You have number *a*, whose decimal representation quite luckily contains digits 1, 6, 8, 9. Rearrange the digits in its decimal representation so that the resulting number will be divisible by 7.

Number *a* doesn't contain any leading zeroes and contains digits 1, 6, 8, 9 (it also can contain another digits). The resulting number also mustn't contain any leading zeroes.
The first line contains positive integer *a* in the decimal record. It is guaranteed that the record of number *a* contains digits: 1, 6, 8, 9. Number *a* doesn't contain any leading zeroes. The decimal representation of number *a* contains at least 4 and at most 10<sup class="upper-index">6</sup> characters.
import sys
array=[1869,8196,9168,8691,6891,1689,1968]

N=[int(x) for x in list(sys.stdin.readline())]
numberlist=[0,-1,0,0,0,0,-1,0,-1,-1]

for i in N:
    numberlist[i]+=1
    
number=[]
for i in range(1,10):
    number=number+[i]*numberlist[i]
dummynumber=number+[0]*4
dummynumber=[str(x) for x in dummynumber]
dummynumber="".join(dummynumber)
dummynumber=int(dummynumber)+int(array[int(dummynumber)%7])
dummynumber=[dummynumber]+[0]*numberlist[0]
print(*dummynumber,sep="")