Fox Ciel has a board with *n* rows and *n* columns. So, the board consists of *n* × *n* cells. Each cell contains either a symbol '.', or a symbol '#'.

A cross on the board is a connected set of exactly five cells of the board that looks like a cross. The picture below shows how it looks.

Ciel wants to draw several (may be zero) crosses on the board. Each cross must cover exactly five cells with symbols '#', and any cell with symbol '#' must belong to some cross. No two crosses can share a cell.

Please, tell Ciel if she can draw the crosses in the described way.
The first line contains an integer *n* (3 ≤ *n* ≤ 100) — the size of the board.

Each of the next *n* lines describes one row of the board. The *i*-th line describes the *i*-th row of the board and consists of *n* characters. Each character is either a symbol '.', or a symbol '#'.
def check(i, j):
    global matrix, n
    if j==0 or j==n-1 or i>n-3:
        return False
    matrix[i][j] = '.'
    matrix[i+1][j] = '.'
    matrix[i+2][j] = '.'
    matrix[i+1][j-1] = '.'
    matrix[i+1][j+1] = '.'
    return True
    

n = int(input())

matrix = []

for i in range(n):
    l = list(input())
    matrix.append(l)

ans = True
for i in range(n):
    for j in range(n):
        if matrix[i][j] == '#':
            ans = check(i, j)
            if not ans:
                break

if ans:
    print("YES")
else:
    print("NO")

 	  			 		 	 	 		   	 		 	    	