You have 2n integers 1, 2, ..., 2n. You have to redistribute these 2n elements into n pairs. After that, you choose x pairs and take minimum elements from them, and from the other n - x pairs, you take maximum elements.

Your goal is to obtain the set of numbers \\{b_1, b_2, ..., b_n\} as the result of taking elements from the pairs.

What is the number of different x-s (0 ≤ x ≤ n) such that it's possible to obtain the set b if for each x you can choose how to distribute numbers into pairs and from which x pairs choose minimum elements?

Input

The first line contains a single integer t (1 ≤ t ≤ 1000) — the number of test cases.

The first line of each test case contains the integer n (1 ≤ n ≤ 2 ⋅ 10^5).

The second line of each test case contains n integers b_1, b_2, ..., b_n (1 ≤ b_1 < b_2 < ... < b_n ≤ 2n) — the set you'd like to get.

It's guaranteed that the sum of n over test cases doesn't exceed 2 ⋅ 10^5.

Output

For each test case, print one number — the number of different x-s such that it's possible to obtain the set b.

Example

Input


3
1
1
5
1 4 5 9 10
2
3 4


Output


1
3
1

Note

In the first test case, x = 1 is the only option: you have one pair (1, 2) and choose the minimum from this pair.

In the second test case, there are three possible x-s. If x = 1, then you can form the following pairs: (1, 6), (2, 4), (3, 5), (7, 9), (8, 10). You can take minimum from (1, 6) (equal to 1) and the maximum elements from all other pairs to get set b.

If x = 2, you can form pairs (1, 2), (3, 4), (5, 6), (7, 9), (8, 10) and take the minimum elements from (1, 2), (5, 6) and the maximum elements from the other pairs.

If x = 3, you can form pairs (1, 3), (4, 6), (5, 7), (2, 9), (8, 10) and take the minimum elements from (1, 3), (4, 6), (5, 7).

In the third test case, x = 0 is the only option: you can form pairs (1, 3), (2, 4) and take the maximum elements from both of them.

import java.util.*;
import java.io.*;
import java.math.BigInteger;
public class Mamo {
	//  Solution 
    public static void main(String [] args) throws IOException {
    	//Dir by MohammedElkady
    	int tt=in.nextInt();
    	while(tt-->0) {
    		int n=in.nextInt(),ans=0;
    	int a[]=in.arr(n);
    	ans++;
    	int s=0,sl=0,sd=0;
    	for(int i=0;i<n;i++) {
    		if((a[i]-s)<(i+1-s)*2) {
    			s++;
    		}
    	}
    	boolean B[]=new boolean[n*2+5];
    	for(int i:a)
    		B[i]=true;
    	
    	for(int i=2*n;i>=1;i--) {
    		if(!B[i]) {sl++;}
    		else if(sl>0) {sl--;sd++;}
    	}
    //	System.out.println(s+" "+sd);
    	
    	ans+=sd-s;
    	out.append(ans+" \n");
    	}
	out.close();
        
    }
    static StringBuilder Sd=new StringBuilder();
    static Reader in=new Reader();
    public static PrintWriter out = new PrintWriter(new BufferedOutputStream(System.out));
    static class Reader 
    { 
        private InputStream mIs;private byte[] buf = new byte[1024];private int curChar,numChars;public Reader() { this(System.in); }public Reader(InputStream is) { mIs = is;} 
        public int read() {if (numChars == -1) throw new InputMismatchException();if (curChar >= numChars) {curChar = 0;try { numChars = mIs.read(buf);} catch (IOException e) { throw new InputMismatchException();}if (numChars <= 0) return -1; }return buf[curChar++];} 
        public String nextLine(){int c = read();while (isSpaceChar(c)) c = read();StringBuilder res = new StringBuilder();do {res.appendCodePoint(c);c = read();}while (!isEndOfLine(c));return res.toString() ;} 
        public String s(){int c = read();while (isSpaceChar(c)) c = read();StringBuilder res = new StringBuilder();do {res.appendCodePoint(c);c = read();}while (!isSpaceChar(c));return res.toString();} 
        public long l(){int c = read();while (isSpaceChar(c)) c = read();int sgn = 1;if (c == '-') { sgn = -1 ; c = read() ; }long res = 0; do{ if (c < '0' || c > '9') throw new InputMismatchException();res *= 10 ; res += c - '0' ; c = read();}while(!isSpaceChar(c));return res * sgn;} 
        public int nextInt(){int c = read() ;while (isSpaceChar(c)) c = read();int sgn = 1;if (c == '-') { sgn = -1 ; c = read() ; }int res = 0;do{if (c < '0' || c > '9') throw new InputMismatchException();res *= 10 ; res += c - '0' ; c = read() ;}while(!isSpaceChar(c));return res * sgn;} 
        public double d() throws IOException {return Double.parseDouble(s()) ;}
        public boolean isSpaceChar(int c) { return c == ' ' || c == '\n' || c == '\r' || c == '\t' || c == -1; } 
        public boolean isEndOfLine(int c) { return c == '\n' || c == '\r' || c == -1; } 
        public int[] arr(int n){int[] ret = new int[n];for (int i = 0; i < n; i++) {ret[i] = nextInt();}return ret;}
    }
}
class node {

