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Come November 1, Programming Puzzles and Code Golf will graduate, so in the next 11 months, we'll want to save some memories from when we were ungraduated.
Write a program that produces the PPCG favicon, seen below.
[![enter image description here](https://i.stack.imgur.com/6Tpou.png)](https://i.stack.imgur.com/6Tpou.png)
* The image must be at least 64x64 pixels.
* The blue must be the color #62B0DF. The background can be white or a light gray.
* The image need not be pixelated like it is here.
* Alternatively, create text (with dimensions at least 64x64 non-whitespace characters) using standard bright [ANSI color codes](https://en.wikipedia.org/wiki/ANSI_escape_code#) of Cyan and White.
* Built in images and importing the PPCG logo are not allowed.
---
This is code golf, so standard rules apply. Shortest code in bytes wins.
  
[Answer]
# Bash (OSX), ~~33~~ ~~27~~ ~~23~~ 18 Bytes
You heard the man, any way we like.
```
open http:yon.se/q
```
~~I am aware that this is a popularity contest. But hey, when you can code golf it, why not?~~
It is now a code golf. \o/ This was valid at the time of posting.
> 
> [![](https://i.stack.imgur.com/sxyCJ.png)](https://i.stack.imgur.com/sxyCJ.png)
> 
> 
> 
There was even an exception made for me at some point! But, as @AlexA. pointed out...
> 
> "*You can use whatever methods you want (except loading the image, with the exception of VoteToClose's response)*" It isn't fair to allow exceptions for specific users/answers. - Alex A.
> 
> 
> 
I agree with this, and, as of such, do not wish this to be picked as the answer. Doesn't mean I won't still try to golf it down more. ;)
Thanks to @ΚριτικσιΛίθος for shaving off 6 bytes with a fancy short URL!
Thanks to @ev3commander for shaving off ANOTHER 5 bytes with an even fancier, shorter URL!
Thanks to @kennytm for pointing out that I can reduce the protocol size *and* remove the quotes, saving me another 4 bytes!
[Answer]
# [BitShift](https://esolangs.org/wiki/BitShift), 2795 bytes
```
10100110010101101001010111001010110100101011100101011010010101110010101101001010111001010110100101011100101011010010101110010101101001010111001010110100101011100101011010010101110010101101111011101010000000110101001011010100011010100010101101010010101101010010101101010010101101010010101101010010101101010011010100101101010001101010010110101001100110010101111111001010111010100101011010100101011010100101011010100101011010100101011010100101011010100101011010100101011001010110100101011001100110101000000011010100010101101010010101101010010101101010010101101010010101101010010101101010010101101010010101101010011010100101101010011001100101011111110010101110101001010110101001010110101001010110101001010110101001010110101001010110101001010110101001010110010101101001010110011001101010000000110101000101011001010110100101011100101011101010010101101010011010100101101010001010110101001010110010101101001010111001010111010100110101001011010100110011001010111111100101011101010011010100010101101010011010100010101100101011101010010101100101011101010011010100010101101010010101101010011010100101101010011001100101011111110010101110101001101010010110101000110101000101011010100110101000101011010100101011010100110101000101011001010110100101011101010011010100101101010011001100101011111110010101110101001101010001010110101001010110101001101010001010110101001101010001010110010101110101001010110010101110101001101010010110101001100110010101111111001010111010100110101000101011010100101011010100101011001010110100101011101010010101101010011010100101101010001010110101001101010010110101001100110010101111111001010111010100101011010100101011010100101011010100101011010100101011010100101011010100101011010100101011001010110100101011001100110101000000011010100101101010001010110101001010110101001010110101001010110101001010110101001010110101001010110101001101010010110101000110101001000010001010111111100101011010010101110010101110101001010110101001010110101001010110101001010110101001010110101001010110010101101001010111001010110100101011001100110101000000011010100101101010001101010010110101000110101001011010100011010100101101010001101010001010110101001010110010101101001010111001010110100101011100101011010010101110010101101111011101010000000110101001011010100011010100101101010001101010010110101000110101001011010100011010100010101101010011010100101101010001101010010110101000110101001011010100011010100101101010011001100101011111110010101101001010111001010110100101011100101011010010101110010101101001010111001010111010100110101001011010100011010100101101010001101010010110101000110101001011010100011010100100001000101011111110010101101001010111001010110100101011100101011010010101110010101101001010111001010110100101011100101011010010101110010101101001010111001010110100101011100101011010010101110010101
```
This outputs
```
   @@@@@@@@@@@@    
 @@@@@@@@@@@@@@@@  
 @@@@@@@@@@@@@@@@  
 @@@@@@@@@@@@@@@@  
 @   @@@  @@@   @  
 @ @@ @ @@ @ @@@@  
 @   @@ @@@@ @  @  
 @ @@@@ @@ @ @@ @  
 @ @@@@@  @@@  @@  
 @@@@@@@@@@@@@@@@  
  @@@@@@@@@@@@@@   
   @@@@@@@@@@@@    
         @@@       
         @@        
         @         
                   
```
 
This is probably the shortest code with which you can actually still recognize the logo... I created a terrible language :(
Try it [here](https://dl.dropboxusercontent.com/u/10914578/Bitshift.html)
**Note**  
This was submitted before the rules were changed, by the current rules this answer is invalid. I will leave it here to perhaps inspire people
[Answer]
# JavaScript
*Note: This answer was made before the rules were **significantly** changed so this answer is **not** competing.*
---
This prints in into the your browser console, through some crazy and awesome string processing.
I've made a shorter version of this but I can't seem to find it anywhere.
