Fox Ciel has some flowers: r red flowers, g green flowers and b blue flowers. She wants to use these flowers to make several bouquets. There are 4 types of bouquets:

  * To make a "red bouquet", it needs 3 red flowers. 
  * To make a "green bouquet", it needs 3 green flowers. 
  * To make a "blue bouquet", it needs 3 blue flowers. 
  * To make a "mixing bouquet", it needs 1 red, 1 green and 1 blue flower. 



Help Fox Ciel to find the maximal number of bouquets she can make.

Input

The first line contains three integers r, g and b (0 ≤ r, g, b ≤ 109) — the number of red, green and blue flowers.

Output

Print the maximal number of bouquets Fox Ciel can make.

Examples

Input

3 6 9


Output

6


Input

4 4 4


Output

4


Input

0 0 0


Output

0

Note

In test case 1, we can make 1 red bouquet, 2 green bouquets and 3 blue bouquets.

In test case 2, we can make 1 red, 1 green, 1 blue and 1 mixing bouquet.
import java.util.Arrays;
import java.util.Scanner;

public class CeilFlowers190B {

	public static void main(String[] args) {
		Scanner s =new Scanner(System.in);
		
		int r = s.nextInt();
		int b = s.nextInt();
		int g = s.nextInt();
		
		
		int ans= r/3 + b /3 + g/3;
		
		if(r > 0  && b > 0 && g >0) {
			int one = (r-1)/3 + (g-1)/3 + (b-1)/3;
			ans = Math.max(ans, 1 +  one);
			if(r > 1 && b >1 && g >1) {
				int two = (r-2)/3 + (g-2)/3 + (b-2)/3;
				ans = Math.max(ans, 2 + two);
			}
		}
		System.out.println(ans);
		}
	
	
	

}
