Fox Ciel has a board with *n* rows and *n* columns. So, the board consists of *n* × *n* cells. Each cell contains either a symbol '.', or a symbol '#'.

A cross on the board is a connected set of exactly five cells of the board that looks like a cross. The picture below shows how it looks.

Ciel wants to draw several (may be zero) crosses on the board. Each cross must cover exactly five cells with symbols '#', and any cell with symbol '#' must belong to some cross. No two crosses can share a cell.

Please, tell Ciel if she can draw the crosses in the described way.
The first line contains an integer *n* (3 ≤ *n* ≤ 100) — the size of the board.

Each of the next *n* lines describes one row of the board. The *i*-th line describes the *i*-th row of the board and consists of *n* characters. Each character is either a symbol '.', or a symbol '#'.
tam=int(input())
matriz=[]
contador=0
for i in range(tam):
    matriz.append(list(input()))
    contador+=matriz[i].count("#")
if contador%5!=0:
    print("NO")
else:
    i=1
    j=1
    while i <(tam-1):
        j=1
        while j<(tam-1):
            if(matriz[i][j]=="#"):
               
                if ((matriz[i-1][j] == "#") and (matriz[i][j-1] == "#") and (matriz[i+1][j] == "#") and (matriz[i][j+1] == "#")):
                    
                    matriz[i-1][j] = "."
                    matriz[i][j-1] = "."
                    matriz[i+1][j] = "."
                    matriz[i][j+1] = "."
                    matriz[i][j]="."
            j+=1
        i+=1
    
    falhou=False
    for i in range(tam):
        if matriz[i].count(".")!=0:
            print("NO")
            falhou=True
            break
    if not falhou:
         print("YES")
   				  			  			    			    	 	