It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.
The single line contains integer *y* (1000 ≤ *y* ≤ 9000) — the year number.
#include <bits/stdc++.h>
using namespace std;
#define ll long long 

bool unik(int n){
    string s = to_string(n);
    set<int> uniDigits(s.begin(), s.end());
    if (s.length() == uniDigits.size()) return true;
    return false;
}

int distyear(int n){
    if(n>= 1000 && n<=9000){
        while(!unik(n)){
            n = n+1;
        }
    }
    return n;
}

int main(){
    ios_base::sync_with_stdio(false);
    cin.tie(NULL);
    int s;cin>>s;
    cout<<distyear(s+1)<<endl;
    return 0;
}