Given a String(only lower case letters) , check if any substring has occured Twice :

 Example : iwsagoodboody
Here, substring  "ood" occurs twice.

Output "YES"  if there is any such substring else output "NO" .(without qoutes)

Input:

First line of input consists of an integer T (1 ≤ T ≤ 100) ,  indicating the number of test cases. 
For each test case, there will be a string s (1 ≤ |s| ≤ 2000)

Output:
    Print "YES"  if there is any such substring else Print "NO" .(without quotes)

SAMPLE INPUT
3
abcdefghi
dogsbarkatdogs
howtheydo

SAMPLE OUTPUT
NO
YES
YES
def subString(s):
    count=0
    for sub in s:
        s=s[:s.find(sub)]+s[s.find(sub)+1:]
        if s.find(sub) >=0:
            count+=1
            break
    if count>0:
        print "YES"
    else:
        print "NO"


    pass
if __name__ == '__main__':
    t=int(raw_input())
    for i in range(t):
        s=raw_input()
        subString(s)