You have number *a*, whose decimal representation quite luckily contains digits 1, 6, 8, 9. Rearrange the digits in its decimal representation so that the resulting number will be divisible by 7.

Number *a* doesn't contain any leading zeroes and contains digits 1, 6, 8, 9 (it also can contain another digits). The resulting number also mustn't contain any leading zeroes.
The first line contains positive integer *a* in the decimal record. It is guaranteed that the record of number *a* contains digits: 1, 6, 8, 9. Number *a* doesn't contain any leading zeroes. The decimal representation of number *a* contains at least 4 and at most 10<sup class="upper-index">6</sup> characters.
from itertools import permutations
def seven(n):
    ans=[]
    n=n.replace("1","",1)
    n = n.replace("6", "", 1)
    n = n.replace("8", "", 1)
    n = n.replace("9", "", 1)
    lst=[str(i) for i in str(1689)]
    p=list(permutations(lst))
    val=["".join(i) for i in p]
    if n=="0":
        return 18690
    for i in val:
        temp=int(n+i)
        if temp%7==0:
            return temp
    return 0


print(seven(input()))