Fox Ciel has some flowers: r red flowers, g green flowers and b blue flowers. She wants to use these flowers to make several bouquets. There are 4 types of bouquets:

  * To make a "red bouquet", it needs 3 red flowers. 
  * To make a "green bouquet", it needs 3 green flowers. 
  * To make a "blue bouquet", it needs 3 blue flowers. 
  * To make a "mixing bouquet", it needs 1 red, 1 green and 1 blue flower. 



Help Fox Ciel to find the maximal number of bouquets she can make.

Input

The first line contains three integers r, g and b (0 ≤ r, g, b ≤ 109) — the number of red, green and blue flowers.

Output

Print the maximal number of bouquets Fox Ciel can make.

Examples

Input

3 6 9


Output

6


Input

4 4 4


Output

4


Input

0 0 0


Output

0

Note

In test case 1, we can make 1 red bouquet, 2 green bouquets and 3 blue bouquets.

In test case 2, we can make 1 red, 1 green, 1 blue and 1 mixing bouquet.
#include <bits/stdc++.h>
using namespace std;
int main() {
  long long int r, g, b;
  cin >> r >> g >> b;
  long long int ans = 0;
  if (r % 3 == 2 && b % 3 == 2 && g >= 3) {
    ans += 2;
    r -= 2;
    b -= 2;
    g -= 2;
  } else if (r % 3 == 2 && g % 3 == 2 && b >= 3) {
    ans += 2;
    r -= 2;
    b -= 2;
    g -= 2;
  } else if (b % 3 == 2 && g % 3 == 2 && r >= 3) {
    ans += 2;
    r -= 2;
    b -= 2;
    g -= 2;
  } else {
    ans += min(min(r % 3, b % 3), g % 3);
    r -= ans;
    b -= ans;
    g -= ans;
  }
  ans += r / 3;
  ans += g / 3;
  ans += b / 3;
  cout << ans << endl;
  return 0;
}
