There are n people participating in some contest, they start participating in x minutes intervals. That means the first participant starts at time 0, the second participant starts at time x, the third — at time 2 ⋅ x, and so on.

Duration of contest is t minutes for each participant, so the first participant finishes the contest at time t, the second — at time t + x, and so on. When a participant finishes the contest, their dissatisfaction equals to the number of participants that started the contest (or starting it now), but haven't yet finished it.

Determine the sum of dissatisfaction of all participants.

Input

The first line contains a single integer k (1 ≤ k ≤ 1000) — the number of test cases.

Each of the next k lines contains three integers n, x, t (1 ≤ n, x, t ≤ 2 ⋅ 10^9) — the number of participants, the start interval and the contest duration.

Output

Print k lines, in the i-th line print the total dissatisfaction of participants in the i-th test case.

Example

Input


4
4 2 5
3 1 2
3 3 10
2000000000 1 2000000000


Output


5
3
3
1999999999000000000

Note

In the first example the first participant starts at 0 and finishes at time 5. By that time the second and the third participants start, so the dissatisfaction of the first participant is 2. 

The second participant starts at time 2 and finishes at time 7. By that time the third the fourth participants start, so the dissatisfaction of the second participant is 2. 

The third participant starts at 4 and finishes at 9. By that time the fourth participant starts, so the dissatisfaction of the third participant is 1.

The fourth participant starts at 6 and finishes at 11. By time 11 everyone finishes the contest, so the dissatisfaction of the fourth participant is 0.

In the second example the first participant starts at 0 and finishes at time 2. By that time the second participants starts, and the third starts at exactly time 2. So the dissatisfaction of the first participant is 2. 

The second participant starts at time 1 and finishes at time 3. At that time the third participant is solving the contest.
# DEFINING SOME GOOD STUFF
import heapq
import sys
from math import *
import threading
from heapq import *
from itertools import count
from pprint import pprint
from collections import defaultdict

'''
    intialise defaultdict by any kind of value by default you want to take ( int -> 0 | list -> [] )
'''
from heapq import heapify, heappop, heappush

sys.setrecursionlimit(300000)
# threading.stack_size(10**8)
'''
-> if you are increasing recursionlimit then remember submitting using python3 rather pypy3
-> sometimes increasing stack size don't work locally but it will work on CF
'''

mod = 10 ** 9+7
inf = 10 ** 15
decision = ['NO', 'YES']
yes = 'YES'
no = 'NO'

# ------------------------------FASTIO----------------------------
import os

from io import BytesIO, IOBase

BUFSIZE = 8192


class FastIO(IOBase):
    newlines = 0

    def __init__(self, file):
        self._fd = file.fileno()
        self.buffer = BytesIO()
        self.writable = "x" in file.mode or "r" not in file.mode
        self.write = self.buffer.write if self.writable else None

    def read(self):
        while True:
            b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
            if not b:
                break
            ptr = self.buffer.tell()
            self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
        self.newlines = 0
        return self.buffer.read()

    def readline(self):
        while self.newlines == 0:
            b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
            self.newlines = b.count(b"\n")+(not b)
            ptr = self.buffer.tell()
            self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
        self.newlines -= 1
        return self.buffer.readline()

    def flush(self):
        if self.writable:
            os.write(self._fd, self.buffer.getvalue())
            self.buffer.truncate(0), self.buffer.seek(0)


class IOWrapper(IOBase):
    def __init__(self, file):
        self.buffer = FastIO(file)
        self.flush = self.buffer.flush
        self.writable = self.buffer.writable
        self.write = lambda s: self.buffer.write(s.encode("ascii"))
        self.read = lambda: self.buffer.read().decode("ascii")
        self.readline = lambda: self.buffer.readline().decode("ascii")


sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
input = lambda: sys.stdin.readline().rstrip("\r\n")