**Chrome/Firefox**
This version just doubles up on each pixel so it looks more proportional
```
var a = `<long_string_here>`;
console.log.apply(console, [].concat.apply( [Array(+a.split('\n')[1].split(' ')[1] ).join(' ').split(' ').map(function(l){return'%c█'.repeat(+a.split('\n')[1].split(' ')[0]).repeat(2)}).join('\n')], a.split`
`.slice(3).map(function(l){return [].concat.apply([], l.match(/\d+ \d+ \d+/g).map(function(l){return [l.replace(/(\d+) (\d+) (\d+)/,"color:rgb($1,$2,$3)"),l.replace(/(\d+) (\d+) (\d+)/,"color:rgb($1,$2,$3)")]}))})))
```
**Safari**
```
var a = `<long_string_here>`;
console.log.apply(console, [].concat.apply( [Array(+a.split('\n')[1].split(' ')[1] ).join(' ').split(' ').map(function(l){return'%c█'.repeat(+a.split('\n')[1].split(' ')[0])}).join('\n')], a.split`
`.slice(3).map(function(l){return l.match(/\d+ \d+ \d+/g).map(function(l){return l.replace(/(\d+) (\d+) (\d+)/,"color:rgb($1,$2,$3)")})})))
```
---
The `long_string_here` is an *ppm*, I wrote this script a while back to print an arbitrary image **to the console**.
---
How does this work? Well JavaScript has a feature in `console.log` where you can provide css to style the message. 
I the unicode character `█` and color that the correct color, which is retrieved from the ppm.
---
To display any other image run: `convert my_img.png -resize 50x50 -trim -compress none -blur 1x2 -flatten -background white ppm:-`, then copy the output to `<long_string_here>`
### Full code
Because this is quite massive, I've put the full code in pastebins so you can run them
**Chrome/Firefox:** [pastebin](http://pastebin.com/raw.php?i=YyNJdfDk)
**Safari:** [pastebin](http://pastebin.com/raw.php?i=3RiRqbeH)
---
## Result
[![enter image description here](https://i.stack.imgur.com/fdM3s.png)](https://i.stack.imgur.com/fdM3s.png)
[Firefox Result](https://i.stack.imgur.com/OTMdd.png)
[Safari Result](https://i.stack.imgur.com/jSOhU.png)
[Answer]
# Ruby with Shoes
```
zoom = 10
Shoes.app(width: 19 * zoom, height: 18 * zoom) {
    background white
    stroke fill '#62B0DF'
    rect 1 * zoom, 1 * zoom, 17 * zoom, 13 * zoom, 3 * zoom
    skew 0, -45
    rect 10 * zoom, 11 * zoom, 5 * zoom, 4 * zoom
    stack(left: 1 * zoom, top: 3 * zoom) {
        para('PCG').style size: (5.66 * zoom).to_i, weight: 700, stroke: white
    }
}
```
Sample output:
![PPCG logo drawn with Shoes](https://i.stack.imgur.com/5fw7R.png)
[Answer]
## Javascript (ES2015), 199 bytes
*(+72 bytes of CSS)*
My code prints the logo into the `<body>` element of a page through some unicode sequences. Suggestions improving the code are welcome (especially for `0`-pads task)
> 
> Demo (tested on MacOsX/Chrome 46): <http://codepen.io/anon/pen/EVBmKN?editors=011>
> 
> 
> 
---
**Javascript** 
(newlines inserted for readability)
```
f=l=>{for(l of[49155,0,0,0,29070,19024,29206,16978,16780,0,0,32769,49155,65311,
65343,65407].map(r=>(1e15+r.toString(2)).slice(-16)))document.body.innerText+=
[...l].map(b=>["▉", " "][b]).join``+"\n"}
```
**CSS**
```
*{letter-spacing:-.1em;font:1em/.96 arial;white-space:pre;color:#62B0DF}
```
---
**Result**
[![PCG Logo](https://i.stack.imgur.com/fP8fn.png)](https://i.stack.imgur.com/fP8fn.png)
---
**Ungolfed and Explained**
If we consider the original 16x16 PCG icon originally posted, we could encode the information in a binary format. 
E.g. the first line would be encoded as `1100 0000 0000 0011` where `[0, 1]` maps to `[blue, white]`. Every binary number can be easily stored in decimal format so `1100 0000 0000 0011` is `49155`. The array
```
[49155,0,0,0,29070,19024,29206,16978,16780,0,0,32769,49155,65311,65343,65407]
```
contains all the information (in decimal format) about each pixel color. Each element of the array represents a line to draw. Note that some lines are `0` (full-blue lines) or their length is less than `16` digits (a line starting with a blue pixel): then we need to right-pad these binary numbers
```
[...].map(r=>(1e15+r.toString(2)).slice(-16))
```
The `map` function add 15 zeroes to the left plus the binary number concatenated. Thus the result is sliced by `16` pixel to the left. Now the array is actually
```
0:  "1100000000000011"
1:  "0000000000000000"
2:  "0000000000000000"
3:  "0000000000000000"
4:  "0111000110001110"
5:  "0100101001010000"
6:  "0111001000010110"
7:  "0100001001010010"
8:  "0100000110001100"
9:  "0000000000000000"
10: "0000000000000000"
11: "1000000000000001"
12: "1100000000000011"
13: "1111111100011111"
14: "1111111100111111"
15: "1111111101111111"
```
Take a look closer at the digits above: we can almost see the PCG logo. :)  
*Note that if we store this information in the array, we need to use 16x18 bytes (288 bytes). This approach requires instead 135 bytes*
The next step is draw each line. The construct
```
for(l of [...].map(...))
```
loop over the array `values` (ES6 feature) and we add to the body
```
document.body.innerText += [...l]
```
where `[...l`] represent the binary string as an array . E.g. the first line would be read as 
```
["1", "1", "0", "0" ... , "0", "0", "1", "1"]
```
then again we use `map()` to transform each value:
```
 b=>["▉", " "][b]
```
if the value is `0` then it becomes a `LEFT SEVEN EIGHTHS BLOCK (U+2589)` otherwise it is a space `EM SPACE (U+2003)`. In short this assignment 
```
document.body.innerText += [...l].map(b=>["▉", " "][b]).join``+"\n"
```
converts each `0` or `1` either into a squared block or into a space: then the array is joined and, along with a trailing newline sequence, is appended to the body.
