A median in an array with the length of n is an element which occupies position number <image> after we sort the elements in the non-decreasing order (the array elements are numbered starting with 1). A median of an array (2, 6, 1, 2, 3) is the number 2, and a median of array (0, 96, 17, 23) — the number 17.

We define an expression <image> as the integer part of dividing number a by number b.

One day Vasya showed Petya an array consisting of n integers and suggested finding the array's median. Petya didn't even look at the array and said that it equals x. Petya is a very honest boy, so he decided to add several numbers to the given array so that the median of the resulting array would be equal to x.

Petya can add any integers from 1 to 105 to the array, including the same numbers. Of course, he can add nothing to the array. If a number is added multiple times, then we should consider it the number of times it occurs. It is not allowed to delete of change initial numbers of the array. 

While Petya is busy distracting Vasya, your task is to find the minimum number of elements he will need.

Input

The first input line contains two space-separated integers n and x (1 ≤ n ≤ 500, 1 ≤ x ≤ 105) — the initial array's length and the required median's value. The second line contains n space-separated numbers — the initial array. The elements of the array are integers from 1 to 105. The array elements are not necessarily different.

Output

Print the only integer — the minimum number of elements Petya needs to add to the array so that its median equals x.

Examples

Input

3 10
10 20 30


Output

1


Input

3 4
1 2 3


Output

4

Note

In the first sample we can add number 9 to array (10, 20, 30). The resulting array (9, 10, 20, 30) will have a median in position <image>, that is, 10.

In the second sample you should add numbers 4, 5, 5, 5. The resulting array has median equal to 4.
"""
    Author - Satwik Tiwari .
    19th Jan , 2021  - Tuesday
"""

#===============================================================================================
#importing some useful libraries.

from __future__ import division, print_function
# from fractions import Fraction
import sys
import os
from io import BytesIO, IOBase

# from itertools import *
from heapq import *
from math import gcd, factorial,floor,ceil,sqrt,log2

from copy import deepcopy
from collections import deque


from bisect import bisect_left as bl
from bisect import bisect_right as br
from bisect import bisect

#==============================================================================================
#fast I/O region
BUFSIZE = 8192


class FastIO(IOBase):
    newlines = 0

    def __init__(self, file):
        self._fd = file.fileno()
        self.buffer = BytesIO()
        self.writable = "x" in file.mode or "r" not in file.mode
        self.write = self.buffer.write if self.writable else None

    def read(self):
        while True:
            b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
            if not b:
                break
            ptr = self.buffer.tell()
            self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
        self.newlines = 0
        return self.buffer.read()

    def readline(self):
        while self.newlines == 0:
            b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
            self.newlines = b.count(b"\n") + (not b)
            ptr = self.buffer.tell()
            self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
        self.newlines -= 1
        return self.buffer.readline()

    def flush(self):
        if self.writable:
            os.write(self._fd, self.buffer.getvalue())
            self.buffer.truncate(0), self.buffer.seek(0)


class IOWrapper(IOBase):
    def __init__(self, file):
        self.buffer = FastIO(file)
        self.flush = self.buffer.flush
        self.writable = self.buffer.writable
        self.write = lambda s: self.buffer.write(s.encode("ascii"))
        self.read = lambda: self.buffer.read().decode("ascii")
        self.readline = lambda: self.buffer.readline().decode("ascii")


def print(*args, **kwargs):
    """Prints the values to a stream, or to sys.stdout by default."""
    sep, file = kwargs.pop("sep", " "), kwargs.pop("file", sys.stdout)
    at_start = True
    for x in args:
        if not at_start:
            file.write(sep)
        file.write(str(x))
        at_start = False
    file.write(kwargs.pop("end", "\n"))
    if kwargs.pop("flush", False):
        file.flush()


if sys.version_info[0] < 3:
    sys.stdin, sys.stdout = FastIO(sys.stdin), FastIO(sys.stdout)
else:
    sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)

# inp = lambda: sys.stdin.readline().rstrip("\r\n")

#===============================================================================================
### START ITERATE RECURSION ###
from types import GeneratorType
def iterative(f, stack=[]):
  def wrapped_func(*args, **kwargs):
    if stack: return f(*args, **kwargs)
    to = f(*args, **kwargs)
    while True:
      if type(to) is GeneratorType:
        stack.append(to)
        to = next(to)
        continue
      stack.pop()
      if not stack: break
      to = stack[-1].send(to)
    return to
  return wrapped_func
#### END ITERATE RECURSION ####

