Fox Ciel has a board with *n* rows and *n* columns. So, the board consists of *n* × *n* cells. Each cell contains either a symbol '.', or a symbol '#'.

A cross on the board is a connected set of exactly five cells of the board that looks like a cross. The picture below shows how it looks.

Ciel wants to draw several (may be zero) crosses on the board. Each cross must cover exactly five cells with symbols '#', and any cell with symbol '#' must belong to some cross. No two crosses can share a cell.

Please, tell Ciel if she can draw the crosses in the described way.
The first line contains an integer *n* (3 ≤ *n* ≤ 100) — the size of the board.

Each of the next *n* lines describes one row of the board. The *i*-th line describes the *i*-th row of the board and consists of *n* characters. Each character is either a symbol '.', or a symbol '#'.
n = int(input())
a = [[0] * n for i in range(n)]
ans = 'YES'
for i in range(n):
    s = input()
    for j in range(n):
        if s[j] == '#':
            a[i][j] = 1
#print(a)
for i in range(n - 2):
    for j in range(1, n - 1):
        if a[i][j] == 1:
            if a[i + 1][j] == 1 and a[i + 2][j] == 1 and a[i + 1][j - 1] == 1 and a[i + 1][j + 1] == 1:
                a[i][j] = 0
                a[i + 1][j] = 0
                a[i + 2][j] = 0
                a[i + 1][j - 1] = 0
                a[i + 1][j + 1] = 0
            else:
                ans = 'NO'
#print(a)
for i in range(n):
    if sum(a[i]) != 0:
        ans = 'NO'
print(ans)
                