XXI Berland Annual Fair is coming really soon! Traditionally fair consists of n booths, arranged in a circle. The booths are numbered 1 through n clockwise with n being adjacent to 1. The i-th booths sells some candies for the price of a_i burles per item. Each booth has an unlimited supply of candies.

Polycarp has decided to spend at most T burles at the fair. However, he has some plan in mind for his path across the booths:

  * at first, he visits booth number 1; 
  * if he has enough burles to buy exactly one candy from the current booth, then he buys it immediately; 
  * then he proceeds to the next booth in the clockwise order (regardless of if he bought a candy or not). 



Polycarp's money is finite, thus the process will end once he can no longer buy candy at any booth.

Calculate the number of candies Polycarp will buy.

Input

The first line contains two integers n and T (1 ≤ n ≤ 2 ⋅ 10^5, 1 ≤ T ≤ 10^{18}) — the number of booths at the fair and the initial amount of burles Polycarp has.

The second line contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 10^9) — the price of the single candy at booth number i.

Output

Print a single integer — the total number of candies Polycarp will buy.

Examples

Input

3 38
5 2 5


Output

10


Input

5 21
2 4 100 2 6


Output

6

Note

Let's consider the first example. Here are Polycarp's moves until he runs out of money:

  1. Booth 1, buys candy for 5, T = 33; 
  2. Booth 2, buys candy for 2, T = 31; 
  3. Booth 3, buys candy for 5, T = 26; 
  4. Booth 1, buys candy for 5, T = 21; 
  5. Booth 2, buys candy for 2, T = 19; 
  6. Booth 3, buys candy for 5, T = 14; 
  7. Booth 1, buys candy for 5, T = 9; 
  8. Booth 2, buys candy for 2, T = 7; 
  9. Booth 3, buys candy for 5, T = 2; 
  10. Booth 1, buys no candy, not enough money; 
  11. Booth 2, buys candy for 2, T = 0. 



No candy can be bought later. The total number of candies bought is 10.

In the second example he has 1 burle left at the end of his path, no candy can be bought with this amount.
import javax.print.DocFlavor;
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.nio.charset.IllegalCharsetNameException;
import java.util.*;



public class Main {



    public static void main(String[] args) throws IOException {
        Reader.init(System.in);
        /*int q = Reader.nextInt();
        while (q-->0){
            solve();
        }*/
        int n = Reader.nextInt();
        long T = Reader.nextLong();
        long[] arr = new long[n];
        long ans = 0;
        for (int i = 0; i < n ; i++){
            arr[i] = Reader.nextInt();
        }
        while (T>0){
            long tt = T;
            int cnt = 0;
            for (int i = 0; i < n ; i++){
                if (arr[i]<=tt){
                    tt-=arr[i];
                    cnt++;
                }
            }
            //System.out.println(ans + " " +cnt);
            if (cnt==0){
                //System.out.println("BREAK");
                break;
            }
            ans+= (T/(T-tt))*cnt;

            T%=(T-tt);
            //System.out.println(ans + " " + T);

        }
        System.out.println(ans);


    }
    static void solve() throws IOException{
        int n = Reader.nextInt();
        int r = Reader.nextInt();
        TreeSet<Integer> sett = new TreeSet<Integer>();

        int[] x = new int[n];
        for (int i = 0; i < n; i ++) {
            x[i] = Reader.nextInt();
            sett.add(x[i]);
        }
        int count = 0;
        int origin = 0;

        while(!sett.isEmpty()) {
            count += 1;

            sett.remove(sett.last());
            origin += r;

            // System.out.println(sett.toString());

            if(sett.size() == 0)
                break;

            while(!sett.isEmpty() && sett.first() <= origin) {
                sett.remove(sett.first());
            }

            // System.out.println(sett.toString());

        }

        System.out.println(count);










    }

    static long gcd(long a, long b)
    {
        if (a == 0)
            return b;
        return gcd(b % a, a);
    }

    // method to return LCM of two numbers
    static long lcm(long a, long b)
    {
        return (a*b)/gcd(a, b);
    }

















}

class Edge implements Comparable<Edge>{
    int x , y , w;

    public Edge(int x, int y, int w) {
        this.x = x;
        this.y = y;
        this.w = w;
    }

    @Override
    public int compareTo(Edge o) {
        return this.w - o.w;
    }
}
class Reader {
    static BufferedReader reader;
    static StringTokenizer tokenizer;

    /** call this method to initialize reader for InputStream */
    static void init(InputStream input) {
        reader = new BufferedReader(
                new InputStreamReader(input) );
        tokenizer = new StringTokenizer("");
    }
    /** get next word */
    static String next() throws IOException {
        while ( ! tokenizer.hasMoreTokens() ) {
            //TODO add check for eof if necessary
            tokenizer = new StringTokenizer(
                    reader.readLine() );
        }
        return tokenizer.nextToken();
    }

    static int nextInt() throws IOException {
        return Integer.parseInt( next() );
    }
    static long nextLong() throws IOException {
        return Long.parseLong( next() );
    }

    static double nextDouble() throws IOException {
        return Double.parseDouble( next() );
    }
}
class MergeSort
{
    // Merges two subarrays of arr[].
    // First subarray is arr[l..m]
    // Second subarray is arr[m+1..r]
    void merge(int arr[], int l, int m, int r)
    {
        // Find sizes of two subarrays to be merged
        int n1 = m - l + 1;
        int n2 = r - m;

        /* Create temp arrays */
        int L[] = new int [n1];
        int R[] = new int [n2];

        /*Copy data to temp arrays*/
        for (int i=0; i<n1; ++i)
            L[i] = arr[l + i];
        for (int j=0; j<n2; ++j)
            R[j] = arr[m + 1+ j];


        /* Merge the temp arrays */

        // Initial indexes of first and second subarrays
        int i = 0, j = 0;

        // Initial index of merged subarry array
        int k = l;
        while (i < n1 && j < n2)
        {
            if (L[i] <= R[j])
            {
                arr[k] = L[i];
                i++;
            }
            else
            {
                arr[k] = R[j];
                j++;
            }
            k++;
        }

        /* Copy remaining elements of L[] if any */
        while (i < n1)
        {
            arr[k] = L[i];
            i++;
            k++;
        }

        /* Copy remaining elements of R[] if any */
        while (j < n2)
        {
            arr[k] = R[j];
            j++;
            k++;
        }
    }

    // Main function that sorts arr[l..r] using
    // merge()
    void sort(int arr[], int l, int r)
    {
        if (l < r)
        {
            // Find the middle point
            int m = (l+r)/2;

            // Sort first and second halves
            sort(arr, l, m);
            sort(arr , m+1, r);

            // Merge the sorted halves
            merge(arr, l, m, r);
        }
    }

    /* A utility function to print array of size n */
    static void printArray(int arr[])
    {
        int n = arr.length;
        for (int i=0; i<n; ++i)
            System.out.print(arr[i] + " ");
        System.out.println();
    }

    // Driver method

}

class Node implements Comparable<Node>{
    int a;
    int b;
    Node (int a , int b){
        this.a = a;
        this.b = b;
    }



    public int compareTo(Node o) {
        if (this.a != o.a) {
            return this.a - o.a;
        }
        else{
            return this.b - o.b;
        }
    }
}