Chubby Yang is studying linear equations right now. He came up with a nice problem. In the problem you are given an *n* × *n* matrix *W*, consisting of integers, and you should find two *n* × *n* matrices *A* and *B*, all the following conditions must hold: 
 -  *A*<sub class="lower-index">*ij*</sub> = *A*<sub class="lower-index">*ji*</sub>, for all *i*, *j* (1 ≤ *i*, *j* ≤ *n*); -  *B*<sub class="lower-index">*ij*</sub> =  - *B*<sub class="lower-index">*ji*</sub>, for all *i*, *j* (1 ≤ *i*, *j* ≤ *n*); -  *W*<sub class="lower-index">*ij*</sub> = *A*<sub class="lower-index">*ij*</sub> + *B*<sub class="lower-index">*ij*</sub>, for all *i*, *j* (1 ≤ *i*, *j* ≤ *n*). 
Can you solve the problem?
The first line contains an integer *n* (1 ≤ *n* ≤ 170). Each of the following *n* lines contains *n* integers. The *j*-th integer in the *i*-th line is *W*<sub class="lower-index">*ij*</sub> (0 ≤ |*W*<sub class="lower-index">*ij*</sub>| &lt; 1717).
'''

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'''
n = int(input())
matrix = [] 
for i in range(n):
    listA = input().split()
    for i in range(0,len(listA)):
        listA[i] = int(listA[i])
    matrix.append(listA)
matAt = [[0 for x in range(n)] for y in range(n)]
matBt = [[0 for x in range(n)] for y in range(n)]
for i in range(n):
    for j in range(n):
        matAt[i][j] = matrix[j][i]
        matAt[i][j] = float(matAt[i][j] + matrix[i][j])/2
for i in range(n):
    for j in range(n):
        matBt[i][j] = 0 - matrix[j][i]
        matBt[i][j] = float(matBt[i][j] + matrix[i][j])/2

for i in range(n):
    print(*matAt[i])
for i in range(n):
    print(*matBt[i])

