It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.
The single line contains integer *y* (1000 ≤ *y* ≤ 9000) — the year number.
current_year=int(input())
test=current_year+1
l=[]
while(True):
    checker=test
    while(checker>0):
        unit=checker%10
        l.append(unit)
        checker=checker//10
    counter=0
    for i in l:
        counter=counter+l.count(i)
    if(counter==len(l)):
        break
    else:
        test+=1
        l=[]
print(test)

