While walking down the street Vanya saw a label "Hide&Seek". Because he is a programmer, he used & as a bitwise AND for these two words represented as a integers in base 64 and got new word. Now Vanya thinks of some string s and wants to know the number of pairs of words of length |s| (length of s), such that their bitwise AND is equal to s. As this number can be large, output it modulo 109 + 7.

To represent the string as a number in numeral system with base 64 Vanya uses the following rules:

  * digits from '0' to '9' correspond to integers from 0 to 9; 
  * letters from 'A' to 'Z' correspond to integers from 10 to 35; 
  * letters from 'a' to 'z' correspond to integers from 36 to 61; 
  * letter '-' correspond to integer 62; 
  * letter '_' correspond to integer 63. 

Input

The only line of the input contains a single word s (1 ≤ |s| ≤ 100 000), consisting of digits, lowercase and uppercase English letters, characters '-' and '_'.

Output

Print a single integer — the number of possible pairs of words, such that their bitwise AND is equal to string s modulo 109 + 7.

Examples

Input

z


Output

3


Input

V_V


Output

9


Input

Codeforces


Output

130653412

Note

For a detailed definition of bitwise AND we recommend to take a look in the corresponding article in Wikipedia.

In the first sample, there are 3 possible solutions: 

  1. z&_ = 61&63 = 61 = z
  2. _&z = 63&61 = 61 = z
  3. z&z = 61&61 = 61 = z
import java.io.*;
import java.util.*;

public class c1 {
	public static void main(String[] args) throws FileNotFoundException {
		Scanner in = new Scanner(System.in);
		PrintWriter out = new PrintWriter(System.out);
		
		String s = in.next();
		int n = s.length();
		
		long ans = 1;
		
		
		int a[] = new int[64];
		Arrays.fill(a, 0);
		
		for (int i = 0; i < 64; i++) {
			for (int j = 0; j < 64; j++) {
				a[(i & j)]++;
			}
		}
		
		for (int i = 0; i < n; i++) {
			char c = s.charAt(i);
			
			int cur = 0;
			
			if (c <= 'Z' && c >= 'A'){
				cur = (int) c - (int)'A' + 10;
			}
			if (c <= 'z' && c >= 'a'){
				cur = (int) c - (int)'a' + 36;
			}
			if (c <= '9' && c >= '0'){
				cur = (int) c - (int)'0';
			}
			if (c == '-'){
				cur = 62;
			}
			if (c == '_'){
				cur = 63;
			}
			
			//out.println(cur + " " + a[cur]);
			
			ans = 1l * ans * a[cur];
			
			ans = ans % (1000000007);
		}
		
		out.println(ans);
		
		out.close();
	}
}
