Fox Ciel has some flowers: r red flowers, g green flowers and b blue flowers. She wants to use these flowers to make several bouquets. There are 4 types of bouquets:

  * To make a "red bouquet", it needs 3 red flowers. 
  * To make a "green bouquet", it needs 3 green flowers. 
  * To make a "blue bouquet", it needs 3 blue flowers. 
  * To make a "mixing bouquet", it needs 1 red, 1 green and 1 blue flower. 



Help Fox Ciel to find the maximal number of bouquets she can make.

Input

The first line contains three integers r, g and b (0 ≤ r, g, b ≤ 109) — the number of red, green and blue flowers.

Output

Print the maximal number of bouquets Fox Ciel can make.

Examples

Input

3 6 9


Output

6


Input

4 4 4


Output

4


Input

0 0 0


Output

0

Note

In test case 1, we can make 1 red bouquet, 2 green bouquets and 3 blue bouquets.

In test case 2, we can make 1 red, 1 green, 1 blue and 1 mixing bouquet.
import java.util.Scanner;

public class CielAndFlowers {
    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        int R = in.nextInt();
        int G = in.nextInt();
        int B = in.nextInt();
        int answer = triplets(R, G, B);
        if (R >= 1 && G >= 1 && B >= 1) {
            answer = Math.max(answer, 1+triplets(R-1, G-1, B-1));
            if (R >=2 && G >= 2 && B >= 2) {
                answer = Math.max(answer, 2+triplets(R-2, G-2, B-2));
            }
        }
        System.out.println(answer);
    }

    static int triplets(int R, int G, int B) {
        return R/3+G/3+B/3;
    }

}
