You have a card deck of n cards, numbered from top to bottom, i. e. the top card has index 1 and bottom card — index n. Each card has its color: the i-th card has color a_i.

You should process q queries. The j-th query is described by integer t_j. For each query you should: 

  * find the highest card in the deck with color t_j, i. e. the card with minimum index; 
  * print the position of the card you found; 
  * take the card and place it on top of the deck. 

Input

The first line contains two integers n and q (2 ≤ n ≤ 3 ⋅ 10^5; 1 ≤ q ≤ 3 ⋅ 10^5) — the number of cards in the deck and the number of queries.

The second line contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 50) — the colors of cards.

The third line contains q integers t_1, t_2, ..., t_q (1 ≤ t_j ≤ 50) — the query colors. It's guaranteed that queries ask only colors that are present in the deck.

Output

Print q integers — the answers for each query.

Example

Input


7 5
2 1 1 4 3 3 1
3 2 1 1 4


Output


5 2 3 1 5 

Note

Description of the sample: 

  1. the deck is [2, 1, 1, 4, \underline{3}, 3, 1] and the first card with color t_1 = 3 has position 5; 
  2. the deck is [3, \underline{2}, 1, 1, 4, 3, 1] and the first card with color t_2 = 2 has position 2; 
  3. the deck is [2, 3, \underline{1}, 1, 4, 3, 1] and the first card with color t_3 = 1 has position 3; 
  4. the deck is [\underline{1}, 2, 3, 1, 4, 3, 1] and the first card with color t_4 = 1 has position 1; 
  5. the deck is [1, 2, 3, 1, \underline{4}, 3, 1] and the first card with color t_5 = 4 has position 5. 
# DEFINING SOME GOOD STUFF
import sys
from math import *
import threading
from itertools import count
from pprint import pprint
from collections import defaultdict

'''
    intialise defaultdict by any kind of value by default you want to take ( int -> 0 | list -> [] )
'''
from heapq import heapify, heappop, heappush

sys.setrecursionlimit(300000)
# threading.stack_size(10**8)
'''
-> if you are increasing recursionlimit then remember submitting using python3 rather pypy3
-> sometimes increasing stack size don't work locally but it will work on CF
'''

mod = 10 ** 9+7
inf = 10 ** 15
decision = ['NO', 'YES']
yes = 'YES'
no = 'NO'

# ------------------------------FASTIO----------------------------
import os

from io import BytesIO, IOBase

BUFSIZE = 8192


class FastIO(IOBase):
    newlines = 0

    def __init__(self, file):
        self._fd = file.fileno()
        self.buffer = BytesIO()
        self.writable = "x" in file.mode or "r" not in file.mode
        self.write = self.buffer.write if self.writable else None

    def read(self):
        while True:
            b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
            if not b:
                break
            ptr = self.buffer.tell()
            self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
        self.newlines = 0
        return self.buffer.read()

    def readline(self):
        while self.newlines == 0:
            b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
            self.newlines = b.count(b"\n")+(not b)
            ptr = self.buffer.tell()
            self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
        self.newlines -= 1
        return self.buffer.readline()

    def flush(self):
        if self.writable:
            os.write(self._fd, self.buffer.getvalue())
            self.buffer.truncate(0), self.buffer.seek(0)


class IOWrapper(IOBase):
    def __init__(self, file):
        self.buffer = FastIO(file)
        self.flush = self.buffer.flush
        self.writable = self.buffer.writable
        self.write = lambda s: self.buffer.write(s.encode("ascii"))
        self.read = lambda: self.buffer.read().decode("ascii")
        self.readline = lambda: self.buffer.readline().decode("ascii")


sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
input = lambda: sys.stdin.readline().rstrip("\r\n")


# _______________________________________________________________#

def npr(n, r):
    return (factorial(n)%mod) // (factorial(n-r)%mod) if n >= r else 0


def ncr(n, r):
    return (factorial(n)%mod) // ((factorial(r)%mod) * (factorial(n-r)%mod)) if n >= r else 0


def lower_bound(li, num):
    answer = -1
    start = 0
    end = len(li)-1

    while (start <= end):
        middle = (end+start) // 2
        if li[middle] >= num:
            answer = middle
            end = middle-1
        else:
            start = middle+1
    return answer  # min index where x is not less than num


def upper_bound(li, num):
    answer = -1
    start = 0
    end = len(li)-1

    while (start <= end):
        middle = (end+start) // 2

        if li[middle] <= num:
            answer = middle
            start = middle+1

        else:
            end = middle-1
    return answer  # max index where x is not greater than num


def abs(x):
    return x if x >= 0 else -x


def binary_search(li, val):
    # print(lb, ub, li)
    ans = -1
    lb = 0
    ub = len(li)-1
    while (lb <= ub):
        mid = (lb+ub) // 2
        # print('mid is',mid, li[mid])
        if li[mid] > val:
            ub = mid-1
        elif val > li[mid]:
            lb = mid+1
        else:
            ans = mid  # return index
            break
    return ans


def kadane(x):  # maximum sum contiguous subarray
    sum_so_far = 0
    current_sum = 0
    for i in x:
        current_sum += i
        if current_sum < 0:
            current_sum = 0
        else:
            sum_so_far = max(sum_so_far, current_sum)
    return sum_so_far


# def pref(li):
#     pref_sum = [0]
#     for i in li:
#         pref_sum.append(pref_sum[-1]+i)
#     return pref_sum


def SieveOfEratosthenes(n):
    prime = [True for i in range(n+1)]
    p = 2
    li = []
    while (p * p <= n):
        if (prime[p] == True):
            for i in range(p * p, n+1, p):
                prime[i] = False
        p += 1

    for p in range(2, len(prime)):
        if prime[p]:
            li.append(p)
    return li


def primefactors(n):
    factors = []
    while (n % 2 == 0):
        factors.append(2)
        n //= 2
    for i in range(3, int(sqrt(n))+1, 2):  # only odd factors left
        while n % i == 0:
            factors.append(i)
            n //= i
    if n > 2:  # incase of prime
        factors.append(n)
    return factors


def prod(li):
    ans = 1
    for i in li:
        ans *= i
    return ans


def sumk(a, b):
    print('called for', a, b)
    ans = a * (a+1) // 2
    ans -= b * (b+1) // 2
    return ans

def sumi(n):
    ans = 0
    if len(n) > 1:
        for x in n:
            ans += int(x)
        return ans
    else:
        return int(n)

# _______________________________________________________________#


# def main():
# karmanya = int(input())
karmanya = 1
while karmanya != 0:
    karmanya -= 1
    # n = int(input())
    n, q = map(int, input().split())
    # a = [int(x) for x in input()]
    a = list(map(int, input().split()))
    b = list(map(int, input().split()))
    # c = list(map(int, input().split()))
    d = defaultdict(int)
    for i in range(n):
        if a[i] in d:
            continue
        else:
            d[a[i]] = i+1
    # print(d)
    for i in b:
        ind = d[i]
        # print('ind of', i,'is', d[i])
        print(d[i], end=' ')
        d[i] = 1
        # print(d)
        for k, v in d.items():
            if v < ind and k != i:
                d[k] = v + 1
        # print('now d becomes', d)
    print('')






























































# t = threading.Thread(target=main)
# t.start()
# t.join()