It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.
The single line contains integer *y* (1000 ≤ *y* ≤ 9000) — the year number.
def func(x):
    b = list(str(x))
    k = 0
    for i in range(len(b)):
        if b[i] == b[i-1] or b[i] == b[i-2] or b[i] == b[i-3]:
            return False
        else:
            k+=1
    if k == 4:
        return True
def boo(x):
    if x==False:
        return True
    else:
        return False
a = int(input())
b=a+1
while(boo(func(b))):
    b+=1
print(b)