[Question]
  [
As we all know, the Zelda series are one of the best game series ever made. In honor of that, let us play some songs on the ocarina.
## Challenge:
Write a program which, given a song, outputs the score to stdout for that particular song.
## Input:
The song which you will have to output the score of will be given by a unique three character combination as seen below:
```
zel - Zelda's Lullaby
sas - Saria's Song
eps - Epona's Song
sos - Sun's Song
sot - Song of Time
sst - Song of Storms
```
**Bonus songs, -7 % each:**
```
mof - Minuet of Forest
bof - Bolero of Fire
sow - Serenade of Water
nos - Nocturne of Shadow
ros - Requiem of Spirit
pol - Prelude of Light
```
**Bonus song 2, -8 %:**
```
scs - Scarecrow's song 
```
As we all know, the Scarecrow's song is a song you compose yourself.
This song needs to have eight notes. Output a score you compose yourself which is different from all the other scores.
If you decide to include all songs, it will total to a -50 % bonus to your byte score.
## Output:
The notes in the output are symbolized by the following characters:
```
^
<
>
V
A
```
Output a score on the following format:
```
-^-^-^-^-^-^-^-^-
-<-<-<-<-<-<-<-<-
->->->->->->->->-
-V-V-V-V-V-V-V-V-
-A-A-A-A-A-A-A-A-
```
Only one note per column is allowed.
For simplicity's sake I've added another row to the original four rows.
Each note correspond to a different row:
```
^: ----------------
<: ----------------
>: ----------------
V: ----------------
A: ----------------
```
Output shall be written to stdout. Trailing newlines are allowed.
## Examples:
**Input (Zelda's Lullaby):**
```
zel
```
**Output:**
```
---^-----^-------
-<-----<---------
----->----->-----
-----------------
-----------------
```
**Input (Bolero of Fire):**
```
bof
```
**Output:**
```
-----------------
-----------------
--------->--->---
-V---V-----V---V-
---A---A---------
```
**Note cheat sheet:**
```
zel
<^><^>
sas
V><V><
eps
^<>^<>
sos
>V^>V^
sot
>AV>AV
sst
AV^AV^
mof
A^<><>
bof
VAVA>V>V
sow
AV>><
nos
<>>A<>V
ros
AVA>VA
pol
^>^><^
```
Since we play the ocarina code golf, the shortest program in bytes wins!
## Song references:
<http://www.thonky.com/ocarina-of-time/ocarina-songs>
<http://www.zeldadungeon.net/Zelda05-ocarina-of-time-ocarina-songs.php>
  
[Answer]
# [Funciton](http://esolangs.org/wiki/Funciton), 4322 − 50% = 2161
Not really trying to golf here. Going more for the beauty angle. I think the main program looks really neat, a perfect rectangular box tucked away on the right.
As always, you can get a better rendering by executing `$('pre').css('line-height',1)` in your browser console.
