Fox Ciel has a board with *n* rows and *n* columns. So, the board consists of *n* × *n* cells. Each cell contains either a symbol '.', or a symbol '#'.

A cross on the board is a connected set of exactly five cells of the board that looks like a cross. The picture below shows how it looks.

Ciel wants to draw several (may be zero) crosses on the board. Each cross must cover exactly five cells with symbols '#', and any cell with symbol '#' must belong to some cross. No two crosses can share a cell.

Please, tell Ciel if she can draw the crosses in the described way.
The first line contains an integer *n* (3 ≤ *n* ≤ 100) — the size of the board.

Each of the next *n* lines describes one row of the board. The *i*-th line describes the *i*-th row of the board and consists of *n* characters. Each character is either a symbol '.', or a symbol '#'.
n = int(input())
matriz = []
yes = True
listNull = []
for i in range(n+4):
    listNull.append('.')
for i in range(n+4):
    if(i == 0 or i == 1 or i == n+2 or i == n+3):
        matriz.append(listNull)
    else:
        lista = list(input())
        lista.insert(0, '.')
        lista.insert(1, '.')
        lista.append('.')
        lista.append('.')
        matriz.append(lista)

flag = True
for i in range(2,n+2):
    for j in range(2,n+2):
        if(matriz[i][j] == '#'):
            if(matriz[i+1][j] == '#' and matriz[i+2][j] and matriz[i+1][j-1] and matriz[i+1][j+1]):
                matriz[i][j] = '.'
                matriz[i+1][j] = '.'
                matriz[i+2][j] = '.'
                matriz[i+1][j-1] = '.'
                matriz[i+1][j+1] = '.'
            else:
                flag = False
                break
    if(flag == False):
        break
if(flag == False):
    print('NO')
else:
    print('YES')
        

	 					 	  		 	      		  	 			