Farmer John has just given the cows a program to play with! The program contains two integer variables, *x* and *y*, and performs the following operations on a sequence *a*<sub class="lower-index">1</sub>, *a*<sub class="lower-index">2</sub>, ..., *a*<sub class="lower-index">*n*</sub> of positive integers:
 1.  Initially, *x* = 1 and *y* = 0. If, after any step, *x* ≤ 0 or *x* &gt; *n*, the program immediately terminates. 1.  The program increases both *x* and *y* by a value equal to *a*<sub class="lower-index">*x*</sub> simultaneously. 1.  The program now increases *y* by *a*<sub class="lower-index">*x*</sub> while decreasing *x* by *a*<sub class="lower-index">*x*</sub>. 1.  The program executes steps 2 and 3 (first step 2, then step 3) repeatedly until it terminates (it may never terminate). So, the sequence of executed steps may start with: step 2, step 3, step 2, step 3, step 2 and so on. 
The cows are not very good at arithmetic though, and they want to see how the program works. Please help them!

You are given the sequence *a*<sub class="lower-index">2</sub>, *a*<sub class="lower-index">3</sub>, ..., *a*<sub class="lower-index">*n*</sub>. Suppose for each *i* (1 ≤ *i* ≤ *n* - 1) we run the program on the sequence *i*, *a*<sub class="lower-index">2</sub>, *a*<sub class="lower-index">3</sub>, ..., *a*<sub class="lower-index">*n*</sub>. For each such run output the final value of *y* if the program terminates or -1 if it does not terminate.
The first line contains a single integer, *n* (2 ≤ *n* ≤ 2·10<sup class="upper-index">5</sup>). The next line contains *n* - 1 space separated integers, *a*<sub class="lower-index">2</sub>, *a*<sub class="lower-index">3</sub>, ..., *a*<sub class="lower-index">*n*</sub> (1 ≤ *a*<sub class="lower-index">*i*</sub> ≤ 10<sup class="upper-index">9</sup>).
b=[None]*(2*100001)
def dfs(a,x1,y1,n,j)
    if x1<=0 || x1>n:
        return y1
    if x1==n:
        return -1
    if b[x1]!=None
        return y1
    else:
        if j%2==0:
            return b[x1]=dfs(a,x1-a[x1],y1+a[x1],n,j+1)
        else:
            return b[x1]=dfs(a,x1+a[x1],y1+a[x1],n,j+1)
        
n=input()
a=['0','1']
for i in range(2,n):
    a.append(input())
for i in range(1,n):
    a[1]=i
    t=dfs(a,1,0,n,1)
    print(t)
    