You have number *a*, whose decimal representation quite luckily contains digits 1, 6, 8, 9. Rearrange the digits in its decimal representation so that the resulting number will be divisible by 7.

Number *a* doesn't contain any leading zeroes and contains digits 1, 6, 8, 9 (it also can contain another digits). The resulting number also mustn't contain any leading zeroes.
The first line contains positive integer *a* in the decimal record. It is guaranteed that the record of number *a* contains digits: 1, 6, 8, 9. Number *a* doesn't contain any leading zeroes. The decimal representation of number *a* contains at least 4 and at most 10<sup class="upper-index">6</sup> characters.
from itertools import permutations as pp

n = input()

a = sorted([n.find('1'), n.find('6'), n.find('8'), n.find('9')])
d = list(map(str, [1, 6, 8, 9]))

for p in pp(d):
    x = n[:a[0]] + p[0] + n[a[0] + 1:a[1]] + p[1] + n[a[1] + 1:a[2]] + p[2] + \
            n[a[2] + 1:a[3]] + p[3] + n[a[3] + 1:]
    if int(x) % 7 == 0:
        print(x)
        break
