It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.
The single line contains integer *y* (1000 ≤ *y* ≤ 9000) — the year number.
#!/usr/bin/env python3
# -*- coding: utf-8 -*-
"""
Created on Wed Sep 13 19:22:46 2023

@author: huangxiaoyuan
"""

s=int(input())
if 1000<=s<=9000:
    a=s//1000
    b=(s//100)%10
    c=(s//10)%10
    d=s%10
list=[a,b,c,d]
e=len(list)
list1=set(list)
f=len(list1)
if e==f:
    s=s+1
    a=s//1000
    b=(s//100)%10
    c=(s//10)%10
    d=s%10
    list=[a,b,c,d]
    e=len(list)
    list1=set(list)
    f=len(list1)     
    if e==f:
       print(s)
    else:
        while e!=f:
            s=s+1
            a=s//1000
            b=(s//100)%10
            c=(s//10)%10
            d=s%10
            list=[a,b,c,d]
            e=len(list)
            list1=set(list)
            f=len(list1)     
        print(s)
    
    
        
    