The polar bears are going fishing. They plan to sail from (*s*<sub class="lower-index">*x*</sub>, *s*<sub class="lower-index">*y*</sub>) to (*e*<sub class="lower-index">*x*</sub>, *e*<sub class="lower-index">*y*</sub>). However, the boat can only sail by wind. At each second, the wind blows in one of these directions: east, south, west or north. Assume the boat is currently at (*x*, *y*).
 -  If the wind blows to the east, the boat will move to (*x* + 1, *y*). -  If the wind blows to the south, the boat will move to (*x*, *y* - 1). -  If the wind blows to the west, the boat will move to (*x* - 1, *y*). -  If the wind blows to the north, the boat will move to (*x*, *y* + 1). 
Alternatively, they can hold the boat by the anchor. In this case, the boat stays at (*x*, *y*). Given the wind direction for *t* seconds, what is the earliest time they sail to (*e*<sub class="lower-index">*x*</sub>, *e*<sub class="lower-index">*y*</sub>)?
The first line contains five integers *t*, *s*<sub class="lower-index">*x*</sub>, *s*<sub class="lower-index">*y*</sub>, *e*<sub class="lower-index">*x*</sub>, *e*<sub class="lower-index">*y*</sub> (1 ≤ *t* ≤ 10<sup class="upper-index">5</sup>,  - 10<sup class="upper-index">9</sup> ≤ *s*<sub class="lower-index">*x*</sub>, *s*<sub class="lower-index">*y*</sub>, *e*<sub class="lower-index">*x*</sub>, *e*<sub class="lower-index">*y*</sub> ≤ 10<sup class="upper-index">9</sup>). The starting location and the ending location will be different.

The second line contains *t* characters, the *i*-th character is the wind blowing direction at the *i*-th second. It will be one of the four possibilities: "E" (east), "S" (south), "W" (west) and "N" (north).
#298B

arr = list(map(int, input().split(" ")))
t = arr[0]
sx = arr[1]
sy = arr[2]
ex = arr[3]
ey = arr[4]

s = input()
direction = [0, 0, 0, 0] #EWNS

xdiff = ex - sx
ydiff = ey - sy
curr = -1
i = 0
b = 0
while i < t:
	if s[i] == "E":
		direction[0] += 1
	elif s[i] == "W":
		direction[1] += 1
	elif s[i] == "N":
		direction[2] += 1
	else:
		direction[3] += 1
	if (xdiff - direction[0] == 0 or xdiff + direction[1] == 0) and (ydiff - direction[2] == 0 or ydiff + direction[3] == 0):
		curr = i + 1
		i = t
		b = 1
	else:
		i += 1

print(curr)