The CSS I've used fixes the `line-height` and the `letter-spacing` (I've tested on Chrome, so the result may slightly vary in other browsers)
[Answer]
# Brainfuck, 120148 bytes
### This answer is now non-competitive. This was before the rules were changed, and this has absolutely no hope of winning as code-golf.
Brainfuck code to output hex value of image. Very, very, long.
Here is a pastebin link, and the first couple lines.
<https://paste.ee/p/LtcCy>
```
+[--------->+<]>-.+.----.-----.++++.-[--->++++<]>+.>-[----->+<]>+.+++.-------.--[-->+++<]>-.+[--->++<]>++.[--->++++<]>+.-[---->+++<]>+.-[--->++++<]>+.-[---->+++<]>.[--->++++<]>+.-[---->+++<]>.......--[-->+++<]>-.[---->+++<]>+.+++++.-----.++++.----..+.---.--......+.++.---......+.+.--.++++++++.--------.++++++.------......----[-->+++<]>.---------.---------.--[-->+++<]>--.++.-[------>+<]>-.+.+++.---------....+.+++++++.------.+++.+.+++.-----.-.+.-.++.-----.++++.+++++.-----.-.+.-.-.--.+++++.-----.+++++++.-----.++++.[->++++++<]>++.--[------>+<]>...+++.-- 
```
[Answer]
# [Snap](http://snap.berkeley.edu/snapsource/snap.html#open:http://snap.berkeley.edu/snapsource/tools.xml), 16 blocks
![enter image description here](https://i.stack.imgur.com/xSTGM.jpg)  
Tell me if this is invalid.
[Answer]
# Javascript ES6, 461 bytes
I need to work on the compression more.
```
x.style.cssText='display:block;font:4px/2px monospace;color:#62B0DF',x.innerHTML=`  28
 38
 31
${a=`5
`.repeat(8)}6   a   a    7
6  8  8 8  8  8  6
6  8  +  7  71
6      +9 6
6  a9 6
6  6a 8  1 6
698   +  6
6  7+   1+    7
${a} 31
 38
  3+
   28
47
46
41+
41
48
4+`[r='replace'](/a/g,'  1')[r](/9/g,'  7  +  ')[r](/8/g,'++')[r](/7/g,11)[r](/6/g,'1++')[r](/5/g,'31+')[r](/4/g,Array(18).join` `)[r](/3/g,21)[r](/2/g,11111111)[r](/1/g,'+++')
```
```
<pre id=x></pre>
```
[Answer]
# [Bubblegum](https://esolangs.org/wiki/Bubblegum), 175 bytes
One of the rare times Bubblegum is useful for [graphical-output](/questions/tagged/graphical-output "show questions tagged 'graphical-output'")!
Run in a terminal that supports ANSI escape codes.
```
0000000: e060 3e00 a75d 000d 97c4 b1da c813 35e1  .`>..]........5.
0000010: 9ebb 75d8 b95a ea28 a23d e9c6 5d80 7ce0  ..u..Z.(.=..].|.
0000020: 8d72 884f 2eb0 23f0 a6dc 406b 5724 9b78  .r.O..#...@kW$.x
0000030: 229d 11b7 29c8 9be6 7b76 26d4 f41a 69e0  "...)...{v&...i.
0000040: e626 1923 061a 07fc 4ca6 3cc9 f947 7760  .&.#....L.<..Gw`
0000050: 86df 1d86 37a8 6825 dd9d a3b4 a050 573c  ....7.h%.....PW<
0000060: 7efa 920a 446d 98f8 eeb9 91f7 f912 ca3b  ~...Dm.........;
0000070: 9360 ddba 3450 30ff cee0 fb32 31d1 06cd  .`..4P0....21...
0000080: 0d46 2f2d 5371 896c 6bb0 5fb8 3d6d f096  .F/-Sq.lk._.=m..
0000090: 67e9 8cb8 f92f 9eaa 7d35 0914 a742 6315  g..../..}5...Bc.
00000a0: 1a62 f54d b969 b980 c832 8a3f 8c00 00    .b.M.i...2.?...
```
Reverse the hexdump with `xxd -r`
Here's a screenshot of output:
[![Screenshot of program output](https://i.stack.imgur.com/aGYf1.png)](https://i.stack.imgur.com/aGYf1.png)
Note: On my Windows machine with the MinGW terminal, the Windows Python binary [doesn't output ANSI codes correctly](http://prntscr.com/97ogkg) so the above was `python <esolangs reference implementation>.py <infile> | cat` but it should work correctly on Linux machines.
[Answer]
## Javascript (ES6), 192 bytes
```
document.body.innerHTML='<svg><path fill=#62B0DF d="'+"m01Q0010L60Q7071L74Q7565L55L37L35L15Q0504z".split('').map(v=>v*20||v).join(" ")+'"/><text y=65 fill=#FFF style="font:38pt arial">\xa0PCG'
```
This takes a compressed version of a SVG D path. Spaces are removed, so all arguments have to be a single decimal, so any number is multiplied by 20 before being written to the actual svg.
Output:  
[![enter image description here](https://i.stack.imgur.com/Fwk1A.png)](https://i.stack.imgur.com/Fwk1A.png)  
Demo: <https://jsfiddle.net/Luy6qj80/>
[Answer]
# [LibreLogo](https://help.libreoffice.org/Writer/LibreLogo_Toolbar#LibreLogo_programming_language), ~~122~~ ~~116~~ 115 bytes
> 
> Using [Logo](https://en.wikipedia.org/wiki/Logo_(programming_language)) to create a [Logo](https://i.stack.imgur.com/6Tpou.png). Does this count as recursion?