```
                 ┌─────────────────────────┐
               ┌─┴─╖                     ┌─┴─╖
      ┌────────┤ · ╟─────────────────────┤ · ╟─────────────┐    ╔═════════╗   ╔════╗  ╔════╗
      │        ╘═╤═╝     ╔═════════╗     ╘═╤═╝ ╓───╖       │    ║ 1257283 ║ ┌─╢ 40 ║  ║ 25 ║
      │          │       ║ 2097151 ║       ├───╢ ʫ ╟───┐   │    ║ 6456094 ║ │ ╚════╝  ╚══╤═╝
    ┌─┴─╖        │       ╚════╤════╝     ┌─┴─╖ ╙─┬─╜ ┌─┴─╖ │    ║ 8219021 ║ │  ┌───╖   ┌─┴─╖
┌───┤ · ╟────────┴────┐       └─────┬────┤ · ╟───┴───┤ · ╟─┤    ║ 4660190 ║ └──┤ × ╟───┤ % ║
│   ╘═╤═╝             │            ┌┴┐   ╘═╤═╝       ╘═╤═╝ │    ╚════════╤╝    ╘═╤═╝   ╘═╤═╝
│     │               │            └┬┘     │           │   │    ╔═══╗  ┌─┴─╖  ┌──┴─╖   ╔═╧═╗
│     │  ╔═══╗ ┌────╖ │           ┌─┴─╖ ┌┐ │           │   │    ║ 8 ╟──┤ ʫ ╟──┤ >> ║   ║   ║
│     │  ║ 1 ╟─┤ >> ╟─┘       ┌───┤ ? ╟─┤├─┤           │   │    ╚═══╝  ╘═╤═╝  ╘══╤═╝   ╚═══╝
│     │  ╚═══╝ ╘══╤═╝         │   ╘═╤═╝ └┘ │           │   │    ╔════════════════╧═════════╗
│     │         ┌─┴─╖ ┌───╖ ┌─┴─╖ ┌─┴─╖  ╔═╧═╗         │   │    ║ 609678112368778425678534 ║
│   ┌─┴─────────┤ ʫ ╟─┤ ‼ ╟─┤ · ╟─┤ ‼ ║  ║ 1 ║         │   │    ║ 616189712722605554111376 ║
│   │           ╘═╤═╝ ╘═╤═╝ ╘═╤═╝ ╘═╤═╝  ╚═══╝         │   │    ║ 461573643915077926310571 ║
│   │             │     │     │   ╔═╧══╗               │   │    ║ 355541007599150245813976 ║
│   │   ╔══════╗  │     │     └───╢ 45 ║               │   │    ║ 426564826002362964111793 ║
│   │   ║ 2097 ║  │   ┌─┴─╖ ┌───╖ ╚════╝               │   │    ║ 714054902293682079346275 ║
│   │   ║ 1565 ║  └───┤ · ╟─┤ ♭ ╟─┐                    │   │    ║ 663973372550500581508544 ║
│   │   ╚═╤════╝      ╘═╤═╝ ╘═══╝ ├────────────────────┘   │    ║ 874263187322344354338195 ║
│   │   ┌─┴─╖         ┌─┴─╖       │                        │    ║ 642609790172899326178321 ║
│   │   │ ‼ ╟─────────┤ ? ╟───────┘                        │    ║ 071643306454414932126243 ║
│   │   ╘═╤═╝         ╘═╤═╝                                │    ║ 308860823981077902637848 ║
│ ┌─┴─╖ ┌─┴─╖ ╔═══╗   ┌─┴─╖                                │    ║ 322657399386789617074176 ║
└─┤ · ╟─┤ ʫ ╟─╢ 8 ║ ┌─┤ ? ╟────────────────────────────────┘    ╚══════════════════════════╝
  ╘═╤═╝ ╘═╤═╝ ╚═══╝ │ ╘═╤═╝
    │ ┌───┴╖ ╔════╗ │ ╔═══╗
    └─┤ >> ╟─╢ 21 ║ └─╢ 0 ║
      ╘════╝ ╚════╝   ╚═══╝
```
Continuing in the tradition of giving Funciton functions names consisting of a single, strange, rarely-used Unicode character, I thought about what could best represent this challenge, and it occurred to me that *Link* and *Zelda* (or, if you want, *Legend* of *Zelda*) give you *LZ*, so the lower-case digraph ʫ (U+02AB, ʟᴀᴛɪɴ sᴍᴀʟʟ ʟᴇᴛᴛᴇʀ ʟᴢ ᴅɪɢʀᴀᴘʜ) seems appropriate.
# Explanation
As explained in the esolangs article, the Funciton program receives the input encoded as what I would call “UTF-21”, but as a single humongous integer. If I wanted to use this number as a key to a hashmap (dictionary, associative array), I’d need a hash function that satisfies two criteria: one, it’s simple enough to implement in Funciton, and two, all of the 13 expected input strings give a different hash value. The simplest hash function I could think of was `input % m` for some value of `m`. Therefore, I tried `m` = 13, 14, 15, etc. until I got to the smallest integer for which all the hash values are unique. Turns out this number is 25.
