Fox Ciel has some flowers: r red flowers, g green flowers and b blue flowers. She wants to use these flowers to make several bouquets. There are 4 types of bouquets:

  * To make a "red bouquet", it needs 3 red flowers. 
  * To make a "green bouquet", it needs 3 green flowers. 
  * To make a "blue bouquet", it needs 3 blue flowers. 
  * To make a "mixing bouquet", it needs 1 red, 1 green and 1 blue flower. 



Help Fox Ciel to find the maximal number of bouquets she can make.

Input

The first line contains three integers r, g and b (0 ≤ r, g, b ≤ 109) — the number of red, green and blue flowers.

Output

Print the maximal number of bouquets Fox Ciel can make.

Examples

Input

3 6 9


Output

6


Input

4 4 4


Output

4


Input

0 0 0


Output

0

Note

In test case 1, we can make 1 red bouquet, 2 green bouquets and 3 blue bouquets.

In test case 2, we can make 1 red, 1 green, 1 blue and 1 mixing bouquet.
import java.util.Scanner;

public class CF322B {
    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        int r = scanner.nextInt();
        int g = scanner.nextInt();
        int b = scanner.nextInt();

        int opt1 = 0;
        if (r >= 1 && g >= 1 && b >= 1) {
            opt1 = 1 + (r-1) / 3 + (g-1) / 3 + (b-1) / 3;
        }

        int opt2 = 0;
        if (r >= 2 && g >= 2 && b >= 2) {
            opt2 = 2 + (r-2) / 3 + (g-2) / 3 + (b-2) / 3;
        }

        int opt3 = r / 3 + g / 3 + b / 3;

        System.out.println(Math.max(opt3, Math.max(opt1, opt2)));

    }
}
