You are given a forest with N vertices and M edges. The vertices are numbered 0 through N-1. The edges are given in the format (x_i,y_i), which means that Vertex x_i and y_i are connected by an edge.

Each vertex i has a value a_i. You want to add edges in the given forest so that the forest becomes connected. To add an edge, you choose two different vertices i and j, then span an edge between i and j. This operation costs a_i + a_j dollars, and afterward neither Vertex i nor j can be selected again.

Find the minimum total cost required to make the forest connected, or print `Impossible` if it is impossible.

Constraints

* 1 ≤ N ≤ 100,000
* 0 ≤ M ≤ N-1
* 1 ≤ a_i ≤ 10^9
* 0 ≤ x_i,y_i ≤ N-1
* The given graph is a forest.
* All input values are integers.

Input

Input is given from Standard Input in the following format:


N M
a_0 a_1 .. a_{N-1}
x_1 y_1
x_2 y_2
:
x_M y_M


Output

Print the minimum total cost required to make the forest connected, or print `Impossible` if it is impossible.

Examples

Input

7 5
1 2 3 4 5 6 7
3 0
4 0
1 2
1 3
5 6


Output

7


Input

5 0
3 1 4 1 5


Output

Impossible


Input

1 0
5


Output

0
class UF:
    def __init__(self, N):
        self.uf = [-1]*N
        self.n = N

    def find(self, x):
        if self.uf[x]<0: return x
        self.uf[x] = self.find(self.uf[x])
        return self.uf[x]

    def size(self, x):
        return -self.uf[self.find(x)]

    def union(self, x, y):
        x, y = self.find(x), self.find(y)
        if x==y: return
        if self.size(x) > self.size(y): x, y = y, x
        self.uf[y] += self.uf[x]
        self.uf[x] = y
        self.n -= 1
        
N, M = map(int, input().split())
A = list(map(int, input().split()))
uf = UF(N)
for _ in range(M):
    x, y = map(int, input().split())
    uf.union(x,y)

D = {}
for x, a in enumerate(A):
    c = uf.find(x)
    if c not in D: D[c]=[]
    D[c].append(a)

ans = 0
L = []
for d in D.values():
    d.sort()
    ans += d[0]
    L += d[1:]

L.sort()

P = len(D)-2
if len(D)==1:
    ans = 0
elif len(L)>=P:
    ans += sum(L[:len(D)-2])
else:
    ans = 'Impossible'

print(ans)
