The polar bears are going fishing. They plan to sail from (*s*<sub class="lower-index">*x*</sub>, *s*<sub class="lower-index">*y*</sub>) to (*e*<sub class="lower-index">*x*</sub>, *e*<sub class="lower-index">*y*</sub>). However, the boat can only sail by wind. At each second, the wind blows in one of these directions: east, south, west or north. Assume the boat is currently at (*x*, *y*).
 -  If the wind blows to the east, the boat will move to (*x* + 1, *y*). -  If the wind blows to the south, the boat will move to (*x*, *y* - 1). -  If the wind blows to the west, the boat will move to (*x* - 1, *y*). -  If the wind blows to the north, the boat will move to (*x*, *y* + 1). 
Alternatively, they can hold the boat by the anchor. In this case, the boat stays at (*x*, *y*). Given the wind direction for *t* seconds, what is the earliest time they sail to (*e*<sub class="lower-index">*x*</sub>, *e*<sub class="lower-index">*y*</sub>)?
The first line contains five integers *t*, *s*<sub class="lower-index">*x*</sub>, *s*<sub class="lower-index">*y*</sub>, *e*<sub class="lower-index">*x*</sub>, *e*<sub class="lower-index">*y*</sub> (1 ≤ *t* ≤ 10<sup class="upper-index">5</sup>,  - 10<sup class="upper-index">9</sup> ≤ *s*<sub class="lower-index">*x*</sub>, *s*<sub class="lower-index">*y*</sub>, *e*<sub class="lower-index">*x*</sub>, *e*<sub class="lower-index">*y*</sub> ≤ 10<sup class="upper-index">9</sup>). The starting location and the ending location will be different.

The second line contains *t* characters, the *i*-th character is the wind blowing direction at the *i*-th second. It will be one of the four possibilities: "E" (east), "S" (south), "W" (west) and "N" (north).
arr=[int(x) for x in input().split()]
string=input()
xDist=arr[3]-arr[1]
yDist=arr[4]-arr[2]
N=0
W=0
E=0
S=0
if xDist<0:
    W=-1*xDist
if xDist>0:
    E=xDist
if yDist>0:
    N=yDist
if yDist<0:
    S=-1*yDist
if string.count('N')>=N and string.count('S')>=S and string.count('W')>=W and string.count('E')>=E:
    n=len(string)
    while(True):
        if string[:n].count('N')>=N and string[:n].count('S')>=S and string[:n].count('W')>=W and string[:n].count('E')>=E:
            n-=1
            continue
        else:
            break
    if (n+1)<=arr[0]:
        print(n+1)
    else:
        print(-1)
else:
    print(-1)
    