We have a long seat of width X centimeters. There are many people who wants to sit here. A person sitting on the seat will always occupy an interval of length Y centimeters.

We would like to seat as many people as possible, but they are all very shy, and there must be a gap of length at least Z centimeters between two people, and between the end of the seat and a person.

At most how many people can sit on the seat?

Constraints

* All input values are integers.
* 1 \leq X, Y, Z \leq 10^5
* Y+2Z \leq X

Input

Input is given from Standard Input in the following format:


X Y Z


Output

Print the answer.

Examples

Input

13 3 1


Output

3


Input

12 3 1


Output

2


Input

100000 1 1


Output

49999


Input

64146 123 456


Output

110


Input

64145 123 456


Output

109
import java.util.Scanner;

class Main {

  public static void main(String[] args) {
    new Main().run();
  }

  private static Scanner sc = new Scanner(System.in);

  private void run() {
    int X = Integer.parseInt(sc.next());
    int Y = Integer.parseInt(sc.next());
    int Z = Integer.parseInt(sc.next());

    int man = X / Y;

    while (true) {
      if (man * Y + Z * (man + 1) > X) {
        man--;
      } else {
        break;
      }
    }
    System.out.println(man);
  }
}
