While walking down the street Vanya saw a label "Hide&Seek". Because he is a programmer, he used & as a bitwise AND for these two words represented as a integers in base 64 and got new word. Now Vanya thinks of some string s and wants to know the number of pairs of words of length |s| (length of s), such that their bitwise AND is equal to s. As this number can be large, output it modulo 109 + 7.

To represent the string as a number in numeral system with base 64 Vanya uses the following rules:

  * digits from '0' to '9' correspond to integers from 0 to 9; 
  * letters from 'A' to 'Z' correspond to integers from 10 to 35; 
  * letters from 'a' to 'z' correspond to integers from 36 to 61; 
  * letter '-' correspond to integer 62; 
  * letter '_' correspond to integer 63. 

Input

The only line of the input contains a single word s (1 ≤ |s| ≤ 100 000), consisting of digits, lowercase and uppercase English letters, characters '-' and '_'.

Output

Print a single integer — the number of possible pairs of words, such that their bitwise AND is equal to string s modulo 109 + 7.

Examples

Input

z


Output

3


Input

V_V


Output

9


Input

Codeforces


Output

130653412

Note

For a detailed definition of bitwise AND we recommend to take a look in the corresponding article in Wikipedia.

In the first sample, there are 3 possible solutions: 

  1. z&_ = 61&63 = 61 = z
  2. _&z = 63&61 = 61 = z
  3. z&z = 61&61 = 61 = z
import java.io.BufferedReader;
import java.io.File;
import java.io.FileInputStream;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.HashMap;
import java.util.StringTokenizer;

public class C {

	public static int count(int n) {
		int r = 0;
		for (int i = 0; i < 6; i++) {
			r += n & 1;
			n /= 2;
		}
		return (int)Math.pow(3, 6 - r);
	}

	public static void main(String[] args) throws IOException {
		File inputFile = new File("entradaC");
		if (inputFile.exists())
			System.setIn(new FileInputStream(inputFile));
		BufferedReader in = new BufferedReader(new InputStreamReader(System.in));
		StringBuilder out = new StringBuilder();
		String line = "";
		HashMap<Character, Integer> map = new HashMap<>(64);
		for (int i = 0; i < 10; i++)
			map.put((char) ('0' + i), i);
		for (int i = 'A'; i <= 'Z'; i++)
			map.put((char) i, i - 'A' + 10);
		for (int i = 'a'; i <= 'z'; i++)
			map.put((char) i, i - 'a' + 36);
		map.put('-', 62);
		map.put('_', 63);
		long MOD = 1000000007L;
		while ((line = in.readLine()) != null) {
			char[] l = line.trim().toCharArray();
			long ans = 1;
			for (int i = 0; i < l.length; i++)
				ans = (ans * count(map.get(l[i]))) % MOD;
			out.append(ans + "\n");
		}
		System.out.print(out);
	}

	static int[] readInts(String line) {
		StringTokenizer st = new StringTokenizer(line.trim());
		int a[] = new int[st.countTokens()], index = 0;
		while (st.hasMoreTokens())
			a[index++] = Integer.parseInt(st.nextToken());
		return a;
	}

	static long[] readLongs(String line) {
		StringTokenizer st = new StringTokenizer(line.trim());
		long a[] = new long[st.countTokens()];
		int index = 0;
		while (st.hasMoreTokens())
			a[index++] = Long.parseLong(st.nextToken());
		return a;
	}

	static double[] readDoubles(String line) {
		StringTokenizer st = new StringTokenizer(line.trim());
		double a[] = new double[st.countTokens()];
		int index = 0;
		while (st.hasMoreTokens())
			a[index++] = Double.parseDouble(st.nextToken());
		return a;
	}
}
