It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.
The single line contains integer *y* (1000 ≤ *y* ≤ 9000) — the year number.
def valid(num):
    str1 = str(num)
    hashmap = {}
    for i in range(0 , 10):
        hashmap[i] = 0
    for c in str1:
        if hashmap[int(c)] == 1:
            return False
        else:
            hashmap[int(c)] = 1
    return True

n = input()
n = int(n)
for i in range(n + 1 , 9200):
    if valid(i):
        print(i)
        break;
