It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.
The single line contains integer *y* (1000 ≤ *y* ≤ 9000) — the year number.
def has_distinct_digits(year):
    # Convert year to a string and check if all digits are distinct
    return len(set(str(year))) == len(str(year))

# Input
y = int(input())

# Find the minimum year number with distinct digits
while not has_distinct_digits(y + 1):
    y += 1

# Output the result
print(y + 1)

	    		  	 		 			   		    	  	