The polar bears are going fishing. They plan to sail from (*s*<sub class="lower-index">*x*</sub>, *s*<sub class="lower-index">*y*</sub>) to (*e*<sub class="lower-index">*x*</sub>, *e*<sub class="lower-index">*y*</sub>). However, the boat can only sail by wind. At each second, the wind blows in one of these directions: east, south, west or north. Assume the boat is currently at (*x*, *y*).
 -  If the wind blows to the east, the boat will move to (*x* + 1, *y*). -  If the wind blows to the south, the boat will move to (*x*, *y* - 1). -  If the wind blows to the west, the boat will move to (*x* - 1, *y*). -  If the wind blows to the north, the boat will move to (*x*, *y* + 1). 
Alternatively, they can hold the boat by the anchor. In this case, the boat stays at (*x*, *y*). Given the wind direction for *t* seconds, what is the earliest time they sail to (*e*<sub class="lower-index">*x*</sub>, *e*<sub class="lower-index">*y*</sub>)?
The first line contains five integers *t*, *s*<sub class="lower-index">*x*</sub>, *s*<sub class="lower-index">*y*</sub>, *e*<sub class="lower-index">*x*</sub>, *e*<sub class="lower-index">*y*</sub> (1 ≤ *t* ≤ 10<sup class="upper-index">5</sup>,  - 10<sup class="upper-index">9</sup> ≤ *s*<sub class="lower-index">*x*</sub>, *s*<sub class="lower-index">*y*</sub>, *e*<sub class="lower-index">*x*</sub>, *e*<sub class="lower-index">*y*</sub> ≤ 10<sup class="upper-index">9</sup>). The starting location and the ending location will be different.

The second line contains *t* characters, the *i*-th character is the wind blowing direction at the *i*-th second. It will be one of the four possibilities: "E" (east), "S" (south), "W" (west) and "N" (north).
t,xi, yi, xf, yf = [int(x) for x in input().split()]
s= input()
# h , v = 0 ,0 
hs, ys = None , None
if xf - xi > 0:
    hs = "E"
else:
    hs = 'W'
h = abs(xf - xi)
if yf - yi > 0:
    ys = "N"
else:
    ys = 'S'
v = abs(yf - yi)
hcount , vcount =  0 ,0
flag = 0   
j = 0 
for i in range(t):
    if hcount == h and vcount == v:
        flag = 1
        break
    if s[i] == hs and hcount != h:
        hcount += 1
    if s[i] == ys and vcount != v:
        vcount += 1    
    j += 1    
if flag:
    print(j)
else:
    print(-1)    
# print(hcount, vcount ,j)       


# while( (hcount != h and vcount != v) or i <t):
#     if s[i] == hs:
#         hcount += 1
#     if s[i] == ys:
#         vcount += 1
#     i+= 1    
# if hcount == h and vcount == v:
#     print(i+1)
# else:
#     print(-1)    