You are given a forest with N vertices and M edges. The vertices are numbered 0 through N-1. The edges are given in the format (x_i,y_i), which means that Vertex x_i and y_i are connected by an edge.

Each vertex i has a value a_i. You want to add edges in the given forest so that the forest becomes connected. To add an edge, you choose two different vertices i and j, then span an edge between i and j. This operation costs a_i + a_j dollars, and afterward neither Vertex i nor j can be selected again.

Find the minimum total cost required to make the forest connected, or print `Impossible` if it is impossible.

Constraints

* 1 ≤ N ≤ 100,000
* 0 ≤ M ≤ N-1
* 1 ≤ a_i ≤ 10^9
* 0 ≤ x_i,y_i ≤ N-1
* The given graph is a forest.
* All input values are integers.

Input

Input is given from Standard Input in the following format:


N M
a_0 a_1 .. a_{N-1}
x_1 y_1
x_2 y_2
:
x_M y_M


Output

Print the minimum total cost required to make the forest connected, or print `Impossible` if it is impossible.

Examples

Input

7 5
1 2 3 4 5 6 7
3 0
4 0
1 2
1 3
5 6


Output

7


Input

5 0
3 1 4 1 5


Output

Impossible


Input

1 0
5


Output

0
from collections import deque
import heapq
N,M = map(int,input().split())
A = list(map(int,input().split()))
G = {i:[] for i in range(N)}
for _ in range(M):
    x,y = map(int,input().split())
    G[x].append(y)
    G[y].append(x)
F = []
hist = [0 for _ in range(N)]
for i in range(N):
    T = []
    if hist[i]==0:
        que = deque([i])
        hist[i]=1
        heapq.heappush(T,A[i])
        while que:
            x = que.popleft()
            for y in G[x]:
                if hist[y]==0:
                    que.append(y)
                    hist[y]=1
                    heapq.heappush(T,A[y])
        F.append(T)
K = len(F)
if K>N//2+1:        
    cnt = -1
elif K==1:
    cnt = 0
else:
    cnt = 0
    for i in range(K):
        cnt += heapq.heappop(F[i])
    F1 = []
    for T in F:
        F1 += T
    F1 = sorted(F1)
    for i in range(K-2):
        cnt += F1[i]
if cnt<0:
    print("Impossible")
else:
    print(cnt)