The hash values are:
```
zel =  6
sas = 19
eps = 10
sos = 22
sot =  1
sst =  9
mof = 14
bof =  3
sow = 13
nos = 17
ros = 21
pol = 16
scs = 23
```
We encode each song by having one bit represent the presence or absence of a note. For example, Zelda's Lullaby would be encoded as follows:
```
---^-----^------- = 01001000
-<-----<--------- = 10010000
----->----->----- = 00100100
----------------- = 00000000
----------------- = 00000000
```
except that the bits are in the opposite order; the top left cell is in the least significant bit. This means every song is 40 bits long.
We thus create a (moderately sparse) hash table by taking a 40×25 = 1000-bit number and placing the bit pattern for each song in the right place according to its hash value. The monstrous number in the program is exactly this hash table.
Here’s what each of the remaining numbers mean:
* `45` = `0x2D` is the Unicode for `-`.
* `1257283645609482190214660190`: This is the string `^<>VA` in UTF-21. In hindsight I could have used 7 bits per character here, making the number shorter, but UTF-21 is so deeply traditional in Funciton that it simply didn’t occur to me.
* `2097151` = `0x1FFFFF` = (1 << 21) − 1. Used to get the first character from the above string.
* `20971565`: This is the string `-\n`, which is appended to the end of each line.
	+ It may seem curious that this number and the previous look so similar, but if you think about it, it’s because we’re using decimal and the Unicode for `\n` happens to be 10. That last number is (10 << 21) + 45.
The program now proceeds as follows:
* The main program calls `ʫ` with the following 3 parameters:
	+ *B*: The hash table, shifted right by 40 bits times the hash value of the input. The song we want to output is now in the 40 least significant bits.
	+ *c*: The string `^<>VA`.
	+ *a*: The number 8.
* In each iteration of `ʫ`,
	+ if *c* is not empty,
		- if *a* is not zero, look at the bottom bit of *B*. Output `-`, followed by another `-` if it is zero or the first character of *c* otherwise. Shift right *B* by one to remove one bit and decrement *a*.
		- if *a* is zero, output `-\n`, then chop off the first character from *c* and start another loop with *a* = 8.
	+ if *c* is empty, we are done.
[Answer]
# Python 2, 143.5 (287 bytes - 50%)
```
i='^<>VA'
u=dict(zel="<^>"*2,sas="V><"*2,eps="^<>"*2,sos=">V^"*2,sot=">AV"*2,sst="AV^"*2,mof="A^<><>",bof="VAVA>V>V",sow="AV>><",nos="<>>A<>V",ros="AVA>VA",pol="^>^><^",scs="<"*8)[raw_input()]
r=[17*['-']for _ in[1]*5]
x=0
for g in u:r[i.find(g)][x*2+1]=g;x+=1
for h in r:print''.join(h)
```
The grid is generated with dashes; then indexed and replaced with notes.
[Answer]
# Pyth, 56.5 (113 bytes − 6 × 7% − 8%)
```
VtJ" ^<>VA"+K\-sm+?qNdNKK@LJj@jC"þØí§V^G¤×¹z1«bëë¶ñRõr¤çM"1391423xcs@LGjC"cc0Á:xqç÷\rS  Íó×º:9"lG3z6
```
It contains unprintable characters, so here is a reversible `xxd` hexdump:
```
0000000: 5674 4a22 205e 3c3e 5641 222b 4b5c 2d73  VtJ" ^<>VA"+K\-s
0000010: 6d2b 3f71 4e64 4e4b 4b40 4c4a 6a40 6a43  m+?qNdNKK@LJj@jC
0000020: 2207 fe85 d880 ed0e a756 5e47 8ba4 d7b9  "........V^G....
0000030: 7a9e 0531 ab1b 62eb ebb6 f112 52f5 72a4  z..1..b.....R.r.
