Walking along a riverside, Mino silently takes a note of something.

"Time," Mino thinks aloud.

"What?"

"Time and tide wait for no man," explains Mino. "My name, taken from the river, always reminds me of this."

"And what are you recording?"

"You see it, tide. Everything has its own period, and I think I've figured out this one," says Mino with confidence.

Doubtfully, Kanno peeks at Mino's records. 

The records are expressed as a string s of characters '0', '1' and '.', where '0' denotes a low tide, '1' denotes a high tide, and '.' denotes an unknown one (either high or low).

You are to help Mino determine whether it's possible that after replacing each '.' independently with '0' or '1', a given integer p is not a period of the resulting string. In case the answer is yes, please also show such a replacement to Mino.

In this problem, a positive integer p is considered a period of string s, if for all 1 ≤ i ≤ \lvert s \rvert - p, the i-th and (i + p)-th characters of s are the same. Here \lvert s \rvert is the length of s.

Input

The first line contains two space-separated integers n and p (1 ≤ p ≤ n ≤ 2000) — the length of the given string and the supposed period, respectively.

The second line contains a string s of n characters — Mino's records. s only contains characters '0', '1' and '.', and contains at least one '.' character.

Output

Output one line — if it's possible that p is not a period of the resulting string, output any one of such strings; otherwise output "No" (without quotes, you can print letters in any case (upper or lower)).

Examples

Input

10 7
1.0.1.0.1.


Output

1000100010


Input

10 6
1.0.1.1000


Output

1001101000


Input

10 9
1........1


Output

No

Note

In the first example, 7 is not a period of the resulting string because the 1-st and 8-th characters of it are different.

In the second example, 6 is not a period of the resulting string because the 4-th and 10-th characters of it are different.

In the third example, 9 is always a period because the only constraint that the first and last characters are the same is already satisfied.

Note that there are multiple acceptable answers for the first two examples, you can print any of them.

import java.io.*;
import java.math.BigInteger;
import java.text.DateFormat;
import java.text.ParseException;
import java.text.SimpleDateFormat;
import java.util.*;

public class Main {

    static final int INF = Integer.MAX_VALUE;

    static void mergeSort(int[] a, int p, int r) {
        if (p < r) {
            int q = (p + r) / 2;
            mergeSort(a, p, q);
            mergeSort(a, q + 1, r);
            merge(a, p, q, r);
        }
    }

    static void merge(int[] a, int p, int q, int r) {
        int n1 = q - p + 1;
        int n2 = r - q;
        int[] L = new int[n1 + 1], R = new int[n2 + 1];
        // int[] L1 = new int[n1 + 1], R1 = new int[n2 + 1];

        for (int i = 0; i < n1; i++) {
            L[i] = a[p + i];
            //  L1[i] = b[p + i];

        }
        for (int i = 0; i < n2; i++) {
            R[i] = a[q + 1 + i];
            // R1[i] = b[q + 1 + i];

        }
        L[n1] = R[n2] = INF;
        // L1[n1] = R1[n2] = INF;

        for (int k = p, i = 0, j = 0; k <= r; k++) {
            if (L[i] <= R[j]) {

                a[k] = L[i++];
                //  b[k] = L1[i++];

            } else {
                a[k] = R[j++];
                // b[k] = R1[j++];

            }
        }
    }

    static void mergeSort(int[] a, int[] b, int p, int r) {
        if (p < r) {
            int q = (p + r) / 2;
            mergeSort(a, b, p, q);
            mergeSort(a, b, q + 1, r);
            merge(a, b, p, q, r);
        }
    }

    static void merge(int[] a, int[] b, int p, int q, int r) {
        int n1 = q - p + 1;
        int n2 = r - q;
        int[] L = new int[n1 + 1], R = new int[n2 + 1];
        int[] L1 = new int[n1 + 1], R1 = new int[n2 + 1];
        // int[] L2 = new int[n1 + 1], R2 = new int[n2 + 1];

