Fox Ciel is playing a game with numbers now. 

Ciel has *n* positive integers: *x*<sub class="lower-index">1</sub>, *x*<sub class="lower-index">2</sub>, ..., *x*<sub class="lower-index">*n*</sub>. She can do the following operation as many times as needed: select two different indexes *i* and *j* such that *x*<sub class="lower-index">*i*</sub> &gt; *x*<sub class="lower-index">*j*</sub> hold, and then apply assignment *x*<sub class="lower-index">*i*</sub> = *x*<sub class="lower-index">*i*</sub> - *x*<sub class="lower-index">*j*</sub>. The goal is to make the sum of all numbers as small as possible.

Please help Ciel to find this minimal sum.
The first line contains an integer *n* (2 ≤ *n* ≤ 100). Then the second line contains *n* integers: *x*<sub class="lower-index">1</sub>, *x*<sub class="lower-index">2</sub>, ..., *x*<sub class="lower-index">*n*</sub> (1 ≤ *x*<sub class="lower-index">*i*</sub> ≤ 100).
from sys  import stdin,stdout

st=lambda:list(stdin.readline().strip())
li=lambda:list(map(int,stdin.readline().split()))
mp=lambda:map(int,stdin.readline().split())
inp=lambda:int(stdin.readline())
pr=lambda n: stdout.write(str(n)+"\n")
from  math import floor
mod=1000000007
INF= float('inf')
def solve():
    n=inp()
    l=li()
    i=0
    l.sort()
    while i<n:
        f=1
        while f:
            p=0
            for j in range(n):
                if i==j:
                    continue
                if l[j]>l[i]:
                    l[j]-=l[i]
                    p+=1
            if p==0:
                break
        i+=1

    pr(sum(l))
  
for _ in range(1):
    solve()