# _______________________________________________________________#

def npr(n, r):
    return (factorial(n)%mod) // (factorial(n-r)%mod) if n >= r else 0


def ncr(n, r):
    return (factorial(n)%mod) // ((factorial(r)%mod) * (factorial(n-r)%mod)) if n >= r else 0


def lower_bound(li, num):
    answer = -1
    start = 0
    end = len(li)-1

    while (start <= end):
        middle = (end+start) // 2
        if li[middle] >= num:
            answer = middle
            end = middle-1
        else:
            start = middle+1
    return answer  # min index where x is not less than num


def upper_bound(li, num):
    answer = -1
    start = 0
    end = len(li)-1

    while (start <= end):
        middle = (end+start) // 2

        if li[middle] <= num:
            answer = middle
            start = middle+1

        else:
            end = middle-1
    return answer  # max index where x is not greater than num


def abs(x):
    return x if x >= 0 else -x


def binary_search(li, val):
    # print(lb, ub, li)
    ans = -1
    lb = 0
    ub = len(li)-1
    while (lb <= ub):
        mid = (lb+ub) // 2
        # print('mid is',mid, li[mid])
        if li[mid] > val:
            ub = mid-1
        elif val > li[mid]:
            lb = mid+1
        else:
            ans = mid  # return index
            break
    return ans


def kadane(x):  # maximum sum contiguous subarray
    sum_so_far = 0
    current_sum = 0
    for i in x:
        current_sum += i
        if current_sum < 0:
            current_sum = 0
        else:
            sum_so_far = max(sum_so_far, current_sum)
    return sum_so_far


def pref(li):
    pref_sum = [0]
    for i in li:
        pref_sum.append(pref_sum[-1]+i)
    return pref_sum


def SieveOfEratosthenes(n):
    prime = [{1, i} for i in range(n+1)]
    p = 2
    while (p <= n):
        for i in range(p * 2, n+1, p):
            prime[i].add(p)
        p += 1
    return prime


def primefactors(n):
    factors = []
    while (n % 2 == 0):
        factors.append(2)
        n //= 2
    for i in range(3, int(sqrt(n))+1, 2):  # only odd factors left
        while n % i == 0:
            factors.append(i)
            n //= i
    if n > 2:  # incase of prime
        factors.append(n)
    return factors


def prod(li):
    ans = 1
    for i in li:
        ans *= i
    return ans


def sumk(a, b):
    print('called for', a, b)
    ans = a * (a+1) // 2
    ans -= b * (b+1) // 2
    return ans

def sumi(n):
    ans = 0
    if len(n) > 1:
        for x in n:
            ans += int(x)
        return ans
    else:
        return int(n)

def checkwin(x, a):
    if a[0][0] == a[1][1] == a[2][2] == x:
        return 1
    if a[0][2] == a[1][1] == a[2][0] == x:
        return 1
    if (len(set(a[0])) == 1 and a[0][0] == x) or (len(set(a[1])) == 1 and a[1][0] == x) or (len(set(a[2])) == 1 and a[2][0] == x):
        return 1
    if (len(set(a[0][:])) == 1 and a[0][0] == x) or (len(set(a[1][:])) == 1 and a[0][1] == x) or (len(set(a[2][:])) == 1 and a[0][0] == x):
        return 1
    return 0

# _______________________________________________________________#


# def main():
karmanya = int(input())
# karmanya = 1
# divisors = SieveOfEratosthenes(200010)
# print(divisors)
while karmanya != 0:
    karmanya -= 1
    # n = int(input())
    n,x,t= map(int, input().split())
    # n,m= map(int, input().split())
    # k = int(input())
    # a = [int(x) for x in input()]
    # a = list(map(int, input().split()))
    # b = list(map(int, input().split()))
    # c = list(map(int, input().split()))
    # d = defaultdict(int)
    p = min(n, t//x) # number of students in a particular interval of paper
    ans = p*(p-1)//2 + p*(n-p)
    print(ans)


# sum of numbers from 1 to p-1 = p*(p-1)//2









































































































































# t = threading.Thread(target=main)
# t.start()
# t.join()