#===============================================================================================
#some shortcuts

def inp(): return sys.stdin.readline().rstrip("\r\n") #for fast input
def out(var): sys.stdout.write(str(var))  #for fast output, always take string
def lis(): return list(map(int, inp().split()))
def stringlis(): return list(map(str, inp().split()))
def sep(): return map(int, inp().split())
def strsep(): return map(str, inp().split())
# def graph(vertex): return [[] for i in range(0,vertex+1)]
def testcase(t):
    for pp in range(t):
        solve(pp)
def google(p):
    print('Case #'+str(p)+': ',end='')
def lcm(a,b): return (a*b)//gcd(a,b)
def power(x, y, p) :
    y%=(p-1)  #not so sure about this. used when y>p-1. if p is prime.
    res = 1     # Initialize result
    x = x % p  # Update x if it is more , than or equal to p
    if (x == 0) :
        return 0
    while (y > 0) :
        if ((y & 1) == 1) : # If y is odd, multiply, x with result
            res = (res * x) % p

        y = y >> 1      # y = y/2
        x = (x * x) % p
    return res
def ncr(n,r): return factorial(n) // (factorial(r) * factorial(max(n - r, 1)))
def isPrime(n) :
    if (n <= 1) : return False
    if (n <= 3) : return True
    if (n % 2 == 0 or n % 3 == 0) : return False
    i = 5
    while(i * i <= n) :
        if (n % i == 0 or n % (i + 2) == 0) :
            return False
        i = i + 6
    return True
inf = pow(10,21)
mod = 10**9+7
#===============================================================================================
# code here ;))

def bucketsort(order, seq):
    buckets = [0] * (max(seq) + 1)
    for x in seq:
        buckets[x] += 1
    for i in range(len(buckets) - 1):
        buckets[i + 1] += buckets[i]

    new_order = [-1] * len(seq)
    for i in reversed(order):
        x = seq[i]
        idx = buckets[x] = buckets[x] - 1
        new_order[idx] = i

    return new_order


def ordersort(order, seq, reverse=False):
    bit = max(seq).bit_length() >> 1
    mask = (1 << bit) - 1
    order = bucketsort(order, [x & mask for x in seq])
    order = bucketsort(order, [x >> bit for x in seq])
    if reverse:
        order.reverse()
    return order


def long_ordersort(order, seq):
    order = ordersort(order, [int(i & 0x7fffffff) for i in seq])
    return ordersort(order, [int(i >> 31) for i in seq])


def multikey_ordersort(order, *seqs, sort=ordersort):
    for i in reversed(range(len(seqs))):
        order = sort(order, seqs[i])
    return order

class DisjointSetUnion:
    def __init__(self, n):
        self.parent = list(range(n))
        self.size = [1] * n
        self.num_sets = n

    def find(self, a):
        acopy = a
        while a != self.parent[a]:
            a = self.parent[a]
        while acopy != a:
            self.parent[acopy], acopy = a, self.parent[acopy]
        return a

    def union(self, a, b):
        a, b = self.find(a), self.find(b)
        if a != b:
            if self.size[a] < self.size[b]:
                a, b = b, a

            self.num_sets -= 1
            self.parent[b] = a
            self.size[a] += self.size[b]

    def set_size(self, a):
        return self.size[self.find(a)]

    def __len__(self):
        return self.num_sets



def solve(case):
    n,x = sep()
    a = lis()
    a.sort()
    ind = bl(a,x)
    if(ind == n or a[ind] != x):
        l = ind
        r = ind
        ans = 1
    else:
        l = ind
        r = bl(a,x+1)-1
        ans = 0

    # print(l,r,ans)
    f = True
    while(f):
        ind = (n + ans)//2 if (n+ans)%2 else ((n+ans)//2)-1
        # print(ind,n+ans,ans)
        if(l <= ind <= r):
            break
        else:
            r+=1
            ans+=1

    print(ans)


testcase(1)
# testcase(int(inp()))





