It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.
The single line contains integer *y* (1000 ≤ *y* ≤ 9000) — the year number.
def prov(a):
    a = str(a)
    A = []
    for i in range(len(a)):
        if a[i] not in A:
            A.append(a[i])
    if len(a) == len(A):
        return True
    else:
        return False
a = int(input())
a += 1
while not prov(a):
    a += 1
print(a)