You are given a forest with N vertices and M edges. The vertices are numbered 0 through N-1. The edges are given in the format (x_i,y_i), which means that Vertex x_i and y_i are connected by an edge.

Each vertex i has a value a_i. You want to add edges in the given forest so that the forest becomes connected. To add an edge, you choose two different vertices i and j, then span an edge between i and j. This operation costs a_i + a_j dollars, and afterward neither Vertex i nor j can be selected again.

Find the minimum total cost required to make the forest connected, or print `Impossible` if it is impossible.

Constraints

* 1 ≤ N ≤ 100,000
* 0 ≤ M ≤ N-1
* 1 ≤ a_i ≤ 10^9
* 0 ≤ x_i,y_i ≤ N-1
* The given graph is a forest.
* All input values are integers.

Input

Input is given from Standard Input in the following format:


N M
a_0 a_1 .. a_{N-1}
x_1 y_1
x_2 y_2
:
x_M y_M


Output

Print the minimum total cost required to make the forest connected, or print `Impossible` if it is impossible.

Examples

Input

7 5
1 2 3 4 5 6 7
3 0
4 0
1 2
1 3
5 6


Output

7


Input

5 0
3 1 4 1 5


Output

Impossible


Input

1 0
5


Output

0
class UnionFindVerSize():
    def __init__(self, N):
        """ N個のノードのUnion-Find木を作成する """
        # 親の番号を格納する。自分が親だった場合は、自分の番号になり、それがそのグループの番号になる
        self._parent = [n for n in range(0, N)]
        # グループのサイズ（個数）
        self._size = [1] * N

    def find_root(self, x):
        """ xの木の根(xがどのグループか)を求める """
        if self._parent[x] == x: return x
        self._parent[x] = self.find_root(self._parent[x]) # 縮約
        return self._parent[x]

    def unite(self, x, y):
        """ xとyの属するグループを併合する """
        gx = self.find_root(x)
        gy = self.find_root(y)
        if gx == gy: return

        # 小さい方を大きい方に併合させる（木の偏りが減るので）
        if self._size[gx] < self._size[gy]:
            self._parent[gx] = gy
            self._size[gy] += self._size[gx]
        else:
            self._parent[gy] = gx
            self._size[gx] += self._size[gy]

    def get_size(self, x):
        """ xが属するグループのサイズ（個数）を返す """
        return self._size[self.find_root(x)]

    def is_same_group(self, x, y):
        """ xとyが同じ集合に属するか否か """
        return self.find_root(x) == self.find_root(y)

    def calc_group_num(self):
        """ グループ数を計算して返す """
        N = len(self._parent)
        ans = 0
        for i in range(N):
            if self.find_root(i) == i:
                ans += 1
        return ans

import sys,heapq

input=sys.stdin.readline

N,M=map(int,input().split())
a=list(map(int,input().split()))
uf=UnionFindVerSize(N)
for i in range(M):
    x,y=map(int,input().split())
    uf.unite(x,y)

dic={}
for i in range(0,N):
    if uf.find_root(i) not in dic:
        dic[uf.find_root(i)]=[]
        heapq.heapify(dic[uf.find_root(i)])
    heapq.heappush(dic[uf.find_root(i)],a[i])

m=len(dic)
if m==1:
    print(0)
    exit()
ans=0
for i in dic:
    ans+=heapq.heappop(dic[i])

data=[]
for i in dic:
    data+=dic[i]
data.sort()
if len(data)<m-2:
    print("Impossible")
else:
    print(ans+sum(data[:m-2]))
    