Fox Ciel has some flowers: r red flowers, g green flowers and b blue flowers. She wants to use these flowers to make several bouquets. There are 4 types of bouquets:

  * To make a "red bouquet", it needs 3 red flowers. 
  * To make a "green bouquet", it needs 3 green flowers. 
  * To make a "blue bouquet", it needs 3 blue flowers. 
  * To make a "mixing bouquet", it needs 1 red, 1 green and 1 blue flower. 



Help Fox Ciel to find the maximal number of bouquets she can make.

Input

The first line contains three integers r, g and b (0 ≤ r, g, b ≤ 109) — the number of red, green and blue flowers.

Output

Print the maximal number of bouquets Fox Ciel can make.

Examples

Input

3 6 9


Output

6


Input

4 4 4


Output

4


Input

0 0 0


Output

0

Note

In test case 1, we can make 1 red bouquet, 2 green bouquets and 3 blue bouquets.

In test case 2, we can make 1 red, 1 green, 1 blue and 1 mixing bouquet.
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;


public class cielAndFlowers {

    public static void main(String[] args) throws IOException {
        BufferedReader br=new BufferedReader(new InputStreamReader(System.in));
        String[] s=br.readLine().split(" ");
        int r=Integer.parseInt(s[0]);
        int g=Integer.parseInt(s[1]);
        int b=Integer.parseInt(s[2]);
        
        long max=0;
        while(r>3&&b>3&&g>3){
            r-=3;
            g-=3;
            b-=3;
            max+=3;
        }
        while(r>3){
            max+=1;
            r-=3;
        }
        while(b>3){
            max+=1;
            b-=3;
        }
        while(g>3){
            max+=1;
            g-=3;
        }
//      System.out.println(r+" "+b+" "+g);
        int a=r/3+g/3+b/3;
        int min=Math.min(r, Math.min(g, b));
//      max+=min;
        g-=min;
        b-=min;
        r-=min;
        int z=r/3+g/3+b/3+min;
        System.out.println(max+Math.max(a, z));
    }

}
