Snuke is introducing a robot arm with the following properties to his factory:

* The robot arm consists of m sections and m+1 joints. The sections are numbered 1, 2, ..., m, and the joints are numbered 0, 1, ..., m. Section i connects Joint i-1 and Joint i. The length of Section i is d_i.
* For each section, its mode can be specified individually. There are four modes: `L`, `R`, `D` and `U`. The mode of a section decides the direction of that section. If we consider the factory as a coordinate plane, the position of Joint i will be determined as follows (we denote its coordinates as (x_i, y_i)):
* (x_0, y_0) = (0, 0).
* If the mode of Section i is `L`, (x_{i}, y_{i}) = (x_{i-1} - d_{i}, y_{i-1}).
* If the mode of Section i is `R`, (x_{i}, y_{i}) = (x_{i-1} + d_{i}, y_{i-1}).
* If the mode of Section i is `D`, (x_{i}, y_{i}) = (x_{i-1}, y_{i-1} - d_{i}).
* If the mode of Section i is `U`, (x_{i}, y_{i}) = (x_{i-1}, y_{i-1} + d_{i}).



Snuke would like to introduce a robot arm so that the position of Joint m can be matched with all of the N points (X_1, Y_1), (X_2, Y_2), ..., (X_N, Y_N) by properly specifying the modes of the sections. Is this possible? If so, find such a robot arm and how to bring Joint m to each point (X_j, Y_j).

Constraints

* All values in input are integers.
* 1 \leq N \leq 1000
* -10^9 \leq X_i \leq 10^9
* -10^9 \leq Y_i \leq 10^9

Input

Input is given from Standard Input in the following format:


N
X_1 Y_1
X_2 Y_2
:
X_N Y_N


Output

If the condition can be satisfied, follow the following format. If the condition cannot be satisfied, print `-1`.


m
d_1 d_2 ... d_m
w_1
w_2
:
w_N


m and d_i are the configurations of the robot arm. Refer to the problem statement for what each of them means. Here, 1 \leq m \leq 40 and 1 \leq d_i \leq 10^{12} must hold. Also, m and d_i must all be integers.

w_j is a string of length m that represents the way to bring Joint m of the robot arm to point (X_j, Y_j). The i-th character of w_j should be one of the letters `L`, `R`, `D` and `U`, representing the mode of Section i.

Examples

Input

3
-1 0
0 3
2 -1


Output

2
1 2
RL
UU
DR


Input

5
0 0
1 0
2 0
3 0
4 0


Output

-1


Input

2
1 1
1 1


Output

2
1 1
RU
UR


Input

3
-7 -3
7 3
-3 -7


Output

5
3 1 4 1 5
LRDUL
RDULR
DULRD
import java.util.*;

public class Main {

	public static void main(String[] args) {
		Scanner sc = new Scanner(System.in);
		
		int n = sc.nextInt();
		long x[] = new long[n], y[] = new long[n];
		
		for(int i=0;i<n;i++){
			x[i] = sc.nextLong();
			y[i] = sc.nextLong();
		}
		
		long parity = Math.abs((x[0] + y[0]) % 2);
		
		boolean f = true;
		for(int i=1;i<n;i++){
			if(Math.abs((x[i]+y[i])%2) != parity)
				f = false;
		}
		
		if(f){
			long a[] = new long[31];
			
			a[0] = 1;
			for(int i=1;i<31;i++){
				a[i] = a[i-1]*2;
			}
			
			
			if(parity==0){
				System.out.println(32);
				System.out.print(1+" ");
			}
			else{
				System.out.println(31);
			}
			
			for(int i=30;i>=0;i--){
				System.out.print(i==30 ? a[i]:" "+a[i]);
			}
			System.out.println();
			
			
			for(int i=0;i<n;i++){
				if(parity==0){
					if(Math.abs(x[i]-1) + Math.abs(y[i]) <= (1L<<31) -1){
						x[i] -= 1;
						System.out.print("R");
					}
					else if(Math.abs(x[i]+1) + Math.abs(y[i]) <= (1L<<31) -1){
						x[i] += 1;
						System.out.print("L");
					}
					else if(Math.abs(x[i]) + Math.abs(y[i]-1) <= (1L<<31) -1){
						y[i] -=1;
						System.out.print("U");
					}
					else{
						y[i]+=1;
						System.out.print("D");
					}
				}
				
				
				for(int j=30;j>=0;j--){
					
					if(Math.abs(x[i]-a[j]) + Math.abs(y[i]) <= (1L<<j) -1){
						x[i] -= a[j];
						System.out.print("R");
					}
					else if(Math.abs(x[i]+a[j]) + Math.abs(y[i]) <= (1L<<j) -1){
						x[i] += a[j];
						System.out.print("L");
					}
					else if(Math.abs(x[i]) + Math.abs(y[i]-a[j]) <= (1L<<j) -1){
						y[i] -= a[j];
						System.out.print("U");
					}
					else{
						y[i] += a[j];
						System.out.print("D");
					}
				}
				System.out.println();
			}
			
		}
		else{
			System.out.println(-1);
		}
	}

}
