We have a sequence of N \times K integers: X=(X_0,X_1,\cdots,X_{N \times K-1}). Its elements are represented by another sequence of N integers: A=(A_0,A_1,\cdots,A_{N-1}). For each pair i, j (0 \leq i \leq K-1,\ 0 \leq j \leq N-1), X_{i \times N + j}=A_j holds.

Snuke has an integer sequence s, which is initially empty. For each i=0,1,2,\cdots,N \times K-1, in this order, he will perform the following operation:

* If s does not contain X_i: add X_i to the end of s.
* If s does contain X_i: repeatedly delete the element at the end of s until s no longer contains X_i. Note that, in this case, we do not add X_i to the end of s.



Find the elements of s after Snuke finished the operations.

Constraints

* 1 \leq N \leq 2 \times 10^5
* 1 \leq K \leq 10^{12}
* 1 \leq A_i \leq 2 \times 10^5
* All values in input are integers.

Input

Input is given from Standard Input in the following format:


N K
A_0 A_1 \cdots A_{N-1}


Output

Print the elements of s after Snuke finished the operations, in order from beginning to end, with spaces in between.

Examples

Input

3 2
1 2 3


Output

2 3


Input

5 10
1 2 3 2 3


Output

3


Input

6 1000000000000
1 1 2 2 3 3


Output




Input

11 97
3 1 4 1 5 9 2 6 5 3 5


Output

9 2 6
N, K = list(map(int, input().split()))
A = list(map(int, input().split()))

if N==1:
  if K%2:
    print(A[0])
  else:
    print('')
  exit()
  

#print(*range(10000))

def func(L):
  s = []
  for l in L:
    if l in s:
      del s[s.index(l):]
      #s_set.remove(l)
    else:
      s.append(l)
      #s_set.add(l)
  return s




index_dict={}
for i,a in enumerate(A):
  index_dict.setdefault(a,[]).append(i)

next_i = [0]*N
cycle_i = [0]*N
for k,v in index_dict.items():
  for i in range(len(v)):
    next_i[v[i]] = (v[(i+1)%len(v)]+1)%N
    cycle_i[v[i]] = (i+1)//len(v)
#print(next_i)
#print(cycle_i)

from_in_cycle=[]

i = 0
while True:
  j = next_i[i]
  if cycle_i[i]:
    from_in_cycle.append(i)
  i = j
  # 循環の評価
  if i==0:
    break
    
#print(from_in_cycle)

if from_in_cycle:
  k = K%(len(from_in_cycle)+1)
  #print(*func(A[from_in_cycle[k-1]:]))

  ans = []
  i = from_in_cycle[k-1]
  while i < N:
    if cycle_i[i]:
      ans.append(A[i])
      i += 1
    else:
      if next_i[i]==0:
        break
      i = next_i[i]
  print(*ans)


else:
  print('')