We have a long seat of width X centimeters. There are many people who wants to sit here. A person sitting on the seat will always occupy an interval of length Y centimeters.

We would like to seat as many people as possible, but they are all very shy, and there must be a gap of length at least Z centimeters between two people, and between the end of the seat and a person.

At most how many people can sit on the seat?

Constraints

* All input values are integers.
* 1 \leq X, Y, Z \leq 10^5
* Y+2Z \leq X

Input

Input is given from Standard Input in the following format:


X Y Z


Output

Print the answer.

Examples

Input

13 3 1


Output

3


Input

12 3 1


Output

2


Input

100000 1 1


Output

49999


Input

64146 123 456


Output

110


Input

64145 123 456


Output

109
import java.util.Scanner;




public class Main {

    public static void main(String[] args) {

    	Main main=new Main();

    	main.run();

    }

    void run() {
    	Scanner sc=new Scanner(System.in);
    	int X=sc.nextInt();
    	int Y=sc.nextInt();
    	int Z=sc.nextInt();

    	int ninzu=0;
    	while(true) {

    		int next=ninzu+1;
    		if(X>=next*Y+Z*(next+1)) {
    			ninzu=next;
    		}else {
    			break;
    		}


    	}

    	System.out.println(ninzu);

    }


}

