

Input

The first line of the input contains a single integer N (1 ≤ N ≤ 24). The next N lines contain 5 space-separated integers each. The first three integers will be between 0 and 2, inclusive. The last two integers will be between 0 and 3, inclusive. The sum of the first three integers will be equal to the sum of the last two integers.

Output

Output the result – a string of lowercase English letters.

Examples

Input


1
1 0 0 1 0


Output


a


Input


10
2 0 0 1 1
1 1 1 2 1
2 1 0 1 2
1 1 0 1 1
2 1 0 2 1
1 1 1 2 1
1 2 1 3 1
2 0 0 1 1
1 1 0 1 1
1 1 2 2 2


Output


codeforcez
table = {
    (1, 0, 0, 1, 0): 'a',
    (1, 1, 0, 2, 0): 'b',
    (2, 0, 0, 1, 1): 'c',
    (2, 1, 0, 1, 2): 'd',
    (1, 1, 0, 1, 1): 'e',
    (2, 1, 0, 2, 1): 'f',
    (2, 2, 0, 2, 2): 'g',
    (1, 2, 0, 2, 1): 'h',
    # (1, 1, 0, 1, 1): 'i',
    (1, 2, 0, 1, 2): 'j',
    (1, 0, 1, 2, 0): 'k',
    (1, 1, 1, 3, 0): 'l',
    (2, 0, 1, 2, 1): 'm',
    (2, 1, 1, 2, 2): 'n',
    (1, 1, 1, 2, 1): 'o',
    (2, 1, 1, 3, 1): 'p',
    (2, 2, 1, 3, 2): 'q',
    (1, 2, 1, 3, 1): 'r',
    # (1, 1, 1, 2, 1): 's',
    (1, 2, 1, 2, 2): 't',
    (1, 0, 2, 2, 1): 'u',
    (1, 1, 2, 3, 1): 'v',
    (1, 2, 1, 1, 3): 'w',
    (2, 0, 2, 2, 2): 'x',
    (2, 1, 2, 2, 3): 'y',
    (1, 1, 2, 2, 2): 'z',
}

for item in table:
    if item[0] + item[1] + item[2] !=item[3] + item[4]:
        print(table[item])
        exit(1)

ans = []
for _ in range(int(input())):
    a = tuple(map(int, input().split()))
    ans.append(table[a])
print(''.join(ans))
