[Question]
  [
Your task is to write a program, that given a list of chat messages, count how many times each person gets pinged, so I can know how popular everyone is. But, since I have to do it surreptitiously, I need it to be as small as possible so I can hide the code.
# Specs
* The input comes in a list of 2-tuples, with each item being of the form `("username", "message")`.
* A ping to another user is defined as an `@` followed by 3 or more letters that unambiguously refers to that user.
* However, you also have to consider replies, which have to start with `:messageid` followed by a space.
* Assume the first message has id `0` and proceed sequentially.
* Output each user and say how many times each one got pinged.
* The output can be in any order/reasonable format.
* This is [code-golf](/questions/tagged/code-golf "show questions tagged 'code-golf'"), so shortest code in **bytes** wins!
# Test Cases
```
[["AlexA.", "I am wrong"], ["Quartatoes", "@Alex you are very wrong"], ["AlexA.", ":1 I am only slightly wrong"]]
AlexA.: 1
Quartatoes: 1
[["Doorknob", "I have never eaten an avocad."], ["AquaTart", ":0 I will ship you an avocad"], ["AlexA.", ":0 this is shocking"]]
Doorknob: 2
AquaTart: 0
AlexA.: 0
[["Geobits", "I like causing sadness through downvotes."], ["Flawr", "I want to put random message ids in my chat messages :0 askjdaskdj"]]
Geobits: 0
Flawr: 0
[["Downgoat", "goatigfs.com/goatgif"], ["Downotherthing", "@Downgoat cool gifs"], ["Dennis", "@Down cool gifs this is an ambiguous ping"]]
Downgoat: 1
Downotherthing: 0
Dennis: 0
```
  
[Answer]
# JavaScript (ES6), ~~245~~ 210 bytes
```
a=>(p={},a.map(b=>p[b[0]]=0),(a.map(b=>b[1].match(/@[a-z]{3,}|^:\d+/gi)||[]).map(c=>c.map(d=>(z=(d[0]=='@'?(y=Object.keys(p).filter(e=>e.startsWith(d.slice(1)))).length<2?y:0:a[d.slice(1)[0]]))&&p[z[0]]++))),p)
```
Uses an object to create a unique list of names alongside pings. Then it looks through the messages for matches to either ping condition. If a name, it looks through the list of names to find if there is only one match, and then increments. If a reply, it simply references that index in the message array and pulls the name to be incremented. Finally, it returns the object.
[Answer]
# PHP, 227 Bytes
```
foreach($_GET[a]as $c){$r[]=&$n[$c[0]]??$n[$c[0]]=0;preg_match("#^(:(\d+)|@(\w+))#",$c[1],$m);$m[2]==""?!$m[3]?:count($a=preg_grep("#^{$m[3]}#",array_keys($n)))>1?:$n[end($a)]++:$r[$m[2]]++;}foreach(($n)as$k=>$v)echo"$k: $v\n";
```
]