Fox Ciel starts to learn programming. The first task is drawing a fox! However, that turns out to be too hard for a beginner, so she decides to draw a snake instead.

A snake is a pattern on a n by m table. Denote c-th cell of r-th row as (r, c). The tail of the snake is located at (1, 1), then it's body extends to (1, m), then goes down 2 rows to (3, m), then goes left to (3, 1) and so on.

Your task is to draw this snake for Fox Ciel: the empty cells should be represented as dot characters ('.') and the snake cells should be filled with number signs ('#').

Consider sample tests in order to understand the snake pattern.

Input

The only line contains two integers: n and m (3 ≤ n, m ≤ 50). 

n is an odd number.

Output

Output n lines. Each line should contain a string consisting of m characters. Do not output spaces.

Examples

Input

3 3


Output

###
..#
###


Input

3 4


Output

####
...#
####


Input

5 3


Output

###
..#
###
#..
###


Input

9 9


Output

#########
........#
#########
#........
#########
........#
#########
#........
#########
import java.util.*;

public class A_fox {

	public static void main(String[] args) {
		Scanner in = new Scanner(System.in);

		int n = in.nextInt();
		int m = in.nextInt();
		char[][] arr = new char[n][m];
		boolean back = false;
		boolean front = true;
		boolean temp;
		boolean on = false;
		for (int i = 0; i < n; i++) {
			if (i % 2 != 0) {
				on = true;
				temp = back;
				back = front;
				front = temp;
			} else if (i % 2 == 0)
				on = false;
			for (int j = 0; j < m; j++) {
				if ((on) && (front) && (j == 0)) {
					arr[i][j] = '#';
				} else if ((on) && (back) && (j == (m - 1))) {
					arr[i][j] = '#';
				} else if (on)
					arr[i][j] = '.';
				else if (!(on))
					arr[i][j] = '#';

			}
		}
		for (int i = 0; i < n; i++) {			
			for (int j = 0; j < m; j++)
				System.out.print(arr[i][j]);
			System.out.println();
		}
	}

}
