You are given an array a consisting of n integers. Indices of the array start from zero (i. e. the first element is a_0, the second one is a_1, and so on).

You can reverse at most one subarray (continuous subsegment) of this array. Recall that the subarray of a with borders l and r is a[l; r] = a_l, a_{l + 1}, ..., a_{r}.

Your task is to reverse such a subarray that the sum of elements on even positions of the resulting array is maximized (i. e. the sum of elements a_0, a_2, ..., a_{2k} for integer k = ⌊(n-1)/(2)⌋ should be maximum possible).

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The first line of the test case contains one integer n (1 ≤ n ≤ 2 ⋅ 10^5) — the length of a. The second line of the test case contains n integers a_0, a_1, ..., a_{n-1} (1 ≤ a_i ≤ 10^9), where a_i is the i-th element of a.

It is guaranteed that the sum of n does not exceed 2 ⋅ 10^5 (∑ n ≤ 2 ⋅ 10^5).

Output

For each test case, print the answer on the separate line — the maximum possible sum of elements on even positions after reversing at most one subarray (continuous subsegment) of a.

Example

Input


4
8
1 7 3 4 7 6 2 9
5
1 2 1 2 1
10
7 8 4 5 7 6 8 9 7 3
4
3 1 2 1


Output


26
5
37
5
import java.util.*;
import java.io.*;
public class MainClass
{
    public static void main(String[] args) throws IOException
    {
        Reader in = new Reader();
        int t = in.nextInt();
        StringBuilder stringBuilder = new StringBuilder();
        while (t-- > 0)
        {
            int n = in.nextInt();
            long[] A = new long[n];
            for (int i=0;i<n;i++)   A[i] = in.nextLong();
            long sum = 0L;
            for (int i=0;i<n;i++)
            {
                if (i % 2 == 0) sum += A[i];
            }
            ArrayList<Long> haha = new ArrayList<>();
            for (int i=0;i<n - 1;i+=2)
            {
                haha.add(A[i + 1] - A[i]);
            }
            ArrayList<Long> ahaha = new ArrayList<>();
            for (int i=1;i<n - 1;i+=2)
            {
                ahaha.add(A[i] - A[i + 1]);
            }
            long[] C = new long[haha.size()];
            long[] D = new long[ahaha.size()];
            for (int i=0;i<haha.size();i++) C[i] = haha.get(i);
            for (int i=0;i<ahaha.size();i++)    D[i] = ahaha.get(i);
            long ans1 = solve(C);
            long ans2 = solve(D);
            long ans = Math.max(ans1, ans2);
            if (ans > 0)
                stringBuilder.append(sum + ans).append("\n");
            else
                stringBuilder.append(sum).append("\n");
        }
        System.out.println(stringBuilder);
    }
    public static long solve(long[] A)
    {
        long maxSoFar = Long.MIN_VALUE;
        long maxEndingHere = 0L;
        int n = A.length;
        for (int i=0;i<n;i++)
        {
            maxEndingHere += A[i];
            if (maxEndingHere > maxSoFar)
            {
                maxSoFar = maxEndingHere;
            }
            if (maxEndingHere < 0)
                maxEndingHere = 0L;
        }
        return maxSoFar;
    }
}
class Reader
{
    final private int BUFFER_SIZE = 1 << 16;
    private DataInputStream din;
    private byte[] buffer;
    private int bufferPointer, bytesRead;

    public Reader()
    {
        din = new DataInputStream(System.in);
        buffer = new byte[BUFFER_SIZE];
        bufferPointer = bytesRead = 0;
    }

    public Reader(String file_name) throws IOException
    {
        din = new DataInputStream(new FileInputStream(file_name));
        buffer = new byte[BUFFER_SIZE];
        bufferPointer = bytesRead = 0;
    }

    public String readLine() throws IOException
    {
        byte[] buf = new byte[64]; // line length
        int cnt = 0, c;
        while ((c = read()) != -1)
        {
            if (c == '\n')
                break;
            buf[cnt++] = (byte) c;
        }
        return new String(buf, 0, cnt);
    }

    public int nextInt() throws IOException
    {
        int ret = 0;
        byte c = read();
        while (c <= ' ')
            c = read();
        boolean neg = (c == '-');
        if (neg)
            c = read();
        do
        {
            ret = ret * 10 + c - '0';
        }  while ((c = read()) >= '0' && c <= '9');

        if (neg)
            return -ret;
        return ret;
    }

    public long nextLong() throws IOException
    {
        long ret = 0;
        byte c = read();
        while (c <= ' ')
            c = read();
        boolean neg = (c == '-');
        if (neg)
            c = read();
        do {
            ret = ret * 10 + c - '0';
        }
        while ((c = read()) >= '0' && c <= '9');
        if (neg)
            return -ret;
        return ret;
    }

    public double nextDouble() throws IOException
    {
        double ret = 0, div = 1;
        byte c = read();
        while (c <= ' ')
            c = read();
        boolean neg = (c == '-');
        if (neg)
            c = read();

        do {
            ret = ret * 10 + c - '0';
        }
        while ((c = read()) >= '0' && c <= '9');

        if (c == '.')
        {
            while ((c = read()) >= '0' && c <= '9')
            {
                ret += (c - '0') / (div *= 10);
            }
        }

        if (neg)
            return -ret;
        return ret;
    }

    private void fillBuffer() throws IOException
    {
        bytesRead = din.read(buffer, bufferPointer = 0, BUFFER_SIZE);
        if (bytesRead == -1)
            buffer[0] = -1;
    }

    private byte read() throws IOException
    {
        if (bufferPointer == bytesRead)
            fillBuffer();
        return buffer[bufferPointer++];
    }

    public void close() throws IOException
    {
        if (din == null)
            return;
        din.close();
    }
}