Valera has got a rectangle table consisting of *n* rows and *m* columns. Valera numbered the table rows starting from one, from top to bottom and the columns – starting from one, from left to right. We will represent cell that is on the intersection of row *x* and column *y* by a pair of integers (*x*, *y*).

Valera wants to place exactly *k* tubes on his rectangle table. A tube is such sequence of table cells (*x*<sub class="lower-index">1</sub>, *y*<sub class="lower-index">1</sub>), (*x*<sub class="lower-index">2</sub>, *y*<sub class="lower-index">2</sub>), ..., (*x*<sub class="lower-index">*r*</sub>, *y*<sub class="lower-index">*r*</sub>), that: 
 -  *r* ≥ 2; -  for any integer *i* (1 ≤ *i* ≤ *r* - 1) the following equation |*x*<sub class="lower-index">*i*</sub> - *x*<sub class="lower-index">*i* + 1</sub>| + |*y*<sub class="lower-index">*i*</sub> - *y*<sub class="lower-index">*i* + 1</sub>| = 1 holds; -  each table cell, which belongs to the tube, must occur exactly once in the sequence. 
Valera thinks that the tubes are arranged in a fancy manner if the following conditions are fulfilled: 
 -  no pair of tubes has common cells; -  each cell of the table belongs to some tube. 
Help Valera to arrange *k* tubes on his rectangle table in a fancy manner.
The first line contains three space-separated integers *n*, *m*, *k* (2 ≤ *n*, *m* ≤ 300; 2 ≤ 2*k* ≤ *n*·*m*) — the number of rows, the number of columns and the number of tubes, correspondingly.
n,m,k=[int(x) for x in input().split()]
i=0
currx=1
curry=1
x=1
while i<k:
    if i==k-1:
        ans=[]
        while currx<=n and curry<=m:
            ans.append([currx,curry])
            if curry==1 and x==-1:
                currx+=1
                x=1
            elif curry==m and x==1:
                currx+=1
                x=-1
            else:
                curry+=x
        print(len(ans),end=' ')
        for i in ans:
            print(i[0],i[1],end=' ')
        break
    else:
        
        print(2,end=' ')
        print(currx,curry,end=' ')
        
        if curry==1 and x==-1:
            
            currx+=1
            x=1
        elif curry==m and x==1:
                
            currx+=1
            x=-1
        else:
            curry+=x
        print(currx,curry)
        if curry==1 and x==-1:
            currx+=1
            x=1
        elif curry==m and x==1:
                
            currx+=1
            x=-1
        else:
            curry+=x
        i+=1
        