We have a tree with N vertices, whose i-th edge connects Vertex u_i and Vertex v_i. Vertex i has an integer a_i written on it. For every integer k from 1 through N, solve the following problem:

* We will make a sequence by lining up the integers written on the vertices along the shortest path from Vertex 1 to Vertex k, in the order they appear. Find the length of the longest increasing subsequence of this sequence.



Here, the longest increasing subsequence of a sequence A of length L is the subsequence A_{i_1} , A_{i_2} , ... , A_{i_M} with the greatest possible value of M such that 1 \leq i_1 < i_2 < ... < i_M \leq L and A_{i_1} < A_{i_2} < ... < A_{i_M}.

Constraints

* 2 \leq N \leq 2 \times 10^5
* 1 \leq a_i \leq 10^9
* 1 \leq u_i , v_i \leq N
* u_i \neq v_i
* The given graph is a tree.
* All values in input are integers.

Input

Input is given from Standard Input in the following format:


N
a_1 a_2 ... a_N
u_1 v_1
u_2 v_2
:
u_{N-1} v_{N-1}


Output

Print N lines. The k-th line, print the length of the longest increasing subsequence of the sequence obtained from the shortest path from Vertex 1 to Vertex k.

Example

Input

10
1 2 5 3 4 6 7 3 2 4
1 2
2 3
3 4
4 5
3 6
6 7
1 8
8 9
9 10


Output

1
2
3
3
4
4
5
2
2
3
from bisect import bisect_left


def main():
    N = int(input())
    A = [int(x) for x in input().split()]
    tree = [list() for _ in range(N)]
    for _ in range(N-1):
        u, v = [int(x) for x in input().split()]
        u -= 1
        v -= 1
        tree[u].append(v)
        tree[v].append(u)

    ans = [1] * N

    # dfs
    def dfs(u, par):
        nonlocal ans
        nonlocal dp
        pos = bisect_left(dp, A[u])
        old = dp[pos]
        dp[pos] = A[u]

        ans[u] = bisect_left(dp, float("inf")) - 1

        for v in tree[u]:
            if v == par:
                continue
            dfs(v, u)

        dp[pos] = old

    dp = [float("inf")] * (N+1)
    dp[0] = float("-inf")
    dfs(0, -1)

    for i in range(N):
        print(ans[i])


if __name__ == '__main__':
    import sys
    sys.setrecursionlimit(10**6)
    main()
