There are N points on the 2D plane, i-th of which is located on (x_i, y_i). There can be multiple points that share the same coordinate. What is the maximum possible Manhattan distance between two distinct points?

Here, the Manhattan distance between two points (x_i, y_i) and (x_j, y_j) is defined by |x_i-x_j| + |y_i-y_j|.

Constraints

* 2 \leq N \leq 2 \times 10^5
* 1 \leq x_i,y_i \leq 10^9
* All values in input are integers.

Input

Input is given from Standard Input in the following format:


N
x_1 y_1
x_2 y_2
:
x_N y_N


Output

Print the answer.

Examples

Input

3
1 1
2 4
3 2


Output

4


Input

2
1 1
1 1


Output

0
import java.util.Scanner;

public class Main {
	public static void main(String[] args) {
		try (Scanner sc = new Scanner(System.in);) {
			int n = sc.nextInt();

			int[] x = new int[n];
			int[] y = new int[n];

			int minValue1 = Integer.MAX_VALUE;
			int maxValue1 = Integer.MIN_VALUE;
			int minValue2 = Integer.MAX_VALUE;
			int maxValue2 = Integer.MIN_VALUE;

			for (int i = 0; i < n; i++) {
				int a = x[i] = sc.nextInt();
				int b = y[i] = sc.nextInt();

				int u = a + b;
				if (u < minValue1) {
					minValue1 = u;
				}
				if (maxValue1 < u) {
					maxValue1 = u;
				}

				int v = a - b;
				if (v < minValue2) {
					minValue2 = v;
				}
				if (maxValue2 < v) {
					maxValue2 = v;
				}
			}

			System.out.println(Math.max(maxValue1-minValue1, maxValue2-minValue2));

		} catch (Exception e) {
			e.printStackTrace();
		}

	}

}