> 
> 
> 
**Code:**
```
fontsize 20 fontcolor [3]fontweight "bold pc [24]fc 6402271 bk 40 rt 45 fd 40 fill home rectangle[64,52,5]text "PCG
```
**Result:**
[![enter image description here](https://i.stack.imgur.com/kquCt.png)](https://i.stack.imgur.com/kquCt.png)
**Explanation:**
```
fontsize 20             ; Font Size   = 20pt
fontcolor [3]           ; Font Color  = white
fontweight "bold        ; Font Weight = bold
pc [24]                 ; Pen Color   = invisible
fc 6402271              ; Fill Color  = #61B0DF
bk 40                   ; Move Back 40pt
rt 45                   ; Turn Clockwise 45 Degrees
fd 40                   ; Move Forward 40pt
fill                    ; Close and Fill the Line Shape
home                    ; Reset Initial Turtle Settings and Position
rectangle[64,52,5]      ; Draw a Rectangle with Rounded Corners
text "PCG               ; Set Text of the Actual Drawing Object as "PCG"
```
**Previous Attempts:**
116 Bytes:
```
fontsize 20 fontcolor [3]fontweight "bold pc [24]fc 0x61b0df bk 40 rt 45 fd 40 fill home rectangle[64,52,5]text "PCG
```
122 Bytes:
```
ht fontsize 20 fontcolor [3]fontweight "bold pc [24]fc [97,176,223]bk 40 rt 45 fd 40 fill home rectangle[64,52,5]text "PCG
```
[Answer]
# JavaScript, 680 bytes
Well, I had this already finished for the original contest, which rules were changed drastically. This is definitely not the shortest code you can come up with. It was designed for the popularity contest and it creates the original favicon pixel by pixel. It has some more features, too. :)
```
f=c=>{x=(d=document).body.appendChild(d.createElement`canvas`).getContext`2d`;if(c.b)x.scale(4,4);x.fillStyle=c.m?'#2d2d2d':'#62b0df';x.fillRect(0,0,16,16);x.fillStyle='#fff';for(i=0;i<(w=[0,0,1,0,14,0,15,0,0,11,15,11,0,12,1,12,14,12,15,12,0,13,1,13,2,13,3,13,4,13,5,13,6,13,7,13,11,13,12,13,13,13,14,13,15,13,0,14,1,14,2,14,3,14,4,14,5,14,6,14,7,14,10,14,11,14,12,14,13,14,14,14,15,14,0,15,1,15,2,15,3,15,4,15,5,15,6,15,7,15,9,15,10,15,11,15,12,15,13,15,14,15,15,15,1,4,2,4,3,4,7,4,8,4,12,4,13,4,14,4,1,5,4,5,6,5,9,5,11,5,1,6,2,6,3,6,6,6,11,6,13,6,14,6,1,7,6,7,9,7,11,7,14,7,1,8,7,8,8,8,12,8,13,8,]).length;i++)(t=a=>setTimeout(_=>x.fillRect(w[a++],w[a++],1,1),(c.a||0)*i))(i++)}
```
You can call the function with up to three parameters:
```
f({});
f({m:true});
f({b:true});
f({a:50});
f({m:true,b:true,a:50});
```
`m` goes *meta* and changes the color accordingly. And if you find it to small, use `b` to supersize it from *16x16px* to *64x64px*. Finally `a` animates the logo, like it is engraved into a blue board. The value is the speed for each animation step.
**Ungolfed**
```
f=c=>{
    x=(d=document).body.appendChild(d.createElement`canvas`).getContext`2d`;
    if (c.b) x.scale(4,4);
    x.fillStyle = c.m?'#2d2d2d':'#62b0df';
    x.fillRect(0,0,16,16);
    x.fillStyle='#fff';
    for(i=0;i<(w=[0,0,1,0,14,0,15,0,0,11,15,11,0,12,1,12,14,12,15,12,0,13,1,13,2,13,3,13,4,13,5,13,6,13,7,13,11,13,12,13,13,13,14,13,15,13,0,14,1,14,2,14,3,14,4,14,5,14,6,14,7,14,10,14,11,14,12,14,13,14,14,14,15,14,0,15,1,15,2,15,3,15,4,15,5,15,6,15,7,15,9,15,10,15,11,15,12,15,13,15,14,15,15,15,1,4,2,4,3,4,7,4,8,4,12,4,13,4,14,4,1,5,4,5,6,5,9,5,11,5,1,6,2,6,3,6,6,6,11,6,13,6,14,6,1,7,6,7,9,7,11,7,14,7,1,8,7,8,8,8,12,8,13,8,]).length;i++)
        (t=a=>setTimeout(_=>x.fillRect(w[a++],w[a++],1,1),(c.a||0)*i)
        )(i++);       
}
```
**Output**
*Default*
![PPCG Favicon reproduction](https://i.stack.imgur.com/E5JB1.png)
*Animated*
![PPCG Favicon reproduction animated](https://i.stack.imgur.com/0uhvS.gif)
[Answer]
# Python 3, 10,069 bytes
Writes the hex from the original logo to a new file.
