Fox Ciel has some flowers: r red flowers, g green flowers and b blue flowers. She wants to use these flowers to make several bouquets. There are 4 types of bouquets:

  * To make a "red bouquet", it needs 3 red flowers. 
  * To make a "green bouquet", it needs 3 green flowers. 
  * To make a "blue bouquet", it needs 3 blue flowers. 
  * To make a "mixing bouquet", it needs 1 red, 1 green and 1 blue flower. 



Help Fox Ciel to find the maximal number of bouquets she can make.

Input

The first line contains three integers r, g and b (0 ≤ r, g, b ≤ 109) — the number of red, green and blue flowers.

Output

Print the maximal number of bouquets Fox Ciel can make.

Examples

Input

3 6 9


Output

6


Input

4 4 4


Output

4


Input

0 0 0


Output

0

Note

In test case 1, we can make 1 red bouquet, 2 green bouquets and 3 blue bouquets.

In test case 2, we can make 1 red, 1 green, 1 blue and 1 mixing bouquet.
import java.util.Arrays;
import java.util.Scanner;

public class Main{

    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        int r = in.nextInt();
        int g = in.nextInt();
        int v = in.nextInt();
        if (r != 0 && g != 0 && v != 0) {
            int com1 = r / 3 + g / 3 + v / 3;
            int r1 = r % 3;
            int g1 = g % 3;
            int v1 = v % 3;
            int[] a = {r1, g1, v1};
            Arrays.sort(a);

            if (a[0] != 0) {
                com1 += a[0];
            } else {
                if (a[1] == 2) {
                    com1++;
                }
            }
            System.out.println(com1);
        } else {
            System.out.println((r / 3 + g / 3 + v / 3));
        }
    }
}
