Fox Ciel has a board with *n* rows and *n* columns. So, the board consists of *n* × *n* cells. Each cell contains either a symbol '.', or a symbol '#'.

A cross on the board is a connected set of exactly five cells of the board that looks like a cross. The picture below shows how it looks.

Ciel wants to draw several (may be zero) crosses on the board. Each cross must cover exactly five cells with symbols '#', and any cell with symbol '#' must belong to some cross. No two crosses can share a cell.

Please, tell Ciel if she can draw the crosses in the described way.
The first line contains an integer *n* (3 ≤ *n* ≤ 100) — the size of the board.

Each of the next *n* lines describes one row of the board. The *i*-th line describes the *i*-th row of the board and consists of *n* characters. Each character is either a symbol '.', or a symbol '#'.
n = int(input())
arr = []
for i in range(n):
    arr.append(list(input()))
k = 1
for i in range(n):
    for j in range(n):
        if arr[i][j] == '#':
            if i+2<=n-1 and j-1>=0 and j+1<=n-1:
                if arr[i+1][j-1] == '#' and arr[i+1][j] == '#' and arr[i+1][j+1] == '#' and arr[i+2][j] == '#':
                    arr[i+1][j-1] = '.'
                    arr[i+1][j] = '.'
                    arr[i+1][j+1] = '.'
                    arr[i+2][j] = '.'
                    arr[i][j] = '.'
                else:
                    k = 0
                    break
            else:
                k = 0
                break
if k == 1:
    print('YES')
else:
    print('NO')