You have number *a*, whose decimal representation quite luckily contains digits 1, 6, 8, 9. Rearrange the digits in its decimal representation so that the resulting number will be divisible by 7.

Number *a* doesn't contain any leading zeroes and contains digits 1, 6, 8, 9 (it also can contain another digits). The resulting number also mustn't contain any leading zeroes.
The first line contains positive integer *a* in the decimal record. It is guaranteed that the record of number *a* contains digits: 1, 6, 8, 9. Number *a* doesn't contain any leading zeroes. The decimal representation of number *a* contains at least 4 and at most 10<sup class="upper-index">6</sup> characters.
import sys
input = sys.stdin.readline
from itertools import permutations
from collections import Counter

s = input()[:-1]
w = Counter(s)
a = '1689'
for i in a:
    w[i] -= 1
s = ''.join([i*w[i] for i in w if i != '0'])
p = set(map(lambda x:''.join(x), permutations(a, 4)))
for i in p:
    if int(s+i)%7 == 0:
        print(s+i+'0'*w['0'])
        exit()
print(0)