You have number *a*, whose decimal representation quite luckily contains digits 1, 6, 8, 9. Rearrange the digits in its decimal representation so that the resulting number will be divisible by 7.

Number *a* doesn't contain any leading zeroes and contains digits 1, 6, 8, 9 (it also can contain another digits). The resulting number also mustn't contain any leading zeroes.
The first line contains positive integer *a* in the decimal record. It is guaranteed that the record of number *a* contains digits: 1, 6, 8, 9. Number *a* doesn't contain any leading zeroes. The decimal representation of number *a* contains at least 4 and at most 10<sup class="upper-index">6</sup> characters.
perms = [('1', '6', '8', '9'), ('1', '6', '9', '8'), ('1', '8', '6', '9'), ('1', '8', '9', '6'), ('1', '9', '6', '8'), ('1', '9', '8', '6'), ('6', '1', '8', '9'), ('6', '1', '9', '8'), ('6', '8', '1', '9'), ('6', '8', '9', '1'), ('6', '9', '1', '8'), ('6', '9', '8', '1'), ('8', '1', '6', '9'), ('8', '1', '9', '6'), ('8', '6', '1', '9'), ('8', '6', '9', '1'), ('8', '9', '1', '6'), ('8', '9', '6', '1'), ('9', '1', '6', '8'), ('9', '1', '8', '6'), ('9', '6', '1', '8'), ('9', '6', '8', '1'), ('9', '8', '1', '6'), ('9', '8', '6', '1')]

n = input()
zeros = [x for x in n if x == '0']
n = [x for x in n if x != '0']
forbid = [n.index('1'), n.index('6'), n.index('8'), n.index('9')]
n = [x for i, x in enumerate(n) if i not in forbid]

n = "".join(n)
zeros = "".join(zeros)

for p in perms:
    number = int(n + "".join(p) + zeros)
    if number % 7 == 0:
        print(number)
        exit(0)
print(0)