0000040: e74d 2231 3339 3134 3233 7863 7340 4c47  .M"1391423xcs@LG
0000050: 6a43 229a 6317 6330 c13a 9278 71e7 10f7  jC".c.c0.:.xq...
0000060: 5c72 5309 87cd f3d7 ba3a 3922 6c47 337a  \rS......:9"lG3z
0000070: 36                                       6
```
You can also [try it online](https://pyth.herokuapp.com/?code=VtJ%22%20%5E%3C%3EVA%22%2BK%5C-sm%2B%3FqNdNKK%40LJj%40jC%22%07%C3%BE%C2%85%C3%98%C2%80%C3%AD%0E%C2%A7V%5EG%C2%8B%C2%A4%C3%97%C2%B9z%C2%9E%051%C2%AB%1Bb%C3%AB%C3%AB%C2%B6%C3%B1%12R%C3%B5r%C2%A4%C3%A7M%221391423xcs%40LGjC%22%C2%9Ac%17c0%C3%81%3A%C2%92xq%C3%A7%10%C3%B7%5CrS%09%C2%87%C3%8D%C3%B3%C3%97%C2%BA%3A9%22lG3z6&input=scs&debug=0).
## Explanation
I store the songs in base-6 numbers, re-encoded to base 1391423 and then base 256 to save space. I had to choose base 6 since some of the songs start with `^`, and numbers can't really start with a 0 after decoding.
```
  J" ^<>VA"                                                      save characters in J
 t                                                               discard the space
V                                                                loop over all characters
                               C"..."                            parse base256 string (songs) to int
                              j      1391423                     convert to base 1391423 (separate songs)
                                                   C"..."        parse base256 string (codes) to int
                                                  j      lG      convert to base-26
                                               @LG               replace indices by corresponding letters
                                              s                  concatenate
                                             c             3     chop to 3-character codes
                                            x               z    find index of input code
                             @                                   get correct song
                            j                                6   convert to base 6
                         @LJ                                     replace indices by corresponding ^<>VA
                m                                                map d over the above
                  ?qNdNK                                         take the current character if at its row,
                                                                 otherwise a dash
                 +      K                                        add a dash
               s                                                 concatenate
           +K\-                                                  add a dash and print
```
[Answer]
# Perl 5, 125 (~~320~~ ~~260~~ 250 Bytes -6x7% bonus songs -8% scarecrow song)
Yay, finally an opportunity to experiment with that Perlish hash syntax. 
```
$_=pop;@B={qw(zel <^><^> sas V><V>< eps ^<>^<> sos >V^>V^ sot >AV>AV sst AV^AV^ mof A^<><> bof VAVA>V>V sow AV>>< nos <>>A<>V ros AVA>VA pol ^>^><^ scs <^V>>V^<)}->{$_}=~/./g;map{@L=('-')x17;for$i(0..@B){$L[1+2*$i]=$_,if$B[$i]eq$_}say@L}qw(^ < > V A)
```
### Test
```
$ perl -M5.010 ocarina.pl scs
---^---------^---
-<-------------<-
------->->-------
-----V-----V-----
-----------------
```
[Answer]
# Perl, 75 (150 bytes - 50%)
```
#!perl -nl
$i=vec~$_,0,32;print+qw(- - ^ < > V A)[0,map{vec('w2$$W4F4w7DeweTFwR$Ew$C2wVdeVe3cw4B#EEVVwC5Tw44bwR&e',$i/480%15*8-$_,4)==$.&&$.,0}1..8]while$.++<6
```
Counting the shebang as 2, input is taken from stdin.
