Fox Ciel has a board with *n* rows and *n* columns. So, the board consists of *n* × *n* cells. Each cell contains either a symbol '.', or a symbol '#'.

A cross on the board is a connected set of exactly five cells of the board that looks like a cross. The picture below shows how it looks.

Ciel wants to draw several (may be zero) crosses on the board. Each cross must cover exactly five cells with symbols '#', and any cell with symbol '#' must belong to some cross. No two crosses can share a cell.

Please, tell Ciel if she can draw the crosses in the described way.
The first line contains an integer *n* (3 ≤ *n* ≤ 100) — the size of the board.

Each of the next *n* lines describes one row of the board. The *i*-th line describes the *i*-th row of the board and consists of *n* characters. Each character is either a symbol '.', or a symbol '#'.
n=int(input())
x=[]

for i in range(n):
    x.append(list(input()))

for i in range(n):
    for j in range(n):
        if x[i][j]=='#':
            if i==0 or i==n-1 or j==0 or j==n-1:
                x[i][j]='X'
            elif x[i-1][j]=='X' and x[i+1][j]=='X' and x[i][j+1]=='X' and x[i][j-1]=='X':
                pass
            else:
                x[i][j]='X'


for i in range(n):
    for j in range(n):
        t=0
        if x[i][j]=='X':
            try:
                if x[i][j+1]=='#':
                    t=1
            except IndexError:
                pass
            try:
                if x[i][j-1]=='#':
                    t=1
            except IndexError:
                pass
            try:
                if x[i+1][j]=='#':
                    t=1
            except IndexError:
                pass
            try:
                if x[i-1][j]=='#':
                    t=1
            except IndexError:
                pass
            if t==0:
                print('NO')
                quit()
print('YES')
