Fox Ciel has a board with *n* rows and *n* columns. So, the board consists of *n* × *n* cells. Each cell contains either a symbol '.', or a symbol '#'.

A cross on the board is a connected set of exactly five cells of the board that looks like a cross. The picture below shows how it looks.

Ciel wants to draw several (may be zero) crosses on the board. Each cross must cover exactly five cells with symbols '#', and any cell with symbol '#' must belong to some cross. No two crosses can share a cell.

Please, tell Ciel if she can draw the crosses in the described way.
The first line contains an integer *n* (3 ≤ *n* ≤ 100) — the size of the board.

Each of the next *n* lines describes one row of the board. The *i*-th line describes the *i*-th row of the board and consists of *n* characters. Each character is either a symbol '.', or a symbol '#'.
n = int(input())
s = []
for _ in range(n):
    s.append(list(input()))
#print(s)
for i in range(n):
    for j in range(n):
        if s[i][j]=='#':
            if i>n-3:
                print('NO')
                exit(0)
            if j==0 or j==n-1:
                print('NO')
                exit(0)
            if s[i+1][j-1]=='#' and s[i+1][j]=='#' and s[i+1][j+1]=='#' and s[i+2][j]=='#':
                s[i + 1][j - 1] = '.'
                s[i + 1][j] = '.'
                s[i + 1][j + 1] = '.'
                s[i + 2][j] = '.'
            else:
                print('NO')
                exit(0)
print('YES')