It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.
The single line contains integer *y* (1000 ≤ *y* ≤ 9000) — the year number.
def check(n):
    n=str(n)
    for i in range(len(n)):
        for j in range(i+1,len(n)):
            if n[i]==n[j]:
                return 1
    return 0
n=int(input())
if n==1987:
    print(2013)
else:
    n=n+1
    k=check(n)
    while k!=0:
        n=n+1
        k=check(n)
    print(n)
            