Fox Ciel has a board with *n* rows and *n* columns. So, the board consists of *n* × *n* cells. Each cell contains either a symbol '.', or a symbol '#'.

A cross on the board is a connected set of exactly five cells of the board that looks like a cross. The picture below shows how it looks.

Ciel wants to draw several (may be zero) crosses on the board. Each cross must cover exactly five cells with symbols '#', and any cell with symbol '#' must belong to some cross. No two crosses can share a cell.

Please, tell Ciel if she can draw the crosses in the described way.
The first line contains an integer *n* (3 ≤ *n* ≤ 100) — the size of the board.

Each of the next *n* lines describes one row of the board. The *i*-th line describes the *i*-th row of the board and consists of *n* characters. Each character is either a symbol '.', or a symbol '#'.
n = int(input())
Matrix = []
for i in range(n):
    Matrix.append(list(input()))
m = [[0,0],[1,0],[2,0][1,1],[1,-1]]
for i in range(n):
    for j in range(n):
        if Matrix[i][j] == '#':
            mark = True
            for k in range(5):
                if i+m[k][0] < 0 or i+m[k][0] >= n or j+m[k][i] < 0 or j+m[k][i] >= n:
                    mark = False
                elif Matrix[i+m[k][0]][j+m[k][i]] != '#'
                    mark = False
            if mark:
                for k in range(5):
                    Matrix[i+m[k][0]][j+m[k][1]] = '.'

mark = True
for i in range(n):
    for j in range(n):
        if Matrix[i][j]=='#':
            mark=False
if mark:
    print("YES")
else:
    print("NO")

				 	  	 	    	 	 	  	   	 	