Replace set of defined characters

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EnlighterJS 3 Syntax Highlighter
<hr><pre class="EnlighterJSRAW" data-enlighter-language="visualbasic">Function ReplaceDefinChar(ByVal InString As String, CharToRep As String, ReplacementChar As String)
'Replaces a group of a defined character by a single instance of a defined character
' For example, the string "sdfdes------sdfhd-----kghgh----hsdfh--", using the arguments CharToRep as "-" &
' ReplacementChar as " " will return "sdfdes sdfhd kghgh hsdfh"
Dim StrLen As Integer, CurrCharInd As Integer, NextCharInd As Integer, TmpInd As Integer
Dim WholeStr As String, CurrChar As String, NextChar As String, ResultString As String
Dim LoopOne As Boolean
'Initialise
ResultString = ""
WholeStr = Trim(InString)
StrLen = Len(WholeStr)
'Check the suitability of the Input string (InString)
'Exit if string is too short
If StrLen <= 1 Or Len(CharToRep) > 1 Or Len(ReplacementChar) > 1 Then
Exit Function
End If
'Exit if character to replace (CharToRep) is not contained within the string
If Not IsNumeric(InStr(CharToRep, WholeStr)) Then
Exit Function
End If
'Only applies if more than 1 character matches so only count
' upto the second last character
'Logic: Move along the input string, one character at a time. Put each character
' not matching character to replace in the return string. Instances of character
' to replace are not put in return string but are instead replaces with a single
' instance of the replacement character.
TmpInd = 1
'Loop through the input string
Do While TmpInd <= (StrLen - 1)
CurrChar = Mid(WholeStr, TmpInd, 1)
LoopOne = True
Do While CurrChar = CharToRep
'Add replacement character only for the first instance
If LoopOne = True Then
ResultString = ResultString & ReplacementChar
LoopOne = False
End If
TmpInd = TmpInd + 1
'Case where char to replace is at the end of the string
If TmpInd > StrLen Then
CurrChar = ""
Exit Do
End If
CurrChar = Mid(WholeStr, TmpInd, 1)
Loop
ResultString = ResultString & CurrChar
TmpInd = TmpInd + 1
Loop
ReplaceDefinChar = ResultString
End Function</pre>
<hr><pre class="EnlighterJSRAW" data-enlighter-language="visualbasic">Function ReplaceDefinChar(ByVal InString As String, CharToRep As String, ReplacementChar As String) 'Replaces a group of a defined character by a single instance of a defined character ' For example, the string "sdfdes------sdfhd-----kghgh----hsdfh--", using the arguments CharToRep as "-" & ' ReplacementChar as " " will return "sdfdes sdfhd kghgh hsdfh" Dim StrLen As Integer, CurrCharInd As Integer, NextCharInd As Integer, TmpInd As Integer Dim WholeStr As String, CurrChar As String, NextChar As String, ResultString As String Dim LoopOne As Boolean 'Initialise ResultString = "" WholeStr = Trim(InString) StrLen = Len(WholeStr) 'Check the suitability of the Input string (InString) 'Exit if string is too short If StrLen <= 1 Or Len(CharToRep) > 1 Or Len(ReplacementChar) > 1 Then Exit Function End If 'Exit if character to replace (CharToRep) is not contained within the string If Not IsNumeric(InStr(CharToRep, WholeStr)) Then Exit Function End If 'Only applies if more than 1 character matches so only count ' upto the second last character 'Logic: Move along the input string, one character at a time. Put each character ' not matching character to replace in the return string. Instances of character ' to replace are not put in return string but are instead replaces with a single ' instance of the replacement character. TmpInd = 1 'Loop through the input string Do While TmpInd <= (StrLen - 1) CurrChar = Mid(WholeStr, TmpInd, 1) LoopOne = True Do While CurrChar = CharToRep 'Add replacement character only for the first instance If LoopOne = True Then ResultString = ResultString & ReplacementChar LoopOne = False End If TmpInd = TmpInd + 1 'Case where char to replace is at the end of the string If TmpInd > StrLen Then CurrChar = "" Exit Do End If CurrChar = Mid(WholeStr, TmpInd, 1) Loop ResultString = ResultString & CurrChar TmpInd = TmpInd + 1 Loop ReplaceDefinChar = ResultString End Function</pre>
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EnlighterJS 3 Syntax Highlighter
Function ReplaceDefinChar(ByVal InString As String, CharToRep As String, ReplacementChar As String)
    'Replaces a group of a defined character by a single instance of a defined character
    '   For example, the string "sdfdes------sdfhd-----kghgh----hsdfh--", using the arguments CharToRep as "-" &
    '   ReplacementChar as " " will return "sdfdes sdfhd kghgh hsdfh"
    Dim StrLen As Integer, CurrCharInd As Integer, NextCharInd As Integer, TmpInd As Integer
    Dim WholeStr As String, CurrChar As String, NextChar As String, ResultString As String
    Dim LoopOne As Boolean
    'Initialise
    ResultString = ""
    WholeStr = Trim(InString)
    StrLen = Len(WholeStr)
    'Check the suitability of the Input string (InString)
    'Exit if string is too short
    If StrLen <= 1 Or Len(CharToRep) > 1 Or Len(ReplacementChar) > 1 Then
        Exit Function
    End If
    'Exit if character to replace (CharToRep) is not contained within the string
    If Not IsNumeric(InStr(CharToRep, WholeStr)) Then
        Exit Function
    End If
    'Only applies if more than 1 character matches so only count
    '   upto the second last character
    'Logic: Move along the input string, one character at a time. Put each character
    '   not matching character to replace in the return string. Instances of character
    '   to replace are not put in return string but are instead replaces with a single
    '   instance of the replacement character.
    TmpInd = 1
    'Loop through the input string
    Do While TmpInd <= (StrLen - 1)
        CurrChar = Mid(WholeStr, TmpInd, 1)
        LoopOne = True
        Do While CurrChar = CharToRep
            'Add replacement character only for the first instance
            If LoopOne = True Then
                ResultString = ResultString & ReplacementChar
                LoopOne = False
            End If
            TmpInd = TmpInd + 1
            'Case where char to replace is at the end of the string
            If TmpInd > StrLen Then
                CurrChar = ""
                Exit Do
            End If
            CurrChar = Mid(WholeStr, TmpInd, 1)
        Loop
        ResultString = ResultString & CurrChar
        TmpInd = TmpInd + 1
    Loop
    ReplaceDefinChar = ResultString
End Function
Function ReplaceDefinChar(ByVal InString As String, CharToRep As String, ReplacementChar As String)
    'Replaces a group of a defined character by a single instance of a defined character
    '   For example, the string "sdfdes------sdfhd-----kghgh----hsdfh--", using the arguments CharToRep as "-" &
    '   ReplacementChar as " " will return "sdfdes sdfhd kghgh hsdfh"

