Kurt reaches nirvana when he finds the product of all the digits of some positive integer. Greater value of the product makes the nirvana deeper.

Help Kurt find the maximum possible product of digits among all integers from 1 to n.

Input

The only input line contains the integer n (1 ≤ n ≤ 2⋅10^9).

Output

Print the maximum product of digits among all integers from 1 to n.

Examples

Input


390


Output


216


Input


7


Output


7


Input


1000000000


Output


387420489

Note

In the first example the maximum product is achieved for 389 (the product of digits is 3⋅8⋅9=216).

In the second example the maximum product is achieved for 7 (the product of digits is 7).

In the third example the maximum product is achieved for 999999999 (the product of digits is 9^9=387420489).
'''
    Auther: ghoshashis545 Ashis Ghosh
    College: jalpaiguri Govt Enggineerin College
    Date:03/06/2020

'''
import sys
from collections import deque,defaultdict as dd 
from bisect import bisect,bisect_left,bisect_right,insort,insort_left,insort_right
from itertools import permutations
from datetime import datetime
from math import ceil,sqrt,log,gcd
def ii():return int(input())
def si():return input()
def mi():return map(int,input().split())
def li():return list(mi())
abc='abcdefghijklmnopqrstuvwxyz'
abd={'a': 0, 'b': 1, 'c': 2, 'd': 3, 'e': 4, 'f': 5, 'g': 6, 'h': 7, 'i': 8, 'j': 9, 'k': 10, 'l': 11, 'm': 12, 'n': 13, 'o': 14, 'p': 15, 'q': 16, 'r': 17, 's': 18, 't': 19, 'u': 20, 'v': 21, 'w': 22, 'x': 23, 'y': 24, 'z': 25}
mod=1000000007
#mod=998244353
inf = float("inf")
vow=['a','e','i','o','u']
dx,dy=[-1,1,0,0],[0,0,1,-1]
def read():
    tc=0
    if tc:
        input=sys.stdin.readline
    else:
        sys.stdin=open('input1.txt', 'r')
        sys.stdout=open('output1.txt','w')






def solve():
    
    
    
    s=si()
    x=[]
    for i in s:
        x.append(int(i))
    n=len(x)
    ans=[]
    ans1=1
    for i in range(n-1):
        if(x[i]==0):
            continue
        p=ans1
        if(x[i]!=1):
            p*=(x[i]-1)
        p*=pow(9,n-i-1)
        ans.append(p)
        ans1*=x[i]
    ans.append(ans1*x[n-1])
    print(max(ans))
    
    
    
        
    
    
if __name__ =="__main__":
    # read()
    solve()
    