It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.
The single line contains integer *y* (1000 ≤ *y* ≤ 9000) — the year number.
def v(y):
    y,ys,cv = str(y),set(),True
    for i in y: ys.add(i)
    if len(y) == len(ys): return True
    else: return False
try:
    y = int(input())
    if y >= 1000 and y <= 9000:
        if v(y) == True: y+=1
        while v(y) != True: y+=1
        print(y)
except: pass