You are given an array a consisting of n integers. Indices of the array start from zero (i. e. the first element is a_0, the second one is a_1, and so on).

You can reverse at most one subarray (continuous subsegment) of this array. Recall that the subarray of a with borders l and r is a[l; r] = a_l, a_{l + 1}, ..., a_{r}.

Your task is to reverse such a subarray that the sum of elements on even positions of the resulting array is maximized (i. e. the sum of elements a_0, a_2, ..., a_{2k} for integer k = ⌊(n-1)/(2)⌋ should be maximum possible).

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The first line of the test case contains one integer n (1 ≤ n ≤ 2 ⋅ 10^5) — the length of a. The second line of the test case contains n integers a_0, a_1, ..., a_{n-1} (1 ≤ a_i ≤ 10^9), where a_i is the i-th element of a.

It is guaranteed that the sum of n does not exceed 2 ⋅ 10^5 (∑ n ≤ 2 ⋅ 10^5).

Output

For each test case, print the answer on the separate line — the maximum possible sum of elements on even positions after reversing at most one subarray (continuous subsegment) of a.

Example

Input


4
8
1 7 3 4 7 6 2 9
5
1 2 1 2 1
10
7 8 4 5 7 6 8 9 7 3
4
3 1 2 1


Output


26
5
37
5
import java.io.*;
import java.util.InputMismatchException;
import java.util.*;
public class EvenPos{
	public static void main(String[] args) throws IOException{
		FastReader sc = new FastReader();
		BufferedWriter out = new BufferedWriter(new OutputStreamWriter(new FileOutputStream(java.io.FileDescriptor.out),"ASCII"),512);
		int t = sc.nextInt();
		while(t-- > 0){
			int n = sc.nextInt();
			long sum = 0l;
			int[] a = new int[n];
			ArrayList<Integer> diff1 = new ArrayList<Integer>();
			ArrayList<Integer> diff2 = new ArrayList<Integer>();
			for(int i=0;i<n;i++){
				a[i] = sc.nextInt();
				if(i%2==0){
					if(i>0) diff2.add(a[i-1]-a[i]);
					sum += a[i];
				}else diff1.add(a[i]-a[i-1]);
			}
			long max_curr = 0l;
			long max_global = 0l;
			for(int i=0;i<diff1.size();i++){
				int temp = diff1.get(i);
				max_curr = Math.max(temp,(temp+max_curr));
				max_global = Math.max(max_curr,max_global);
			}
			max_curr = 0;
			for(int i=0;i<diff2.size();i++){
				int temp = diff2.get(i);
				max_curr = Math.max(temp,(temp+max_curr));
				max_global = Math.max(max_curr,max_global);
			}
			out.write((sum+max_global) + "");
			out.write('\n');
		}
		out.flush();
	}
}
class FastReader{
	BufferedReader br;
	StringTokenizer st;
	public FastReader(){
		br = new BufferedReader(new InputStreamReader(System.in));
	}
	String next(){
		while(st == null || !st.hasMoreElements()){
			try{ 
				st = new StringTokenizer(br.readLine()); 
			} 
			catch (IOException  e){ 
				e.printStackTrace(); 
			} 
		} 
		return st.nextToken();
	}
	int nextInt(){ 
        return Integer.parseInt(next()); 
	}
    long nextLong(){ 
        return Long.parseLong(next()); 
    }
    double nextDouble(){ 
        return Double.parseDouble(next()); 
    }
    String nextLine(){ 
        String str = ""; 
        try{ 
            str = br.readLine(); 
        } 
		catch (IOException e){ 
            e.printStackTrace(); 
        } 
        return str; 
    }
}