You have number *a*, whose decimal representation quite luckily contains digits 1, 6, 8, 9. Rearrange the digits in its decimal representation so that the resulting number will be divisible by 7.

Number *a* doesn't contain any leading zeroes and contains digits 1, 6, 8, 9 (it also can contain another digits). The resulting number also mustn't contain any leading zeroes.
The first line contains positive integer *a* in the decimal record. It is guaranteed that the record of number *a* contains digits: 1, 6, 8, 9. Number *a* doesn't contain any leading zeroes. The decimal representation of number *a* contains at least 4 and at most 10<sup class="upper-index">6</sup> characters.
#fk this pos had to get this out off my not solved dumbass question
n = [int(d) for d in input()]
for x in [1,6,8,9]:
	for i in range(len(n)):
		if n[i]==x:
			del n[i]
			break
prefix = [1869,6189,1689,6198,1698,9861,1896]
L = sum([n[i]*pow(10,len(n)-i-1,7) for i in range(len(n))])%7
print(prefix[(-L)*pow(10,5*len(n),7)%7],end='')
print(*n, sep='')