Fox Ciel starts to learn programming. The first task is drawing a fox! However, that turns out to be too hard for a beginner, so she decides to draw a snake instead.

A snake is a pattern on a n by m table. Denote c-th cell of r-th row as (r, c). The tail of the snake is located at (1, 1), then it's body extends to (1, m), then goes down 2 rows to (3, m), then goes left to (3, 1) and so on.

Your task is to draw this snake for Fox Ciel: the empty cells should be represented as dot characters ('.') and the snake cells should be filled with number signs ('#').

Consider sample tests in order to understand the snake pattern.

Input

The only line contains two integers: n and m (3 ≤ n, m ≤ 50). 

n is an odd number.

Output

Output n lines. Each line should contain a string consisting of m characters. Do not output spaces.

Examples

Input

3 3


Output

###
..#
###


Input

3 4


Output

####
...#
####


Input

5 3


Output

###
..#
###
#..
###


Input

9 9


Output

#########
........#
#########
#........
#########
........#
#########
#........
#########

import java.util.Scanner;

public class Problem_510_A {

    public static void main(String[] args) {
        Scanner Input = new Scanner(System.in);
        char A[][] = new char[Input.nextInt()][Input.nextInt()];
        boolean K = true;
        boolean F = true;
        int X = 0;
        for (int I = 0; I < A.length; I++) {
            for (int J = 0; J < A[I].length; J++) {
                A[I][J] = '#';
                if (I % 2 == 1 && K) {
                    A[I][J] = '.';
                    if (J == A[I].length-1 && K && F && I != X) {
                        A[I][J] = '#';
                        K = false;
                    }

                } else if (I % 2 == 1 && !K) {
                    A[I][J] = '.';
                    if (J == 0 && !K) {
                        A[I][J] = '#';
                        K = true;
                        X = I;
                    }

                }

                //A[I][J] = 0;
                System.out.print(A[I][J]);
            }

            System.out.println("");
        }
    }

}