Fox Ciel has a board with *n* rows and *n* columns. So, the board consists of *n* × *n* cells. Each cell contains either a symbol '.', or a symbol '#'.

A cross on the board is a connected set of exactly five cells of the board that looks like a cross. The picture below shows how it looks.

Ciel wants to draw several (may be zero) crosses on the board. Each cross must cover exactly five cells with symbols '#', and any cell with symbol '#' must belong to some cross. No two crosses can share a cell.

Please, tell Ciel if she can draw the crosses in the described way.
The first line contains an integer *n* (3 ≤ *n* ≤ 100) — the size of the board.

Each of the next *n* lines describes one row of the board. The *i*-th line describes the *i*-th row of the board and consists of *n* characters. Each character is either a symbol '.', or a symbol '#'.
if __name__ == '__main__':
    n = int(input())
    x = [list(input()) for i in range(n)]
    y = [['.' for j in range(n)] for i in range(n)]

    error = False
    for i in range(n):
        for j in range(n):
            if x[i][j] == '.' and y[i][j] == '.':
                continue
            elif x[i][j] == '.' and y[i][j] == '#':
                error = True
                break
            elif x[i][j] == '#' and y[i][j] == '.':
                if j == 0 or j == n - 1 or i > n - 3:
                    error = True
                    break
                else:
                    y[i][j] = '#'
                    y[i + 1][j - 1] = '#'
                    y[i + 1][j] = '#'
                    y[i + 1][j + 1] = '#'
                    y[i + 2][j] = '#'

    if not error:
        print('YES')
    else:
        print('NO')
 	 					 		  	     				  				 	