Fox Ciel has some flowers: r red flowers, g green flowers and b blue flowers. She wants to use these flowers to make several bouquets. There are 4 types of bouquets:

  * To make a "red bouquet", it needs 3 red flowers. 
  * To make a "green bouquet", it needs 3 green flowers. 
  * To make a "blue bouquet", it needs 3 blue flowers. 
  * To make a "mixing bouquet", it needs 1 red, 1 green and 1 blue flower. 



Help Fox Ciel to find the maximal number of bouquets she can make.

Input

The first line contains three integers r, g and b (0 ≤ r, g, b ≤ 109) — the number of red, green and blue flowers.

Output

Print the maximal number of bouquets Fox Ciel can make.

Examples

Input

3 6 9


Output

6


Input

4 4 4


Output

4


Input

0 0 0


Output

0

Note

In test case 1, we can make 1 red bouquet, 2 green bouquets and 3 blue bouquets.

In test case 2, we can make 1 red, 1 green, 1 blue and 1 mixing bouquet.
//https://codeforces.com/problemset/problem/322/B
//B. Ciel and Flowers
import java.util.*;
import java.io.*;
public class Ciel_And_Flowers{
	public static void main(String[] args) throws Exception{
		
		BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
		PrintWriter pw = new PrintWriter(new OutputStreamWriter(System.out));
		StringBuilder sb = new StringBuilder();

		StringTokenizer st = new StringTokenizer(br.readLine().trim());
		int a = Integer.parseInt(st.nextToken());
		int b = Integer.parseInt(st.nextToken());
		int c = Integer.parseInt(st.nextToken());

		int min = (a<b)?((a<c)?a:c):(b<c)?b:c;
		int max = 0;
		if(min==0)
			max = Math.max(max,a/3+b/3+c/3);
		else if(min==1){
			max = Math.max(max,(a-1)/3+(b-1)/3+(c-1)/3+1);
			max = Math.max(max,a/3+b/3+c/3);
		}
		else{
			max = Math.max(max,(a-2)/3+(b-2)/3+(c-2)/3+2);
			max = Math.max(max,(a-1)/3+(b-1)/3+(c-1)/3+1);
			max = Math.max(max,a/3+b/3+c/3);
		}

		pw.print(max);
		pw.flush();
		pw.close();
	}
}