Fox Ciel has a board with *n* rows and *n* columns. So, the board consists of *n* × *n* cells. Each cell contains either a symbol '.', or a symbol '#'.

A cross on the board is a connected set of exactly five cells of the board that looks like a cross. The picture below shows how it looks.

Ciel wants to draw several (may be zero) crosses on the board. Each cross must cover exactly five cells with symbols '#', and any cell with symbol '#' must belong to some cross. No two crosses can share a cell.

Please, tell Ciel if she can draw the crosses in the described way.
The first line contains an integer *n* (3 ≤ *n* ≤ 100) — the size of the board.

Each of the next *n* lines describes one row of the board. The *i*-th line describes the *i*-th row of the board and consists of *n* characters. Each character is either a symbol '.', or a symbol '#'.
n = int(input())
m = [list(input()) for i in range(n)]

def test(m, n):
  for r in range(n):
    for c in range(n):
      if m[r][c] == "#":
        if c == 0 or c == n - 1 or r >= n - 2:
          return False
        elif (m[r+1][c-1] == "#") and (m[r+1][c] == "#") and (m[r+1][c+1] == "#") and (m[r+2][c] == "#") :
             m[r+1][c-1] = "."
             m[r+1][c]   = "."
             m[r+1][c+1] = "."
             m[r+2][c]   = "."
        else:
          return False
  return True
  
print("YES" if test(m) else "NO")