The polar bears are going fishing. They plan to sail from (*s*<sub class="lower-index">*x*</sub>, *s*<sub class="lower-index">*y*</sub>) to (*e*<sub class="lower-index">*x*</sub>, *e*<sub class="lower-index">*y*</sub>). However, the boat can only sail by wind. At each second, the wind blows in one of these directions: east, south, west or north. Assume the boat is currently at (*x*, *y*).
 -  If the wind blows to the east, the boat will move to (*x* + 1, *y*). -  If the wind blows to the south, the boat will move to (*x*, *y* - 1). -  If the wind blows to the west, the boat will move to (*x* - 1, *y*). -  If the wind blows to the north, the boat will move to (*x*, *y* + 1). 
Alternatively, they can hold the boat by the anchor. In this case, the boat stays at (*x*, *y*). Given the wind direction for *t* seconds, what is the earliest time they sail to (*e*<sub class="lower-index">*x*</sub>, *e*<sub class="lower-index">*y*</sub>)?
The first line contains five integers *t*, *s*<sub class="lower-index">*x*</sub>, *s*<sub class="lower-index">*y*</sub>, *e*<sub class="lower-index">*x*</sub>, *e*<sub class="lower-index">*y*</sub> (1 ≤ *t* ≤ 10<sup class="upper-index">5</sup>,  - 10<sup class="upper-index">9</sup> ≤ *s*<sub class="lower-index">*x*</sub>, *s*<sub class="lower-index">*y*</sub>, *e*<sub class="lower-index">*x*</sub>, *e*<sub class="lower-index">*y*</sub> ≤ 10<sup class="upper-index">9</sup>). The starting location and the ending location will be different.

The second line contains *t* characters, the *i*-th character is the wind blowing direction at the *i*-th second. It will be one of the four possibilities: "E" (east), "S" (south), "W" (west) and "N" (north).
#https://codeforces.com/problemset/problem/276/B



from collections import defaultdict
t , x1,y1,x2,y2=map(int,input().split())
s =input()
dif1 =x2-x1 
dif2=y2-y1

if dif1>0:
    c1='E'
else:
    c1='W'
if dif2>0:
    c2='N'
else:
    c2='S'
dif1 =abs(x2-x1) 
dif2=abs(y2-y1)
c=0
ans =-1
s1=s2=0
for i in  s:
    c+=1
    if i==c1:
        s1+=1 
    elif i==c2:
        s2+=1 
    if s1>=dif1 and s2>= dif2:
        ans=c
        break
print(ans)
        
        
    

