Snuke is introducing a robot arm with the following properties to his factory:

* The robot arm consists of m sections and m+1 joints. The sections are numbered 1, 2, ..., m, and the joints are numbered 0, 1, ..., m. Section i connects Joint i-1 and Joint i. The length of Section i is d_i.
* For each section, its mode can be specified individually. There are four modes: `L`, `R`, `D` and `U`. The mode of a section decides the direction of that section. If we consider the factory as a coordinate plane, the position of Joint i will be determined as follows (we denote its coordinates as (x_i, y_i)):
* (x_0, y_0) = (0, 0).
* If the mode of Section i is `L`, (x_{i}, y_{i}) = (x_{i-1} - d_{i}, y_{i-1}).
* If the mode of Section i is `R`, (x_{i}, y_{i}) = (x_{i-1} + d_{i}, y_{i-1}).
* If the mode of Section i is `D`, (x_{i}, y_{i}) = (x_{i-1}, y_{i-1} - d_{i}).
* If the mode of Section i is `U`, (x_{i}, y_{i}) = (x_{i-1}, y_{i-1} + d_{i}).



Snuke would like to introduce a robot arm so that the position of Joint m can be matched with all of the N points (X_1, Y_1), (X_2, Y_2), ..., (X_N, Y_N) by properly specifying the modes of the sections. Is this possible? If so, find such a robot arm and how to bring Joint m to each point (X_j, Y_j).

Constraints

* All values in input are integers.
* 1 \leq N \leq 1000
* -10^9 \leq X_i \leq 10^9
* -10^9 \leq Y_i \leq 10^9

Input

Input is given from Standard Input in the following format:


N
X_1 Y_1
X_2 Y_2
:
X_N Y_N


Output

If the condition can be satisfied, follow the following format. If the condition cannot be satisfied, print `-1`.


m
d_1 d_2 ... d_m
w_1
w_2
:
w_N


m and d_i are the configurations of the robot arm. Refer to the problem statement for what each of them means. Here, 1 \leq m \leq 40 and 1 \leq d_i \leq 10^{12} must hold. Also, m and d_i must all be integers.

w_j is a string of length m that represents the way to bring Joint m of the robot arm to point (X_j, Y_j). The i-th character of w_j should be one of the letters `L`, `R`, `D` and `U`, representing the mode of Section i.

Examples

Input

3
-1 0
0 3
2 -1


Output

2
1 2
RL
UU
DR


Input

5
0 0
1 0
2 0
3 0
4 0


Output

-1


Input

2
1 1
1 1


Output

2
1 1
RU
UR


Input

3
-7 -3
7 3
-3 -7


Output

5
3 1 4 1 5
LRDUL
RDULR
DULRD
#include <bits/stdc++.h>
using namespace std;

int main(){
    int N; cin >> N;
    vector<int> U(N), V(N);
    for(int i=0; i<N; i++){
        int X, Y;  cin >> X >> Y;
        U[i] = X + Y;
        V[i] = X - Y;
    }
    for(int i=1; i<N; i++){
        if(abs(U[i])%2 != abs(U[0])%2){
            cout << -1 << endl;
            return 0;
        }
    }

    int m = 31 + 1 - abs(U[0])%2;
    vector<int> d(m);
    for(int i=0; i<=30; i++) d[30-i] = pow(2,i);
    if(m==32) d[31] = 1;

    cout << m << endl;
    for(int i=0; i<m-1; i++) cout << d[i] << " ";
    cout << d[m-1] << endl;

    for(int i=0; i<N; i++){
        string mode = "";
        int u = 0, v = 0;
        for(int j=0; j<m; j++){
            //cerr << U[i] << " " << V[i] << " : " << u << " " << v << "  -- > ";
            if(u < U[i] && v < V[i]){
                u += d[j];  v += d[j];
                mode += "R";
            }else if(u >= U[i] && v < V[i]){
                u -= d[j];  v += d[j];
                mode += "D";
            }else if(u < U[i] && v >= V[i]){
                u += d[j];  v -= d[j];
                mode += "U";
            }else if(u >= U[i] && v >= V[i]){
                u -= d[j];  v -= d[j];
                mode += "L";
            }
            //cerr << u << " " << v << endl;
        }
        cout << mode << endl;
    }
}
