Sometimes one has to spell email addresses over the phone. Then one usually pronounces a dot as dot, an at sign as at. As a result, we get something like vasyaatgmaildotcom. Your task is to transform it into a proper email address ([[email protected]](/cdn-cgi/l/email-protection)). 

It is known that a proper email address contains only such symbols as . @ and lower-case Latin letters, doesn't start with and doesn't end with a dot. Also, a proper email address doesn't start with and doesn't end with an at sign. Moreover, an email address contains exactly one such symbol as @, yet may contain any number (possible, zero) of dots. 

You have to carry out a series of replacements so that the length of the result was as short as possible and it was a proper email address. If the lengths are equal, you should print the lexicographically minimal result. 

Overall, two variants of replacement are possible: dot can be replaced by a dot, at can be replaced by an at.
The first line contains the email address description. It is guaranteed that that is a proper email address with all the dots replaced by dot an the at signs replaced by at. The line is not empty and its length does not exceed 100 symbols.
s=input()
if s[:3]=="dot" or s[:2]=="at" or s[len(s)-2:]=="at" or s[len(s)-3:]=="dot":
    if s[:3]=="dot":
        t=s[3:]
        a=t.split('dot')
        l=".".join(a)
        b=l.find("at")
        o=l[:b]+"@"+l[b+2:]
        q="dot"+o
        if q[-1]==".":
            a=q[:len(q)-1]
            s=a+"dot"
        if q[-1]=="@":
            a=q[:len(q)-1]
            s=a+"at"


    if s[:2]=="at":
        t=s[2:]
        a=t.split('dot')
        l=".".join(a)
        b=l.find('at')
        o=l[:b]+"@"+l[b+2:]
        q="at"+o
        if q[-1]==".":
            a=q[:len(q)-1]
            s=a+"dot"
        if q[-1]=="@":
            a=q[:len(q)-1]
            s=a+"at"

    if s[len(s)-3:]=="dot":
        t=s[:len(s)-3]
        a=t.split('dot')
        l=".".join(a)
        b=l.find('at')
        q=l[:b]+"@"+l[b+2:]
        s=q+"dot"
    if s[len(s)-2:]=="at":
        t=s[:len(s)-2]
        a=t.split('dot')
        l=".".join(a)
        b=l.find('at')
        q=l[:b]+"@"+l[b+2:]
        s=q+"at"


    print(s)

else:
    a=s.split('dot')
    l=".".join(a)
    b=l.find('at')
    q=l[:b]+"@"+l[b+2:]
    print(q)