The polar bears are going fishing. They plan to sail from (*s*<sub class="lower-index">*x*</sub>, *s*<sub class="lower-index">*y*</sub>) to (*e*<sub class="lower-index">*x*</sub>, *e*<sub class="lower-index">*y*</sub>). However, the boat can only sail by wind. At each second, the wind blows in one of these directions: east, south, west or north. Assume the boat is currently at (*x*, *y*).
 -  If the wind blows to the east, the boat will move to (*x* + 1, *y*). -  If the wind blows to the south, the boat will move to (*x*, *y* - 1). -  If the wind blows to the west, the boat will move to (*x* - 1, *y*). -  If the wind blows to the north, the boat will move to (*x*, *y* + 1). 
Alternatively, they can hold the boat by the anchor. In this case, the boat stays at (*x*, *y*). Given the wind direction for *t* seconds, what is the earliest time they sail to (*e*<sub class="lower-index">*x*</sub>, *e*<sub class="lower-index">*y*</sub>)?
The first line contains five integers *t*, *s*<sub class="lower-index">*x*</sub>, *s*<sub class="lower-index">*y*</sub>, *e*<sub class="lower-index">*x*</sub>, *e*<sub class="lower-index">*y*</sub> (1 ≤ *t* ≤ 10<sup class="upper-index">5</sup>,  - 10<sup class="upper-index">9</sup> ≤ *s*<sub class="lower-index">*x*</sub>, *s*<sub class="lower-index">*y*</sub>, *e*<sub class="lower-index">*x*</sub>, *e*<sub class="lower-index">*y*</sub> ≤ 10<sup class="upper-index">9</sup>). The starting location and the ending location will be different.

The second line contains *t* characters, the *i*-th character is the wind blowing direction at the *i*-th second. It will be one of the four possibilities: "E" (east), "S" (south), "W" (west) and "N" (north).
t,sx,sy,ex,ey=map(int,input().split())
s=input()
q,c,flag,flag1="",0,0,0
a=ex-sx
b=ey-sy
# print(a,b)
if a<0:
    q=q+"W"*abs(a)
    if q.count("W")==s.count("W"):
        flag+=1
        # print("1")
if a>0:
    q=q+"E"*abs(a)
    if q.count("E")==s.count("E"):
        flag+=1
        # print("2")
if b<0:
    q=q+"S"*abs(b)
    if q.count("S")==s.count("S"):
        flag1+=1
        # print("3")
if b>0:
    q=q+"N"*abs(b)
    if q.count("N")==s.count("N"):
        flag1+=1
        # print("4")
# print(q,flag)
# d1=[]
# for i in q:
#     d1.append(q.count(i))
# print(d1)
# d={}
# for i in s:
#     d[i]=s.count(i)
# print(d)
# print(flag,flag1)
if flag>0 and flag1>0:
    print((a+b)*2)
else:
    print("-1")

