You have number *a*, whose decimal representation quite luckily contains digits 1, 6, 8, 9. Rearrange the digits in its decimal representation so that the resulting number will be divisible by 7.

Number *a* doesn't contain any leading zeroes and contains digits 1, 6, 8, 9 (it also can contain another digits). The resulting number also mustn't contain any leading zeroes.
The first line contains positive integer *a* in the decimal record. It is guaranteed that the record of number *a* contains digits: 1, 6, 8, 9. Number *a* doesn't contain any leading zeroes. The decimal representation of number *a* contains at least 4 and at most 10<sup class="upper-index">6</sup> characters.
# https://codeforces.com/problemset/problem/375/A

from itertools import permutations


# 1-6198
# 2-1896
# 3-1689
# 4-1986
# 5-1968
# 6-1698

def div_seven(num):
    if (int(num) % 7 == 0):
        return num
    seven = {0: '1869', 1: '6198', 2: '1896', 3: '1689', 4: '1986', 5: '1968', 6: '1698'}
    k = len(num)
    num = num.replace('1', '', 1)
    num = num.replace('6', '', 1)
    num = num.replace('8', '', 1)
    num = num.replace('9', '', 1)
    # print(num)
    if (num == ''):
        num = '0'
    temp = int(num) % 7
    num += seven[temp]
    num = str(int(num))
    num += (k - len(num)) * '0'
    return num


a = input().strip()
print(div_seven(a))
