You've got an undirected graph, consisting of *n* vertices and *m* edges. We will consider the graph's vertices numbered with integers from 1 to *n*. Each vertex of the graph has a color. The color of the *i*-th vertex is an integer *c*<sub class="lower-index">*i*</sub>.

Let's consider all vertices of the graph, that are painted some color *k*. Let's denote a set of such as *V*(*k*). Let's denote the value of the neighbouring color diversity for color *k* as the cardinality of the set *Q*(*k*) = {*c*<sub class="lower-index">*u*</sub> :  *c*<sub class="lower-index">*u*</sub> ≠ *k* and there is vertex *v* belonging to set *V*(*k*) such that nodes *v* and *u* are connected by an edge of the graph}.

Your task is to find such color *k*, which makes the cardinality of set *Q*(*k*) maximum. In other words, you want to find the color that has the most diverse neighbours. Please note, that you want to find such color *k*, that the graph has at least one vertex with such color.
The first line contains two space-separated integers *n*, *m* (1 ≤ *n*, *m* ≤ 10<sup class="upper-index">5</sup>) — the number of vertices end edges of the graph, correspondingly. The second line contains a sequence of integers *c*<sub class="lower-index">1</sub>, *c*<sub class="lower-index">2</sub>, ..., *c*<sub class="lower-index">*n*</sub> (1 ≤ *c*<sub class="lower-index">*i*</sub> ≤ 10<sup class="upper-index">5</sup>) — the colors of the graph vertices. The numbers on the line are separated by spaces.

Next *m* lines contain the description of the edges: the *i*-th line contains two space-separated integers *a*<sub class="lower-index">*i*</sub>, *b*<sub class="lower-index">*i*</sub> (1 ≤ *a*<sub class="lower-index">*i*</sub>, *b*<sub class="lower-index">*i*</sub> ≤ *n*; *a*<sub class="lower-index">*i*</sub> ≠ *b*<sub class="lower-index">*i*</sub>) — the numbers of the vertices, connected by the *i*-th edge. 

It is guaranteed that the given graph has no self-loops or multiple edges.
from sys import stdin
from collections import *


def arr_inp(n):
    if n == 1:
        return [int(x) for x in stdin.readline().split()]
    elif n == 2:
        return [float(x) for x in stdin.readline().split()]
    else:
        return list(stdin.readline()[:-1])


def main():
    n, m = arr_inp(1)
    c, ans, ma = arr_inp(1), float('inf'), 0
    mem = defaultdict(set)

    for i in range(m):
        u, v = arr_inp(1)
        u -= 1
        v -= 1
        if c[u] != c[v]:
            mem[c[u]].add(c[v])
            mem[c[v]].add(c[u])

    for i, j in mem.items():
        if len(j) > ma:
            ma = max(ma, len(j))
            ans = i
        if len(j) == ma:
            ans = min(ans, i)

    print(ans if ans != float('inf') else min(c))


if __name__ == '__main__':
    main()
