Chubby Yang is studying linear equations right now. He came up with a nice problem. In the problem you are given an *n* × *n* matrix *W*, consisting of integers, and you should find two *n* × *n* matrices *A* and *B*, all the following conditions must hold: 
 -  *A*<sub class="lower-index">*ij*</sub> = *A*<sub class="lower-index">*ji*</sub>, for all *i*, *j* (1 ≤ *i*, *j* ≤ *n*); -  *B*<sub class="lower-index">*ij*</sub> =  - *B*<sub class="lower-index">*ji*</sub>, for all *i*, *j* (1 ≤ *i*, *j* ≤ *n*); -  *W*<sub class="lower-index">*ij*</sub> = *A*<sub class="lower-index">*ij*</sub> + *B*<sub class="lower-index">*ij*</sub>, for all *i*, *j* (1 ≤ *i*, *j* ≤ *n*). 
Can you solve the problem?
The first line contains an integer *n* (1 ≤ *n* ≤ 170). Each of the following *n* lines contains *n* integers. The *j*-th integer in the *i*-th line is *W*<sub class="lower-index">*ij*</sub> (0 ≤ |*W*<sub class="lower-index">*ij*</sub>| &lt; 1717).
n=int(input())
w=[]
for i in range(n):
    w.append([int(i) for i in input().split()])
a=[[0 for i in range(n)]for j in range(n)]
b=[[0 for i in range(n)]for j in range(n)]
for i in range(n):
    a[i][i]=w[i][i]
for i in range(n-1):
    for j in range(i+1,n):
        x=(w[i][j]+w[j][i])/2
        y=(w[i][j]-w[j][i])/2
        a[i][j]=x
        a[j][i]=x
        b[i][j]=y
        b[j][i]=-y
for i in a:
    for j in i:
        print(j,'',end='')
    print()
for i in b:
    for j in i:
        print(j,'',end='')
    print()