It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.
The single line contains integer *y* (1000 ≤ *y* ≤ 9000) — the year number.
listofyear = []

for i in range(1000,9010):
    x = str(i)
    if x.count(x[0])==1 and x.count(x[1])==1 and x.count(x[2])==1 and x.count(x[3])==1:
        listofyear.append(int(x))

year = int(input())
newlist=[]
for i in range(len(listofyear)):
    if year<listofyear[i]:
        newlist.append(listofyear[i])
print(min(newlist))

