A permutation of length n is an array p=[p_1,p_2,...,p_n], which contains every integer from 1 to n (inclusive) and, moreover, each number appears exactly once. For example, p=[3,1,4,2,5] is a permutation of length 5.

For a given number n (n ≥ 2), find a permutation p in which absolute difference (that is, the absolute value of difference) of any two neighboring (adjacent) elements is between 2 and 4, inclusive. Formally, find such permutation p that 2 ≤ |p_i - p_{i+1}| ≤ 4 for each i (1 ≤ i < n).

Print any such permutation for the given integer n or determine that it does not exist.

Input

The first line contains an integer t (1 ≤ t ≤ 100) — the number of test cases in the input. Then t test cases follow.

Each test case is described by a single line containing an integer n (2 ≤ n ≤ 1000).

Output

Print t lines. Print a permutation that meets the given requirements. If there are several such permutations, then print any of them. If no such permutation exists, print -1.

Example

Input


6
10
2
4
6
7
13


Output


9 6 10 8 4 7 3 1 5 2 
-1
3 1 4 2 
5 3 6 2 4 1 
5 1 3 6 2 4 7 
13 9 7 11 8 4 1 3 5 2 6 10 12 
import random
import math
LI = lambda: list(map(int,input().split()))
MI = lambda: map(int,input().split())
yes = lambda: print("Yes")
no = lambda: print("No")
I = lambda: list(input())
J = lambda x: "".join(x)
II = lambda: int(input())
SI = lambda: input()
#---khan17---template
t = II()
for q in range(t):
	n = II()
	if n in [2,3]:
		print(-1)
	else:
		a = []
		b = []
		for i in range(n):
			if i%2 == 0:
				a.append(i+1)
			else:
				b.append(i+1)
		a+=b[:][::-1]
		if n%2 == 0:
			a[n//2-1],a[n//2-2] = a[n//2-2],a[n//2-1]
		else:
			a[n//2+1],a[n//2+2] = a[n//2+2],a[n//2+1]
		print(*a)