You have number *a*, whose decimal representation quite luckily contains digits 1, 6, 8, 9. Rearrange the digits in its decimal representation so that the resulting number will be divisible by 7.

Number *a* doesn't contain any leading zeroes and contains digits 1, 6, 8, 9 (it also can contain another digits). The resulting number also mustn't contain any leading zeroes.
The first line contains positive integer *a* in the decimal record. It is guaranteed that the record of number *a* contains digits: 1, 6, 8, 9. Number *a* doesn't contain any leading zeroes. The decimal representation of number *a* contains at least 4 and at most 10<sup class="upper-index">6</sup> characters.
a = input()

c = len(a) - len(a.strip('0'))

a = a.strip('0')

v = []
for i in "1689":
	v.append(a.find(i))

v.sort()

m = ["", "1869", "1968", "1689", "6198", "1698", "1986", "1896"]
k = a[:v[0]] + a[v[0]+1 : v[1]] + a[v[1]+1 : v[2]] + a[v[2]+1 : v[3]] + a[v[3]+1:]
if (k == ""):
	l = 0
else:
	l = int(k)
print(k + m[7 - (l*10000 % 7)] + "0"*c)

     								 		 		 	  			 		