It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.
The single line contains integer *y* (1000 ≤ *y* ≤ 9000) — the year number.
a = int(input())
while True:
    a += 1
    b = str(a)
    if b.count('1') < 2 and b.count('2') < 2 and b.count('3') < 2 and b.count('4') < 2 and b.count('5') < 2 and b.count('6') < 2 and b.count('7') < 2 and b.count('8') < 2 and b.count('9') < 2 and b.count('0') < 2:
        print(a)
        break
    
