Ksusha is a beginner coder. Today she starts studying arrays. She has array *a*<sub class="lower-index">1</sub>, *a*<sub class="lower-index">2</sub>, ..., *a*<sub class="lower-index">*n*</sub>, consisting of *n* positive integers.

Her university teacher gave her a task. Find such number in the array, that all array elements are divisible by it. Help her and find the number!
The first line contains integer *n* (1 ≤ *n* ≤ 10<sup class="upper-index">5</sup>), showing how many numbers the array has. The next line contains integers *a*<sub class="lower-index">1</sub>, *a*<sub class="lower-index">2</sub>, ..., *a*<sub class="lower-index">*n*</sub> (1 ≤ *a*<sub class="lower-index">*i*</sub> ≤ 10<sup class="upper-index">9</sup>) — the array elements.
#include <stdio.h>

int main()
{
    int n,i;
    
    int a[n];
    for(i=0;i<n;i++)
        scanf("%d",&a[i]);
    sort(a,a+n);
    for(i=0;i<n;i++)
    {
        if(a[i]%a[0]!=0)
        {
            cout<-1;
            break;
        }
        if(i==n-1)
        cout<a[0];
    }
    return 0;
			    	 	 		     	 	  				