Let us define two functions *f* and *g* on positive integer numbers. 

<img align="middle" class="tex-formula" src="https://espresso.codeforces.com/120df92771639f1f51a4b216dccd3ed7c32bb859.png" style="max-width: 100.0%;max-height: 100.0%;"/> 

You need to process *Q* queries. In each query, you will be given three integers *l*, *r* and *k*. You need to print the number of integers *x* between *l* and *r* inclusive, such that *g*(*x*) = *k*.
The first line of the input contains an integer *Q* (1 ≤ *Q* ≤ 2 × 10<sup class="upper-index">5</sup>) representing the number of queries. 

*Q* lines follow, each of which contains 3 integers *l*, *r* and *k* (1 ≤ *l* ≤ *r* ≤ 10<sup class="upper-index">6</sup>, 1 ≤ *k* ≤ 9).
In the first example:
 -  *g*(33) = 9 as *g*(33) = *g*(3 × 3) = *g*(9) = 9 -  *g*(47) = *g*(48) = *g*(60) = *g*(61) = 6 -  There are no such integers between 47 and 55. -  *g*(4) = *g*(14) = *g*(22) = *g*(27) = *g*(39) = *g*(40) = *g*(41) = *g*(58) = 4
4
22 73 9
45 64 6
47 55 7
2 62 4
1
4
0
8
4
82 94 6
56 67 4
28 59 9
39 74 4
3
1
1
5
def g(x) :
    if x < 10 : return x
    else :
        p = 1
        while x != 0 : p *= max(1, x % 10); x //= 10
        return g(p)

psum = [[0,0,0,0,0,0,0,0,0,0] for i in range(1000001)]

for i in range(1, 1000001) :
    for j in range(10) :
        psum[i][j] = psum[i-1][j]
    psum[i][g(i)] += 1

for i in range(int(input())) :
    l, r, k = map(int, input().split())
    print(psum[r][k] - psum[l-1][k])