    Dim StrLen As Integer, CurrCharInd As Integer, NextCharInd As Integer, TmpInd As Integer
    Dim WholeStr As String, CurrChar As String, NextChar As String, ResultString As String
    Dim LoopOne As Boolean

    'Initialise
    ResultString = ""
    WholeStr = Trim(InString)
    StrLen = Len(WholeStr)

    'Check the suitability of the Input string (InString)
    'Exit if string is too short
    If StrLen <= 1 Or Len(CharToRep) > 1 Or Len(ReplacementChar) > 1 Then
        Exit Function
    End If

    'Exit if character to replace (CharToRep) is not contained within the string
    If Not IsNumeric(InStr(CharToRep, WholeStr)) Then
        Exit Function
    End If

    'Only applies if more than 1 character matches so only count
    '   upto the second last character
    'Logic: Move along the input string, one character at a time. Put each character
    '   not matching character to replace in the return string. Instances of character
    '   to replace are not put in return string but are instead replaces with a single
    '   instance of the replacement character.
    TmpInd = 1
    'Loop through the input string
    Do While TmpInd <= (StrLen - 1)
        CurrChar = Mid(WholeStr, TmpInd, 1)
        LoopOne = True
        Do While CurrChar = CharToRep
            'Add replacement character only for the first instance
            If LoopOne = True Then
                ResultString = ResultString & ReplacementChar
                LoopOne = False
            End If
            TmpInd = TmpInd + 1
            'Case where char to replace is at the end of the string
            If TmpInd > StrLen Then
                CurrChar = ""
                Exit Do
            End If
            CurrChar = Mid(WholeStr, TmpInd, 1)
        Loop
        ResultString = ResultString & CurrChar
        TmpInd = TmpInd + 1
    Loop

    ReplaceDefinChar = ResultString

End Function
Function ReplaceDefinChar(ByVal InString As String, CharToRep As String, ReplacementChar As String)
    'Replaces a group of a defined character by a single instance of a defined character
    '   For example, the string "sdfdes------sdfhd-----kghgh----hsdfh--", using the arguments CharToRep as "-" &
    '   ReplacementChar as " " will return "sdfdes sdfhd kghgh hsdfh"

    Dim StrLen As Integer, CurrCharInd As Integer, NextCharInd As Integer, TmpInd As Integer
    Dim WholeStr As String, CurrChar As String, NextChar As String, ResultString As String
    Dim LoopOne As Boolean

    'Initialise
    ResultString = ""
    WholeStr = Trim(InString)
    StrLen = Len(WholeStr)

    'Check the suitability of the Input string (InString)
    'Exit if string is too short
    If StrLen <= 1 Or Len(CharToRep) > 1 Or Len(ReplacementChar) > 1 Then
        Exit Function
    End If

    'Exit if character to replace (CharToRep) is not contained within the string
    If Not IsNumeric(InStr(CharToRep, WholeStr)) Then
        Exit Function
    End If

    'Only applies if more than 1 character matches so only count
    '   upto the second last character
    'Logic: Move along the input string, one character at a time. Put each character
    '   not matching character to replace in the return string. Instances of character
    '   to replace are not put in return string but are instead replaces with a single
    '   instance of the replacement character.
    TmpInd = 1
    'Loop through the input string
    Do While TmpInd <= (StrLen - 1)
        CurrChar = Mid(WholeStr, TmpInd, 1)
        LoopOne = True
        Do While CurrChar = CharToRep
            'Add replacement character only for the first instance
            If LoopOne = True Then
                ResultString = ResultString & ReplacementChar
                LoopOne = False
            End If
            TmpInd = TmpInd + 1
            'Case where char to replace is at the end of the string
            If TmpInd > StrLen Then
                CurrChar = ""
                Exit Do
            End If
            CurrChar = Mid(WholeStr, TmpInd, 1)
        Loop
        ResultString = ResultString & CurrChar
        TmpInd = TmpInd + 1
    Loop

    ReplaceDefinChar = ResultString

End Function