Petya learned a new programming language CALPAS. A program in this language always takes one non-negative integer and returns one non-negative integer as well.

In the language, there are only three commands: apply a bitwise operation AND, OR or XOR with a given constant to the current integer. A program can contain an arbitrary sequence of these operations with arbitrary constants from 0 to 1023. When the program is run, all operations are applied (in the given order) to the argument and in the end the result integer is returned.

Petya wrote a program in this language, but it turned out to be too long. Write a program in CALPAS that does the same thing as the Petya's program, and consists of no more than 5 lines. Your program should return the same integer as Petya's program for all arguments from 0 to 1023.
The first line contains an integer *n* (1 ≤ *n* ≤ 5·10<sup class="upper-index">5</sup>) — the number of lines.

Next *n* lines contain commands. A command consists of a character that represents the operation ("&amp;", "|" or "^" for AND, OR or XOR respectively), and the constant *x*<sub class="lower-index">*i*</sub> 0 ≤ *x*<sub class="lower-index">*i*</sub> ≤ 1023.
You can read about bitwise operations in [https://en.wikipedia.org/wiki/Bitwise_operation](https://en.wikipedia.org/wiki/Bitwise_operation).

Second sample:

Let *x* be an input of the Petya's program. It's output is ((*x*&amp;1)&amp;3)&amp;5 = *x*&amp;(1&amp;3&amp;5) = *x*&amp;1. So these two programs always give the same outputs.
3
| 3
^ 2
| 1
2
| 3
^ 2
3
& 1
& 3
& 5
1
& 1
3
^ 1
^ 2
^ 3
0
2
| 999
^ 689
2
| 999
^ 689
3
& 242
^ 506
^ 522
2
| 781
^ 253
2
| 56
^ 875
2
| 56
^ 875
3
^ 125
^ 377
& 1019
2
| 4
^ 260
1
& 123
1
& 123
1
| 123
1
| 123
1
^ 123
1
^ 123
10
^ 218
& 150
| 935
& 61
| 588
& 897
| 411
| 584
^ 800
| 704
2
| 1023
^ 260
10
^ 160
& 1021
& 510
^ 470
& 1022
& 251
& 760
& 1016
| 772
| 515
2
| 775
^ 112
1
& 0
1
& 0
1
| 0
0
1
^ 0
0
1
& 1023
0
1
| 1023
1
| 1023
1
^ 1023
1
^ 1023
x=int(input())
ans=[]
for i in range(x):
    m,p=input().split()
    p=int(p)
    if(i==0):
        ans.append([m,p])
    else:
        if(ans[-1][0]==m):
            if(m=='|'):
                ans[-1][1]|=p
            elif(m=='^'):
                ans[-1][1]^=p
            else:
                ans[-1][1]&=p
        else:
            ans.append([m,p])

    
 

xor=0
ad=0
from collections import defaultdict
al=defaultdict(int)

for i in range(len(ans)):
    if(ans[i][0]=='|'):
        al['add']|=ans[i][1]
    elif(ans[i][0]=='&'):
        al['add']&=ans[i][1]
        if(xor==1):
            al['xor']&=ans[i][1]
        else:
                
            if(ad==0):
                ad=1
                al['and']=ans[i][1]
            else:
                al['and']&=ans[i][1]

            al['add']&=ans[i][1]
    else:
            
        al['add']^=ans[i][1]
        if(ad==1):
            al['and']^=ans[i][1]
        else:
            if(xor==0):
                xor=1
                al['xor']=ans[i][1]
            else:
                al['xor']^=ans[i][1]
    

if(xor==1):
    print(2)
    print('^',al['xor'])
    print('|',al['add'])
else:
    print(2)
    print('&',al['and'])
    print('|',al['add'])

    

    
            
            
            
