It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.
The single line contains integer *y* (1000 ≤ *y* ≤ 9000) — the year number.
import math
y = int(input())
a = math.trunc(y/1000)
b = math.trunc(y/100) - a*10
c = math.trunc(y/10) - a*100 - b*10
d = y - a*1000 - b*100 - c*10


for i in range(1,9000):
    x = y + i
    a = math.trunc(x/1000)
    b = math.trunc(x/100) - a*10
    c = math.trunc(x/10) - a*100 - b*10
    d = x - a*1000 - b*100 - c*10
    if a!=b and a!=c and a!=d and b!=c and b!=d and c!=d:
        print(x)
        break
    