Fox Ciel has a board with *n* rows and *n* columns. So, the board consists of *n* × *n* cells. Each cell contains either a symbol '.', or a symbol '#'.

A cross on the board is a connected set of exactly five cells of the board that looks like a cross. The picture below shows how it looks.

Ciel wants to draw several (may be zero) crosses on the board. Each cross must cover exactly five cells with symbols '#', and any cell with symbol '#' must belong to some cross. No two crosses can share a cell.

Please, tell Ciel if she can draw the crosses in the described way.
The first line contains an integer *n* (3 ≤ *n* ≤ 100) — the size of the board.

Each of the next *n* lines describes one row of the board. The *i*-th line describes the *i*-th row of the board and consists of *n* characters. Each character is either a symbol '.', or a symbol '#'.
k = int(input())
a = []
for i in range(k):
    ai = []
    s = input()
    for ch in s:
        if ch != '.':
            ai.append(1)
        else:
            ai.append(0)
    a.append(ai)
failed = False
for i in range(k):
    for j in range(k):
        if a[i][j] == 1:
            if j == 0 or j == k - 1 or i > k - 3:
                failed = True
                break
            if a[i + 1][j - 1] == a[i + 1][j] == a[i + 1][j + 1] == a[i + 2][j] == 1:
                a[i][j] = 0
                a[i + 1][j - 1] = 0
                a[i + 1][j] = 0
                a[i + 1][j + 1] = 0
                a[i + 2][j] = 0
            else:
                failed = True
                break
    if failed:
        break
if not failed:
    print("YES")
else:
    print("NO")
