We have a sequence of N \times K integers: X=(X_0,X_1,\cdots,X_{N \times K-1}). Its elements are represented by another sequence of N integers: A=(A_0,A_1,\cdots,A_{N-1}). For each pair i, j (0 \leq i \leq K-1,\ 0 \leq j \leq N-1), X_{i \times N + j}=A_j holds.

Snuke has an integer sequence s, which is initially empty. For each i=0,1,2,\cdots,N \times K-1, in this order, he will perform the following operation:

* If s does not contain X_i: add X_i to the end of s.
* If s does contain X_i: repeatedly delete the element at the end of s until s no longer contains X_i. Note that, in this case, we do not add X_i to the end of s.



Find the elements of s after Snuke finished the operations.

Constraints

* 1 \leq N \leq 2 \times 10^5
* 1 \leq K \leq 10^{12}
* 1 \leq A_i \leq 2 \times 10^5
* All values in input are integers.

Input

Input is given from Standard Input in the following format:


N K
A_0 A_1 \cdots A_{N-1}


Output

Print the elements of s after Snuke finished the operations, in order from beginning to end, with spaces in between.

Examples

Input

3 2
1 2 3


Output

2 3


Input

5 10
1 2 3 2 3


Output

3


Input

6 1000000000000
1 1 2 2 3 3


Output




Input

11 97
3 1 4 1 5 9 2 6 5 3 5


Output

9 2 6
from bisect import bisect_left
from collections import defaultdict
N, K, *A = map(int, open(0).read().split())
dic = defaultdict(list)
for i, a in enumerate(A):
  dic[a] += [i]
ls = []
ps = 0
m = A[0]
cycle = 0
while True:
  ls.append(ps+N*cycle+1)
  i = bisect_left(dic[m],ps+1)
  ps = dic[m][i%len(dic[m])]
  if i>=len(dic[m]):
    cycle += 1
  ps += 1
  ps %= N
  m = A[ps]
  if ps==0:
    cycle += 1
    break
k = K%cycle
j = bisect_left(ls,k*N)
if ls[j]==k*N:
  c = (ls[j]-1)%N
  print(A[c])
elif ls[j]==k*N+1:
  pass
else:
  c = (ls[j-1]-1)%N
  M = k*N-ls[j-1]
  ans = [A[c]]
  log = set(ans)
  ind = {}
  ind[A[c]] = 0
  cnt = 0
  while M:
    c += 1
    c %= N
    cnt += 1
    cnt %= N
    M -= 1
    if not A[c] in log:
      log.add(A[c])
      ind[A[c]] = cnt
      ans += [A[c]]
    else:
      log.remove(A[c])
      ans = ans[:ind[A[c]]]
      log = set(ans)
      cnt = ind[A[c]]-1
  print(*ans)
