Fox Ciel has a board with *n* rows and *n* columns. So, the board consists of *n* × *n* cells. Each cell contains either a symbol '.', or a symbol '#'.

A cross on the board is a connected set of exactly five cells of the board that looks like a cross. The picture below shows how it looks.

Ciel wants to draw several (may be zero) crosses on the board. Each cross must cover exactly five cells with symbols '#', and any cell with symbol '#' must belong to some cross. No two crosses can share a cell.

Please, tell Ciel if she can draw the crosses in the described way.
The first line contains an integer *n* (3 ≤ *n* ≤ 100) — the size of the board.

Each of the next *n* lines describes one row of the board. The *i*-th line describes the *i*-th row of the board and consists of *n* characters. Each character is either a symbol '.', or a symbol '#'.
mat = [] # 0 is '.'; 1 is unused "#" ; 2 is used'#';
n = int(input())
for i in range(0,n):
    line = list(input())
    mat.append([])
    for j in range(0,n):
        if line[j]=='.':
            mat[i].append(0)
        else:
            mat[i].append(1)
for i in range(1,n-1):
    for j in range(1,n-1):
        if mat[i][j] == 1 and mat[i+1][j]==1 and mat[i-1][j]==1 and mat[i][j+1]==1 and mat[i][j-1]==1:
            mat[i][j] = 2
            mat[i+1][j] = 2
            mat[i-1][j] = 2
            mat[i][j+1] = 2
            mat[i][j-1] = 2
unused_harshtags = 0
for i in range(0,n):
    for j in range(0,n):
        if mat[i][j] ==1:
            unused_harshtags +=1
if unused_harshtags >0:
    print("NO")
else:
    print("YES")
  	 	  		       					     					