It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.
The single line contains integer *y* (1000 ≤ *y* ≤ 9000) — the year number.
def find_next_distinct_year(y):
    y += 1
    while len(set(str(y))) != len(str(y)):
        y += 1
    return y

# Read input
y = int(input())

# Find and print the minimum year number with distinct digits
print(find_next_distinct_year(y))
