Fox Ciel has a board with *n* rows and *n* columns. So, the board consists of *n* × *n* cells. Each cell contains either a symbol '.', or a symbol '#'.

A cross on the board is a connected set of exactly five cells of the board that looks like a cross. The picture below shows how it looks.

Ciel wants to draw several (may be zero) crosses on the board. Each cross must cover exactly five cells with symbols '#', and any cell with symbol '#' must belong to some cross. No two crosses can share a cell.

Please, tell Ciel if she can draw the crosses in the described way.
The first line contains an integer *n* (3 ≤ *n* ≤ 100) — the size of the board.

Each of the next *n* lines describes one row of the board. The *i*-th line describes the *i*-th row of the board and consists of *n* characters. Each character is either a symbol '.', or a symbol '#'.
import math
import string

def can_i_draw_cross(i, j, t):
    if j < 1 or j > len(t) - 2 or i > len(t) - 3:
        return False
    if t[i + 1][j] == "#" and t[i + 2][j] == "#" and t[i + 1][j + 1] == "#" and t[i + 1][j - 1] == "#":
        t[i][j] = "."
        t[i + 1][j] = "."
        t[i + 1][j + 1] = "."
        t[i + 1][j - 1] = "."
        t[i + 2][j] = "."
        return True
    else:
        return False




def main_function():
    table = [list(input()) for i in range(int(input()))]
    cant_make_it = False
    for i in range(len(table)):
        for j in range(len(table)):
            if table[i][j] == "#":
                if not can_i_draw_cross(i, j, table):
                    print("NO")
                    cant_make_it = True
                    break
        if cant_make_it:
            break
    if not cant_make_it:
        print("YES")







main_function()
