Sereja has got an array, consisting of *n* integers, *a*<sub class="lower-index">1</sub>, *a*<sub class="lower-index">2</sub>, ..., *a*<sub class="lower-index">*n*</sub>. Sereja is an active boy, so he is now going to complete *m* operations. Each operation will have one of the three forms:
 1.  Make *v*<sub class="lower-index">*i*</sub>-th array element equal to *x*<sub class="lower-index">*i*</sub>. In other words, perform the assignment *a*<sub class="lower-index">*v*<sub class="lower-index">*i*</sub></sub> = *x*<sub class="lower-index">*i*</sub>. 1.  Increase each array element by *y*<sub class="lower-index">*i*</sub>. In other words, perform *n* assignments *a*<sub class="lower-index">*i*</sub> = *a*<sub class="lower-index">*i*</sub> + *y*<sub class="lower-index">*i*</sub> (1 ≤ *i* ≤ *n*). 1.  Take a piece of paper and write out the *q*<sub class="lower-index">*i*</sub>-th array element. That is, the element *a*<sub class="lower-index">*q*<sub class="lower-index">*i*</sub></sub>. 
Help Sereja, complete all his operations.
The first line contains integers *n*, *m* (1 ≤ *n*, *m* ≤ 10<sup class="upper-index">5</sup>). The second line contains *n* space-separated integers *a*<sub class="lower-index">1</sub>, *a*<sub class="lower-index">2</sub>, ..., *a*<sub class="lower-index">*n*</sub> (1 ≤ *a*<sub class="lower-index">*i*</sub> ≤ 10<sup class="upper-index">9</sup>) — the original array.

Next *m* lines describe operations, the *i*-th line describes the *i*-th operation. The first number in the *i*-th line is integer *t*<sub class="lower-index">*i*</sub> (1 ≤ *t*<sub class="lower-index">*i*</sub> ≤ 3) that represents the operation type. If *t*<sub class="lower-index">*i*</sub> = 1, then it is followed by two integers *v*<sub class="lower-index">*i*</sub> and *x*<sub class="lower-index">*i*</sub>, (1 ≤ *v*<sub class="lower-index">*i*</sub> ≤ *n*, 1 ≤ *x*<sub class="lower-index">*i*</sub> ≤ 10<sup class="upper-index">9</sup>). If *t*<sub class="lower-index">*i*</sub> = 2, then it is followed by integer *y*<sub class="lower-index">*i*</sub> (1 ≤ *y*<sub class="lower-index">*i*</sub> ≤ 10<sup class="upper-index">4</sup>). And if *t*<sub class="lower-index">*i*</sub> = 3, then it is followed by integer *q*<sub class="lower-index">*i*</sub> (1 ≤ *q*<sub class="lower-index">*i*</sub> ≤ *n*).
n, m = map(int, input().split())
arr = [int(i) for i in input().split()]
res, s = 0, ""
for i in range(m):
    b = [int(x) for x in input().split()]
    if b[0] == 1:
        arr[b[1] - 1] = b[2] - res
    elif b[0] == 2:
        res += b[1]
    else:
        s += str(arr[b[1] - 1] + res) + '\n'
print(s)
