It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.
The single line contains integer *y* (1000 ≤ *y* ≤ 9000) — the year number.
def find_next_year(year):
  year += 1
  # While the year has non-distinct digits, increment it by 1.
  while not has_distinct_digits(year):
    year += 1
  # Return the year.
  return year
def has_distinct_digits(year):
  # Convert the year to a string.
  year_str = str(year)
  # Create a set of the digits in the year.
  digits = set(year_str)
  # Return True if the set has 4 elements, False otherwise.
  return len(digits) == 4
n = int(input)
print(find_next_year(n))