**Sample usage**
```
$ echo zel | perl zelda.pl
---^-----^-------
-<-----<---------
----->----->-----
-----------------
-----------------
$ echo bof | perl zelda.pl
-----------------
-----------------
--------->--->---
-V---V-----V---V-
---A---A---------
$ echo scs | perl zelda.pl
-----------------
---<-<-<---------
-----------------
-----------V-V---
-A-------A-----A-
```
[Answer]
# Haskell, 344 - 50% = 172 bytes
```
import Data.List
s"zel"=82
s"sas"=69
s"eps"=86
s"sos"=48
s"sot"=128
s"sst"=50
z"mof"=11055
z"bof"=373854
z"sow"=1720
z"nos"=73217
z"ros"= -12730
z"pol"=4791
z"scs"=304236
z n=s n*126
p n|n*n== -n="   "|0<1="A^<>V"!!(n`mod`5):p(n`div`5)
o=putStr.unlines.transpose.(l:).concatMap(\c->[map(e c)"^<>VA",l]).take 8.p.z
e c d|c==d=c|0<1='-'
l="-----"
```
`o` does the job.
Thought I could beat Python by using these encodings (took me a long time .\_.), but no. They don't really save a lot of bytes yet. Any suggestions?
Yes, that is a minus in front of the encoding for `"ros"`. Thats because its 'sheet' ends with the character that means `0` in my base-5, because this negative trick wouldn't work for the 'easy songs' encoded by doubling what's encoded in `s`. Unless you use `quot` maybe, but then you can't handle `p (-1)` specially, since `quot (-5) = 0`, so the negativity would vanish. Whatever.
[Answer]
# PHP: 130 bytes (260 ~~270~~ ~~279~~ bytes − 6 × 7% − 8%)
Thanks to Ismael Miguel and Blackhole for some great ideas to save more bytes!
```
<?php $f=str_split;for($z='*^<>VA';++$i<6;print"-
")foreach($f(base_convert(substr(current(preg_grep("/^$argv[1]/",$f(bofttmmeps8jf0mofvff0nosfnfopol99d0rosyxt0sasrgk0scs8m8msosm9p0sotnry0sowylc0sstybp0zeldk90,7))),-4),36,6),1)as$c)echo$i-$c?'--':'-'.$z[$c-0];
```
After the `print"-`, this is a literal insertion of a carriage return. It may translate to two bytes in Windows.
All bonus songs including the Scarecrow's song are included.
Each song is represented in seven bytes of code. I like the new scoring because with the old scoring I would have gained just one meager bonus point overall!
The recent edits make PHP generate a lot of warnings, so to keep things nice and tidy, those are diverted to `/dev/null`.
Save as `zelda.php` and run on the command line:
```
$ php zelda.php zel 2> /dev/null
---^-----^-------                                                                                                                                   
-<-----<---------                                                                                                                                   
----->----->-----                                                                                                                                   
-----------------                                                                                                                                   
-----------------
$ php zelda.php bof 2> /dev/null                                                                                                                            
-----------------                                                                                                                                   
-----------------                                                                                                                                   
--------->--->---                                                                                                                                   
-V---V-----V---V-                                                                                                                                   
---A---A--------- 
$ php zelda.php scs 2> /dev/null                                                                                                                          
-^-------^-------                                                                                                                                   
---<-------<-----                                                                                                                                   
----->------->---                                                                                                                                   
-------V-------V-                                                                                                                                   
-----------------
```
[Answer]
# Python 3 - 138.5 (~~292~~ ~~280~~ 277 bytes - 50%)
Shaved a few bytes off the current Python leader while doing the print-as-you-go method rather than the replace method.
[Try Online](https://repl.it/BK0v/16)
```
s=dict(zel="<^><^>",sas="V><V><",eps="^<>^<>",sos=">V^>V^",sot=">AV>AV",sst="AV^AV^",mof="A^<><>",bof="VAVA>V>V",sow="AV>><",nos="<>>A<>V",ros="AVA>VA",pol="^>^><^",scs="AV><^AV>")[input()]
s+=" "*8
for c in "^<>VA":
 o="-"
 for x in range(8):o+=["--",c+"-"][s[x]==c]
 print(o)
```
Run:
```
> python3 loz.py
bof [return]
```
Output:
```
-----------------
-----------------
--------->--->---
-V---V-----V---V-
---A---A---------
```
[Answer]
# Ruby, rev 1, 192 - 50% = 96
Golfing includes:
removal of whitespace between groups of letters in the magic string (and revision of the denominator at the end of the line to `/4`.) Removal of some other unnecessary whitespace.