```
with open('test.png', 'w+b') as image_file:
    for line in ['\x89PNG\r\n', '\x1a\n', '\x00\x00\x00\rIHDR\x00\x00\x00\x13\x00\x00\x00\x12\x08\x06\x00\x00\x00\xb9\x0c\xe5i\x00\x00\n', '\xa3iCCPICC Profile\x00\x00H\x89\x95\x97\x07T\x13\xe9\x16\xc7\xbf\x99I/\x94\x04"\x9d\xd0;R\x04\x02H\xaf\xa1\x08\xd2\xc1FH\x02\t%\x84@\x10\xb1#\xe2\n', '\xac\x05\x15\x91bAW)\n', "V@\xd6\x82\x88baQ\xec}A\x16\x01u],\xd8Py\x03<\xc2{\xef\xbc=\xef\xbc{\xce\x9d\xf9\x9d{\xee\xfc\xe7\xce7\xf3\x9d\xf3\x1f\x00(]\x1c\xb18\x15V\x00 M\x94%\t\xf3\xf3d\xc6\xc4\xc61\xf1\xbf\x03\x02\xc0\x00\x1ap\x02\xca\x1cn\xa6\xd8#44\x08\xfcm|\xbc\x07\xa0\x89\xf3m\x8b\t\xad\xbf\xef\xfb\xaf\xa1\xc8\xe3gr\x01\x80BQN\xe0er\xd3P>9\x91\\\xb1$\x0b\x00D\x80\xd6\xf5\x96f\x89'\xb8\x18e%\t: \xca{'8i\x8aONp\xc2\x14_\x99\xec\x89\x08\xf3B\xf9\t\x00\x04\n", "\x87#I\x02\x80<\x84\xd6\x99\xd9\xdc$T\x87B@\xd9J\xc4\x13\x8aPf\xa1\xec\xca\x15px(\xe7\xa0l\x9e\x96\x96>\xc1\x07P6N\xf8\x17\x9d\xa4\x7f\xd3L\x90ir8I2\x9ez\x96\xc9 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'\xf9@AP\x18\x14\x0b\xc5CI\x90\x08\x92B+\xa0uP\x11T\x02\x95C\xfb\xa0Z\xe8\x18t\x1a\xba\x00]\x85z\xa0\x87P\x1f4\x0c\xbd\x83\xbe\xc2\x08L\x81\x95`M\xd8\x10\x9e\r\xb3`\x0f8\x10\x8e\x80\x17\xc1Ip\x06\x9c\x0b\xe7\xc3\x9b\xe02\xb8\x1a>\x0c7\xc1\x17\xe0\xeb\xf0]\xb8\x17~\x05\x8f"\x00!#\x0cD\x07\xb1@X\x88\x17\x12\x82\xc4!\x89\x88\x04Y\x85\x14"\xa5H5\xd2\x80\xb4"\x9d\xc8m\xa4\x17y\x8d|\xc1\xe00t\x0c\x13c\x81q\xc6\xf8c"1\\L\x06f\x15\xa6\x18S\x8e\xa9\xc14a:0\xb71}\x98\x11\xcc\x0f,\x15\xab\x815\xc3:a\xd9\xd8\x18l\x12v)\xb6\x00[\x8a=\x88=\x85\xbd\x84\xbd\x8b\x1d\xc0~\xc4\xe1p\x0c\x9c\x11\xce\x01\xe7\x8f\x8b\xc5%\xe3\x96\xe3\x8aqU\xb8F\\\x1b\xae\x07\xd7\x8f\x1b\xc5\xe3\xf1\xaax3\xbc\x0b>\x04\xcf\xc1g\xe1\x0b\xf0\xbb\xf0\x87\xf1\xe7\xf1\xb7\xf0\x03\xf8\xcf\x042A\x9b`C\xf0%\xc4\x11D\x84<B)\xa1\x8ep\x8ep\x8b0H\x18#*\x10\r\x88N\xc4\x10"\x8f\xb8\x8c\xb8\x99x\x80\xd8J\xbcA\x1c \x8e\x91\x14IF$\x17R\x04)\x99\xb4\x96TFj ]"=!\xbd\'\x93\xc9\xbadG\xf2|\xb2\x90\xbc\x86\\F>J\xbeB\xee#\x7f\xa1\xd0(\xa6\x14/\xcaB\x8a\x94\xb2\x89r\x88\xd2FyHyO\xa5R\r\xa9\xee\xd48j\x16u\x13\xb5\x96z\x91\xfa\x8c\xfaY\x8e.g)\xc7\x96\xe3\xc9\xad\x96\xab\x90k\x92\xbb%\xf7F\x9e(o \xef!\xbfX>W\xbeT\xfe\x84\xfc\r\xf9\xd7\n', 'D\x05C\x05/\x05\x8e\xc2*\x85\n', '\x85\xd3\n', 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'OK\x9fi<\xab\xfe\xdd\xe4\xf7\xc6^\xfb\xde\xb3}\xde}]\xcf\xc3\x9f?\xee\xe7\xf6\xbf\xfa#\xf3\x8fo\x03\xf9/\xa8/J\x07\xb5\x07k\x87l\x86\xce\x0c\xfb\x0e\xdf|\xb9\xe0\xe5\xc0+\xf1\xab\xb1\xd7\x05\x7f*\xfeY\xf9\xc6\xf8\xcd\xc9\xbf\xdc\xff\xea\x1a\x89\x19\x19x+y;\xfe\xae\xf8\xbd\xea\xfbC\x1f\xe6|h\x1f\r\x1d}\xf61\xed\xe3\xd8\xa7\xc2\xcf\xaa\x9fk\xbe\xb0\xbet~\x8d\xfe:8\xb6\xf4\x1b\xfe[\xd9w\x93\xef\xad?\x02\x7f<\x19O\x1b\x1f\x17s$\x9cI+\x80\xa0\t\'&\x02\xf0\xee\x10\x00\xd4X\xd4+\xdc\x04\x80$7\xe5\x8b\'\x03\x9a\xf2\xf2\x93\x04\xfe\x8e\xa7\xbc\xf3d\xd8\x03\xb0\xbf\r\xf5"(\x06\xa0^\xa4j\r\x00\x06(\xd3\xd0\x9c\xb0E\x11\xee\x00\xb6\xb5\x95\xe5?#3\xd1\xd6fJ\x8b\x82\xbaK\xec\xe7\xf1\xf1\xf7\x9a\x00\xe0[\x01\xf8.\x19\x1f\x1f\xab\x1a\x1f\xff\x8e\xfao\xe4!\x00m\x19S~|"p\xe8_J\x89:\x0cUyv0\x13\xc1\x7f\xc6?\x00\xea\xa4\xff\x86H\x07*\xad\x00\x00\x01\x9biTXtXML:com.adobe.xmp\x00\x00\x00\x00\x00<x:xmpmeta xmlns:x="adobe:ns:meta/" x:xmptk="XMP Core 5.4.0">\n', '   <rdf:RDF xmlns:rdf="http://www.w3.org/1999/02/22-rdf-syntax-ns#">\n', '      <rdf:Description rdf:about=""\n', '            xmlns:exif="http://ns.adobe.com/exif/1.0/">\n', '         <exif:PixelXDimension>19</exif:PixelXDimension>\n', '         <exif:PixelYDimension>18</exif:PixelYDimension>\n', '      </rdf:Description>\n', '   </rdf:RDF>\n', '</x:xmpmeta>\n', '\x92\xfc\xe9\xf6\x00\x00\x01\xdcIDAT8\x11\xad\x94\xdfM\x1cA\x0c\xc6?