Fox Ciel has a board with *n* rows and *n* columns. So, the board consists of *n* × *n* cells. Each cell contains either a symbol '.', or a symbol '#'.

A cross on the board is a connected set of exactly five cells of the board that looks like a cross. The picture below shows how it looks.

Ciel wants to draw several (may be zero) crosses on the board. Each cross must cover exactly five cells with symbols '#', and any cell with symbol '#' must belong to some cross. No two crosses can share a cell.

Please, tell Ciel if she can draw the crosses in the described way.
The first line contains an integer *n* (3 ≤ *n* ≤ 100) — the size of the board.

Each of the next *n* lines describes one row of the board. The *i*-th line describes the *i*-th row of the board and consists of *n* characters. Each character is either a symbol '.', or a symbol '#'.
def produs_cifre(numar):
 
 produs=1
 for i in numar:
  produs=produs*int(i)
 return (produs)
 
 
 
 
 
 
#z=int(input())
#n,m=list(map(int,input().split()))
n=int(input())
matrix=[]
a=[]
for i in range(0,n):
 stringul=input()
 a=[]
 for l in stringul:
  a.append(l)
 matrix.append(a)


#print(matrix)


 
adev=1
if n<3:
 adev=0
 
for i in range (0,n):
 for j in range(0,n):
 # print(i,j)
  if matrix[i][j]=='#' and (j==0 or j==n-1 or i>n-2):
   adev=0
   break
  elif matrix[i][j]=='#':
   if matrix[i+1][j]!="#" or matrix[i+2][j]!="#" or matrix[i+1][j-1]!="#" or matrix[i+1][j+1]!="#":
    adev=0
    break
   else:
    matrix[i][j]='>'
    matrix[i+1][j]='>' 
    matrix[i+2][j]='>'  
    matrix[i+1][j-1]='>'  
    matrix[i+1][j+1]='>'


if adev==0:
 print("NO")
else:
 print("YES")
 
 
#for i in range(0,n):
 #for j in range(0,n):
  #print(matrix[i][j],end=' ')
 #print()
 
#print(matrix)

