Valera has got a rectangle table consisting of *n* rows and *m* columns. Valera numbered the table rows starting from one, from top to bottom and the columns – starting from one, from left to right. We will represent cell that is on the intersection of row *x* and column *y* by a pair of integers (*x*, *y*).

Valera wants to place exactly *k* tubes on his rectangle table. A tube is such sequence of table cells (*x*<sub class="lower-index">1</sub>, *y*<sub class="lower-index">1</sub>), (*x*<sub class="lower-index">2</sub>, *y*<sub class="lower-index">2</sub>), ..., (*x*<sub class="lower-index">*r*</sub>, *y*<sub class="lower-index">*r*</sub>), that: 
 -  *r* ≥ 2; -  for any integer *i* (1 ≤ *i* ≤ *r* - 1) the following equation |*x*<sub class="lower-index">*i*</sub> - *x*<sub class="lower-index">*i* + 1</sub>| + |*y*<sub class="lower-index">*i*</sub> - *y*<sub class="lower-index">*i* + 1</sub>| = 1 holds; -  each table cell, which belongs to the tube, must occur exactly once in the sequence. 
Valera thinks that the tubes are arranged in a fancy manner if the following conditions are fulfilled: 
 -  no pair of tubes has common cells; -  each cell of the table belongs to some tube. 
Help Valera to arrange *k* tubes on his rectangle table in a fancy manner.
The first line contains three space-separated integers *n*, *m*, *k* (2 ≤ *n*, *m* ≤ 300; 2 ≤ 2*k* ≤ *n*·*m*) — the number of rows, the number of columns and the number of tubes, correspondingly.
n, m, k = map(int, input().split())

c = []
r = [2] * (k - 1) + [n * m - 2 * (k - 1)]

no = 0
f = 1
x = 1
y = 1
for i in range(1, k):
    c.append([])
    for j in range(2):
        if y > m:
            f = -1
            y = m
            x += 1
        if y < 1:
            y = 1
            f = 1
            x += 1
        c[no] += [(x, y)]
        y += f
    no += 1

c.append([]) 
for j in range(r[-1]):
    if y > m:
        f = -1
        y = m
        x += 1
    if y < 1:
        y = 1
        f = 1
        x += 1
    c[no] += [(x, y)]
    y += f
for i in range(k):
    print(r[i],end=' ')
    for x, y in c[i]:
        print(x, y,end=' ')    
    print()
