It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.
The single line contains integer *y* (1000 ≤ *y* ≤ 9000) — the year number.
def is_distinct(a):
	a=list(str(a))
	x={'0':0,'1':0,'2':0,'3':0,'4':0,'5':0,'6':0,'7':0,'8':0,'9':0}
	for i in a:
		x[i]+=1
	if max(x.values())>1:
		return False
	else:
		return True

n=int(input())
while True:
	n+=1
	if is_distinct(n)==True:
		print(n)
		break
