Fox Ciel has a board with *n* rows and *n* columns. So, the board consists of *n* × *n* cells. Each cell contains either a symbol '.', or a symbol '#'.

A cross on the board is a connected set of exactly five cells of the board that looks like a cross. The picture below shows how it looks.

Ciel wants to draw several (may be zero) crosses on the board. Each cross must cover exactly five cells with symbols '#', and any cell with symbol '#' must belong to some cross. No two crosses can share a cell.

Please, tell Ciel if she can draw the crosses in the described way.
The first line contains an integer *n* (3 ≤ *n* ≤ 100) — the size of the board.

Each of the next *n* lines describes one row of the board. The *i*-th line describes the *i*-th row of the board and consists of *n* characters. Each character is either a symbol '.', or a symbol '#'.
n = int(input())

matrix = []

for i in range(n):
    row = input()
    matrix.append([*row])

count = 0
imp = False

for i in range(n):
    for j in range(n):
        if matrix[i][j] == "#":
            if i > n - 2 or j == 0 or j == n - 1:
                imp = True
                break
            else:
                if matrix[i+1][j-1] == '#' \
                and matrix[i+1][j] == '#' \
                and matrix[i+1][j+1] == '#' \
                and matrix[i+2][j] == '#':
                    matrix[i][j] = '.'
                    matrix[i+1][j-1] = '.'
                    matrix[i+1][j] = '.'
                    matrix[i+1][j+1] = '.'
                    matrix[i+2][j] = '.'
                else:
                    imp = True
                    break
    
    if imp:
        break

if imp:
    print("NO")
else:
    print("YES")