Fox Ciel has some flowers: r red flowers, g green flowers and b blue flowers. She wants to use these flowers to make several bouquets. There are 4 types of bouquets:

  * To make a "red bouquet", it needs 3 red flowers. 
  * To make a "green bouquet", it needs 3 green flowers. 
  * To make a "blue bouquet", it needs 3 blue flowers. 
  * To make a "mixing bouquet", it needs 1 red, 1 green and 1 blue flower. 



Help Fox Ciel to find the maximal number of bouquets she can make.

Input

The first line contains three integers r, g and b (0 ≤ r, g, b ≤ 109) — the number of red, green and blue flowers.

Output

Print the maximal number of bouquets Fox Ciel can make.

Examples

Input

3 6 9


Output

6


Input

4 4 4


Output

4


Input

0 0 0


Output

0

Note

In test case 1, we can make 1 red bouquet, 2 green bouquets and 3 blue bouquets.

In test case 2, we can make 1 red, 1 green, 1 blue and 1 mixing bouquet.
import java.util.Scanner;

public class B {

    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        int a = sc.nextInt();
        int b = sc.nextInt();
        int c = sc.nextInt();
        int max = 0;
        for (int i = 0 ;i <= 7;i++)
        {
            int aa = a;
            int bb = b;
            int cc = c;
            int sum = 0;
            if((i&1)!=0)
            {
                sum+=aa/3;
                aa-=(aa/3)*3;
            }
            if((i&2)!=0)
            {
                sum+=bb/3;
                bb-=(bb/3)*3;
                
            }
            if((i&4)!=0)
            {
                sum+=cc/3;
                cc-=(cc/3)*3;
            }
            int min = Math.min(aa, Math.min(bb, cc));
            aa-=min;
            bb-=min;
            cc-=min;
            sum+=min+aa/3+bb/3+cc/3;
            max = Math.max(max, sum);
        }
        System.out.println(max);
    }

}
