Fox Ciel has a board with *n* rows and *n* columns. So, the board consists of *n* × *n* cells. Each cell contains either a symbol '.', or a symbol '#'.

A cross on the board is a connected set of exactly five cells of the board that looks like a cross. The picture below shows how it looks.

Ciel wants to draw several (may be zero) crosses on the board. Each cross must cover exactly five cells with symbols '#', and any cell with symbol '#' must belong to some cross. No two crosses can share a cell.

Please, tell Ciel if she can draw the crosses in the described way.
The first line contains an integer *n* (3 ≤ *n* ≤ 100) — the size of the board.

Each of the next *n* lines describes one row of the board. The *i*-th line describes the *i*-th row of the board and consists of *n* characters. Each character is either a symbol '.', or a symbol '#'.
import sys,math
from collections import defaultdict,Counter
def li(): return list(map(int,sys.stdin.readline().split()))
def ls(): return list(map(int,list(input())))
def la(): return list(input())
def ii():  return int(input())
n = ii()
matrix= []
for _ in range(n):
    matrix.append(la())
for i in range(1,n-1):
    for j in range(1,n-1):
        if matrix[i][j] == "#" and matrix[i-1][j] == "#" and matrix[i+1][j] == "#" and matrix[i][j-1] == "#" and matrix[i][j+1] == "#" :
            matrix[i][j] = "."
            matrix[i-1][j] = "."
            matrix[i+1][j] = "."
            matrix[i][j-1] = "."
            matrix[i][j+1] = "."
            
for i in range(n):
    flag = 0
    for j in range(n):
        if matrix[i][j] == "#":
            flag = 1
            break
    if flag :
        break
 
if flag :
    print("NO")
else:
    print("YES")
    