conversion of the escape sequences into single characters (stack exchange will not display them, so I have put `?` as a placeholder)
redefinition of `g` as a single string containing five runs of 17 `-` followed by newlines, instead of an array of five strings of 17 `-`
```
s=gets.chop
s[?s<=>s[0]]=''
n=("owEkrswuns=;gcsbfbYuze33as&&es77os??otaast??mf?9pl
?"=~/#{s}/)/4
g=(?-*17+'
')*5
(n<4? n+5:6).times{|i|x=$'[i/3].ord/5**(i%3)%5;g[x*18+i*2+1]='^<>VA'[x]}
puts g
```
# Ruby, rev 0, 223 - 50% = 111.5 (ungolfed)
The input code is reduced to 2 letters. If it begins with an `s`, the `s` is deleted, if it begins with a letter after `s` (only applicable to `zel` the last letter is deleted, and if it begins with a letter before `s` the middle letter is deleted. 
The magic string (which in the ungolfed version contains spaces for clarity) contains the 2-letter codes followed by the music data. It is searched using the match operator `=~` which returns the position in the string.
There is exactly one song each of 5, 7, and 8 notes (plus scs which also has 8 notes.) These, along with one arbitrary 6-note song `ros` are bundled at the beginning of the magic string so that the value of `n` given by the position in the string can be used to calculate the number of notes to play. `cs` is squeezed in before `bf`, and with the truncation when the number in `n` is rounded down we just get away with the correct calculation for both. After the fourth cluster, all songs have 6 notes so if `n` is large the number of notes is reduced to a default of 6.
An array of `-` is set up for output and the notes are substituted in one by one. The required music data is extracted from the variable `$'` which contains the part of the original magic string to the right of the match. In this way, irrelevant data is ignored.
The notes are encoded 3 at a time into the magic string, just after the relevant 2-letter song code. They are extracted with division by `5**(i%3)` and a character in `g` is updated accordingly. At the end of the program `g` is printed.
```
s=gets.chop
s[?s<=>s[0]]=''
n=("owEk rswu ns=;g csbfbYu ze33 as&& es77 os\21\21 otaa st\23\23 mf\35\71 pl\n\a"=~/#{s}/)/5
g=(0..4).map{'-'*17}
(n<4? n+5 : 6).times{|i|x=$'[i/3].ord/5**(i%3)%5;g[x][i*2+1]='^<>VA'[x]}
puts g
```
[Answer]
# Python 2, 141.5 Bytes -50% (283 Bytes)
```
s='D  2)AE0*  A2)D  AD )2 A  )D2A 0,"!A D2) A  (2EA"4H !A )2D A 1F`(A)2D  A  p\xc5*'.split("A")['sst pol zel sos sot sow sas ros mof scs nos eps bof'.split().index(raw_input())]
for c,n in zip(s,"^<>VA"):print"-".join([("-"+n)[i>"0"]for i in bin((ord(c)-32)%255)[2:].zfill(8)][::-1])
```
Stores each note as a byte as each line is 8 notes long. Recalls the binary representation and then replaces with the right characters.
[Answer]
# Lua, 249 bytes - 50% = 124.5
```
w=io.write for j=1,5 do n={sst=41881,pol=44915,zel=30814,sos=42315,sot=17577,sow=5953,sas=35588,ros=11065,mof=29335,nos=122170,eps=29729,bof=719576,scs=999999}[...]for i=1,8 do d=n%6 n=(n-d)/6 c=d==6-j and'AV><^':sub(d,d)or'-'w('-',c)end w('-\n')end
```
Pretty simple, just reads back songs encoded as base-6 numbers.
]