Fox Ciel has a board with *n* rows and *n* columns. So, the board consists of *n* × *n* cells. Each cell contains either a symbol '.', or a symbol '#'.

A cross on the board is a connected set of exactly five cells of the board that looks like a cross. The picture below shows how it looks.

Ciel wants to draw several (may be zero) crosses on the board. Each cross must cover exactly five cells with symbols '#', and any cell with symbol '#' must belong to some cross. No two crosses can share a cell.

Please, tell Ciel if she can draw the crosses in the described way.
The first line contains an integer *n* (3 ≤ *n* ≤ 100) — the size of the board.

Each of the next *n* lines describes one row of the board. The *i*-th line describes the *i*-th row of the board and consists of *n* characters. Each character is either a symbol '.', or a symbol '#'.
n = int(input())
rows = [list(input()) for x in range(n)]
a = 0
for x in rows:
    a += x.count("#")
if a % 5 == 0:
    for x in range(1, n - 1):
        for y in range(1, n - 1):
            if rows[x][y] == "#" and rows[x - 1][y] == "#" and rows[x + 1][y] == "#" and rows[x][y - 1] == "#" and rows[x][y + 1] == "#":
                rows[x][y] = rows[x - 1][y] = rows[x + 1][y] = rows[x][y - 1] = rows[x][y + 1] = "."
    for x in rows:
        for y in x:
            if y == "#":
                print("NO")
                break
        else:
            continue
        break
    else:
        print("YES")
else:
    print("NO")