You have number *a*, whose decimal representation quite luckily contains digits 1, 6, 8, 9. Rearrange the digits in its decimal representation so that the resulting number will be divisible by 7.

Number *a* doesn't contain any leading zeroes and contains digits 1, 6, 8, 9 (it also can contain another digits). The resulting number also mustn't contain any leading zeroes.
The first line contains positive integer *a* in the decimal record. It is guaranteed that the record of number *a* contains digits: 1, 6, 8, 9. Number *a* doesn't contain any leading zeroes. The decimal representation of number *a* contains at least 4 and at most 10<sup class="upper-index">6</sup> characters.

d = {3: '9816', 6: '8691', 0: '9681', 2: '8196', 5: '8961', 4: '9861', 1: '6891'}
n = input()
digits = {1:0,0:0,6:0,8:0,9:0}
i = 0
c = 0 
ll =''
while i<len(n):
    if i==0:
        digits[i]+=1
    elif i in digits and digits[i]==0:
        continue 
    else:
        c = c*10+int(n[i])
        ll+=n[i]
ll = ll+d[c]+'0'*digits[0]
print(ll)