We have a tree with N vertices, whose i-th edge connects Vertex u_i and Vertex v_i. Vertex i has an integer a_i written on it. For every integer k from 1 through N, solve the following problem:

* We will make a sequence by lining up the integers written on the vertices along the shortest path from Vertex 1 to Vertex k, in the order they appear. Find the length of the longest increasing subsequence of this sequence.



Here, the longest increasing subsequence of a sequence A of length L is the subsequence A_{i_1} , A_{i_2} , ... , A_{i_M} with the greatest possible value of M such that 1 \leq i_1 < i_2 < ... < i_M \leq L and A_{i_1} < A_{i_2} < ... < A_{i_M}.

Constraints

* 2 \leq N \leq 2 \times 10^5
* 1 \leq a_i \leq 10^9
* 1 \leq u_i , v_i \leq N
* u_i \neq v_i
* The given graph is a tree.
* All values in input are integers.

Input

Input is given from Standard Input in the following format:


N
a_1 a_2 ... a_N
u_1 v_1
u_2 v_2
:
u_{N-1} v_{N-1}


Output

Print N lines. The k-th line, print the length of the longest increasing subsequence of the sequence obtained from the shortest path from Vertex 1 to Vertex k.

Example

Input

10
1 2 5 3 4 6 7 3 2 4
1 2
2 3
3 4
4 5
3 6
6 7
1 8
8 9
9 10


Output

1
2
3
3
4
4
5
2
2
3
import sys
from collections import defaultdict as dd
from bisect import bisect_left as bl
input = sys.stdin.readline
N = int(input())
a = [0] + list(map(int, input().split()))
e = dd(list)
for _ in range(N - 1):
  u, v = map(int, input().split())
  e[u].append(v)
  e[v].append(u)

inf = 10 ** 10
lis = [inf] * (N * 2)
s = [1]
vis = [0] * (N + 1)
euler = []
while len(s):
  x = s.pop()
  if x >= 0:
    vis[x] = 1
    euler.append(x)
    for y in e[x]:
      if vis[y]: continue
      s.append(~y)
      s.append(y)
  else: euler.append(x)

rollback = []
res = [0] * (N + 1)
for x in euler:
  if x >= 0:
    y = bl(lis, a[x])
    rollback.append((y, lis[y]))
    lis[y] = a[x]
    res[x] = bl(lis, inf)
  else:
    y, v = rollback.pop()
    lis[y] = v

for r in res[1: ]: print(r)
