Fox Ciel starts to learn programming. The first task is drawing a fox! However, that turns out to be too hard for a beginner, so she decides to draw a snake instead.

A snake is a pattern on a n by m table. Denote c-th cell of r-th row as (r, c). The tail of the snake is located at (1, 1), then it's body extends to (1, m), then goes down 2 rows to (3, m), then goes left to (3, 1) and so on.

Your task is to draw this snake for Fox Ciel: the empty cells should be represented as dot characters ('.') and the snake cells should be filled with number signs ('#').

Consider sample tests in order to understand the snake pattern.

Input

The only line contains two integers: n and m (3 ≤ n, m ≤ 50). 

n is an odd number.

Output

Output n lines. Each line should contain a string consisting of m characters. Do not output spaces.

Examples

Input

3 3


Output

###
..#
###


Input

3 4


Output

####
...#
####


Input

5 3


Output

###
..#
###
#..
###


Input

9 9


Output

#########
........#
#########
#........
#########
........#
#########
#........
#########
__author__ = 'Devesh Bajpai'

'''
https://codeforces.com/problemset/problem/510/A

Solution: The rows have pattern for even and odd indexed ones. For the former, it has all cells with snake body, 
while the later as alternating empty cells with right/left aligned snake body. Keep track of that with a boolean flag.  
'''


def solve(n, m):

    snakeBody = "#"
    snakeBodies = snakeBody * m
    emptyCells = "." * (m-1)

    # flag denotes if the snake body on the right or the left side for alternate rows
    isRight = True

    for row in xrange(0, n):

        if row % 2 == 0:
            print snakeBodies
        else:
            if isRight:
                print emptyCells + snakeBody
            else:
                print snakeBody + emptyCells
            # toggle it
            isRight = not isRight


if __name__ == "__main__":

    n, m = map(int, raw_input().split(" "))

    solve(n, m)