        for (int i = 0; i < n1; i++) {
            L[i] = a[p + i];
            L1[i] = b[p + i];
            // L2[i] = a[p + i];
        }
        for (int i = 0; i < n2; i++) {
            R[i] = a[q + 1 + i];
            R1[i] = b[q + 1 + i];
            //  R2[i] = a[q + 1 + i];
        }
        L[n1] = R[n2] = INF;
        L1[n1] = R1[n2] = INF;
        // L2[n1] = R2[n2] = INF;

        for (int k = p, i = 0, j = 0; k <= r; k++) {
            if (L[i] <= R[j]) {
                a[k] = L[i];
                b[k] = L1[i++];
                // c[k] = L2[i++];
            } else {
                a[k] = R[j];
                b[k] = R1[j++];
                // c[k] = R2[j++];
            }
        }
    }

    public static int[] sieve(int n) {
        int a[] = new int[n + 1];
        for (int i = 2; i <= n; i++) {
            a[i] = 1;
        }
        for (int i = 2; i <= Math.sqrt(n); i++) {
            if (a[i] == 1) {
                for (int k = 2; i * k <= n; k++) {
                    a[i * k] = 0;
                }
            }
        }
        return a;
    }

    public static long sum(int a) {
        long su = 0;
        while (a > 0) {
            su += (long) a % 10;
            a /= 10;
        }
        return su;
    }

    public static int divi(int b) {
        int n = 0;
        for (int i = 2; i <= Math.sqrt(b); i++) {
            if (b % i == 0) {
                n = i;
                break;
            }
        }
        if (n == 0) {
            return b;
        }
        return n;
    }

    public static boolean prime(int n) {
        if (n == 1) {
            return true;
        }

        for (int i = 2; i <= Math.sqrt(n); i++) {
            if (n % i == 0) {
                return false;
            }
        }
        return true;
    }

    public static String reve(int a, int b, String s) {
        String q = "";
        for (int i = b; i >= a; i--) {
            q += s.charAt(i);
        }
        return q;
    }

    public static boolean isvowel(char c) {
        if (c == 'a' || c == 'e' || c == 'i' || c == 'o' || c == 'u' || c == 'y') {
            return true;
        } else {
            return false;
        }
    }

    static long gcd(long a, long b) {
        return b == 0 ? a : gcd(b, a % b);
    }

    public static int hole(int n) {
        int y = 0;
        if (n == 1) {
            return 0;
        }
        if (prime(n)) {
            return 1;
        }
        for (int i = 2; i <= Math.sqrt(n); i++) {
            if (n % i == 0) {
                if (prime(i)) {
                    y++;
                }
                if (prime(n / i) && i != (n / i)) {
                    y++;
                }
            }
        }
        return y;
    }

    static List<Integer> gd(int a, int b) {
        int m = (int) gcd(a, b);
        List<Integer> q = new ArrayList();
        for (int i = 1; i * i <= m; ++i) {
            if (m % i == 0) {
                q.add(i);
                if (i != m / i) {
                    q.add(m / i);
                }
            }
        }
        return q;
    }

    static boolean contain(int[] a) {
        for (int i = 1; i < a.length; i++) {
            if (a[i] == 0) {
                return true;
            }
        }
        return false;
    }

    static void decrease(int[] a) {
        for (int i = 1; i < a.length; i++) {
            a[i]--;
        }
    }

    static long power(StringBuilder s) {
        long c = 1, sum = 0;
        for (int i = 0; i < s.length(); i++) {
            if (s.charAt(i) == 'C') {
                c *= 2;
            } else {
                sum += c;
            }
        }
        return sum;
    }

    static long sum(long n) {
        return n * (n + 1) / 2;
    }

    static int divisors(int n) {
        Set<Integer> c = new HashSet();
        for (int i = 1; i <= Math.sqrt(n); i++) {
            if (n % i == 0) {
                c.add(i);
                c.add((int) (n / i));
            }
        }
        return c.size();
    }

    static boolean cal(int val, int k, int t) {
        int res = val, p = 1;
        while (val / Math.pow(k, p) > 0) {
            res += val / Math.pow(k, p);
            p++;
        }
        return res >= t;
    }

    static int Last_Ocuu(List<Long> a, int n, long v) {
        int start = 0, end = n - 1, mid, ans = -1;

        while (start <= end) {
            mid = (start + end) >> 1;
            if (a.get(mid) > v) {
                ans = mid;
                end = mid - 1;
            } else if (a.get(mid) < v) {
                //ans=mid;
                start = mid + 1;
            } else {
                return mid;
            }

