You have number *a*, whose decimal representation quite luckily contains digits 1, 6, 8, 9. Rearrange the digits in its decimal representation so that the resulting number will be divisible by 7.

Number *a* doesn't contain any leading zeroes and contains digits 1, 6, 8, 9 (it also can contain another digits). The resulting number also mustn't contain any leading zeroes.
The first line contains positive integer *a* in the decimal record. It is guaranteed that the record of number *a* contains digits: 1, 6, 8, 9. Number *a* doesn't contain any leading zeroes. The decimal representation of number *a* contains at least 4 and at most 10<sup class="upper-index">6</sup> characters.
import sys
input = sys.stdin.readline
# import bisect #-->For bisect.bisect_left=lower_bound and bisect_right=upper_bound

s = input().rstrip()
d = {0:"1869", 1:"1968", 2:"1689", 3:"6198", 4:"1698", 5:"1986", 6:"1896"}
s = s.replace('1', '', 1)\
     .replace('6', '', 1)\
     .replace('8', '', 1)\
     .replace('9', '', 1)
x = 0
for i in s[::-1]:
    x = ((x - int(i) + 14) * 5) % 7
print(d[x], s, sep = "")