It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.
The single line contains integer *y* (1000 ≤ *y* ≤ 9000) — the year number.
def distinct(n):
    l = list(str(n))
    alreadyhave = []
    isDistinct = True
    for i in range(len(l)):
        if(l[i] not in alreadyhave):
            alreadyhave.append(l[i])
        else:
            isDistinct = False
    return isDistinct

y = int(input())
found = False
n = y+1
while found == False:
    if distinct(n) == True:
        break
    else:
        n += 1
print(n)
