Fox Ciel has some flowers: r red flowers, g green flowers and b blue flowers. She wants to use these flowers to make several bouquets. There are 4 types of bouquets:

  * To make a "red bouquet", it needs 3 red flowers. 
  * To make a "green bouquet", it needs 3 green flowers. 
  * To make a "blue bouquet", it needs 3 blue flowers. 
  * To make a "mixing bouquet", it needs 1 red, 1 green and 1 blue flower. 



Help Fox Ciel to find the maximal number of bouquets she can make.

Input

The first line contains three integers r, g and b (0 ≤ r, g, b ≤ 109) — the number of red, green and blue flowers.

Output

Print the maximal number of bouquets Fox Ciel can make.

Examples

Input

3 6 9


Output

6


Input

4 4 4


Output

4


Input

0 0 0


Output

0

Note

In test case 1, we can make 1 red bouquet, 2 green bouquets and 3 blue bouquets.

In test case 2, we can make 1 red, 1 green, 1 blue and 1 mixing bouquet.
import java.io.*;
import java.util.*;
public class Solution {
	static Scanner sc=new Scanner(System.in);
	static PrintWriter out=new PrintWriter(System.out);
	//Main
	public static void main(String args[]) {
		int test=1;
		//test=sc.nextInt();
		while(test-->0) {
			long a=sc.nextLong(),b=sc.nextLong(),c=sc.nextLong();
			long x=a%3,y=b%3,z=c%3;
			long ans=Math.min(Math.min(x, y), z);
			x-=ans;y-=ans;z-=ans;
			long tmp[]= {x,y,z};
			Arrays.parallelSort(tmp);
			if(tmp[0]==0 && tmp[1]==2 && tmp[2]==2 && ((a%3==0 && a>1) || (b%3==0 && b>1) || (c%3==0 && c>1))) {
				ans+=2;
				ans+=a/3+b/3+c/3-1;
			}
			else {
				ans+=a/3+b/3+c/3;
			}
			out.println(ans);
		}
		out.flush();
		out.close();
	}
}