It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.
The single line contains integer *y* (1000 ≤ *y* ≤ 9000) — the year number.
n = input()
# l = []
# for i in n:
#     l.append(i)

def check(a):
    for i in range(len(a)):
        for j in range(i, len(a)):
            if j == len(a)-1:
                pass
            else:
                if a[j] == a[j+1]:
                    return False
                # else:
                #     return True

while True:
    t = check(n)
    if not t:
        n = str(int(n)+1)
    else:
        print(n)
        break
    
