You have number *a*, whose decimal representation quite luckily contains digits 1, 6, 8, 9. Rearrange the digits in its decimal representation so that the resulting number will be divisible by 7.

Number *a* doesn't contain any leading zeroes and contains digits 1, 6, 8, 9 (it also can contain another digits). The resulting number also mustn't contain any leading zeroes.
The first line contains positive integer *a* in the decimal record. It is guaranteed that the record of number *a* contains digits: 1, 6, 8, 9. Number *a* doesn't contain any leading zeroes. The decimal representation of number *a* contains at least 4 and at most 10<sup class="upper-index">6</sup> characters.
from collections import Counter
d = {3: '9816', 6: '8691', 0: '9681', 2: '8196', 5: '8961', 4: '9861', 1: '6891'}
n = input()
count = Counter(n)

c = 0 
for i in range(9,0,-1):
    if i==9 or i==8 or i==6 or i==1:
        count[i]-=1
        
    for j in range(count[i]):
        c = c*10+i
        c = c%7 
        ll+=str(i)
ll = ll+d[c]+'0'*count['0']
print(ll)