        }
        return ans;
    }

    static void print(int a, String s) {

        if (a > 0) {
            //s+='*';
            System.out.println(s);
            print(a - 1, '*' + s);
        } else {
            return;
        }
    }

    static long max(int[] a) {

        long m = 0;
        int max = a[a.length - 1];
        for (int i = a.length - 1; i > 0; i--) {
            if (a[i] == a[i - 1]) {
                m++;
            }
        }
        if (m == 0) {
            m++;
        }
        return m;
    }

    static long summtion(long[] a) {
        long s = 0;
        for (int i = 1; i < a.length; i++) {
            s += a[i];
        }
        return s;
    }

    static boolean vv(int i, int j, int n, int m) {
        if (i >= 0 && i < n && j < m && j >= 0) {
            return true;
        }
        return false;
    }

    static boolean valid(char[][] a, int i, int j, int n, int m) {
        char k = a[i][j];
        if (Character.isDigit(k)) {
            int co = 0;
            if (vv(i, j + 1, n, m)) {//
                if (a[i][j + 1] == '*') {
                    co++;
                }
            }
            if (vv(i + 1, j, n, m)) {//
                if (a[i + 1][j] == '*') {
                    co++;
                }
            }
            if (vv(i + 1, j + 1, n, m)) {//
                if (a[i + 1][j + 1] == '*') {
                    co++;
                }
            }
            if (vv(i - 1, j, n, m)) {//
                if (a[i - 1][j] == '*') {
                    co++;
                }
            }
            if (vv(i, j - 1, n, m)) {//
                if (a[i][j - 1] == '*') {
                    co++;
                }
            }
            if (vv(i - 1, j - 1, n, m)) {//
                if (a[i - 1][j - 1] == '*') {
                    co++;
                }
            }
            if (vv(i - 1, j + 1, n, m)) {
                if (a[i - 1][j + 1] == '*') {
                    co++;
                }
            }
            if (vv(i + 1, j - 1, n, m)) {
                if (a[i + 1][j - 1] == '*') {
                    co++;
                }
            }
            if (co == Integer.parseInt(k + "")) {
                return true;
            }
            return false;
        } else if (k == '.') {
            if (vv(i, j + 1, n, m)) {//
                if (a[i][j + 1] == '*') {
                    return false;
                }
            }
            if (vv(i + 1, j, n, m)) {//
                if (a[i + 1][j] == '*') {
                    return false;
                }
            }
            if (vv(i + 1, j + 1, n, m)) {//
                if (a[i + 1][j + 1] == '*') {
                    return false;
                }
            }
            if (vv(i - 1, j, n, m)) {//
                if (a[i - 1][j] == '*') {
                    return false;
                }
            }
            if (vv(i, j - 1, n, m)) {//
                if (a[i][j - 1] == '*') {
                    return false;
                }
            }
            if (vv(i - 1, j - 1, n, m)) {//
                if (a[i - 1][j - 1] == '*') {
                    return false;
                }
            }
            if (vv(i - 1, j + 1, n, m)) {
                if (a[i - 1][j + 1] == '*') {
                    return false;
                }
            }
            if (vv(i + 1, j - 1, n, m)) {
                if (a[i + 1][j - 1] == '*') {
                    return false;
                }
            }

