It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.
The single line contains integer *y* (1000 ≤ *y* ≤ 9000) — the year number.
# -*- coding: utf-8 -*-
"""Codeforce

Automatically generated by Colaboratory.

Original file is located at
    https://colab.research.google.com/drive/1XTEd3xULMSCXZWYeK6wKPXVsZ74tROB6
"""

# read the input
y = int(input())

# loop until we find a valid year
while True:
  # increment the year by one
  y += 1
  # convert the year to a string
  s = str(y)
  # create a set of digits
  d = set(s)
  # check if the size of the set is equal to the length of the string
  if len(d) == len(s):
    # print the answer and break the loop
    print(y)
    break



year = str(int(input()) + 1)
year_digit = ''
result = False

for itm in year:
  if itm not in year_digit:
    year_digit += itm
  else:
    result = False
print(year_digit)

