

Input

The first line of the input contains a single integer N (1 ≤ N ≤ 24). The next N lines contain 5 space-separated integers each. The first three integers will be between 0 and 2, inclusive. The last two integers will be between 0 and 3, inclusive. The sum of the first three integers will be equal to the sum of the last two integers.

Output

Output the result – a string of lowercase English letters.

Examples

Input


1
1 0 0 1 0


Output


a


Input


10
2 0 0 1 1
1 1 1 2 1
2 1 0 1 2
1 1 0 1 1
2 1 0 2 1
1 1 1 2 1
1 2 1 3 1
2 0 0 1 1
1 1 0 1 1
1 1 2 2 2


Output


codeforcez
dic = {}
dic['1 0 0 1 0'] = 'a'
dic['1 1 0 2 0'] = 'b'
dic['2 0 0 1 1'] = 'c'
dic['2 1 0 1 2'] = 'd'
dic['1 1 0 1 1'] = 'e'
dic['2 1 0 2 1'] = 'f'
dic['2 2 0 2 2'] = 'g'
dic['1 2 0 2 1'] = 'h'
# dic['1 1 0 1 1'] = 'i'
dic['1 2 0 1 2'] = 'j'
dic['1 0 1 2 0'] = 'k'
dic['1 1 1 3 0'] = 'l'
dic['2 0 1 2 1'] = 'm'
dic['2 1 1 2 2'] = 'n'
dic['1 1 1 2 1'] = 'o'
dic['2 1 1 3 1'] = 'p'
dic['2 2 1 3 2'] = 'q'
dic['1 2 1 3 1'] = 'r'
# dic['1 1 1 2 1'] = 's'
dic['1 2 1 2 2'] = 't'
dic['1 0 2 2 1'] = 'u'
dic['1 1 2 3 1'] = 'v'
dic['1 2 1 1 3'] = 'w'
dic['2 0 2 2 2'] = 'x'
dic['2 1 2 2 3'] = 'y'
dic['1 1 2 2 2'] = 'z'

ans = ''
for _ in range(int(input())):
    s = input()
    ans += dic[s]
    
print(ans)