        }
        return true;
    }

    static double fact(long n) {
        if (n == 1 || n == 0) {
            return 1.0;
        }
        return (double) (n * fact(n - 1));
    }

    static boolean reachUp(char[][] a, int i, int j) {
        for (int k = i - 1; k >= 0; k--) {
            if (a[k][j] == 'W' || a[k][j] == 'B') {
                return false;
            }
        }
        return true;
    }

    static boolean reachDown(char[][] a, int i, int j) {
        for (int k = i + 1; k <= 7; k++) {
            if (a[k][j] != '.') {
                return false;
            }
        }
        return true;
    }

    static void prin(char[] a, TreeSet<Character> s, int k, int p, PrintWriter or) {
        int c = s.size();
        List<Character> e = new ArrayList<>();
        for (int i = 0; c != 26; i++) {
            if (!s.contains((char) (i + 'A'))) {
                e.add((char) (i + 'A'));
                c++;
            }
        }
        for (int i = k, o = 0; i <= p; i++) {
            if (a[i] == '?') {
                a[i] = e.get(o++);
            }
        }
        for (int j = 0; j < a.length; j++) {
            if (a[j] == '?') {
                or.print('A');
            } else {
                or.print(a[j]);
            }
        }
        or.flush();
    }

    public static void main(String[] args) throws IOException, ParseException {
        Scannerr in = new Scannerr(System.in);
        PrintWriter or = new PrintWriter(System.out);
        //Scanner w = new Scanner(System.in);
        //BitSet s= new BitSet();
        int n = in.nextInt(), p = in.nextInt();
        char[] a = in.nextLine().toCharArray();
        boolean c = false;
        for (int i = 0; i < n - p; i++) {
            if (a[i] == a[i + p] && a[i] != '.') {
            } else {
                c = true;
            }
        }
        if (!c) {
            System.out.println("NO");
            return;
        }
        for (int i = 0; i + p < n; i++) {
            if (a[i] == a[i + p]) {
                if (a[i] == '.') {
                    a[i] = '0';
                    a[i + p] = '1';
                }
            } else if (a[i] == '.') {
                a[i] = (char) (a[i + p] ^ 1);
            } else if (a[i + p] == '.') {
                a[i + p] = (char) (a[i] ^ 1);
            }
        }

        for (int i = 0; i < n; i++) {
            if (a[i] == '.') {
                a[i] = '0';
            }

        }
        for (int i = 0; i < n; i++) {
            or.print(a[i]);
        }

        or.flush();
    }

    static class Scannerr {

        StringTokenizer st;
        BufferedReader br;

        public Scannerr(FileReader fileReader) throws FileNotFoundException {
            br = new BufferedReader(fileReader);
        }

        public Scannerr(InputStream s) throws FileNotFoundException {
            br = new BufferedReader(new InputStreamReader(s));
        }

        public String next() throws IOException {
            while (st == null || !st.hasMoreTokens()) {
                st = new StringTokenizer(br.readLine());
            }
            return st.nextToken();
        }

        public double nextDouble() throws IOException {
            String x = next();
            StringBuilder sb = new StringBuilder("0");
            double res = 0, f = 1;
            boolean dec = false, neg = false;
            int start = 0;
            if (x.charAt(0) == '-') {
                neg = true;
                start++;
            }
            for (int i = start; i < x.length(); i++) {
                if (x.charAt(i) == '.') {
                    res = Long.parseLong(sb.toString());
                    sb = new StringBuilder("0");
                    dec = true;
                } else {
                    sb.append(x.charAt(i));
                    if (dec) {
                        f *= 10;
                    }
                }
            }
            res += Long.parseLong(sb.toString()) / f;
            return res * (neg ? -1 : 1);
        }

        public int nextInt() throws IOException {
            return Integer.parseInt(next());
        }

        public long nextLong() throws IOException {
            return Long.parseLong(next());
        }

        public String nextLine() throws IOException {
            return br.readLine();
        }

        public boolean ready() throws IOException {
            return br.ready();
        }

    }

}

class Pair {

    int ind;
    int val;
    int u;

    public Pair(int n, int p, int r) {
        ind = n;
        val = p;
        u = r;
    }

}