int i;
String name;
node(String S,int ll){
i=ll;
name=S;
}

}
class xtree{
	public xtree(int n,int a[]) {
		this.a=a;
		seg=new int[n*4];
		//lazy=new int[n*4];
		build(1,0,n-1);
	}
	int seg[], a[],lazy[];
	    void check(int p,int s,int e) {
	        if(lazy[p]!=0) {
	            seg[p] += lazy[p];
	            if(s!=e) {
	                lazy[2*p] += lazy[p];
	                lazy[2*p+1] += lazy[p];
	            }
	            lazy[p] = 0;
	        }
	    }
	    
	     void build(int p,int s,int e) {
	        //check(p,s,e);
	        
	        if(s==e) {
	            seg[p] = a[s];
	            return;
	        }
	        
	        build(2*p,s,(s+e)/2);
	        build(2*p+1,(s+e)/2+1,e);
	        
	        seg[p] = seg[2*p]+ seg[2*p+1];
	    }
	    
	   void update(int p,int s,int e,int i,int v) {
	       // check(p,s,e);
	        
	        if(s==e) {
	            seg[p] = v;
	            return;
	        }
	        
	        if(i<=(s+e)/2) update(2*p,s,(s+e)/2,i,v);
	        else update(2*p+1,(s+e)/2+1,e,i,v);
	        
	        seg[p] = seg[2*p]+seg[2*p+1];
	    }
	    
	     void update(int p,int s,int e,int a,int b,int v) {
	        //check(p,s,e);
	        
	        if(s>=a && e<=b) {
	            seg[p] += v;
	            
	            if(s!=e) {
	                lazy[2*p] += v;
	                lazy[2*p+1] += v;
	            }
	            
	            return;
	        }
	        
	        if(s>b || e<a)
	            return;
	        
	        update(2*p,s,(s+e)/2,a,b,v);
	        update(2*p+1,(s+e)/2+1,e,a,b,v);
	        
	        seg[p] = seg[2*p]+seg[2*p+1];
	    }
    
 
    
    int get(int p,int s,int e,int a,int b) {
        if(s>=a && e<=b)
            return seg[p];
        
        if(s>b || e<a)
            return 0; 
        
        return get(2*p,s,(s+e)/2,a,b)+ get(2*p+1,(s+e)/2+1,e,a,b);
    }
}

class FastReader
    {
        BufferedReader br;
        StringTokenizer st;
 
        public FastReader()
        {
            br = new BufferedReader(new
                     InputStreamReader(System.in));
        }
 
        String next()
        {
            while (st == null || !st.hasMoreElements())
            {
                try
                {
                    st = new StringTokenizer(br.readLine());
                }
                catch (IOException  e)
                {
                    e.printStackTrace();
                }
            }
            return st.nextToken();
        }
 
        int nextInt()
        {
            return Integer.parseInt(next());
        }
 
        long nextLong()
        {
            return Long.parseLong(next());
        }
 
        double nextDouble()
        {
            return Double.parseDouble(next());
        }
 
        String nextLine()
        {
            String str = "";
            try
            {
                str = br.readLine();
            }
            catch (IOException e)
            {
                e.printStackTrace();
            }
            return str;
        }
}
 
class Sorting{
 
 public static int[] bucketSort(int[] array, int bucketCount) {
 
 if (bucketCount <= 0) throw new IllegalArgumentException("Invalid bucket count");
 
 if (array.length <= 1) return array; //trivially sorted
 
 
 
 long high = array[0];
 
 long low = array[0];
 
 for (int i = 1; i < array.length; i++) { //find the range of input elements
 
 if (array[i] > high) high = array[i];
 
 if (array[i] < low) low = array[i];
 
