You have number *a*, whose decimal representation quite luckily contains digits 1, 6, 8, 9. Rearrange the digits in its decimal representation so that the resulting number will be divisible by 7.

Number *a* doesn't contain any leading zeroes and contains digits 1, 6, 8, 9 (it also can contain another digits). The resulting number also mustn't contain any leading zeroes.
The first line contains positive integer *a* in the decimal record. It is guaranteed that the record of number *a* contains digits: 1, 6, 8, 9. Number *a* doesn't contain any leading zeroes. The decimal representation of number *a* contains at least 4 and at most 10<sup class="upper-index">6</sup> characters.
import sys
import math

def sin():
	return int(sys.stdin.readline())

def array():
	return list(map(int, sys.stdin.readline().strip().split()))

def two():
	return map(int, sys.stdin.readline().strip().split())

def multiple():
	return [int(x) for x in sys.stdin.readline().split()]

def string():
	return sys.stdin.readline().strip()

from itertools import permutations


n = sin()

l = list(permutations(["1","8","6","9"]))

check = set()
zero = []
ans = []

for i in str(n):
	if i == "1" and i not in check:
		check.add(i)
	elif i == "6" and i not in check:
		check.add(i)
	elif i == "8" and i not in check:
		check.add(i)
	elif i == "9" and i not in check:
		check.add(i)
	elif i == "0":
		zero.append(i)
	else:
		ans.append(i)

res = 0

ans = "".join(ans)
zero = "".join(zero)

for i in l:
	x = "".join(i)
	y = ans + x + zero
	if int(y) % 7 == 0:
		res = int(y)

print(res)