It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.
The single line contains integer *y* (1000 ≤ *y* ≤ 9000) — the year number.
y = int(input()) + 1
while str(y).count("0") > 1 or str(y).count("1") > 1 or str(y).count("2") > 1 or str(y).count("3") > 1 or str(y).count("4") > 1 or str(y).count("5") > 1 or str(y).count("6") > 1 or str(y).count("7") > 1 or str(y).count("8") > 1 or str(y).count("9") > 1:
    y += 1
print(y)
