It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.
The single line contains integer *y* (1000 ≤ *y* ≤ 9000) — the year number.
t = 2019

while True:
    t += 1
    t1 = str(t)
    if t1.count(t1[0]) == 1 and t1.count(t1[1]) == 1 and t1.count(t1[2]) == 1 and t1.count(t1[3]) == 1:
        print(t)
        break
