It is known that there are k fish species in the polar ocean, numbered from 1 to k. They are sorted by non-decreasing order of their weight, which is a positive number. Let the weight of the i-th type of fish be wi, then 0 < w1 ≤ w2 ≤ ... ≤ wk holds.

Polar bears Alice and Bob each have caught some fish, and they are guessing who has the larger sum of weight of the fish he/she's caught. Given the type of the fish they've caught, determine whether it is possible that the fish caught by Alice has a strictly larger total weight than Bob's. In other words, does there exist a sequence of weights wi (not necessary integers), such that the fish caught by Alice has a strictly larger total weight?

Input

The first line contains three integers n, m, k (1 ≤ n, m ≤ 105, 1 ≤ k ≤ 109) — the number of fish caught by Alice and Bob respectively, and the number of fish species.

The second line contains n integers each from 1 to k, the list of fish type caught by Alice. The third line contains m integers each from 1 to k, the list of fish type caught by Bob.

Note that one may have caught more than one fish for a same species.

Output

Output "YES" (without quotes) if it is possible, and "NO" (without quotes) otherwise.

Examples

Input

3 3 3
2 2 2
1 1 3


Output

YES


Input

4 7 9
5 2 7 3
3 5 2 7 3 8 7


Output

NO

Note

In the first sample, if w1 = 1, w2 = 2, w3 = 2.5, then Alice has a total of 2 + 2 + 2 = 6 weight units, while Bob only has 1 + 1 + 2.5 = 4.5.

In the second sample, the fish that Alice caught is a subset of Bob's. Therefore, the total weight of Bob’s fish is always not less than the total weight of Alice’s fish.
import java.util.*;
import java.io.*;

public class Codeforces {
	FastScanner in;
	PrintWriter out;

	public void solve() throws IOException {
		int n = in.nextInt(), m = in.nextInt(), k = in.nextInt();
		Integer[] a = new Integer[n];
		Integer[] b = new Integer[m];
		for (int i = 0; i < n; i++) {
			a[i] = in.nextInt();
		}
		for (int i = 0; i < m; i++) {
			b[i] = in.nextInt();
		}
		Arrays.sort(a);
		Arrays.sort(b);
		int pa = n - 1;
		int pb = m - 1;
		int x = a[n - 1];
		while (pa >= 0 && pb >= 0) {
			if (b[pb] < x && a[pa] > b[pb]) {
				out.println("YES");
				return;
			} else {
				x = Math.min(x, a[pa]);
			}
			pa--;
			pb--;
		}
		if (pa > 0) {
			out.println("YES");
		} else {
			out.println("NO");
		}
	}

	public void run() {
		try {
			in = new FastScanner();
			out = new PrintWriter(System.out);

			solve();

			out.close();
		} catch (IOException e) {
			e.printStackTrace();
		}
	}

	class FastScanner {
		BufferedReader br;
		StringTokenizer st;

		FastScanner() {
			br = new BufferedReader(new InputStreamReader(System.in));
		}

		boolean hasNext() {
			while (st == null || !st.hasMoreTokens()) {
				try {
					String s = br.readLine();
					if (s == null) {
						return false;
					}
					st = new StringTokenizer(s);
				} catch (IOException e) {
					e.printStackTrace();
				}
			}
			return true;
		}

		String next() {
			while (st == null || !st.hasMoreTokens()) {
				try {
					st = new StringTokenizer(br.readLine());
				} catch (IOException e) {
					e.printStackTrace();
				}
			}
			return st.nextToken();
		}

		int nextInt() {
			return Integer.parseInt(next());
		}

		long nextLong() {
			return Long.parseLong(next());
		}

		double nextDouble() {
			return Double.parseDouble(next());
		}
	}

	public static void main(String[] arg) {
		new Codeforces().run();
	}
}