Fox Ciel has a board with *n* rows and *n* columns. So, the board consists of *n* × *n* cells. Each cell contains either a symbol '.', or a symbol '#'.

A cross on the board is a connected set of exactly five cells of the board that looks like a cross. The picture below shows how it looks.

Ciel wants to draw several (may be zero) crosses on the board. Each cross must cover exactly five cells with symbols '#', and any cell with symbol '#' must belong to some cross. No two crosses can share a cell.

Please, tell Ciel if she can draw the crosses in the described way.
The first line contains an integer *n* (3 ≤ *n* ≤ 100) — the size of the board.

Each of the next *n* lines describes one row of the board. The *i*-th line describes the *i*-th row of the board and consists of *n* characters. Each character is either a symbol '.', or a symbol '#'.
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## Author:      GogolGrind
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from sys import *
from math import *

def solve():
    n = int(input())
    f = []
    for i in range(n):
        f.append(list(map(str,input())))
    k = 1
    leftover = 0
    for i in range(n):
        for j in range(n):
            if (f[i][j] == '#'):
                if (i+k < n and j+k < n and i-k >= 0 and j-k >= 0 and f[i+k][j] == '#' and f[i][j+k] == '#' and f[i-k][j] == '#' and f[i][j-k] == '#'  ):
                        leftover -= 5              
    for i in range(n):
        for j in range(n):
            if (f[i][j] == '#'):
                leftover += 1
    return leftover == 0
     
def main ():
    t = 1
    for ii in range(t):
        print ('YES' if solve() else 'NO')
        
if __name__ == '__main__':
    main()
