We have a long seat of width X centimeters. There are many people who wants to sit here. A person sitting on the seat will always occupy an interval of length Y centimeters.

We would like to seat as many people as possible, but they are all very shy, and there must be a gap of length at least Z centimeters between two people, and between the end of the seat and a person.

At most how many people can sit on the seat?

Constraints

* All input values are integers.
* 1 \leq X, Y, Z \leq 10^5
* Y+2Z \leq X

Input

Input is given from Standard Input in the following format:


X Y Z


Output

Print the answer.

Examples

Input

13 3 1


Output

3


Input

12 3 1


Output

2


Input

100000 1 1


Output

49999


Input

64146 123 456


Output

110


Input

64145 123 456


Output

109
import java.util.Scanner;

public class Main {

    public static void main(String[] args) throws Exception {

//    	File file = new File("test.txt");
//    	Scanner sc = new Scanner(file);
    	Scanner sc = new Scanner(System.in);
    	int X = sc.nextInt();
    	int Y = sc.nextInt();
    	int Z = sc.nextInt();
    	sc.close();
    	X = X - Z;
    	int ans = 0;
    	while(X >= 0){
    		X = X - (Y + Z);
    		ans++;
    	}
    	System.out.println(ans == 0 ? 0 : ans-1);
    }
}