Prof. Vasechkin wants to represent positive integer *n* as a sum of addends, where each addends is an integer number containing only 1s. For example, he can represent 121 as 121=111+11+–1. Help him to find the least number of digits 1 in such sum.
The first line of the input contains integer *n* (1 ≤ *n* &lt; 10<sup class="upper-index">15</sup>).
from sys import stdin, stdout
import math,sys,heapq
from itertools import permutations, combinations
from collections import defaultdict,deque,OrderedDict
from os import path
import bisect as bi
def yes():print('YES')
def no():print('NO')
if (path.exists('input.txt')): 
    #------------------Sublime--------------------------------------#
    sys.stdin=open('input.txt','r');sys.stdout=open('output.txt','w');
    def I():return (int(input()))
    def In():return(map(int,input().split()))
else:
    #------------------PYPY FAst I/o--------------------------------#
    def I():return (int(stdin.readline()))
    def In():return(map(int,stdin.readline().split()))

def dict(a):
    d={}
    for x in a:
        if d.get(x,-1)!=-1:
            d[x]+=1
        else:
            d[x]=1
    return d

def find_gt(a, x):
    'Find leftmost value greater than x'
    i = bi.bisect_right(a, x)
    if i != len(a):
        return i
    else:            
        return -1

def main():
    try:
        n=input()
        last,ans=-1,0
        for x in range(len(n)):
            if last==-1:
                ans+=int(n[x])*(len(n)-x)
                last=int(n[x])
            else:
                if int(n[x])>last:
                    ans+=(int(n[x])-last)*(len(n)-x)
                    last=int(n[x])
                elif int(n[x])<last:
                    ans+=(last-int(n[x]))*(len(n)-x)
                    last=int(n[x])
                else:
                    continue
        print(ans)


    except:
        pass
        
M = 998244353
P = 1000000007
 
if __name__ == '__main__':
    #for _ in range(I()):main()
    for _ in range(1):main()


