It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.
The single line contains integer *y* (1000 ≤ *y* ≤ 9000) — the year number.
def Uniq(l):
    s=0
    for i in l:
        s+=l.count(i)
    if s==4:
        return True
    return False
        
n = int(input())+1
l=[0]*4
while True:
    l[0],l[1],l[2],l[3]=(n//1000),(n//100)%10,(n//10)%10,n%10
    if(Uniq(l)):
        break
    n+=1
print(n)