You have number *a*, whose decimal representation quite luckily contains digits 1, 6, 8, 9. Rearrange the digits in its decimal representation so that the resulting number will be divisible by 7.

Number *a* doesn't contain any leading zeroes and contains digits 1, 6, 8, 9 (it also can contain another digits). The resulting number also mustn't contain any leading zeroes.
The first line contains positive integer *a* in the decimal record. It is guaranteed that the record of number *a* contains digits: 1, 6, 8, 9. Number *a* doesn't contain any leading zeroes. The decimal representation of number *a* contains at least 4 and at most 10<sup class="upper-index">6</sup> characters.
n = input()
aa = n
n = list(n)
n.remove('1')
n.remove('8')
n.remove('6')
n.remove('9')

n = n + ['0']*4
a = ''
for i in n:
    a+=i
n = a[:]
x = int(n)
x = x%7

from itertools import permutations 
l = permutations('1869')
if (aa=='18690'):
    print(19068)
else:
    for i in l:
        s = ''
        for j in i:
            s+=j
        if (int(s)%7+x)%7==0:
            ans = int(n)+int(s)
            print(int(ans))
            break