Vasya collects coins: he has exactly one coin for every year from 1 to n. Naturally, Vasya keeps all the coins in his collection in the order in which they were released. Once Vasya's younger brother made a change — he took all the coins whose release year dated from l to r inclusively and put them in the reverse order. That is, he took a certain segment [l, r] and reversed it. At that the segment's endpoints did not coincide. For example, if n = 8, then initially Vasya's coins were kept in the order 1 2 3 4 5 6 7 8. If Vasya's younger brother chose the segment [2, 6], then after the reversal the coin order will change to 1 6 5 4 3 2 7 8. Vasya suspects that someone else could have spoilt the permutation after his brother. Help him to find that out. Check if the given permutation can be obtained from the permutation 1 2 ... n using exactly one segment reversal. If it is possible, find the segment itself.

Input

The first line contains an integer n (1 ≤ n ≤ 1000) which is the number of coins in Vasya's collection. The second line contains space-separated n integers which are the spoilt sequence of coins. It is guaranteed that the given sequence is a permutation, i.e. it contains only integers from 1 to n, and every number is used exactly 1 time.

Output

If it is impossible to obtain the given permutation from the original one in exactly one action, print 0 0. Otherwise, print two numbers l r (1 ≤ l < r ≤ n) which are the endpoints of the segment that needs to be reversed to obtain from permutation 1 2 ... n the given one.

Examples

Input

8
1 6 5 4 3 2 7 8


Output

2 6


Input

4
2 3 4 1


Output

0 0


Input

4
1 2 3 4


Output

0 0


import java.io.*;
import java.util.*;
import static java.lang.Math.*;

public class ProblemB_52 {
    
    final boolean ONLINE_JUDGE=System.getProperty("ONLINE_JUDGE")!=null;
    BufferedReader in;
    PrintWriter out;
    StringTokenizer tok=new StringTokenizer("");
    
    void init() throws FileNotFoundException{
        if (ONLINE_JUDGE){
            in=new BufferedReader(new InputStreamReader(System.in));
            out =new PrintWriter(System.out);
        }
        else{
            in = new BufferedReader(new FileReader("input.txt"));
            out = new PrintWriter("output.txt");
        }
    }
    
    String readString() throws IOException{
        while(!tok.hasMoreTokens()){
            tok=new StringTokenizer(in.readLine());
        }
        return tok.nextToken();
    }
    
    int readInt() throws IOException{
        return Integer.parseInt(readString());
    }
    
    public static void main(String[] args){
        new ProblemB_52().run();
    }
    
    public void run(){
        try{
            long t1=System.currentTimeMillis();
            init();
            solve();
            out.close();
            long t2=System.currentTimeMillis();
            System.err.println("Time = "+(t2-t1));
        }catch (Exception e){
            e.printStackTrace(System.err);
            System.exit(-1);
        }
    }
    
    void solve() throws IOException{
        int n=readInt();
        int i1=0;
        int i2=0;
        boolean exit=false;
        int[] a=new int[n+1];
        for (int i=0; i<n; i++){
            a[i]=readInt();
        }
        a[n]=n+1;
        for (int i=0; i<n; i++){
            if (a[i]!=i+1){
                i1=i+1;
                for (int j=i1; j<n+1; j++){
                    if (a[j]!=a[j-1]-1){
                        if (j==a[i1]+1){
                            i2=j;
                            exit=true;
                        }
                        break;
                    }
                }
                for (int j=i2; j<n; j++){
                    if (a[j]!=j+1){
                        exit=false;
                        out.print(0+" "+0);
                        return;
                    }
                }
                if (exit){
                    break;
                }
            }
        }
        out.print(i1+" "+i2);
    }       
}

