Fox Ciel has a board with *n* rows and *n* columns. So, the board consists of *n* × *n* cells. Each cell contains either a symbol '.', or a symbol '#'.

A cross on the board is a connected set of exactly five cells of the board that looks like a cross. The picture below shows how it looks.

Ciel wants to draw several (may be zero) crosses on the board. Each cross must cover exactly five cells with symbols '#', and any cell with symbol '#' must belong to some cross. No two crosses can share a cell.

Please, tell Ciel if she can draw the crosses in the described way.
The first line contains an integer *n* (3 ≤ *n* ≤ 100) — the size of the board.

Each of the next *n* lines describes one row of the board. The *i*-th line describes the *i*-th row of the board and consists of *n* characters. Each character is either a symbol '.', or a symbol '#'.
def corner(i, j):
   
   return (i == 0 and j == 0) \
        or (i == 0 and j == n-1) \
        or (i == n-1 and j == 0) \
        or (i == n-1 and j == n-1)

n = int(input())

matrix = []

for i in range(n):
    row = input()
    matrix.append(row)

count = 0
imp = False
centers = []
for i in range(n):
    for j in range(n):
        if matrix[i][j] == "#" and corner(i, j):
            imp = True
            break
        elif matrix[i][j] == "#":
            count += 1
            if (0 < i and i < n - 1) and (0 < j and j < n - 1) \
                and matrix[i-1][j] == "#" \
                and matrix[i+1][j] == "#" \
                and matrix[i][j-1] == "#" \
                and matrix[i][j+1] == "#":

                count -= 5

    if imp:
        break

if imp or count != 0:
    answer = "NO"
    print(answer)
else:
    answer = "YES"
    print(answer)