\xcf\xcc\xbe\x11@\xa9 u\xa0\x1c\xa2\x03\x8aH\x0b\x89\x94\x16\x82\xeeJ\xa0\x88T\x90\x874\x92\xe7D,\xdc\xf3\xee\x8c\xf9ya\xc2\xe9 \x12\x87\xe2\x95\xd6\xf3\xc7\xfe\xc6\x1e\x7fc\xbb\xbb\xbdu7W\xae\xae)\x15e\xb9Rn\x9a\xbdH6+M\xae6\x984I%\x9bfK\x12\xb6B\xbb5\x15g?\x99Z5\xc6\x8b\xfb\xa4Z\x92\xbe\xfc\x18u\x88\xacW\xa7\x80\x9aR\xe3\xb08\xfbf\xbb\xf5CA\xf6\x0f\xdc\x9c\xbfW\xf6\x16\x19\xd5\xfd\xbd\x83\xe7$\xaaVH\x93+\xfa\x0f\xc2=G\xa6\x1e\xf9"\xd7\x97\x1f\x16\x1d\xbfO\xdf\x7f\xfd\x1d\xf7\xf5\x97\xd6\xba-\xa5\x90G\x01Z\xa6:\x8f\xd2\x1d\x02 \xc6]\xc7v\x1fw\xdd}\x1et\xa2\xcaN\x9a\x94\xb7K\x18\x86t\xd0e\xf2\xf8\xdb_\xdb\xb5\r\x8a\xc0&\n', '\xe0\x0fiv\x90}\xa7\x0e\xd8\x9d\xfb|\xd7\xce=\xc3\xcb\x14<{\x8a\xac\x1bv\x1d\x0e\x1d\xa4;\xbf\xb4\x96\xa2\x88\xfcl\xbc\x19\xfd\xf3\xcfm\xf7\x7f\x93\xde\\\x1c\xa9R\xc8\xd2\xd2\xbf#{-rk\x03\xa4\x85\x1e\xaaI\xeb\x8f\'\xaf\xf5{f\xf7-|\t\xc8\xad*%\xee\xac\xc2\xde\xcd\xeap\xc0\xab\xf3\xd3x\x9aD\x14<\xcb\xb2\xdft\x8d<U\xd9@\x90\x00\x1b\x1d!\xca\xbc\x14\x19\x0e\xce\x0c\xbe\xee\xdc\xe9\xd5\xea\x1dl"\x00\x1f\x82\n', '\xf2\xb8x|\x88Me\x98]\x80\xaaE\xce\xf0\xc5(s\xe5\x13@\xf4&N}\x92\xf5\xea\x88\t\xb9\x10\xce\x90*\xfb\x94q\xc6>\xb8J\x8eeyM\xac\xe5\x16,6e\x98\x9chK\xd1\xb2\xc28\xee"d}v\xbc\x90(z\x9f\xe1\x14Y\x84\xa5\x91F\x99y\xe2t\r\xfb3\x8e\xd0\x8d-\xc0"\xf7\x16\xa4\xe1\x9d1\xa4\x19\xbaf\x80\x97\xce\xb2DOTX+s\xd9\x14N\x98Y#3\x0e\x8b\xfey\x0f\x08\xf5\xf5\xc8\xe0\xdd\\\x98\x00\x00\x00\x00IEND\xaeB`\x82']:
        image_file.write(line)
```
[Answer]
# R, 189 bytes
```
image(t(matrix(as.integer(sapply(c(32736,28784,62968,62968,64504,65528,63736,63352,63359,64254,65532,63736,63352,62840,29936,32736),intToBits)[1:16,]),nr=16)),ax=F,col=c("white","#62B0DF"))
```
With indents for clarity:
```
image(t(matrix(as.integer(sapply(c(32736,28784,62968,62968,
                                   64504,65528,63736,63352,
                                   63359,64254,65532,63736,
                                   63352,62840,29936,32736),
                                 intToBits)[1:16,]),nr=16)),
      ax=F,col=c("white","#62B0DF"))
```
I'm shamelessly stealing the method from an [old answer of mine](https://codegolf.stackexchange.com/a/19298/6741): I take the base-2 representation of 16 numbers, make it into a 16x16 matrix of 1s and 0s and plot it as is.
[![Screenshot of the result](https://i.stack.imgur.com/kaJmL.png)](https://i.stack.imgur.com/kaJmL.png)
[Answer]
# [Google Blockly](https://blockly-games.appspot.com/turtle?lang=en&level=10), 140 blocks
[![input](https://i.stack.imgur.com/FsdwM.png)](https://i.stack.imgur.com/FsdwM.png)
Produces
[![Output](https://i.stack.imgur.com/SV2Gm.png)](https://i.stack.imgur.com/SV2Gm.png)
Will add an explanation if requested. Try it [here](https://blockly-games.appspot.com/turtle?lang=en&level=10#vi76iz)
Suggestions to reduce the massive function on the left are welcome!
[Answer]
# Python 2, 211 bytes
```
from PIL import Image
I=Image.new('P',(16,16))
I.putdata(map(int,bin(eval('0xc003'+'0'*12+'718e4a5072164252418c'+'0'*8+'8001c003ff1fff3fff7f'))[2:]))
I.putpalette([111,174,221]+[255]*3)
I.resize((64,64)).show()
```
[Answer]
# [05AB1E](https://github.com/Adriandmen/05AB1E), 49 bytes
```
•(!o4¯ZD5µå¹p‹^Ô%í2\AO-Ö"w™ÈõžvlXäà`AF•bT„.@‡19ô»
```
[Try it online!](https://tio.run/nexus/05ab1e#AU4Asf//4oCiKCFvNMKvWkQ1wrXDpcK5cOKAuV7DlCXDrTJcQU8tw5Yid@KEosOIw7XFvnZsWMOkw6BgQUbigKJiVOKAni5A4oChMTnDtMK7//8 "05AB1E – TIO Nexus")
```
...@@@@@@@@@@@@....
