It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.
The single line contains integer *y* (1000 ≤ *y* ≤ 9000) — the year number.
import sys
sum=0
y=int(input("the year number : "))

for i in range (y,9013) :
    l=str(i)
    sum=0
    for w in range(10):
     
     z=l.count(str(w))
     if z ==1 :
      sum=sum+1
      #print(sum)
      if sum == 4 and int(l)!=y:
       print(l) 
       sys.exit()
 
 #Salim
        
         
       
     
