static long nextLong() throws IOException {
        return Long.valueOf(next());
    }

    private void run() throws IOException {
        solve();
    }

    int K, L, M, N, P;

    private void solve() throws IOException {
        long x = nextLong();
        long y = nextLong();
        long l = nextLong();
        long r = nextLong();


        Set<Long> set = new TreeSet<>();
        set.add(0L);
        set.add(1000000000000000001L);
        long xx = 1;
        long yy = 1;
        long xxCurr, yyCurr;
        long sum;

        do {
            do {
                if (l <= xx + yy && xx + yy <= r) {
                    set.add(xx + yy);
                }
                yyCurr = yy;
                yy *= y;
                sum = xx + yy;
            } while (yy/y == yyCurr && sum >= 0);
            xxCurr = xx;
            xx *= x;
            yy = 1;
        } while (xx/x == xxCurr);
        
        long maxLength = 0;
        long[] nums = new long[set.size()];
        int ind = 0;
        for (Long ll : set) {
            nums[ind++] = ll;
        }
        for (int i = 1; i < nums.length; i++) {
            maxLength = Math.max(maxLength, Math.min(nums[i]-1, r) - Math.max(nums[i-1]+1, l) + 1);
        }
        out.println(maxLength);

    }

}