.@@@@@@@@@@@@@@@@..
.@@@@@@@@@@@@@@@@..
.@@@@@@@@@@@@@@@@..
.@...@@@..@@@...@..
.@.@@.@.@@.@.@@@@..
.@...@@.@@@@.@..@..
.@.@@@@.@@.@.@@.@..
.@.@@@@@..@@@..@@..
.@@@@@@@@@@@@@@@@..
..@@@@@@@@@@@@@@...
...@@@@@@@@@@@@....
.........@@@.......
.........@@........
.........@.........
```
[Answer]
# Excel VBA, ~~252~~ ~~246~~ ~~245~~ 237 Bytes
Saved 6 bytes thanks to Taylor Scott.  
Saved another 8 bytes thanks to inspiration from Taylor Scott
```
Sub p()
Set s=Shapes.AddShape(106,0,0,99,82)
With s.TextEffect
.Text="PCG
.FontSize=56
.Alignment=2
End With
s.TextFrame2.WordWrap=0
s.Adjustments.Item(1)=.1
s.Adjustments.Item(2)=.9
s.Line.Visible=0
s.Fill.ForeColor.RGB=14659682
End Sub
```
The code must be run from a worksheet's code page and will add the shape to that worksheet. It's nothing fancy but it does directly use the rounded rectangular callout upon which the icon is based. (For `AddShape`, `106` corresponds to `msoShapeRoundedRectangularCallout`.)
[![Icon](https://i.stack.imgur.com/a8HuI.png)](https://i.stack.imgur.com/a8HuI.png)
Formatting doesn't add much but it does make it easier to read:
```
Sub p()
    Set s = Shapes.AddShape(106, 0, 0, 99, 82)
    With s.TextEffect
        .Text = "PCG"
        .FontSize = 56
        .Alignment = 2
    End With
    s.TextFrame2.WordWrap = 0
    s.Adjustments.Item(1) = 0.1
    s.Adjustments.Item(2) = 0.9
    s.Line.Visible = 0
    s.Fill.ForeColor.RGB = 14659682
End Sub
```
There's also a one-line solution meant to be run in the immediate window that is 1 byte longer:
```
Set s=Sheet1.Shapes.AddShape(106,0,0,99,82):s.TextEffect.Text="PCG":s.TextEffect.FontSize=56:s.TextEffect.Alignment=2:s.TextFrame2.WordWrap=0:s.Adjustments.Item(1)=.1:s.Adjustments.Item(2)=.9:s.Line.Visible=0:s.Fill.ForeColor.RGB=14659682
```
[Answer]
# MATLAB, ~~153 150~~ 140 bytes
```
a=65535;imshow(imresize(dec2bin([16380,a,a,a,36465,46511,36329,48557,48755,a,a,32766,16380,32*[7 6 4]],16)-47,8,'n'),[1 1 1;0.39 0.69 0.88])
```
The code takes an array of 16bit numbers (sadly there is no way of encoding them that reduces the byte count apart from reading from a presaved binary file). EDIT: With a little bit of creativity in how the array is made, I've saved 3 bytes, and with a little bit more and an extra variable, I can save another 10 on top of that.
With this array, it is converted to a binary string where an ascii '1' represents blue and an ascii '0' is white. The array is 2D at this point because each of the 16 numbers becomes a 16 character string.
I subtract 47 to convert this into an array of 1's and 2's (needed for the next bit), where each element represents one pixel. Again this remains as 2D and is our image data.
The image is then scaled up by a factor of 8 using nearest neighbour to produce an image which is at least the required 64x64px minimum size - in fact it is 128x128 because somehow I divided 64 by 16 to get 8 >\_< (don't ask!).
Finally this is displayed using a colour map where any 1 becomes white and any 2 becomes the required #62B0DF shade of blue.
This is the output:
[![Logo](https://i.stack.imgur.com/SD0EX.png)](https://i.stack.imgur.com/SD0EX.png)
[Answer]
## Processing, 211 bytes
```
noStroke();int[]n={49155,0,173175182,1245866062,12674,-2147418112,-117456893,-16777985};for(int x=0;x<256;x++){if(((n[floor(x/32)]>>(x%32))&1)>0)fill(255);else fill(98,176,223);rect(4*(x%16),4*floor(x/16),4,4);}
```
Storing the pixels inside signed integers (seems to be the most efficient way, I'll maybe try 2^64 integers) and then printing them in a frame.
[![enter image description here](https://i.stack.imgur.com/TLFma.png)](https://i.stack.imgur.com/TLFma.png)
[Answer]
# Swift (Playground), 599 Bytes
```
import UIKit;class P:UIView {var b=UIBezierPath();func a(x:CGFloat,y:CGFloat){b.addLineToPoint(CGPoint(x:x,y:y))};override func drawRect(rect:CGRect){UIColor(red:0.384,green:0.690,blue:0.875,alpha:1).setFill();UIBezierPath(roundedRect:CGRectMake(0,0,200,159),cornerRadius:45).fill();b.moveToPoint(CGPoint(x:102, y:146));a(102,y:200);a(157,y:146);a(102,y:146);b.closePath();b.fill();"PCG".drawInRect(CGRectMake(35,41,200,121),withAttributes:[NSFontAttributeName: UIFont(name:".AppleSystemUIFontBold",size: 64)!,NSForegroundColorAttributeName:UIColor.whiteColor()])}}
P(frame: CGRectMake(0,0,200,200))
```
I decided to give it a go, since drawing in Swift is pretty straightforward, and it's not usually golfed like this. Ended up loosing precious bytes with the text... Damn you `NSDescriptiveVariableNames`!
Here's how it looks in the playground:
[![Result](https://i.stack.imgur.com/XYlYl.png)](https://i.stack.imgur.com/XYlYl.png)
I think I could golf it more by aliasing things like `CGRectMake`, grouping objects in the a function etc.
