You have number *a*, whose decimal representation quite luckily contains digits 1, 6, 8, 9. Rearrange the digits in its decimal representation so that the resulting number will be divisible by 7.

Number *a* doesn't contain any leading zeroes and contains digits 1, 6, 8, 9 (it also can contain another digits). The resulting number also mustn't contain any leading zeroes.
The first line contains positive integer *a* in the decimal record. It is guaranteed that the record of number *a* contains digits: 1, 6, 8, 9. Number *a* doesn't contain any leading zeroes. The decimal representation of number *a* contains at least 4 and at most 10<sup class="upper-index">6</sup> characters.
# https://codeforces.com/problemset/problem/375/A

from itertools import permutations


def div_seven(a):
    if (int(a) % 7 == 0):
        return a
    a = list(a)
    check = 0
    for p in permutations(a):
        temp = ''.join(i for i in p)
        if (len(temp) == len(a)):
            if (int(temp) % 7 == 0):
                print(temp)
                check = 1
                break
    if (check == 0):
        print(0)


a = input().strip()
print(div_seven(a))
