You've got an array *a*, consisting of *n* integers: *a*<sub class="lower-index">1</sub>, *a*<sub class="lower-index">2</sub>, ..., *a*<sub class="lower-index">*n*</sub>. Your task is to find a minimal by inclusion segment [*l*, *r*] (1 ≤ *l* ≤ *r* ≤ *n*) such, that among numbers *a*<sub class="lower-index">*l*</sub>,  *a*<sub class="lower-index">*l* + 1</sub>,  ...,  *a*<sub class="lower-index">*r*</sub> there are exactly *k* distinct numbers.

Segment [*l*, *r*] (1 ≤ *l* ≤ *r* ≤ *n*; *l*, *r* are integers) of length *m* = *r* - *l* + 1, satisfying the given property, is called minimal by inclusion, if there is no segment [*x*, *y*] satisfying the property and less then *m* in length, such that 1 ≤ *l* ≤ *x* ≤ *y* ≤ *r* ≤ *n*. Note that the segment [*l*, *r*] doesn't have to be minimal in length among all segments, satisfying the given property.
The first line contains two space-separated integers: *n* and *k* (1 ≤ *n*, *k* ≤ 10<sup class="upper-index">5</sup>). The second line contains *n* space-separated integers *a*<sub class="lower-index">1</sub>, *a*<sub class="lower-index">2</sub>, ..., *a*<sub class="lower-index">*n*</sub> — elements of the array *a* (1 ≤ *a*<sub class="lower-index">*i*</sub> ≤ 10<sup class="upper-index">5</sup>).
#####################
#1: Array, 
#R -> ++Count[]
#L -> --Count[]
line1 = input().split(" ")
arr = list(map(int,input().split()))
n = int(line1[0])
k = int(line1[1])
counts = {}
l = 0
r = 0
count = 0
for i in range(len(arr)):
    if arr[i] in counts:
        counts[arr[i]] += 1
    else:
        count += 1
        counts[arr[i]] = 1
        if count >= k:
            r = i
            break
for i in range(len(arr)):
    l = i
    counts[arr[i]] -= 1
    if counts[arr[i]] == 0:
        l = i
        break
if count < k:
    print("-1 -1")
else:
    print(l + 1, r + 1)