[Answer]
# PHP, 145 bytes, not competing
```
for(;$i<64;)echo strtr(sprintf("%016b\n",[49155,0,0,0,29070,19024,29206,16978,16780,0,0,32769,49155,65311,65343,65407][$i++/4]),["####","    "]);
```
I should use non-blank and colors instead, but I´m too tired atm.  
Guess that will add 10 bytes or so to the count, maybe more.
[Answer]
# Excel VBA, 178 Bytes
Anonymous VBE Immediate window function that takes no input and outputs the PCG Favicon (exactly as in the prompt above) to the range
```
Cells.RowHeight=48:[C1:N13,A2:P11,B12:O12,I14:I16,J14:J15,K14].Interior.Color=&HDFB062:[B5:B9,C5:D5,C7:D7,E6,G6:G8,H5:I5,J6,J8,H9:I9,L6:L8,O7:O9,M5:O5,M9:N9,N7].Interior.Color=-1
```
[![PCG Favicon](https://i.stack.imgur.com/ANHrA.png)](https://i.stack.imgur.com/ANHrA.png)
[Answer]
# [C (gcc)](https://gcc.gnu.org/), 188 bytes
```
y;main(x){int d[]={16380,~0,~0,~0,36465,62893,38833,46525,52861,~0,~0,32766,16380,1792,768,256};for(;y<64;y++){for(x=0;x<16;)printf("\33[48;5;%dm%*s",(d[y/4]>>x++)&1?14:7,8,"");puts("");}}
```
[Try it online!](https://tio.run/##NY3dCoJAFIRfJYRizRO5f2fXjtqDmBehGF5oogaK2KubEsJczAfzMdnllWXLMlL1LGs2uFNZ94c8SaOJo7Q@fPdIVKgBhQ0kSGulhJWFBi0s8n0jDCL8RW4CAQYtCI0zFe@W0RiiotHz3GnDIfJpCDmS27TracGch5SJsqTpmFfHc@cAy5PxqtI4HlbpxO9c3QxYcByXmk/fsa3M87L8AA "C (gcc) – Try It Online")
Uses ANSI escape codes to print 128 horizontal and 64 vertical colored spaces.
[![ANSI PCG](https://i.stack.imgur.com/8167H.png)](https://i.stack.imgur.com/8167H.png)
*(Image resized.)*
[Answer]
## C++ with [SFML](https://www.sfml-dev.org/index.php), 607 bytes
```
#include<SFML\Graphics.hpp>
using namespace sf;using c=Color;using x=Vector2f;RenderWindow w(VideoMode(324,324),"");void p(){RectangleShape r({224.f,144.f});r.setFillColor(c(98,176,223));Vertex v[3]={x(162,324),x(243,224),x(162,224)};for(int i=0;i<3;++i)v[i].color=c(c(98,176,223));Font f;if(!f.loadFromFile("a.ttf"))return;Text t("PCG",f,150);t.setPosition(50,20);while(w.isOpen()){Event e;while(w.pollEvent(e))if(e.type==0)w.close();w.clear(c::White);for(int i=0;i<628;++i){r.setPosition(50+cos(float(i)/100.f)*50,50+sin(float(i)/100.f)*50);w.draw(r);}w.draw(v,3,PrimitiveType(3));w.draw(t);w.display();}}
```
Code that calls the function :
```
int main() {
    w.setFramerateLimit(60);
    w.setVerticalSyncEnabled(true);
    p();
}
```
Requirements :
* You need to have a valid ttf file called `a.ttf` in the current directory where the executable is running, so it can load the fonts to display the text
* You need to have the corresponding SFML DLLs in the current directory where the executable is running
Result :
[![PPGC Icon with C++ and SFML](https://i.stack.imgur.com/TfNyw.jpg)](https://i.stack.imgur.com/TfNyw.jpg)
Explanations :
```
#include<SFML\Graphics.hpp>
using namespace sf;
using c=Color;
using x=Vector2f;
//Create the window that will display stuff. 324x324 dimensions
RenderWindow w(VideoMode(324,324),"");
void p(){
    //Creation of the rectangle
    RectangleShape r({224.f,144.f});
    r.setFillColor(c(98,176,223)); //Logo Color wanted
    //Vertex to draw a blue triangle
    Vertex v[3]={x(162,324),x(243,224),x(162,224)};
    for(int i=0;i<3;++i)
        v[i].color=c(c(98,176,223));
    //Creation an load of the font
    Font f;
    if(!f.loadFromFile("a.ttf"))
        return;
    //Creating the text object that will be used to draw the PCG text
    Text t("PCG",f,150);
    t.setPosition(50,20);
    //Main loop, will run while the window is open
    while(w.isOpen()){
        Event e;
        while(w.pollEvent(e))
            //sf::Event::Close int value is 0
            //It will be triggered if you click on the red cross, or press Alt+F4
            if(e.type==0)
                w.close();
        //Clear the window in white
        w.clear(c::White);
        //6.28 = 2*PI, the number of radians that nearly equals 360 degrees
        for(int i=0;i<628;++i){
            //It draws 628 rectangles, the top left part of the rectangle will do a circle
            //Same for every points of the rectangle
            r.setPosition(50+cos(float(i)/100.f)*50,50+sin(float(i)/100.f)*50);
            w.draw(r);
        }
        //sf::PrimitiveType::Triangle int value is 3
        w.draw(v,3,PrimitiveType(3));
        //Draw the text
        w.draw(t);
        w.display();
    }
}
```
[Answer]
# tcl/tk, 113
```
grid [canvas .c]
.c cr o 2 2 66 48 -f #62B0DF
.c cr t 36 24 -te PCG -fi #FFF
.c cr p 30 66 30 47 44 47 -f #62B0DF
```
# Tcl/tk, 144
```
grid [canvas .c]
.c create oval 2 2 66 48 -fill #62B0DF
.c create text 36 24 -text PCG -fill #FFF
.c create poly 30 66 30 47 44 47 -fill #62B0DF
```
[![pcg logo](https://i.stack.imgur.com/tOZUk.png)](https://i.stack.imgur.com/tOZUk.png)
]