 }
 
 double interval = ((double)(high - low + 1))/bucketCount; //range of one bucket
 
 
 ArrayList<Integer> buckets[] = new ArrayList[bucketCount];
 
 for (int i = 0; i < bucketCount; i++) { //initialize buckets
 
 buckets[i] = new ArrayList();
 
 }
 
 
 
 for (int i = 0; i < array.length; i++) { //partition the input array
 
 buckets[(int)((array[i] - low)/interval)].add(array[i]);
 
 }
 
 
 int pointer = 0;
 
 for (int i = 0; i < buckets.length; i++) {
 
 Collections.sort(buckets[i]); //mergeSort
 
 for (int j = 0; j < buckets[i].size(); j++) { //merge the buckets
 
 array[pointer] = buckets[i].get(j);
 
 pointer++;
 
 }
 
}
 
return array;
 
}
}
 class LongestCommonSubsequence 
{ 
  
  /* Returns length of LCS for X[0..m-1], Y[0..n-1] */
	 int lcs( char[] X, char[] Y, int m, int n ,int K) 
	  { 
		 int L[][] = new int[m+1][n+1]; 
		 int ans[][]=new int[m+1][n+1];
		 int min[][] = new int[m+1][n+1]; 
		 for(int i=0;i<=n;i++) 
			 for(int j=0;j<=m;j++) 
				 min[j][i]='z'+1;
	    /* Following steps build L[m+1][n+1] in bottom up fashion. Note 
	         that L[i][j] contains length of LCS of X[0..i-1] and Y[0..j-1] */
	    for (int i=0; i<=m; i++) 
	    { 
	      for (int j=0; j<=n; j++)
	      { 
	        if (i == 0 || j == 0) 
	            L[i][j] = 0; 
	        else if (X[i-1] == Y[j-1]) { 
	            L[i][j] = L[i-1][j-1] + 1; 
	            ans[i][j]=ans[i-1][j-1]+X[i-1];
	         
	        }
	        else {
	            L[i][j] = max(L[i-1][j], L[i][j-1]); }
	      } 
	    } 
	  return L[m][n]; 
	  } 
	  
	  /* Utility function to get max of 2 integers */
	  int max(int a, int b) 
	  { 
	    return (a > b)? a : b; 
	  } 

     // Returns length of LCS for X[0..m-1], Y[0..n-1] 
     static String lcs(String X, String Y, int m, int n) 
     { 
         int[][] L = new int[m+1][n+1]; 
    
         // Following steps build L[m+1][n+1] in bottom up fashion. Note 
         // that L[i][j] contains length of LCS of X[0..i-1] and Y[0..j-1]  
         for (int i=0; i<=m; i++) 
         { 
             for (int j=0; j<=n; j++) 
             { 
                 if (i == 0 || j == 0) 
                     L[i][j] = 0; 
                 else if (X.charAt(i-1) == Y.charAt(j-1)) 
                     L[i][j] = L[i-1][j-1] + 1; 
                 else
                     L[i][j] = Math.max(L[i-1][j], L[i][j-1]); 
             } 
         } 
    
         // Following code is used to print LCS 
         int index = L[m][n]; 
         int temp = index; 
    
         // Create a character array to store the lcs string 
         char[] lcs = new char[index+1]; 
         lcs[index] = '\u0000'; // Set the terminating character 
    
         // Start from the right-most-bottom-most corner and 
         // one by one store characters in lcs[] 
         int i = m; 
         int j = n; 
         while (i > 0 && j > 0) 
         { 
             // If current character in X[] and Y are same, then 
             // current character is part of LCS 
             if (X.charAt(i-1) == Y.charAt(j-1)) 
             { 
                 // Put current character in result 
                 lcs[index-1] = X.charAt(i-1);  
                   
                 // reduce values of i, j and index 
                 i--;  
                 j--;  
                 index--;      
             } 
    
             // If not same, then find the larger of two and 
             // go in the direction of larger value 
             else if (L[i-1][j] > L[i][j-1]) 
                 i--; 
             else
                 j--; 
         } 
    
         // Print the lcs 
         StringBuilder Sd=new StringBuilder();
         for(int k=0;k<=temp;k++) 
             Sd.append(lcs[k]); 
      return Sd.toString();   
     }
 }