We have a tree with N vertices, whose i-th edge connects Vertex u_i and Vertex v_i. Vertex i has an integer a_i written on it. For every integer k from 1 through N, solve the following problem:

* We will make a sequence by lining up the integers written on the vertices along the shortest path from Vertex 1 to Vertex k, in the order they appear. Find the length of the longest increasing subsequence of this sequence.



Here, the longest increasing subsequence of a sequence A of length L is the subsequence A_{i_1} , A_{i_2} , ... , A_{i_M} with the greatest possible value of M such that 1 \leq i_1 < i_2 < ... < i_M \leq L and A_{i_1} < A_{i_2} < ... < A_{i_M}.

Constraints

* 2 \leq N \leq 2 \times 10^5
* 1 \leq a_i \leq 10^9
* 1 \leq u_i , v_i \leq N
* u_i \neq v_i
* The given graph is a tree.
* All values in input are integers.

Input

Input is given from Standard Input in the following format:


N
a_1 a_2 ... a_N
u_1 v_1
u_2 v_2
:
u_{N-1} v_{N-1}


Output

Print N lines. The k-th line, print the length of the longest increasing subsequence of the sequence obtained from the shortest path from Vertex 1 to Vertex k.

Example

Input

10
1 2 5 3 4 6 7 3 2 4
1 2
2 3
3 4
4 5
3 6
6 7
1 8
8 9
9 10


Output

1
2
3
3
4
4
5
2
2
3

from collections import defaultdict
n = int(input())
a = list(map(int, input().split()))

import sys
sys.setrecursionlimit(max(1000, 2*n))


ns = defaultdict(set)
for _ in range(n-1):
    u,v = [int(c) for c in input().split()]
    ns[u-1].add(v-1)
    ns[v-1].add(u-1)

from bisect import bisect_left
 
l = [a[0]]
# for a in A[1:]:
#     if a > L[-1]:
#         # Lの末尾よりaが大きければ増加部分列を延長できる
#         L.append(a)
#     else:
#         # そうでなければ、「aより小さい最大要素の次」をaにする
#         # 該当位置は、二分探索で特定できる
#         L[bisect_left(L, a)] = a
# return len(L)

ans = [None] * n

def sub(u, prev, lst, old, ind, ans):
    aa = a[u]
    if len(lst)==0 or aa > lst[-1]:
        lst.append(aa)
        old = -1
        ind = None
    else:
        ind = bisect_left(lst, aa)
        old = lst[ind]
        lst[ind] = aa
    ans[u] = len(lst)
#     print(lst)
    for v in ns[u]:
        if prev==v:
            continue
        sub(v, u, lst, old, ind, ans)
    if old==-1:
        lst.pop()
    elif old is not None:
        lst[ind] = old

lst = []
sub(0, -1, lst, None, None, ans)
print("\n".join(map(str, ans)))
