Fox Ciel has a board with *n* rows and *n* columns. So, the board consists of *n* × *n* cells. Each cell contains either a symbol '.', or a symbol '#'.

A cross on the board is a connected set of exactly five cells of the board that looks like a cross. The picture below shows how it looks.

Ciel wants to draw several (may be zero) crosses on the board. Each cross must cover exactly five cells with symbols '#', and any cell with symbol '#' must belong to some cross. No two crosses can share a cell.

Please, tell Ciel if she can draw the crosses in the described way.
The first line contains an integer *n* (3 ≤ *n* ≤ 100) — the size of the board.

Each of the next *n* lines describes one row of the board. The *i*-th line describes the *i*-th row of the board and consists of *n* characters. Each character is either a symbol '.', or a symbol '#'.
import sys

n = int(sys.stdin.readline())
lines = []
for i in range(n):
    lines.append(list(sys.stdin.readline().strip()))
    
def check(lines, x, y, n):
    if x < 0 or x >= n or y < 0 or y >= n:
        return False
    if lines[x][y] != '#':
        return False
    lines[x][y] = '.'
    return True
    
def tryPaint(lines, i, j, n):
    return check(lines, i, j, n) and \
        check(lines, i-1, j+1, n) and \
        check(lines, i, j+1, n) and \
        check(lines, i+1, j+1, n) and \
        check(lines, i, j+2, n)
    
failed = False
    
for j in range(n):
    for i in range(n):
        if lines[i][j] == '#':
            if not tryPaint(lines, i, j, n):
                failed = True
                break
        if failed:
            break

if not failed:
    for i in range(n):
        if "#" in set(lines[i]):
            failed = True
            break

if failed:
    print("NO")
else:
    print("YES")
            
      
