It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.
The single line contains integer *y* (1000 ≤ *y* ≤ 9000) — the year number.
n = int(input())
n += 1

while True:
    s = str(n)
    digit1 = s.count(s[0])
    digit2 = s.count(s[1])
    digit3 = s.count(s[2])
    digit4 = s.count(s[3])

    if digit1 == 1 and digit2 == 1 and digit3 == 1 and digit4 == 1:
        break
    
    n += 1

print(n)
